{"id":4974,"date":"2016-05-19T11:49:00","date_gmt":"2016-05-19T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-7-2\/"},"modified":"2023-03-22T15:11:50","modified_gmt":"2023-03-22T09:41:50","slug":"ncert-solutions-for-class-10-maths-exercise-7-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 7.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#NCERT_Solutions_for_Class_10_Maths_Coordinate_Geometry\" >NCERT Solutions for Class 10 Maths\u00a0Coordinate Geometry<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#1_Find_the_coordinates_of_the_point_which_divides_the_join_of_%E2%80%931_7_and_4_%E2%80%933_in_the_ratio_2_3\" >1. Find the coordinates of the point which divides the join of (\u20131, 7) and (4, \u20133) in the ratio 2:3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#2_Find_the_coordinates_of_the_points_of_trisection_of_the_line_segment_joining_4_%E2%80%931_and_%E2%80%932_%E2%80%933\" >2. Find the coordinates of the points of trisection of the line segment joining (4, \u20131) and (\u20132, \u20133).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#3_To_conduct_sports_day_activities_in_your_rectangular_shaped_school_ground_ABCD_lines_have_been_drawn_with_chalk_powder_at_a_distance_of_1_m_each_100_flower_pots_have_been_placed_at_a_distance_of_1_m_from_each_other_along_AD_Niharika_runs_14th_of_the_distance_AD_on_the_2nd_line_and_posts_a_green_flag_Preet_runs_15th_of_the_distance_AD_on_the_eighth_line_and_posts_a_red_flag_What_is_the_distance_between_both_the_flags_If_Rashmi_has_to_post_a_blue_flag_exactly_halfway_between_the_line_segment_joining_the_two_flags_where_should_she_post_her_flag\" >3. To conduct sports day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1 m each. 100 flower pots have been placed at a distance of 1 m from each other along AD. Niharika runs 14th of the distance AD on the 2nd line and posts a green flag. Preet runs 15th of the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#4_Find_the_ratio_in_which_the_line_segment_joining_the_points_%E2%80%933_10_and_6_%E2%80%938_is_divided_by_%E2%80%931_6\" >4. Find the ratio in which the line segment joining the points (\u20133, 10) and (6, \u20138) is divided by (\u20131, 6).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#5_Find_the_ratio_in_which_the_line_segment_joining_A_1_%E2%80%935_and_B_%E2%80%934_5_is_divided_by_the_x%E2%80%93axis_Also_find_the_coordinates_of_the_point_of_division\" >5. Find the ratio in which the line segment joining A (1, \u20135) and B (\u20134, 5) is divided by the x\u2013axis. Also find the coordinates of the point of division.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#6_If_1_2_4_y_x_6_and_3_5_are_the_vertices_of_a_parallelogram_taken_in_order_find_x_and_y\" >6. If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#7_Find_the_coordinates_of_a_point_A_where_AB_is_the_diameter_of_a_circle_whose_centre_is_2_%E2%80%933_and_B_is_1_4\" >7. Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, \u20133) and B is (1, 4).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#8_If_A_and_B_are_%E2%80%932_%E2%80%932_and_2_%E2%80%934_respectively_find_the_coordinates_of_P_such_that_AP_AB_and_P_lies_on_the_line_segment_AB\" >8. If A and B are (\u20132, \u20132) and (2, \u20134) respectively, find the coordinates of P such that AP = AB and P lies on the line segment AB.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#9_Find_the_coordinates_of_the_points_which_divides_the_line_segment_joining_A_%E2%80%932_2_and_B_2_8_into_four_equal_parts\" >9. Find the coordinates of the points which divides the line segment joining A (\u20132, 2) and B (2, 8) into four equal parts.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#10_Find_the_area_of_a_rhombus_if_its_vertices_are_3_0_4_5_%E2%80%931_4_and_%E2%80%932_%E2%80%931_taken_in_order_Hint_Area_of_a_rhombus_product_of_its_diagonals\" >10. Find the area of a rhombus if its vertices are (3, 0), (4, 5), (\u20131, 4) and (\u20132, \u20131) taken in order. {Hint: Area of a rhombus =  (product of its diagonals)}<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#NCERT_Solutions_for_Class_10_Maths_Exercise_72\" >NCERT Solutions for Class 10 Maths Exercise 7.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-7-2\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<div class=\"addtoany_share_save_container addtoany_content addtoany_content_top\">\n<div class=\"a2a_kit a2a_kit_size_50 addtoany_list\" data-a2a-url=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-7-1\/\" data-a2a-title=\"NCERT Solutions for Class 10 Maths Exercise 7.1\">NCERT Solutions for Class 10 Maths Exercise 7.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/div>\n<\/div>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Coordinate Geometry\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-coordinate-geometry\/1209\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 7.2\" width=\"166\" height=\"205\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Coordinate_Geometry\"><\/span>NCERT Solutions for Class 10 Maths\u00a0Coordinate Geometry<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"1_Find_the_coordinates_of_the_point_which_divides_the_join_of_%E2%80%931_7_and_4_%E2%80%933_in_the_ratio_2_3\"><\/span><strong>1. Find the coordinates of the point which divides the join of (\u20131, 7) and (4, \u20133) in the ratio 2:3.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let <img decoding=\"async\" style=\"height: 24px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image001.png\" \/> and <img decoding=\"async\" style=\"height: 24px; width: 192px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image002.png\" \/><\/p>\n<p style=\"text-align: justify;\">Using Section Formula to find coordinates of point which divides join of (\u20131, 7) and (4, \u20133) in the ratio 2:3, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 45px; width: 306px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image003.