{"id":4990,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-9-maths-exercise-13-3\/"},"modified":"2018-06-19T11:39:43","modified_gmt":"2018-06-19T06:09:43","slug":"ncert-solutions-for-class-9-maths-exercise-13-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/","title":{"rendered":"NCERT Solutions for Class 9 Maths Exercise 13.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\" >NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#Assume_unless_stated_otherwise\" >Assume unless ^stated otherwise.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#1_Diameter_of_the_base_of_a_cone_is_105_cm_and_its_slant_height_is_10_cm_Find_its_curved_surface_area_and_its_total_surface_area\" >1. Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area and its total surface area.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#2_Find_the_total_surface_area_of_a_cone_if_its_slant_height_is_21_cm_and_diameter_of_the_base_is_24_cm\" >2. Find the total surface area of a cone, if its slant height is 21 cm and diameter of the base is 24 cm.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#3_Curved_surface_area_of_a_cone_is_308_cm2_and_its_slant_height_is_14_cm_Find_i_radius_of_the_base_and_ii_total_surface_area_of_the_cone\" >3. Curved surface area of a cone is 308\u00a0cm2 and its slant height is 14 cm.\u00a0Find (i) radius of the base and\u00a0 (ii) total surface area of the cone.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#4_A_conical_tent_is_10_m_high_and_the_radius_of_its_base_is_24_m_Find\" >4. A conical tent is 10 m high and the radius of its base is 24 m. Find:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#5_What_length_of_tarpaulin_3_m_wide_will_be_required_to_make_conical_tent_of_height_8_m_and_base_radius_6_m_Assume_that_the_extra_length_of_material_that_will_be_required_for_stitching_margins_and_wastage_in_cutting_is_approximately_20_cm\" >5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#6_The_slant_height_and_base_diameter_of_a_conical_tomb_are_25_m_and_14_m_respectively_Find_the_cost_of_whitewashing_its_curved_surface_at_the_rate_of_Rs_210_per_100_m2\" >6. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of whitewashing its curved surface at the rate of Rs. 210 per 100 m2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#7_A_Jokers_cap_is_in_the_form_of_a_right_circular_cone_of_base_radius_7_cm_and_height_24_cm_Find_the_area_of_the_sheet_required_to_make_10_such_caps\" >7. A Joker\u2019s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#8_A_bus_stop_is_barricaded_from_the_remaining_part_of_the_road_by_using_50_hollow_cones_made_of_recycled_cardboard_Each_cone_has_a_base_diameter_of_40_cm_and_height_1_m_If_the_outer_side_of_each_of_the_cones_is_to_be_painted_and_the_cost_of_painting_is_Rs_12_per_m2_what_will_be_the_cost_of_painting_all_these_cones\" >8. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs. 12 per m2, what will be the cost of painting all these cones?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#NCERT_Solutions_for_Class_9_Maths_Exercise_133\" >NCERT Solutions for Class 9 Maths Exercise 13.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 9 Maths Exercise 13.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 9 Maths\u00a0<\/strong><strong>Surface Areas and Volumes\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-mathematics-surface-areas-and-volumes\/1247\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Class_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 9 Maths Exercise 13.3\" width=\"178\" height=\"229\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Mathematics_Surface_Areas_and_Volumes\"><\/span>NCERT Solutions for Class 9 Mathematics\u00a0Surface Areas and Volumes<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6><span class=\"ez-toc-section\" id=\"Assume_unless_stated_otherwise\"><\/span><strong>Assume <\/strong><img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image001.png\" \/><strong>unless ^stated otherwise<\/strong>.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1_Diameter_of_the_base_of_a_cone_is_105_cm_and_its_slant_height_is_10_cm_Find_its_curved_surface_area_and_its_total_surface_area\"><\/span><strong>1. <\/strong><strong>Diameter of the base of a cone is 10.5 cm and its slant height is 10 cm. Find its curved surface area and its total surface area.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Diameter = 10.5 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 30\" style=\"height: 150px; width: 160px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image002.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/>Radius <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image004.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image005.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image006.png\" \/>cm<\/p>\n<p>Slant height of cone <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image007.png\" \/>= 10 cm<\/p>\n<p>Curved surface area of cone= <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image009.png\" \/>= 165 cm<sup>2<\/sup><\/p>\n<p>Total surface area of cone = <img decoding=\"async\" style=\"height: 27px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image010.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 45px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image011.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image012.png\" \/>= 251.625 cm<sup>2<\/sup><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"2_Find_the_total_surface_area_of_a_cone_if_its_slant_height_is_21_cm_and_diameter_of_the_base_is_24_cm\"><\/span><strong>2. Find the total surface area of a cone, if its slant height is 21 cm and diameter of the base is 24 cm.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Slant height of cone <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image007.png\" \/>= 21 m<\/p>\n<p>Diameter of cone = 24 m<\/p>\n<p><img decoding=\"async\" id=\"Picture 33\" style=\"height: 211px; width: 200px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image013.