Show that (cos2@- sin2@) = 2tan@/1-tan2@ …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Himanshu Jha 4 years, 9 months ago
- 1 answers
Related Questions
Posted by Anmol Kaushal 1 day, 5 hours ago
- 0 answers
Posted by Jasmine Kaur 1 day, 22 hours ago
- 0 answers
Posted by Kangna Gautam 1 day, 1 hour ago
- 0 answers
Posted by Udaya Peethala 2 days ago
- 0 answers
Posted by Ritika Jain 18 hours ago
- 0 answers
Posted by Bhavan King 3 days, 15 hours ago
- 1 answers
Posted by Geetanjali Mathpal 3 days, 15 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 4 years, 9 months ago
Putting {tex}\theta{/tex} = 30°, we find:
L.H.S. = (cos230° - sin230°)
{tex}= \left\{ \left( \frac { \sqrt { 3 } } { 2 } \right) ^ { 2 } - \left( \frac { 1 } { 2 } \right) ^ { 2 } \right\} = \left( \frac { 3 } { 4 } - \frac { 1 } { 4 } \right) = \frac { 2 } { 4 } = \frac { 1 } { 2 }{/tex}, and
R.H.S. = {tex} \frac { 2 \tan 30 ^ { \circ } } { \left( 1 - \tan ^ { 2 } 30 ^ { \circ } \right) } = \frac { 2 \times \frac { 1 } { \sqrt { 3 } } } { \left[ 1 - \left( \frac { 1 } { \sqrt { 3 } } \right) ^ { 2 } \right] } = \frac { \frac { 2 } { \sqrt { 3 } } } { \left( 1 - \frac { 1 } { 3 } \right) } = \left( \frac { 2 } { \sqrt { 3 } } \times \frac { 3 } { 2 } \right) = \sqrt { 3 }{/tex}
{tex}\therefore{/tex} L.H.S. {tex}\neq{/tex} R.H.S.
Hence, the given equation is not an identity.
0Thank You