No products in the cart.

A rectangular sheet of paper 40cm …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

A rectangular sheet of paper 40cm * 22cm ,is rolled to form a hollow cylinder of height 40cm. The radius of the cylinder ( in cm ) is
  • 1 answers

Nandini Verma 6 years, 9 months ago

H = 40 cm when the sheet is rolled 22 cm becomes the circumference of the base circles. circumference = 22 cm 2 π r = 22 cm 2×22/7×r = 22 cm r = 22×1/2×7/22 r = 7/2 r = 3.5
http://mycbseguide.com/examin8/

Related Questions

Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers
(A + B )²
  • 1 answers
Water
  • 0 answers
Venu Gopal has twice
  • 0 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
X-y=5
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App