{"id":4991,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-9-maths-exercise-13-4\/"},"modified":"2018-06-19T11:40:09","modified_gmt":"2018-06-19T06:10:09","slug":"ncert-solutions-for-class-9-maths-exercise-13-4","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Exercise 13.4"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\" >NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#Assume_unless_stated_otherwise\" >Assume unless stated otherwise.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#1_Find_the_surface_area_of_a_sphere_of_radius\" >1. Find the surface area of a sphere of radius:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#2_Find_the_surface_area_of_a_sphere_of_diameter\" >2. Find the surface area of a sphere of diameter:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#3_Find_the_total_surface_area_of_a_hemisphere_of_radius_10_cm\" >3. Find the total surface area of a\u00a0hemisphere of radius 10 cm.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#4_The_radius_of_a_spherical_balloonincreases_from_7_cm_to_14_cm_as_air_isbeing_pumped_into_it_Find_the_ratio_ofsurface_areas_of_the_balloon_in_the_twocases\" >4. The radius of a spherical balloonincreases from 7 cm to 14 cm as air isbeing pumped into it. Find the ratio ofsurface areas of the balloon in the twocases.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#5A_hemispherical_bowl_made_of_brass_has_inner_diameter_105_cm_Find_the_cost_of_tin-plating_it_on_the_inside_at_the_rate_of_Rs_16_per_100_cm2\" >5.A hemispherical bowl made of brass has inner diameter 105 cm. Find the cost of tin-plating it on the inside at the rate of Rs. 16 per 100 cm2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#6_Find_the_radius_of_a_sphere_whose_surface_area_is_154_cm2\" >6. Find the radius of a sphere whose surface area is 154 cm2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#7The_diameter_of_the_moon_is_approximately_one_fourth_the_diameter_of_the_earth_Find_the_ratio_of_their_surface_areas\" >7.The diameter of the moon is approximately one fourth the diameter of the earth. Find the ratio of their surface areas.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#8_A_hemispherical_bowl_is_made_of_steel_025_cm_thick_The_inner_radius_of_the_bowl_is_5_cm_Find_the_outer_curved_surface_area_of_the_bowl\" >8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#9_A_right_circular_cylinder_just_encloses_a_sphere_of_radius_See_figure_Find\" >9. A right circular cylinder just encloses a sphere of radius (See figure). Find:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#NCERT_Solutions_for_Class_9_Maths_Exercise_134\" >NCERT Solutions for Class 9 Maths Exercise 13.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 9 Maths Exercise 13.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 9 Maths\u00a0<\/strong><strong>Surface Areas and Volumes\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-mathematics-surface-areas-and-volumes\/1247\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Class_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 9 Maths Exercise 13.4\" width=\"169\" height=\"218\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\"><\/span>NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6><span class=\"ez-toc-section\" id=\"Assume_unless_stated_otherwise\"><\/span><strong>Assume <\/strong><img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image001.png\" \/><strong>unless stated otherwise<\/strong>.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1_Find_the_surface_area_of_a_sphere_of_radius\"><\/span><strong>1. <\/strong><strong>Find the surface area of a sphere of radius:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 10.5 cm <\/strong><\/p>\n<p><strong>(ii) 5.6 cm <\/strong><\/p>\n<p><strong>(iii) 14 cm<\/strong><\/p>\n<p><strong>Ans.<\/strong> <strong>(i)<\/strong> Radius of sphere = 105 cm<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 121px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image003.png\" \/>= 1386 cm<sup>2<\/sup><\/p>\n<p><strong>(ii)<\/strong> Radius of sphere = 5.6 m<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image004.png\" \/>= 3.94.84 m<sup>2<\/sup><\/p>\n<p><strong>(iii)<\/strong> Radius of sphere = 14 cm<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image005.png\" \/>= 2464 cm<sup>2<\/sup><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"2_Find_the_surface_area_of_a_sphere_of_diameter\"><\/span><strong>2. Find the surface area of a sphere of diameter:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 14 cm <\/strong><\/p>\n<p><strong>(ii) 21 cm <\/strong><\/p>\n<p><strong>(iii) 3.5 cm<\/strong><\/p>\n<p><strong>Ans. (i)<\/strong> Diameter of sphere = 14 cm,<\/p>\n<p>Therefore Radius of sphere = <img decoding=\"async\" style=\"height: 41px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image006.png\" \/>= 7 cm<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image007.png\" \/>= 616 cm<sup>2<\/sup><\/p>\n<p><strong>(ii)<\/strong> Diameter of sphere = 21 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Radius of sphere = <img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image009.png\" \/>cm<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image010.png\" \/>= 1386 cm<sup>2<\/sup><\/p>\n<p><strong>(iii)<\/strong> Diameter of sphere = 3.5 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Radius of sphere = <img decoding=\"async\" style=\"height: 41px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image011.png\" \/>= 1.75 cm<\/p>\n<p>Surface area of sphere = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 121px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image012.png\" \/>= 38.5 cm<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_Find_the_total_surface_area_of_a_hemisphere_of_radius_10_cm\"><\/span><strong>3. Find the total surface area of a\u00a0hemisphere of radius 10 cm.