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 45px; width: 340px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image004.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, the coordinates of point are (1, 3) which divides join of (\u20131, 7) and<\/p>\n<p style=\"text-align: justify;\">(4, \u20133) in the ratio 2:3.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Find_the_coordinates_of_the_points_of_trisection_of_the_line_segment_joining_4_%E2%80%931_and_%E2%80%932_%E2%80%933\"><\/span><strong>2. Find the coordinates of the points of trisection of the line segment joining (4, \u20131) and (\u20132, \u20133). <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 9\" style=\"height: 207px; width: 231px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image005.jpg\" alt=\"\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong><img decoding=\"async\" id=\"Picture 10\" style=\"height: 71px; width: 297px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image006.jpg\" alt=\"\" \/><\/p>\n<p style=\"text-align: justify;\">We want to find coordinates of the points of trisection of the line segment joining (4, \u20131) and (\u20132, \u20133).<\/p>\n<p style=\"text-align: justify;\">We are given AC = CD = DB<\/p>\n<p style=\"text-align: justify;\">We want to find coordinates of point C and D.<\/p>\n<p style=\"text-align: justify;\">Let coordinates of point C be <img decoding=\"async\" style=\"height: 26px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image007.png\" \/>and let coordinates of point D be <img decoding=\"async\" style=\"height: 26px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image008.png\" \/><\/p>\n<p style=\"text-align: justify;\">Clearly, point C divides line segment AB in 1:2 and point D divides line segment AB in 2:1.<\/p>\n<p style=\"text-align: justify;\">Using Section Formula to find coordinates of point C which divides join of (4, \u20131) and (\u20132, \u20133) in the ratio 1:2, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 232px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image009.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 240px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\">Using Section Formula to find coordinates of point D which divides join of (4, \u20131) and (\u20132, \u20133) in the ratio 2:1, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 236px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 250px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, coordinates of point C are (2, <img decoding=\"async\" style=\"height: 42px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image013.png\" \/>) and coordinates of point D are (0, <img decoding=\"async\" style=\"height: 42px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image014.png\" \/>).<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_To_conduct_sports_day_activities_in_your_rectangular_shaped_school_ground_ABCD_lines_have_been_drawn_with_chalk_powder_at_a_distance_of_1_m_each_100_flower_pots_have_been_placed_at_a_distance_of_1_m_from_each_other_along_AD_Niharika_runs_14th_of_the_distance_AD_on_the_2nd_line_and_posts_a_green_flag_Preet_runs_15th_of_the_distance_AD_on_the_eighth_line_and_posts_a_red_flag_What_is_the_distance_between_both_the_flags_If_Rashmi_has_to_post_a_blue_flag_exactly_halfway_between_the_line_segment_joining_the_two_flags_where_should_she_post_her_flag\"><\/span><strong>3. To conduct sports day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1 m each. 100 flower pots have been placed at a distance of 1 m from each other along AD. Niharika runs 14th of the distance AD on the 2nd line and posts a green flag. Preet runs 15th of the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Niharika runs 14<sup>th<\/sup> of the distance AD on the 2<sup>nd<\/sup> line and posts a green flag.<\/p>\n<p style=\"text-align: justify;\">There are 100 flower pots. It means, she stops at 25th flower pot.<\/p>\n<p style=\"text-align: justify;\">Therefore, the coordinates of point where she stops are (2 m, 25 m).<\/p>\n<p style=\"text-align: justify;\">Preet runs 15th of the distance AD on the eighth line and posts a red flag. There are 100 flower pots. It means, she stops at 20th flower pot.<\/p>\n<p style=\"text-align: justify;\">Therefore, the coordinates of point where she stops are (8, 20).<\/p>\n<p style=\"text-align: justify;\">Using Distance Formula to find distance between points (2 m, 25 m) and (8 m, 20 m), we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 29px; width: 388px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">Rashmi posts a blue flag exactly halfway the line segment joining the two flags.<\/p>\n<p style=\"text-align: justify;\">Using section formula to find the coordinates of this point, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image016.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, coordinates of point, where Rashmi posts her flag are (5, <img decoding=\"async\" style=\"height: 42px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image018.png\" \/>).<\/p>\n<p style=\"text-align: justify;\">It means she posts her flag in 5th line after covering <img decoding=\"async\" style=\"height: 42px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image018.png\" \/> = 22.5 m of distance.