Derived formula of kinetic energy
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Posted by Ashutosh Ranjan 5 years, 4 months ago
- 2 answers
Yogita Ingle 5 years, 4 months ago
The relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, S is v2 - u2 = 2aS
This gives S = (v 2 - u 2)/ 2a
We know F = ma. Thus using above equations, we can write the workdone by the force, F as
W = ma × (v 2 - u 2)/ 2a
or
W = 1 /2 m( v 2 - u 2 )
If object is starting from its stationary position, that is, u = 0, then
W = 1/ 2 m v 2
It is clear that the work done is equal to the change in the kinetic energy of an object.
If u = 0, the work done will be W = 1 /2 m v 2 .
Thus, the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is Ek = ½ mv2
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Zgncjfici Bjfifkci 5 years, 3 months ago
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