( sinA+cosA) ( tanA + cotA …

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( sinA+cosA) ( tanA + cotA )= secA+ cosecA

Posted by M J 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Amaira Khan 6 years, 9 months ago

(sinA+cosA)(sin a /cos a + cos a/ sin a) (Sin a+cos a) (1/sina.cos a) (Sin a/sin a. Cos a.+cos a/sin. Cos) (1/cos a +1sin a) (Sec a+cosec a)

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