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Sec8x-1/sec4x-1=tan8x/tan2x.. Prove

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Sec8x-1/sec4x-1=tan8x/tan2x.. Prove

    • Posted by Prashant Kumar 6 years, 8 months ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Abhishek Yadav 6 years, 8 months ago

    L.H.S. ={(1-cos8x)×cos4x}/{(1-cos4x)×cos8x} ={(1-(1-2sin^2 4x))×cos4x}/{(1-(1-2sin^2 2x))×cos8x} ={(2sin^2 4x)×cos4x}/{(2sin^2 2x)×cos8x} ={(2sin4x cos4x)×sin4x}/{(2sin^2 2x)× cos4x} ={(sin8x)×sin4x}/{(2sin^2 2x)×cos8x} ={tan8x×(2sin2x cos2x)/{2sin^2 2x} ={tan8x}/{sin2x/cos2x} ={tan8x}/{tan2x} =R.H.S.

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