{"id":4997,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-9-maths-exercise-13-9\/"},"modified":"2018-06-19T11:42:55","modified_gmt":"2018-06-19T06:12:55","slug":"ncert-solutions-for-class-9-maths-exercise-13-9","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Exercise 13.9"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\" >NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#1_A_wooden_bookshelf_has_external_dimensions_as_follows_Height_110_cm_Depth_25_cm_Breadth_85_cm_See_fig_The_thickness_of_the_planks_is_5_cm_everywhere_The_external_faces_are_to_be_polished_and_the_inner_faces_are_to_be_painted_If_the_rate_of_polishing_is_20_paise_per_cm2_and_the_rate_of_painting_is_10_paise_per_cm2_find_the_total_expenses_required_for_polishing_and_painting_the_surface_of_the_bookshelf\" >1. A wooden bookshelf has external dimensions as follows: Height = 110 cm, Depth = 25 cm, Breadth = 85 cm [See fig.]. The thickness of the planks is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per cm2 and the rate of painting is 10 paise per cm2, find the total expenses required for polishing and painting the surface of the bookshelf.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#2The_front_compound_wall_of_a_house_is_decorated_by_wooden_spheres_of_diameter_21_cm_placed_on_small_supports_as_shown_in_figure_Eight_such_spheres_are_used_for_this_purpose_and_are_to_be_painted_silver_Each_support_is_a_cylinder_of_radius_15_cm_and_height_7_cm_and_is_to_be_painted_black_Find_he_cost_of_paint_required_if_silver_paint_costs_25_paise_per_cm2_and_black_paint_costs_5_paise_per_cm2\" >2.The front compound wall of a house is decorated by wooden spheres of diameter 21 cm, placed on small supports as shown in figure. Eight such spheres are used for this purpose and are to be painted silver. Each support is a cylinder of radius 1.5 cm and height 7 cm and is to be painted black. Find he cost of paint required if silver paint costs 25 paise per cm2 and black paint costs 5 paise per cm2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#3_If_diameter_of_a_sphere_is_decreased_by_25_then_what_percent_does_its_curved_surface_area_decrease\" >3. If diameter of a sphere is decreased by 25% then what percent does its curved surface area decrease?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#4_Sameera_wants_to_celebrate_the_fifth_birthday_of_her_daughter_with_a_party_She_bought_thick_paper_to_make_the_conical_party_caps_Each_cap_is_to_have_a_base_diameter_of_10_cm_and_height_12_cm_A_sheet_of_the_paper_is_25_cm_by_40_cm_and_approximately_82_of_the_sheet_can_be_effectively_used_for_making_the_caps_after_cutting_What_is_the_minimum_number_of_sheets_of_paper_that_Sameera_would_need_to_buy_if_there_are_to_be_15_children_at_the_party\" >4. Sameera wants to celebrate the fifth birthday of her daughter with a party. She bought thick paper to make the conical party caps. Each cap is to have a base diameter of 10 cm and height 12 cm. A sheet of the paper is 25 cm by 40 cm and approximately 82% of the sheet can be effectively used for making the caps after cutting. What is the minimum number of sheets of paper that Sameera would need to buy, if there are to be 15 children at the party?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#NCERT_Solutions_for_Class_9_Maths_Exercise_139\" >NCERT Solutions for Class 9 Maths Exercise 13.9<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<div class=\"addtoany_share_save_container addtoany_content addtoany_content_top\">\n<div class=\"a2a_kit a2a_kit_size_50 addtoany_list\" data-a2a-url=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-1\/\" data-a2a-title=\"NCERT Solutions for Class 9 Maths Exercise 13.1\">NCERT Solutions for Class 9 Maths Exercise 13.9 solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/div>\n<\/div>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 9 Maths\u00a0<\/strong><strong>Surface Areas and Volumes\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-mathematics-surface-areas-and-volumes\/1247\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Class_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 9 Maths Exercise 13.9\" width=\"173\" height=\"223\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\"><\/span>NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6><span class=\"ez-toc-section\" id=\"1_A_wooden_bookshelf_has_external_dimensions_as_follows_Height_110_cm_Depth_25_cm_Breadth_85_cm_See_fig_The_thickness_of_the_planks_is_5_cm_everywhere_The_external_faces_are_to_be_polished_and_the_inner_faces_are_to_be_painted_If_the_rate_of_polishing_is_20_paise_per_cm2_and_the_rate_of_painting_is_10_paise_per_cm2_find_the_total_expenses_required_for_polishing_and_painting_the_surface_of_the_bookshelf\"><\/span><strong>1.<\/strong> <strong>A wooden bookshelf has external dimensions as follows: Height = 110 cm, Depth = 25 cm, Breadth = 85 cm [See fig.]. The thickness of the planks is 5 cm everywhere. The external faces are to be polished and the inner faces are to be painted. If the rate of polishing is 20 paise per cm<sup>2<\/sup> and the rate of painting is 10 paise per cm2, find the total expenses required for polishing and painting the surface of the bookshelf.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 147\" style=\"height: 209px; width: 217px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image001.