In triangle abc angle a+angle b …
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Tanya Singla 6 years, 6 months ago
Given: a+b=120
Therefore, b=120-a ---Eqn 1
and, a+c=130
Therefore, c=130-a ---Eqn 2
Since we know that the sum of angles of a triangle is 1800
=> a+b+c=1800 ---Eqn 3
Putting values of b and c from Eqn 1 and Eqn 2 in Eqn 3
=> a+1200 -a+1300-a = 1800
=> 2500 -a =1800
=> -a = 1800 - 2500
=> angle a= 700
Now putting value of angle a in Eqn 1 and Eqn 2, we get
angle b= 120-70= 500 and
angle c= 130-70= 600
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