{"id":4993,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-9-maths-exercise-13-6\/"},"modified":"2018-06-19T12:34:46","modified_gmt":"2018-06-19T07:04:46","slug":"ncert-solutions-for-class-9-maths-exercise-13-6","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Exercise 13.6"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\" >NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#1_The_circumference_of_the_base_of_a_cylindrical_vessel_is_132_cm_and_its_height_is_25_cm_How_many_litres_of_water_can_it_hold_1_m3_1000\" >1. The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many litres of water can it hold? (1 m3 = 1000)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#2_The_inner_diameter_of_a_cylindrical_wooden_pipe_is_24_cm_and_its_out_diameter_is_28_cm_The_length_of_the_pipe_is_35_cm_Find_the_mass_of_the_pipe_if_1cm3_of_wood_has_a_mass_of_05_g\" >2. The inner diameter of a cylindrical wooden pipe is 24 cm and its out diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1cm3 of wood has a mass of 0.5 g.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#3_A_soft_drink_is_available_in_two_packs_i_a_tin_can_with_a_rectangular_base_of_length_5_cm_and_width_4_cm_having_height_of_15_cm_ii_a_plastic_cylinder_with_circular_base_of_diameter_7_cm_and_height_10_cm_Which_container_has_greater_capacity_and_how_much\" >3. A soft drink is available in two packs (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having height of 15 cm (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and how much?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#4_If_the_lateral_surface_of_a_cylinder_is_942_cm2_and_its_height_is_5_cm_then_i_radius_of_its_base_ii_volume_of_the_cylinder\" >4. If the lateral surface of a cylinder is\u00a094.2 cm2 and its height is 5 cm, then (i)\u00a0radius of its base (ii) volume\u00a0of the cylinder.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#5_It_costs_Rs_2200_to_paint_the_inner_curved_surface_of_a_cylindrical_vessel_10_m_deep_If_the_cost_of_painting_is_at_the_rate_of_Rs_20_per_m2_find\" >5. It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs. 20 per m2, find:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#6_The_capacity_of_a_closed_cylindrical_vessel_of_height_1_m_is_154_litres_How_many_square_meters_of_metal_sheet_would_be_needed_to_make_it\" >6. The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How many square meters of metal sheet would be needed to make it?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#7_A_bag_of_grain_contains_28_m3_of_grain_How_many_bags_are_needed_to_fill_a_drum_of_radius_42_m_and_height_5_m\" >7. A bag of grain contains 2.8 m3 of grain. How many bags are needed to fill a drum of radius 4.2 m and height 5 m?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#8_A_lead_pencil_consists_of_a_cylinder_of_wood_with_a_solid_cylinder_of_graphite_filled_in_the_interior_The_diameter_of_the_pencil_is_7_mm_and_diameter_of_graphite_is_1_mm_If_the_length_of_the_pencil_is_14_cm_find_the_columns_of_the_wood_and_that_of_the_graphite\" >8. A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior. The diameter of the pencil is 7 mm and diameter of graphite is 1 mm. If the length of the pencil is 14 cm, find the columns of the wood and that of the graphite.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#9_A_patient_in_a_hospital_is_given_soup_daily_in_a_cylindrical_bowl_of_diameter_7_cm_If_the_bowl_is_filled_with_soup_to_a_height_of_4_cm_how_much_soup_the_hospital_has_to_prepare_daily_to_serve_250_patients\" >9. A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#NCERT_Solutions_for_Class_9_Maths_Exercise_136\" >NCERT Solutions for Class 9 Maths Exercise 13.6<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 9 Maths Exercise 13.6 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 9 Maths\u00a0<\/strong><strong>Surface Areas and Volumes\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-mathematics-surface-areas-and-volumes\/1247\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Class_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 9 Maths Exercise 13.6\" width=\"170\" height=\"219\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\"><\/span>NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Assume <img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image001.png\" \/>unless stated otherwise<\/strong>.<\/p>\n<h6><span class=\"ez-toc-section\" id=\"1_The_circumference_of_the_base_of_a_cylindrical_vessel_is_132_cm_and_its_height_is_25_cm_How_many_litres_of_water_can_it_hold_1_m3_1000\"><\/span><strong>1. The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many litres of water can it hold? (1 m<sup>3<\/sup> = 1000<\/strong><strong><img decoding=\"async\" style=\"height: 19px; width: 9px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image002.png\" \/><\/strong><strong>)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Height of vessel = <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 25 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 75\" style=\"height: 115px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image004.jpg\" \/><\/p>\n<p>Circumference of base of vessel<\/p>\n<p>= 132 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image006.png\" \/>= 132<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image007.