A train starting from rest moves ...

A train starting from rest moves with a uniform acceleration of 0.2m/s for five minutes. Calculate the speed acquired and the distance travelled in this time
  • 2 answers
U = 0 A = 0.2m/s^2 t = 5×60=300 sec V=? S=? From second equation S = ut +1/2at^2 = 1/2 0.2 × 90000 = 9000m From third equation V^2 = u^2 + 2as = 2× 0.2 × 9000 = 3600m/s

Krish Mittal 1 year ago

Tmkc

Related Questions:

What is ion??🤔
  • 3 answers
Si unit of impulse
  • 1 answers
What is life
  • 1 answers
Easy and clear define of science
  • 2 answers
What is the molecular formula of iron oxide
  • 2 answers
What is h0mogenious
  • 2 answers

Buy Complete Study Pack

Subscribe complete study pack and get unlimited access to selected subjects. Effective cost is only ₹ 12.5/- per subject per month. Based on the latest CBSE & NCERT syllabus.

CBSE Guide App

Install myCBSEguide mobile app for FREE sample papers, Test Papers, Revision Notes, Previous year question papers, NCERT solutions and MCQ tests

myCBSEguide App

CBSE Test Generator

Create papers in minutes

Print with your name & Logo

Download as PDF

3 Lakhs+ Questions

Solutions Included

Based on CBSE Blueprint

Best fit for Schools & Tutors

Work from Home

  • Work from home with us
  • Create questions or review them from home

No software required, no contract to sign. Simply apply as teacher, take eligibility test and start working with us. Required desktop or laptop with internet connection