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/>Radius of cone <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image004.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image014.png\" \/>= 12 m<\/p>\n<p>Total surface area of cone = <img decoding=\"async\" style=\"height: 27px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image010.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image015.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image016.png\" \/>= 1244.57 m<sup>2<\/sup><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"3_Curved_surface_area_of_a_cone_is_308_cm2_and_its_slant_height_is_14_cm_Find_i_radius_of_the_base_and_ii_total_surface_area_of_the_cone\"><\/span><strong>3. Curved surface area of a cone is 308\u00a0cm<sup>2<\/sup> and its slant height is 14 cm.\u00a0Find (i) radius of the base and\u00a0 (ii) total surface area of the cone.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. (i)<\/strong> Slant height of cone <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image007.png\" \/>= 14 cm<\/p>\n<p>Curved surface area of cone = 308 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/>= 308<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image017.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 75px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image018.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image019.png\" \/>= 7 cm<\/p>\n<p><strong>(ii)<\/strong> Total surface area of the cone<\/p>\n<p>= Curved surface area + Area of circular base<\/p>\n<p>= <img decoding=\"async\" style=\"height: 21px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image020.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image021.png\" \/><\/p>\n<p>= 462 cm<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_A_conical_tent_is_10_m_high_and_the_radius_of_its_base_is_24_m_Find\"><\/span><strong>4. <\/strong><strong>A conical tent is 10 m high and the radius of its base is 24 m. Find:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) <\/strong><strong>slant height of the tent.<\/strong><\/p>\n<p><strong>(ii) <\/strong><strong>cost of the canvas required to make the tent, if the cost of a m<sup>2<\/sup> canvas is Rs. 70.<\/strong><\/p>\n<p><strong>Ans.<\/strong> Height of the conical tent<img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image022.png\" \/>= 10 m<\/p>\n<p>Radius of the conical tent <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image004.png\" \/>= 24 m<\/p>\n<p><strong>(i)<\/strong> Slant height of the tent <img decoding=\"async\" style=\"height: 31px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image023.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 35px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image024.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 24px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image025.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 41px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image026.png\" \/>= 26 m<\/p>\n<p><strong>(ii)<\/strong> Canvas required to make the tent<\/p>\n<p>= Curved surface area of the tent= <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image027.png\" \/>= <img decoding=\"async\" style=\"height: 41px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image028.png\" \/>m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image029.png\" \/>Cost of 1 m<sup>2<\/sup> canvas = Rs. 70<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Cost of <img decoding=\"async\" style=\"height: 41px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image028.png\" \/>m<sup>2<\/sup> canvas<\/p>\n<p>= 70 x <img decoding=\"async\" style=\"height: 41px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image028.png\" \/>= Rs. 137280<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5_What_length_of_tarpaulin_3_m_wide_will_be_required_to_make_conical_tent_of_height_8_m_and_base_radius_6_m_Assume_that_the_extra_length_of_material_that_will_be_required_for_stitching_margins_and_wastage_in_cutting_is_approximately_20_cm\"><\/span><strong>5. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6 m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm. <\/strong><strong><img decoding=\"async\" style=\"height: 27px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image031.png\" \/><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Height of the conical tent <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image022.png\" \/>= 8 m and Radius of the conical tent <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image004.png\" \/>= 6 m<\/p>\n<p>Slant height of the tent <img decoding=\"async\" style=\"height: 31px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image023.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 35px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image032.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image033.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image034.png\" \/>= 10 m<\/p>\n<p>Area of tarpaulin = Curved surface area of tent = <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/>= 3.14 x 6 x 10 = 188.4 m<sup>2<\/sup><\/p>\n<p>Width of tarpaulin = 3 m<\/p>\n<p>Let Length of tarpaulin = L<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Area of tarpaulin = Length x Breadth<\/p>\n<p>= L x 3 = 3L<\/p>\n<p>Now According to question,<\/p>\n<p>3L = 188.4<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/>L = <img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image035.png\" \/>= 62.8 m<\/p>\n<p>The extra length of the material required for stitching margins and cutting is 20 cm = 0.2 m.