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Om Rajput 2 months ago

Given:ABCD is parallelogram AC=BD(diagonal of parallelogram ) Proof:ABCD is rectangle In ∆ ABD and ∆ ABC AC=BD (given) AD=BC ( opposite side of parallelogram) AB=AB (Common) ∆ ABD and ∆ ABC (S.S.S) DAB=CAB ( CPCT ) DAB+CAB=180 DAB+DAB=180 2DAB=180 DAB=90 So, A=B=C=D ABCD is a rectangle

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