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> External faces to be polished<\/p>\n<p>= Area of six faces of cuboidal bookshelf \u2013 3 (Area of open portion ABCD)<\/p>\n<p>= 2 (110 x 25 + 25 x 85 + 85 x 110) \u2013 3 (75 x 30)<\/p>\n[<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image002.png\" \/>AB = 85 \u2013 5 \u2013 5 = 75 cm and AD<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image003.png\" \/>x 110 \u2013 5 \u2013 5 \u2013 5 \u2013 5 = 30 cm]\n<p>= 2 (2750 + 2125 + 9350) \u2013 3 x 2250<\/p>\n<p>= 2 x 14225 \u2013 6750<\/p>\n<p>= 28450 \u2013 6750<\/p>\n<p>= 21700 cm<sup>2<\/sup><\/p>\n<p>Now, cost of painting outer faces of wodden bookshelf at the rate of 20 paise.<\/p>\n<p>= Rs. 0.20 per cm<sup>2<\/sup> = Rs. 0.20 x 21700 = Rs. 4340<\/p>\n<p>Here, three equal five sides inner faces.<\/p>\n<p>Therefore total surface area<\/p>\n<p>= 3 [ 2 (30 + 75) 20 + 30 x 75]\n[<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image002.png\" \/>Depth = 25 \u2013 5 = 20 cm]\n<p>= 3 [ 2 x 105 x 20 + 2250] = 3<\/p>\n[ 4200 + 2250]\n<p>= 3 x 6450 = 19350 cm<sup>2<\/sup><\/p>\n<p>Now, cost of painting inner faces at the rate of 10 paise i.e. Rs. 0.10 per cm<sup>2<\/sup>.<\/p>\n<p>= Rs. 0.10 x 19350 = Rs. 1935<\/p>\n<p>Total expenses required = Rs. 4340 + Rs. 1935 = Rs. 6275<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.9<\/p>\n<h6><span class=\"ez-toc-section\" id=\"2The_front_compound_wall_of_a_house_is_decorated_by_wooden_spheres_of_diameter_21_cm_placed_on_small_supports_as_shown_in_figure_Eight_such_spheres_are_used_for_this_purpose_and_are_to_be_painted_silver_Each_support_is_a_cylinder_of_radius_15_cm_and_height_7_cm_and_is_to_be_painted_black_Find_he_cost_of_paint_required_if_silver_paint_costs_25_paise_per_cm2_and_black_paint_costs_5_paise_per_cm2\"><\/span><strong>2.The front compound wall of a house is decorated by wooden spheres of diameter 21 cm, placed on small supports as shown in figure. Eight such spheres are used for this purpose and are to be painted silver. Each support is a cylinder of radius 1.5 cm and height 7 cm and is to be painted black. Find he cost of paint required if silver paint costs 25 paise per cm<sup>2<\/sup> and black paint costs 5 paise per cm<sup>2<\/sup>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 150\" style=\"height: 124px; width: 186px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image004.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Diameter of a wooden sphere<\/p>\n<p>= 21 cm.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Radius of wooden sphere<img decoding=\"async\" style=\"height: 27px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image006.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image007.png\" \/>cm<\/p>\n<p>And Radius of the cylinder <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image008.png\" \/><\/p>\n<p>= 1.5 cm<\/p>\n<p>Surface area of silver painted part<\/p>\n<p>= Surface area of sphere \u2013 Upper part of cylinder for support<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image009.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image010.png\" \/><\/p>\n<p>=<img decoding=\"async\" style=\"height: 53px; width: 164px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image011.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 45px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image012.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 45px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image013.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image014.png\" \/>= 1378.928 cm<sup>2<\/sup><\/p>\n<p>Surface area of such type of 8 spherical part = 8 x 1378.928<\/p>\n<p>= 11031.424 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image002.png\" \/>Cost of silver paint over 1 cm<sup>2<\/sup><\/p>\n<p>= Rs. 0.25<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Cost of silver paint over 11031.928 cm<sup>2<\/sup> = 0.25 x 11031.928<\/p>\n<p>= Rs. 2757.85<\/p>\n<p>Now, curved surface area of a cylindrical support = <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image015.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image016.png\" \/>= 66 cm<sup>2<\/sup><\/p>\n<p>Curved surface area of 8 such cylindrical supports = 66 x 8 = 528 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image002.png\" \/>Cost of black paint over 1 cm<sup>2<\/sup> of cylindrical support = Rs. 0.50<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Cost of black paint over 528 cm<sup>2<\/sup> of cylindrical support = 0.50 x 528<\/p>\n<p>= Rs. 26.40<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Total cost of paint required<\/p>\n<p>= Rs. 2757.85 + Rs. 26.4<\/p>\n<p>= Rs. 2784.25<\/p>\n<hr \/>\n<p style=\"text-align: center;\"><strong>NCERT Solutions for Class 9 Maths Exercise 13.9<\/strong><\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_If_diameter_of_a_sphere_is_decreased_by_25_then_what_percent_does_its_curved_surface_area_decrease\"><\/span><strong>3. If diameter of a sphere is decreased by 25% then what percent does its curved surface area decrease?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Diameter of original sphere<\/p>\n<p>= D = 2R<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image017.png\" \/>R = <img decoding=\"async\" style=\"height: 41px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image018.png\" \/><\/p>\n<p>Curved surface area of original sphere = <img decoding=\"async\" style=\"height: 21px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image019.png\" \/>= <img decoding=\"async\" style=\"height: 49px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image020.png\" \/>= <img decoding=\"async\" style=\"height: 21px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image021.png\" \/><\/p>\n<p>According to the question,<\/p>\n<p>Decreased diameter = 25% of D<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image022.