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_Find_the_ratio_in_which_the_line_segment_joining_the_points_%E2%80%933_10_and_6_%E2%80%938_is_divided_by_%E2%80%931_6\"><\/span><strong>4. Find the ratio in which the line segment joining the points (\u20133, 10) and (6, \u20138) is divided by (\u20131, 6).<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let (\u20131, 6) divides line segment joining the points (\u20133, 10) and (6, \u20138) in k:1.<\/p>\n<p style=\"text-align: justify;\">Using Section formula, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image019.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 \u2212k \u2013 1 = (\u22123 + 6k)<\/p>\n<p style=\"text-align: justify;\">\u21d2 \u22127k = \u22122<\/p>\n<p style=\"text-align: justify;\">\u21d2 k = <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image020.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, the ratio is <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image020.png\" \/>:1 which is equivalent to 2:7.<\/p>\n<p style=\"text-align: justify;\">Therefore, (\u20131, 6) divides line segment joining the points (\u20133, 10) and (6, \u20138) in 2:7.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_Find_the_ratio_in_which_the_line_segment_joining_A_1_%E2%80%935_and_B_%E2%80%934_5_is_divided_by_the_x%E2%80%93axis_Also_find_the_coordinates_of_the_point_of_division\"><\/span><strong>5. Find the ratio in which the line segment joining A (1, \u20135) and B (\u20134, 5) is divided by the x\u2013axis. Also find the coordinates of the point of division.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let the coordinates of point of division be (x, 0) and suppose it divides line segment joining A (1, \u20135) and B (\u20134, 5) in k:1.<\/p>\n<p style=\"text-align: justify;\">According to Section formula, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 306px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image021.png\" \/> \u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image022.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 5 = 5k<\/p>\n<p style=\"text-align: justify;\">\u21d2 k = 1<\/p>\n<p style=\"text-align: justify;\">Putting value of k in (1), we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 196px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, point (<img decoding=\"async\" style=\"height: 42px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image024.png\" \/>, 0) on x\u2013axis divides line segment joining A (1, \u20135) and B (\u20134, 5) in 1:1.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_If_1_2_4_y_x_6_and_3_5_are_the_vertices_of_a_parallelogram_taken_in_order_find_x_and_y\"><\/span><strong>6. If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let A = (1, 2), B = (4, y), C = (x, 6) and D = (3, 5)<\/p>\n<p style=\"text-align: justify;\">We know that diagonals of parallelogram bisect each other. It means that coordinates of midpoint of diagonal AC would be same as coordinates of midpoint of diagonal BD. \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">Using Section formula, the coordinates of midpoint of AC are:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 134px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\">Using Section formula, the coordinates of midpoint of BD are:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image026.png\" \/><\/p>\n<p style=\"text-align: justify;\">According to condition (1), we have<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 (1 + x) = 7<\/p>\n<p style=\"text-align: justify;\">\u21d2 x = 6<\/p>\n<p style=\"text-align: justify;\">Again, according to condition (1), we also have<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image028.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 8 = 5 + y<\/p>\n<p style=\"text-align: justify;\">\u21d2 y = 3<\/p>\n<p style=\"text-align: justify;\">Therefore, x = 6 and y = 3<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_Find_the_coordinates_of_a_point_A_where_AB_is_the_diameter_of_a_circle_whose_centre_is_2_%E2%80%933_and_B_is_1_4\"><\/span><strong>7. Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, \u20133) and B is (1, 4).<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>We want to find coordinates of point A. AB is the diameter and coordinates of center are (2, \u20133) and, coordinates of point B are (1, 4).<\/p>\n<p style=\"text-align: justify;\">Let coordinates of point A are (x, y). Using section formula, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 58px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image029.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 4 = x + 1<\/p>\n<p style=\"text-align: justify;\">\u21d2 x = 3<\/p>\n<p style=\"text-align: justify;\">Using section formula, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image030.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 \u22126 = 4 + y<\/p>\n<p style=\"text-align: justify;\">\u21d2 y = \u221210<\/p>\n<p style=\"text-align: justify;\">Therefore, Coordinates of point A are (3, \u201310).<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"8_If_A_and_B_are_%E2%80%932_%E2%80%932_and_2_%E2%80%934_respectively_find_the_coordinates_of_P_such_that_AP_AB_and_P_lies_on_the_line_segment_AB\"><\/span><strong>8. If A and B are (\u20132, \u20132) and (2, \u20134) respectively, find the coordinates of P such that AP = <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image031.png\" \/>AB and P lies on the line segment AB.