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image008.png\" \/>= 21 cm<\/p>\n<p>Now, Volume of cylindrical vessel<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image010.png\" \/>= 34650 cm<sup>3<\/sup><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image011.png\" \/>liters [<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image012.png\" \/>1000 cm<sup>3<\/sup> = 1 liter]\n<p>= 34.65 liters<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"2_The_inner_diameter_of_a_cylindrical_wooden_pipe_is_24_cm_and_its_out_diameter_is_28_cm_The_length_of_the_pipe_is_35_cm_Find_the_mass_of_the_pipe_if_1cm3_of_wood_has_a_mass_of_05_g\"><\/span><strong>2. The inner diameter of a cylindrical wooden pipe is 24 cm and its out diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1cm<sup>3<\/sup> of wood has a mass of 0.5 g.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Inner diameter of pipe = 28 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Inner radius of pipe <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image014.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image015.png\" \/>= 12 cm<\/p>\n<p>And Outer diameter of pipe = 28 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Outer radius of pipe (R)<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image016.png\" \/>= 14 m<\/p>\n<p>Length of pipe <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 35 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 78\" style=\"height: 116px; width: 287px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image017.jpg\" \/><\/p>\n<p>Volume of wood = Volume of outer cylinder \u2013 Volume of inner cylinder<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image018.png\" \/>= <img decoding=\"async\" style=\"height: 29px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image019.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 148px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image020.png\" \/><\/p>\n<p>= 110 [ 196 \u2013 144 ] = 110 x 52<\/p>\n<p>= 5720 cm<sup>3<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image012.png\" \/>Weight of 1 cm<sup>3<\/sup> of wood = 0.6 g<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Weight of 5720 cm<sup>3<\/sup> of wood<\/p>\n<p>= 0.6 x 5720 = 3432 g = 3.432 kg<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_A_soft_drink_is_available_in_two_packs_i_a_tin_can_with_a_rectangular_base_of_length_5_cm_and_width_4_cm_having_height_of_15_cm_ii_a_plastic_cylinder_with_circular_base_of_diameter_7_cm_and_height_10_cm_Which_container_has_greater_capacity_and_how_much\"><\/span><strong>3. A soft drink is available in two packs (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having height of 15 cm (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and how much?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> I case: Length of tin <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image021.png\" \/>= 5 cm, Width of tin <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image022.png\" \/>= 4 cm<\/p>\n<p>and Height of tin <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 15 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 81\" style=\"height: 133px; width: 167px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image023.jpg\" \/><br \/>\nThen, Capacity of tin = <img decoding=\"async\" style=\"height: 19px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image024.png\" \/>= 5 x 4 x 15 = 300 cm<sup>3<\/sup><\/p>\n<p>II case: Diameter of base of cylinder = 7 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 122px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image025.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Radius of base of cylinder <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image014.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image026.png\" \/>cm<\/p>\n<p>Height of cylinder <img decoding=\"async\" style=\"height: 27px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image027.png\" \/>= 10 cm<\/p>\n<p>Capacity of cylinder = <img decoding=\"async\" style=\"height: 21px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image028.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image029.png\" \/>= 385 cm<sup>3<\/sup><\/p>\n<p>From the cases I and II, we observed that<\/p>\n<p>cylindrical container has greater capacity<\/p>\n<p>by (385 \u2013 300) = 85 cm<sup>3<\/sup>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_If_the_lateral_surface_of_a_cylinder_is_942_cm2_and_its_height_is_5_cm_then_i_radius_of_its_base_ii_volume_of_the_cylinder\"><\/span><strong>4. If the lateral surface of a cylinder is\u00a094.2 cm<sup>2<\/sup> and its height is 5 cm, then (i)\u00a0radius of its base (ii) volume\u00a0of the cylinder.