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image023.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Diameter of new sphere = <img decoding=\"async\" style=\"height: 41px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image024.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image025.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Radius of new sphere = <img decoding=\"async\" style=\"height: 41px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image026.png\" \/><\/p>\n<p>Now, curved surface area of new sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image027.png\" \/>= <img decoding=\"async\" style=\"height: 49px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image028.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image029.png\" \/><\/p>\n<p>Change in curved surface area<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image021.png\" \/><img decoding=\"async\" style=\"height: 11px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image030.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image029.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image031.png\" \/><\/p>\n<p>Percent change in the curved surface area<\/p>\n<p><img decoding=\"async\" style=\"height: 44px; width: 261px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image032.png\" \/>x 100<\/p>\n<p>= <img decoding=\"async\" style=\"height: 60px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image033.png\" \/>x 100 = <img decoding=\"async\" style=\"height: 41px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image034.png\" \/>= 43.75%<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.9<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_Sameera_wants_to_celebrate_the_fifth_birthday_of_her_daughter_with_a_party_She_bought_thick_paper_to_make_the_conical_party_caps_Each_cap_is_to_have_a_base_diameter_of_10_cm_and_height_12_cm_A_sheet_of_the_paper_is_25_cm_by_40_cm_and_approximately_82_of_the_sheet_can_be_effectively_used_for_making_the_caps_after_cutting_What_is_the_minimum_number_of_sheets_of_paper_that_Sameera_would_need_to_buy_if_there_are_to_be_15_children_at_the_party\"><\/span><strong>4. Sameera wants to celebrate the fifth birthday of her daughter with a party. She bought thick paper to make the conical party caps. Each cap is to have a base diameter of 10 cm and height 12 cm. A sheet of the paper is 25 cm by 40 cm and approximately 82% of the sheet can be effectively used for making the caps after cutting. What is the minimum number of sheets of paper that Sameera would need to buy, if there are to be 15 children at the party? <\/strong><strong><img decoding=\"async\" style=\"height: 27px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image035.png\" \/><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. <\/strong>Diameter of base of conical cap<\/p>\n<p>= 10 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 153\" style=\"height: 133px; width: 141px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image036.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image005.png\" \/>Radius of conical cap <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image008.png\" \/>= 5 cm<\/p>\n<p>Slant height of cone <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image037.png\" \/>= <img decoding=\"async\" style=\"height: 27px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image038.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 35px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image039.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 24px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image040.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image041.png\" \/>= 13 cm<\/p>\n<p>Curved surface area of a cap<\/p>\n<p>= <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image042.png\" \/>= 3.14 x 5 x 13 = 204.1 cm<sup>2<\/sup><\/p>\n<p>Curved surface area of 15 caps<\/p>\n<p>= 15 x 204.1 = 3061.5 cm<sup>2<\/sup><\/p>\n<p>Area of a sheet of paper used for making caps = 25 x 40 = 1000 cm<sup>2<\/sup><\/p>\n<p>82% of sheet is used after cutting<\/p>\n<p>= 82% of 1000 cm<sup>2<\/sup><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image043.png\" \/>= 820 cm<sup>2<\/sup><\/p>\n<p>Number of sheet = <img decoding=\"async\" style=\"height: 41px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_9\/image044.png\" \/>= 3.73<\/p>\n<p>Hence 4 sheets area needed .<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Maths_Exercise_139\"><\/span>NCERT Solutions for Class 9 Maths Exercise 13.9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 9 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Maths Exercise 13.9 solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 9 Maths Exercise 13.9\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-9\/\" aria-label=\"More on NCERT Solutions for Class 9 Maths Exercise 13.9\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1376,281],"tags":[283,1344,321,1485,216],"class_list":["post-4997","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-09","category-ncert-solutions","tag-cbse-study-material","tag-class-9","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Maths Exercise 13.9 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Maths Exercise 13.9 in PDF format for free download. 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