Show that 12n cannot end with …
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Posted by Riddham Dalal 4 years, 10 months ago
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Sia ? 4 years, 10 months ago
12 = 22 {tex}\times{/tex} 3
{tex}\therefore 12^n=(2^2 \times3)^n=(2^2)^n \times3^n{/tex}
So, only primes in the factorisation of 12n are 2 and 3 and, not 5.
Hence, 12n cannot end with digit 0 or 5.
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