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong><img decoding=\"async\" style=\"height: 27px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image013.png\" \/><\/strong><\/p>\n<p><strong>Ans.<\/strong> Radius of hemisphere <img decoding=\"async\" style=\"height: 27px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image014.png\" \/>10 cm<\/p>\n<p>Total surface area of hemisphere = <img decoding=\"async\" style=\"height: 21px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image015.png\" \/><\/p>\n<p>= 3 x 3.14 x 10 x 10 = 942 cm<sup>2<\/sup><\/p>\n<p>Hence total surface area of hemisphere is<\/p>\n<p>942 cm<sup>2<\/sup>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_The_radius_of_a_spherical_balloonincreases_from_7_cm_to_14_cm_as_air_isbeing_pumped_into_it_Find_the_ratio_ofsurface_areas_of_the_balloon_in_the_twocases\"><\/span><strong>4. The radius of a spherical balloonincreases from 7 cm to 14 cm as air isbeing pumped into it. Find the ratio ofsurface areas of the balloon in the twocases.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> I case: Radius of balloon <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image016.png\" \/>= 7 cm<\/p>\n<p>Surface area of balloon = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 19px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image017.png\" \/>cm<sup>2<\/sup>\u2026\u2026\u2026.(i)<\/p>\n<p><img decoding=\"async\" id=\"Picture 45\" style=\"height: 185px; width: 350px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image018.jpg\" \/><br \/>\nII case: Radius of balloon (R) = 14 cm<\/p>\n<p>Surface area of balloon = <img decoding=\"async\" style=\"height: 21px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image019.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 19px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image020.png\" \/>cm2 \u2026\u2026.(ii)<\/p>\n<p>Now, Ratio [from eq. (i) and (ii)],<\/p>\n<p><img decoding=\"async\" style=\"height: 41px; width: 135px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image021.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image022.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image023.png\" \/><\/p>\n<p>Hence, required ratio = 1 : 4<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5A_hemispherical_bowl_made_of_brass_has_inner_diameter_105_cm_Find_the_cost_of_tin-plating_it_on_the_inside_at_the_rate_of_Rs_16_per_100_cm2\"><\/span><strong>5.A hemispherical bowl made of brass has inner diameter 105 cm. Find the cost of tin-plating it on the inside at the rate of Rs. 16 per 100 cm<sup>2<\/sup>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong><img decoding=\"async\" id=\"Picture 48\" style=\"height: 116px; width: 184px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image024.jpg\" \/><\/strong><\/p>\n<p><strong>Ans. <\/strong>Inner diameter of bowl<\/p>\n<p>= 10.5 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Inner radius of bowl <img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image025.png\" \/><\/p>\n<p>= 5.25 cm<\/p>\n<p>Now, Inner surface area of bowl<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image026.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image027.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image028.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image029.png\" \/>cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image030.png\" \/>Cost of tin-plating per 100 cm<sup>2<\/sup><\/p>\n<p>= Rs. 16<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Cost of tin-plating per 1 cm<sup>2<\/sup> = <img decoding=\"async\" style=\"height: 41px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image031.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Cost of tin-plating per <img decoding=\"async\" style=\"height: 41px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image029.png\" \/>cm<sup>2<\/sup><\/p>\n<p>=<img decoding=\"async\" style=\"height: 41px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image032.png\" \/>= Rs. 27.72<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"6_Find_the_radius_of_a_sphere_whose_surface_area_is_154_cm2\"><\/span><strong>6. Find the radius of a sphere whose surface area is 154 cm<sup>2<\/sup>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Surface area of sphere = 154 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image033.png\" \/><img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/>= 154<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image033.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image034.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image033.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image035.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image033.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 53px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image036.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image033.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image037.png\" \/>= 3.5 cm<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7The_diameter_of_the_moon_is_approximately_one_fourth_the_diameter_of_the_earth_Find_the_ratio_of_their_surface_areas\"><\/span><strong>7.The diameter of the moon is approximately one fourth the diameter of the earth. Find the ratio of their surface areas.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Let diameter of Earth = <img decoding=\"async\" style=\"height: 15px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image038.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Radius of Earth <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image016.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image039.