The melting point of three members …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
The melting point of three members A, B and C of a homologous series of hydrocarbons are -183degree Celsius, -138degree Celsius and -130degree Celsius respectively. Which one of the three would have the lowest no of carbon atoms in its molecule. Explain.
Posted by Priyanshi Singh 6 years, 2 months ago
- 0 answers
ANSWER
Related Questions
Posted by Mannat Gill 12 hours ago
- 0 answers
Posted by Sss Sss 2 days, 4 hours ago
- 1 answers
Posted by Anuj Gupta 1 day, 4 hours ago
- 0 answers
Posted by Mukesh Kumar Mukesh Kumar 12 hours ago
- 1 answers
Posted by Rachit Aglawe 2 days, 1 hour ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app