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PQR is a right angled triangle …

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PQR is a right angled triangle right angled at Q.PQ=5cm, QR=12cm.A circle with centre O is inscribed in ΔPQR, touching its ll sides.Find the radius of the circle.

    • Posted by Perni Soma Akash 5 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Yagyanshu Yadav 5 years, 5 months ago

    What

    1Thank You

    Yagyanshu Yadav 5 years, 5 months ago

    (PQ)^2+(QR)^2=(PR)^2 (5)^2+(12)^2=(PR)^2 13=PR let the centre of circle be O and radius be"r" ar(por)+ar(qor)+ar(poq)=ar(PQR) 1/2*13*r+1/2*5*r+1/2*12*r=√15(15-12)+(15-5)(15-13) 15r=30 r=2

    3Thank You

    Abhinav Bhargav 5 years, 5 months ago

    I don't know

    1Thank You

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