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If a parallelogram and a triangle …

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If a parallelogram and a triangle are on the common base and between the same parallels,then prove that the area of the triangle is equal to half the area of the parallelogram.
  • 1 answers

Jayavel Arumugam 5 years, 4 months ago

Let ΔABP and a parallelogram ABCD be on the same base AB and between the same parallels AB and PC. To Prove : ar( ΔPAB ) = (1/2)ar( ABCD) Draw BQ ||AP to obtain another parallelogram.ABQP and ABCD are on the same base AB and between the same parallels AB and PC. There fore, ar(ABQP) = ar(ABCD) But ΔPAB ≅ ΔBQP( Diagonals PB divides parallelogram ABQP into two congruent triangles. So ar (PAB) = ar(BQP) -----------(2) ∴ ar (PAB) = (1/2)ar(ABQP) -----------------(3) [ from (2)] This gives ar (PAB) = (1/2)ar(ABCD) [ from (1) and (3)]
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