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If a+b+c=1 and ab+bc+ca=1/3 find a:b:c

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If a+b+c=1 and ab+bc+ca=1/3 find a:b:c
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Yaar 5 years, 4 months ago

(a+b+c)^2=1^2; = a^2+ b^2+ c^2+ 2ab+ 2bc+ 2ca= 1; = ab + bc + ca = 1- a^2- b^2 -c^2 /2; = 1/3 a^2 + b^2 + c^2 = -2/3 + 1 = 1/3 ab + bc + ca = a^2 + b^2 + c^2 On comparison, a^2 = ab, b^2 = bc, c^2 = ac So a = b, b = c, c = a a : b : c = 1 : 1 : 1
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