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Tan+sin/tan-sin=sec+1/sec-1

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Tan+sin/tan-sin=sec+1/sec-1

Posted by Anshuman Singh 4 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 4 years, 10 months ago

<address>{tex}\text { L.H.S. } = \frac { \tan \theta + \sin \theta } { \tan \theta - \sin \theta } = \frac { \frac { \sin \theta } { \cos \theta } + \sin \theta } { \frac { \sin \theta } { \cos \theta } - \sin \theta }{/tex}
{tex}= \frac { \sin \theta \left( \frac { 1 } { \cos \theta } + 1 \right) } { \sin \theta \left( \frac { 1 } { \cos \theta } - 1 \right) } = \frac { \sec \theta + 1 } { \sec \theta - 1 } = R . H S{/tex}</address>

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