There has number 1 to 8 find,

1   probabolity of 7

2   even no

3    multiple of 3

4    factor of 28

Posted by Rathi Kajal (Mar 20, 2017 10:57 p.m.) (Question ID: 4277)

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  • Ans. Total number = 8

    (1) No of favourable case for 7 = 1

    P(7) = 1/8

    (2) total even numbers = 4

    P(even No) = 4/8 = 1/2

    (3) Total multiple of 3 = 2

    P(Multiple of 3) = 2/8 = 1/4

    (4) Factors of 28 = 2

    P(Factor of 28) = 2/8 = 1/4

    Answered by Naveen Sharma (Mar 21, 2017 7:05 a.m.)
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