No products in the cart.

find the value of p when …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

find the value of p when the distance between the A(3,p) B(4,1)is underroot 10
  • 1 answers

Sia ? 4 years, 9 months ago

We have P(3, a) and Q(4,1)
Here, 
x1 = 3, y1 = a
x2 = 4, y2 = 1
PQ = {tex}\sqrt { 10 }{/tex}
{tex}P Q = \sqrt { \left( x _ { 2 } - x _ { 1 } \right) ^ { 2 } + \left( y _ { 2 } - y _ { 1 } \right) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad \sqrt { 10 } = \sqrt { ( 4 - 3 ) ^ { 2 } + ( 1 - a ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad \sqrt { 10 } = \sqrt { ( 1 ) ^ { 2 } + ( 1 - a ) ^ { 2 } }{/tex}
{tex}\Rightarrow \quad \sqrt { 10 } = \sqrt { 1 + 1 + a ^ { 2 } - 2 a }{/tex} 
{tex}\Rightarrow \quad \sqrt { 10 } = \sqrt { 2 + a ^ { 2 } - 2 a }{/tex}
Squaring both sides
{tex}\Rightarrow ( \sqrt { 10 } ) ^ { 2 } = \left( \sqrt { 2 + a ^ { 2 } - 2 a } \right) ^ { 2 }{/tex}
{tex}\Rightarrow{/tex} 10 = 2 + a2 - 2a
{tex}\Rightarrow{/tex} {tex}a^2 - 2a + 2 - 10 = 0{/tex}
{tex}\Rightarrow{/tex} {tex}a^2 - 2a - 8 =0{/tex}
Splitting the middle term.
{tex}\Rightarrow{/tex} a2 - 4a + 2a - 8 = 0
{tex}\Rightarrow{/tex} {tex}a(a - 4) + 2 (a - 4)=0{/tex}
{tex}\Rightarrow{/tex} {tex}(a - 4)(a + 2) = 0{/tex}
{tex}\Rightarrow{/tex}{tex} a = 4, a = -2{/tex}

http://mycbseguide.com/examin8/

Related Questions

[ ]/[ ] of 125 =100
  • 0 answers
3×+2y=5
  • 1 answers
X²-3x-4=0
  • 0 answers
2x-3y=8 answer
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App