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A train starting from rest moves …

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A train starting from rest moves with a uniform acceleration of 0.2m/s for five minutes. Calculate the speed acquired and the distance travelled in this time

Posted by Aditya Arju 5 years, 11 months ago

CBSE > Class 09 > Science

2 answers

Muskan Sarawagi 5 years, 11 months ago

U = 0 A = 0.2m/s^2 t = 5×60=300 sec V=? S=? From second equation S = ut +1/2at^2 = 1/2 0.2 × 90000 = 9000m From third equation V^2 = u^2 + 2as = 2× 0.2 × 9000 = 3600m/s

Krish Mittal 5 years, 11 months ago

Tmkc

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