In what ratio does the point …
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Posted by Shivkumar Sharma 4 years, 8 months ago
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Sia ? 4 years, 8 months ago
Let (-4, 6) divide AB internally in the ratio k:1. Using the section formula, we get
{tex}( - 4,6 ) = \left( \frac { 3 k - 6 } { k + 1 } , \frac { - 8 k + 10 } { k + 1 } \right){/tex}
So, {tex}- 4 = \frac { 3 k - 6 } { k + 1 }{/tex}
i.e., -4k - 4 = 3k - 6
i.e., 7k = 2
i.e., k:1 = 2:7
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