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Surface area of Earth = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image040.png\" \/><img decoding=\"async\" style=\"height: 21px; width: 41px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image041.png\" \/><\/p>\n<p><img decoding=\"async\" id=\"Picture 51\" style=\"height: 186px; width: 287px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image042.jpg\" \/><\/p>\n<p>Now, Diameter of Moon = <img decoding=\"async\" style=\"height: 41px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image043.png\" \/>of diameter of Earth = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image044.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Radius of Moon <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image016.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image045.png\" \/><\/p>\n<p>Surface area of Moon = <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image046.png\" \/>= <img decoding=\"async\" style=\"height: 44px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image047.png\" \/><\/p>\n<p>Now, Ratio = <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image048.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 61px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image049.png\" \/>= <img decoding=\"async\" style=\"height: 44px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image050.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image051.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Required ratio = 1 : 16<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_A_hemispherical_bowl_is_made_of_steel_025_cm_thick_The_inner_radius_of_the_bowl_is_5_cm_Find_the_outer_curved_surface_area_of_the_bowl\"><\/span><strong>8. A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Inner radius of bowl <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image016.png\" \/>= 5 cm<\/p>\n<p>Thickness of steel <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image052.png\" \/>= 0.25 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Outer radius of bowl (R) = <img decoding=\"async\" style=\"height: 16px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image053.png\" \/><\/p>\n<p>= 5 +0.25 = 5.25 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Outer curved surface area of bowl<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image054.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image027.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image028.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image029.png\" \/>= 173.25 cm<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"9_A_right_circular_cylinder_just_encloses_a_sphere_of_radius_See_figure_Find\"><\/span><strong>9. A right circular cylinder just encloses a sphere of radius <\/strong><strong><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image055.png\" \/><\/strong><strong>(See figure). Find:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) <\/strong><strong>Surface area of the sphere.<\/strong><\/p>\n<p><strong>(ii) <\/strong><strong>Curved surface area of the cylinder.<\/strong><\/p>\n<p><strong>(iii) <\/strong><strong>Ratio of the areas obtained in (i) and (ii).<\/strong><\/p>\n<p><strong><img decoding=\"async\" id=\"Picture 54\" style=\"height: 141px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image056.jpg\" \/><\/strong><\/p>\n<p><strong>Ans. (i) <\/strong>Radius of sphere = <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image055.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Surface area of sphere<\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 131px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image057.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image030.png\" \/>The cylinder just encloses the sphere in it.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>The height of cylinder will be equal to diameter of sphere.<\/p>\n<p>And The radius of cylinder will be equal to radius of sphere.<\/p>\n<p><strong>(ii) <\/strong><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/> Curved surface area of cylinder<\/p>\n<p>= <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image058.png\" \/>= <img decoding=\"async\" style=\"height: 19px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image059.png\" \/><img decoding=\"async\" style=\"height: 27px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image060.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image002.png\" \/><\/p>\n<p><strong>(iii)<\/strong> <img decoding=\"async\" style=\"height: 44px; width: 208px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image061.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 44px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image062.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_4\/image008.png\" \/>Required ratio = 1 :1<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Maths_Exercise_134\"><\/span>NCERT Solutions for Class 9 Maths Exercise 13.4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 9 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Maths Exercise 13.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter &#8230; <a title=\"NCERT Solutions for Class 9 Maths Exercise 13.4\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-4\/\" aria-label=\"More on NCERT Solutions for Class 9 Maths Exercise 13.4\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1376,281],"tags":[283,1344,321,1485,216],"class_list":["post-4991","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-09","category-ncert-solutions","tag-cbse-study-material","tag-class-9","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Maths Exercise 13.4 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Maths Exercise 13.4 in PDF format for free download. 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