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>A = (\u20132, \u20132) and B = (2, \u20134)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 11\" style=\"height: 64px; width: 249px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image032.jpg\" alt=\"\" \/><\/p>\n<p style=\"text-align: justify;\">It is given that AP=<img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image031.png\" \/>AB<\/p>\n<p style=\"text-align: justify;\">PB = AB \u2013 AP = AB \u2212 <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image031.png\" \/>AB = <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image033.png\" \/>AB<\/p>\n<p style=\"text-align: justify;\">So, we have AP: PB = 3: 4<\/p>\n<p style=\"text-align: justify;\">Let coordinates of P be (x, y)<\/p>\n<p style=\"text-align: justify;\">Using Section formula to find coordinates of P, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 207px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image034.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 253px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image035.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, Coordinates of point P are <img decoding=\"async\" style=\"height: 45px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image036.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"9_Find_the_coordinates_of_the_points_which_divides_the_line_segment_joining_A_%E2%80%932_2_and_B_2_8_into_four_equal_parts\"><\/span><strong>9. Find the coordinates of the points which divides the line segment joining A (\u20132, 2) and B (2, 8) into four equal parts.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>A = (\u20132, 2) and B = (2, 8)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 12\" style=\"height: 70px; width: 251px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image037.jpg\" alt=\"Sec\" \/><\/p>\n<p style=\"text-align: justify;\">Let P, Q and R are the points which divide line segment AB into 4 equal parts.<\/p>\n<p style=\"text-align: justify;\">Let coordinates of point<img decoding=\"async\" style=\"height: 26px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image038.png\" \/>, <img decoding=\"async\" style=\"height: 26px; width: 195px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image039.png\" \/><\/p>\n<p style=\"text-align: justify;\">We know AP = PQ = QR = RS.<\/p>\n<p style=\"text-align: justify;\">It means, point P divides line segment AB in 1:3.<\/p>\n<p style=\"text-align: justify;\">Using Section formula to find coordinates of point P, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 252px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image040.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 210px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image041.png\" \/><\/p>\n<p style=\"text-align: justify;\">Since, AP = PQ = QR = RS.<\/p>\n<p style=\"text-align: justify;\">It means, point Q is the mid-point of AB.<\/p>\n<p style=\"text-align: justify;\">Using Section formula to find coordinates of point Q, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 231px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image042.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 206px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image043.png\" \/><\/p>\n<p style=\"text-align: justify;\">Because, AP = PQ = QR = RS.<\/p>\n<p style=\"text-align: justify;\">It means, point R divides line segment AB in 3:1<\/p>\n<p style=\"text-align: justify;\">Using Section formula to find coordinates of point P, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 232px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image044.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 228px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image045.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, P = (\u20131, <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image046.png\" \/>), Q= (0, <img decoding=\"async\" style=\"height: 19px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image047.png\" \/>)and R = (1, <img decoding=\"async\" style=\"height: 42px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image048.png\" \/>)<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 7.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"10_Find_the_area_of_a_rhombus_if_its_vertices_are_3_0_4_5_%E2%80%931_4_and_%E2%80%932_%E2%80%931_taken_in_order_Hint_Area_of_a_rhombus_product_of_its_diagonals\"><\/span><strong>10. Find the area of a rhombus if its vertices are (3, 0), (4, 5), (\u20131, 4) and (\u20132, \u20131) taken in order.<\/strong> <strong>{Hint: Area of a rhombus = <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image049.png\" \/><\/strong> <strong>(product of its diagonals)}<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let A = (3, 0), B = (4, 5), C = (\u20131, 4) and D = (\u20132, \u20131)<\/p>\n<p style=\"text-align: justify;\">Using Distance Formula to find length of diagonal AC, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 31px; width: 432px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\">Using Distance Formula to find length of diagonal BD, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 31px; width: 431px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image051.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image052.png\" \/> Area of rhombus = \u00bd (product of its diagonals)<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 42px; width: 194px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch07\/Ex7.2\/image053.png\" \/>= 24 sq. units<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_72\"><\/span>NCERT Solutions for Class 10 Maths Exercise 7.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<strong><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\">the best app for CBSE\u00a0<\/a><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 7.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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