{"id":5016,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-9-maths-exercise-4-1\/"},"modified":"2018-06-18T10:56:16","modified_gmt":"2018-06-18T05:26:16","slug":"ncert-solutions-for-class-9-maths-exercise-4-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Exercise 4.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#_NCERT_Solutions_for_Class_9_Mathematics_Linear_Equations_in_Two_Variables\" >\u00a0NCERT Solutions for Class 9 Mathematics\u00a0Linear Equations in Two Variables<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#1_The_cost_of_a_notebook_is_twice_the_cost_of_a_pen_Write_a_linear_equation_in_two_variables_to_represent_this_statement\" >1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#Take_the_cost_of_a_notebook_to_be_Rs_x_and_that_of_a_pen_to_be_Rs_y\" >(Take the cost of a notebook to be Rs x and that of a pen to be Rs y).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#2_Express_the_following_linear_equations_in_the_form_ax_by_c_0_and_indicate_the_values_of_a_b_and_c_in_each_case\" >2. Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#ii\" >(ii)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#iii\" >(iii)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#iv\" >(iv)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#v\" >(v)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#vi\" >(vi)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#vii\" >(vii)<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#NCERT_Solutions_for_Class_9_Maths_Exercise_41\" >NCERT Solutions for Class 9 Maths Exercise 4.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 9 Maths Exercise 4.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 9 Maths\u00a0<\/strong><strong>Linear Equations in Two Variables\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-mathematics-linear-equations-in-two-variables\/1238\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Class_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 9 Maths Exercise 4.1\" width=\"174\" height=\"224\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"_NCERT_Solutions_for_Class_9_Mathematics_Linear_Equations_in_Two_Variables\"><\/span>\u00a0NCERT Solutions for Class 9 Mathematics\u00a0Linear Equations in Two Variables<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"1_The_cost_of_a_notebook_is_twice_the_cost_of_a_pen_Write_a_linear_equation_in_two_variables_to_represent_this_statement\"><\/span><strong>1. The cost of a notebook is twice the cost of a pen. Write a linear equation in two variables to represent this statement.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"Take_the_cost_of_a_notebook_to_be_Rs_x_and_that_of_a_pen_to_be_Rs_y\"><\/span><strong>(Take the cost of a notebook to be Rs <em>x <\/em>and that of a pen to be Rs <em>y<\/em>).<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let the cost of a notebook be<img decoding=\"async\" style=\"height: 21px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image001.png\" \/>.<\/p>\n<p style=\"text-align: justify;\">Let the cost of a pen be<img decoding=\"async\" style=\"height: 21px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image002.png\" \/>.<\/p>\n<p style=\"text-align: justify;\">We need to write a linear equation in two variables to represent the statement, \u201cCost of a notebook is twice the cost of a pen\u201d.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that the required statement will be<img decoding=\"async\" style=\"height: 21px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image003.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 4.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Express_the_following_linear_equations_in_the_form_ax_by_c_0_and_indicate_the_values_of_a_b_and_c_in_each_case\"><\/span><strong>2. Express the following linear equations in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c <\/em>in each case:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) <img decoding=\"async\" style=\"height: 25px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image004.png\" \/> <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image005.png\" \/> <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <img decoding=\"async\" style=\"height: 21px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image006.png\" \/> <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iv) <img decoding=\"async\" style=\"height: 21px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image007.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(v) <img decoding=\"async\" style=\"height: 21px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image008.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(vi) <img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image009.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(vii) <img decoding=\"async\" style=\"height: 21px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image010.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(viii) <img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image011.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i) <\/strong><img decoding=\"async\" style=\"height: 25px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image004.png\" \/><\/p>\n<p>We need to express the linear equation<img decoding=\"async\" style=\"height: 25px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image004.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c.<\/em><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 25px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image004.png\" \/> can also be written as <img decoding=\"async\" style=\"height: 25px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 25px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image013.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 25px; width: 165px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image014.png\" \/>.<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"ii\"><\/span><strong>(ii) <\/strong><img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image005.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image005.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image005.png\" \/>can also be written as <img decoding=\"async\" style=\"height: 41px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 41px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image016.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 41px; width: 167px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image017.png\" \/>.<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"iii\"><\/span><strong>(iii) <\/strong><img decoding=\"async\" style=\"height: 21px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image006.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 21px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image006.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 21px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image006.png\" \/>can also be written as <img decoding=\"async\" style=\"height: 21px; width: 110px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image019.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image020.png\" \/>.<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"iv\"><\/span><strong>(iv) <\/strong><img decoding=\"async\" style=\"height: 21px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image007.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 21px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image007.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 21px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image007.png\" \/>can also be written as<img decoding=\"async\" style=\"height: 21px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image021.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image022.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image023.png\" \/>.<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"v\"><\/span><strong>(v) <\/strong><img decoding=\"async\" style=\"height: 21px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image008.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 21px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image008.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 21px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image008.png\" \/>can also be written as<img decoding=\"async\" style=\"height: 21px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image024.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image025.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 137px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image026.png\" \/>.<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"vi\"><\/span><strong>(vi) <\/strong><img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image009.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image009.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image009.png\" \/>can also be written as <img decoding=\"async\" style=\"height: 21px; width: 110px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image028.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 137px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image029.png\" \/>.<\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 4.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"vii\"><\/span><strong>(vii) <\/strong><img decoding=\"async\" style=\"height: 21px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image010.png\" \/><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 21px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image010.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 21px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image010.png\" \/>can also be written as <img decoding=\"async\" style=\"height: 21px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image030.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 111px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image031.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image032.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(viii) <\/strong><img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to express the linear equation<img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image011.png\" \/>in the form <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0 and indicate the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image011.png\" \/>can also be written as <img decoding=\"async\" style=\"height: 21px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\">We need to compare the equation<img decoding=\"async\" style=\"height: 21px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image034.png\" \/>with the general equation <em>ax <\/em>+ <em>by <\/em>+ <em>c <\/em>= 0, to get the values of <em>a<\/em>, <em>b <\/em>and <em>c<\/em>.<\/p>\n<p style=\"text-align: justify;\">Therefore, we can conclude that<img decoding=\"async\" style=\"height: 21px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/ch04\/Ex4.1\/image035.png\" \/>.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Maths_Exercise_41\"><\/span>NCERT Solutions for Class 9 Maths Exercise 4.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 9 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Maths Exercise 4.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter &#8230; <a title=\"NCERT Solutions for Class 9 Maths Exercise 4.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-4-1\/\" aria-label=\"More on NCERT Solutions for Class 9 Maths Exercise 4.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1376,281],"tags":[283,1344,321,1485,216],"class_list":["post-5016","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-09","category-ncert-solutions","tag-cbse-study-material","tag-class-9","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Maths Exercise 4.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Maths Exercise 4.1 in PDF format for free download. 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