find the value of k so …
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Sia ? 4 years, 10 months ago
2x2 + kx +3=0
We know that quadratic equation has two equal roots only when the value of discriminant is equal to zero.
Comparing equation 2x 2 +kx +3=0 with general quadratic equation ax2 + bx + c =0, we get a = 2, b = k and c = 3
Discriminant = b2 − 4ac = k2 - 4(2)(3) = k2 - 24
Putting discriminant equal to zero
k2 - 24 = 0 ⇒ k2 = 24
{tex}\Rightarrow k = \pm \sqrt { 24 } = \pm 2 \sqrt { 6 } \Rightarrow k = 2 \sqrt { 6 } , - 2 \sqrt { 6 }{/tex}
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