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Height of the cylinder <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 5 cm<\/p>\n<p>Lateral surface area of the cylinder<\/p>\n<p>= 94.2 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image030.png\" \/>= 94.2<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/>2 x 3.14 x <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image031.png\" \/>x 5 = 94.2<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image032.png\" \/>= 3 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Volume of cylinder = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/><\/p>\n<p>= 3.14 x 3 x 3 x 5 = 141.3 cm<sup>3<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5_It_costs_Rs_2200_to_paint_the_inner_curved_surface_of_a_cylindrical_vessel_10_m_deep_If_the_cost_of_painting_is_at_the_rate_of_Rs_20_per_m2_find\"><\/span><strong>5. It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If the cost of painting is at the rate of Rs. 20 per m<sup>2<\/sup>, find:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) <\/strong><strong>inner curved surface area of the vessel.<\/strong><\/p>\n<p><strong>(ii) <\/strong><strong>radius of the base.<\/strong><\/p>\n<p><strong>(iii) <\/strong><strong>capacity of the vessel.<\/strong><\/p>\n<p><strong>Ans.<\/strong> Total cost to paint inner curved surface area of the vessel = Rs. 2200<\/p>\n<p>Rate = Rs. 20 per square meter<\/p>\n<p><strong>(i)<\/strong> Inner curved surface area of vessel = <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image033.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image034.png\" \/><\/p>\n<p>= 110 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 128px; width: 142px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image035.png\" \/><br \/>\n<strong>(ii)<\/strong> Depth of the vessel <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 10 m<\/p>\n<p>Now, Inner surface area of vessel<\/p>\n<p>= 110 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image030.png\" \/>= 110<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 129px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image036.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image037.png\" \/>= 1.75 m<\/p>\n<p><strong>(iii)<\/strong> Since <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image031.png\" \/>= 1.75 m and<\/p>\n<p><img decoding=\"async\" style=\"height: 19px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image038.png\" \/>= 10 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Capacity of vessel<\/p>\n<p>= Volume of cylinder = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image039.png\" \/>= 96.25 m<sup>3<\/sup><\/p>\n<p>= 96.25 kl [<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image012.png\" \/>1 m<sup>3<\/sup> = 1 kl]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"6_The_capacity_of_a_closed_cylindrical_vessel_of_height_1_m_is_154_litres_How_many_square_meters_of_metal_sheet_would_be_needed_to_make_it\"><\/span><strong>6. The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How many square meters of metal sheet would be needed to make it?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Height of the vessel <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 1 m<\/p>\n<p><img decoding=\"async\" id=\"Picture 90\" style=\"height: 130px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image040.jpg\" \/><\/p>\n<p>Capacity of vessel = 15.4 liters<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image041.png\" \/>kilo liters<\/p>\n<p>= 0.0154 m<sup>3<\/sup> [<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image012.png\" \/>1 m<sup>3<\/sup> = 1 kl]\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/>= 0.0154<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image042.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image043.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/><img decoding=\"async\" style=\"height: 20px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image044.png\" \/>= 0.0007 x 7 = 0.0048<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image005.png\" \/> <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image031.png\" \/>= 0.07 m<\/p>\n<p>Now, Area of metal sheet required = TSA of cylindrical vessel<\/p>\n<p><img decoding=\"async\" style=\"height: 164px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image045.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 75px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image046.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image047.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image048.png\" \/><\/p>\n<p>= 0.4708 m<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7_A_bag_of_grain_contains_28_m3_of_grain_How_many_bags_are_needed_to_fill_a_drum_of_radius_42_m_and_height_5_m\"><\/span><strong>7. A bag of grain contains 2.8 m<sup>3<\/sup> of grain. How many bags are needed to fill a drum of radius 4.2 m and height 5 m?