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If sinA =4/5,find the value of …

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If sinA =4/5,find the value of 16+16cot^2A

    • Posted by Majunath Bm 6 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Majunath Bm 6 years, 9 months ago

    Let ABC be a right angle triangle,right angled at B Therefore sinA =BC/AC=4/5 AC^2=BC^2+AB^2 25=16+AB^2 AB^2=9 AB=3 CotA=3/4 16+16cot^2A =16+16(3/4)^2 =16+16(9/16) =16+9=25

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