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A road roller takes 750 complete …

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A road roller takes 750 complete revolutions to move once over to level a road.find the area of the road if the diameter of a road roller is 84 cm and length is 1 m

Posted by Karthikeya Chowdary 6 years, 9 months ago

CBSE > Class 08 > Mathematics

2 answers

Palak Kalantri 6 years, 9 months ago

diameter=84 radius=42 h=1m=100 cm LSA=2 pie r h =2×22÷7×42×100 1 revolution=26400 cm square total revolution=26400×750=19800000 =19800000÷100×100=1980 m square

Isheta Singh 6 years, 9 months ago

Area covered by road roller in one Revolution =curved surface area of cylinder. =2pie rh =2*22/7*42*100 =44*600 =26400cm square Area of road in 750 revolutions=26400*750 =19800000cm square =1980 m square

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