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Radius of drum <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image014.png\" \/>= 4.2 m and Height of drum <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 5 m<\/p>\n<p><img decoding=\"async\" style=\"height: 148px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image049.png\" \/><\/p>\n<p>Volume of a drum = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image050.png\" \/><\/p>\n<p>= 22 x 0.6 x 4.2 x 5 = 277.2 m<sup>3<\/sup><\/p>\n<p>Now, Number of bags<\/p>\n<p>= <img decoding=\"async\" style=\"height: 44px; width: 191px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image051.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image052.png\" \/>= 99<\/p>\n<p>Hence 99 bags are needed to fill the drum.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_A_lead_pencil_consists_of_a_cylinder_of_wood_with_a_solid_cylinder_of_graphite_filled_in_the_interior_The_diameter_of_the_pencil_is_7_mm_and_diameter_of_graphite_is_1_mm_If_the_length_of_the_pencil_is_14_cm_find_the_columns_of_the_wood_and_that_of_the_graphite\"><\/span><strong>8. A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior. The diameter of the pencil is 7 mm and diameter of graphite is 1 mm. If the length of the pencil is 14 cm, find the columns of the wood and that of the graphite.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Diameter of graphite = 1 mm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Radius of drum = 0.5 mm<\/p>\n<p>= 0.05 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 99\" style=\"height: 185px; width: 202px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image053.jpg\" \/><\/p>\n<p>Height of graphite <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 14 cm<\/p>\n<p>Volume of graphite = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image054.png\" \/>= 0.11 cm<sup>3<\/sup><\/p>\n<p>Diameter of pencil = 7 mm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Radius of pencil (R) = 3.5 mm<\/p>\n<p>= 0.35 cm<\/p>\n<p>Volume of pencil= <img decoding=\"async\" style=\"height: 21px; width: 41px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image055.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image056.png\" \/>= 5.39 cm<sup>3<\/sup><\/p>\n<p>Now, Volume of wood = Volume of pencil \u2013 Volume of graphite<\/p>\n<p>= 5.39 \u2013 0.11 = 5.28 cm<sup>3<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"9_A_patient_in_a_hospital_is_given_soup_daily_in_a_cylindrical_bowl_of_diameter_7_cm_If_the_bowl_is_filled_with_soup_to_a_height_of_4_cm_how_much_soup_the_hospital_has_to_prepare_daily_to_serve_250_patients\"><\/span><strong>9. A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Diameter of circular base of cylindrical bowl = 7 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 102\" style=\"height: 91px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image057.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Radius of circular base of cylindrical<\/p>\n<p>bowl <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image014.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image026.png\" \/>cm<\/p>\n<p>Height of the bowl <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image003.png\" \/>= 4 cm<\/p>\n<p>Now, Volume of cylindrical bowl = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image009.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image058.png\" \/>= 22 x 7 = 154 cm<sup>3<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image013.png\" \/>Quantity of soup filled in a bowl<\/p>\n<p>= 154 cm<sup>3<\/sup><\/p>\n<p>Therefore, total quantity of soup to be prepared by the hospital = 250 x 154<\/p>\n<p>= 38500 cm<sup>3<\/sup><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image059.png\" \/>liter [<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_6\/image012.png\" \/>1 liter = 1000 cm<sup>3<\/sup>]\n<p>= 38.5 liters<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Maths_Exercise_136\"><\/span>NCERT Solutions for Class 9 Maths Exercise 13.6<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 9 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Maths Exercise 13.6 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter &#8230; <a title=\"NCERT Solutions for Class 9 Maths Exercise 13.6\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-6\/\" aria-label=\"More on NCERT Solutions for Class 9 Maths Exercise 13.6\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1376,281],"tags":[283,1344,321,1485,216],"class_list":["post-4993","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-09","category-ncert-solutions","tag-cbse-study-material","tag-class-9","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Maths Exercise 13.6 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Maths Exercise 13.6 in PDF format for free download. 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