f(x) = sin (x+1) f(x+h)=sin (x+h+1) f'x =limh-0 f(x+h)-f(x)/h f'x= lim h-0 sin (x+h+ 1) - sin (x+1) /h Lim h-0 2cos (2x+h+2 /2) sin(h/2) /h Lim h-0 cos (x+1+h/2 ) Lim h/2-0 ( sin h/2/h/2 ) h-0 =h/2 - o/2 =0 Hence cos (x+1) ..

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Nancy Rajput 5 years, 3 months ago

pls its urgent ?

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Nancy Rajput 5 years, 3 months ago

by using this formulae f'x=lim x-->xf(t)-f(x)/t-x

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