<\/p>\n<p>So the total length of tarpaulin bought is (62.8 + 0.2) m = 63 m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"6_The_slant_height_and_base_diameter_of_a_conical_tomb_are_25_m_and_14_m_respectively_Find_the_cost_of_whitewashing_its_curved_surface_at_the_rate_of_Rs_210_per_100_m2\"><\/span><strong>6. The slant height and base diameter of a conical tomb are 25 m and 14 m respectively. Find the cost of whitewashing its curved surface at the rate of Rs. 210 per 100 m<sup>2<\/sup>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. <\/strong>Slant height of conical tomb <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image007.png\" \/><\/p>\n<p>= 25 m, Diameter of tomb = 14 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Radius of the tomb <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image036.png\" \/>= 7 m<\/p>\n<p>Curved surface are of tomb = <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image037.png\" \/>= 550 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image029.png\" \/>Cost of white washing 100 m<sup>2<\/sup><\/p>\n<p>= Rs. 210<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Cost of white washing 1 m<sup>2<\/sup> = <img decoding=\"async\" style=\"height: 41px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image038.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Cost of white washing 550 m<sup>2<\/sup><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image039.png\" \/>= Rs. 1155<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7_A_Jokers_cap_is_in_the_form_of_a_right_circular_cone_of_base_radius_7_cm_and_height_24_cm_Find_the_area_of_the_sheet_required_to_make_10_such_caps\"><\/span><strong>7. A Joker\u2019s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Radius of cap <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image004.png\" \/>= 7 cm,<\/p>\n<p>Height of cap <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image022.png\" \/>= 24 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 36\" style=\"height: 131px; width: 157px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image040.jpg\" \/><\/p>\n<p>Slant height of the cone <img decoding=\"async\" style=\"height: 31px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image023.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 35px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image041.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 24px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image042.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image043.png\" \/>= 25 cm<\/p>\n<p>Area of sheet required to make a cap<\/p>\n<p>= CSA of cone =<img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image037.png\" \/>= 550 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Area of sheet required to make 10 caps = 10 x 550 = 5500 cm<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Maths Exercise 13.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_A_bus_stop_is_barricaded_from_the_remaining_part_of_the_road_by_using_50_hollow_cones_made_of_recycled_cardboard_Each_cone_has_a_base_diameter_of_40_cm_and_height_1_m_If_the_outer_side_of_each_of_the_cones_is_to_be_painted_and_the_cost_of_painting_is_Rs_12_per_m2_what_will_be_the_cost_of_painting_all_these_cones\"><\/span><strong>8. A bus stop is barricaded from the remaining part of the road, by using 50 hollow cones made of recycled cardboard. Each cone has a base diameter of 40 cm and height 1 m. If the outer side of each of the cones is to be painted and the cost of painting is Rs. 12 per m<sup>2<\/sup>, what will be the cost of painting all these cones? <img decoding=\"async\" style=\"height: 32px; width: 245px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image044.png\" \/><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Diameter of cone = 40 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image003.png\" \/>Radius of cone <img decoding=\"async\" style=\"height: 41px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image045.png\" \/>= 20 cm<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image046.png\" \/>m = 0.2 m<\/p>\n<p><img decoding=\"async\" id=\"Picture 39\" style=\"height: 211px; width: 187px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image047.jpg\" \/><\/p>\n<p>Height of cone <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image022.png\" \/>= 1 m<\/p>\n<p>Slant height of cone <img decoding=\"async\" style=\"height: 31px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image023.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 35px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image048.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image049.png\" \/>m<\/p>\n<p>Curved surface area of cone = <img decoding=\"async\" style=\"height: 19px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image008.png\" \/><\/p>\n<p>= 3.14 x 0.2 x <img decoding=\"async\" style=\"height: 24px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image049.png\" \/><\/p>\n<p>= 0.64056 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image029.png\" \/>Cost of painting 1 m<sup>2<\/sup> of a cone<\/p>\n<p>= Rs. 12<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Cost of painting 0.64056 m<sup>2<\/sup> of a cone<\/p>\n<p>= 12 x 0.64056= Rs. 7.68672<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/maths\/13_3\/image030.png\" \/>Cost of painting of 50 such cones<\/p>\n<p>= 50 x 7.68672 = Rs. 384.34 (approx.)<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Maths_Exercise_133\"><\/span>NCERT Solutions for Class 9 Maths Exercise 13.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 9 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Maths Exercise 13.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Maths chapter &#8230; <a title=\"NCERT Solutions for Class 9 Maths Exercise 13.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths-exercise-13-3\/\" aria-label=\"More on NCERT Solutions for Class 9 Maths Exercise 13.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1376,281],"tags":[283,1344,321,1485,216],"class_list":["post-4990","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-09","category-ncert-solutions","tag-cbse-study-material","tag-class-9","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Maths Exercise 13.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Maths Exercise 13.3 in PDF format for free download. 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