Solve the equation by factorisation x^2+(b/a-b+a-b/b)x+1=0.
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Posted by Bhawani Kumawat 4 years, 9 months ago
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Sia ? 4 years, 9 months ago
We have, {tex}x^2 +({a \over a+b}+ {a+b \over a})x +1 = 0{/tex}
{tex}\implies x^2 + {a \over a+b}x + {a+b \over a}x + 1=0{/tex}
{tex}\implies x (x + {a \over a+b}) +{a+b \over a}(x + {a \over a+b}) = 0 {/tex}
{tex}\implies (x + {a \over a+b}) (x +{a+b \over a}) = 0{/tex}
{tex}Either \, x + {a \over a+b} = 0 \,or\, x + {a+b \over a}=0{/tex}
{tex}\implies x = -{a \over a+b} ,\, - {a+b \over a}{/tex}
{tex}\therefore x = -{a \over a+b} ,\, - {a+b \over a}{/tex} are the required roots.
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