{"id":4953,"date":"2016-05-19T09:49:00","date_gmt":"2016-05-19T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/"},"modified":"2023-03-22T15:18:51","modified_gmt":"2023-03-22T09:48:51","slug":"ncert-solutions-class-10-maths-exercise-12-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 12.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#NCERT_Solutions_for_Class_10_Maths_123_Area_Related_to_Circles\" >NCERT Solutions for Class 10 Maths 12.3 (Area Related to Circles)<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_1_of_123_class_10_Maths\" >Q. 1 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_2_of_123_class_10_Maths\" >Q. 2 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_3_of_123_class_10_Maths\" >Q. 3 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_4_of_123_class_10_Maths\" >Q. 4 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_5_of_123_class_10_Maths\" >Q. 5 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_6_of_123_class_10_Maths\" >Q. 6 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_7_of_123_class_10_Maths\" >Q. 7 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_8_of_123_class_10_Maths\" >Q. 8 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_9_of_123_class_10_Maths\" >Q. 9 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_10_of_123_class_10_Maths\" >Q. 10 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_11_of_123_class_10_Maths\" >Q. 11 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_12_of_123_class_10_Maths\" >Q. 12 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_13_of_123_class_10_Maths\" >Q. 13 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_14_of_123_class_10_Maths\" >Q. 14 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_15_of_123_class_10_Maths\" >Q. 15 of 12.3 class 10 Maths<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Q_16_of_123_class_10_Maths\" >Q. 16 of 12.3 class 10 Maths<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#NCERT_Solutions_for_Class_10_Maths_Chapter_12\" >NCERT Solutions for Class 10 Maths Chapter 12<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Area_Related_to_Circles_Exercise_121\" >Area Related to Circles Exercise 12.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Area_Related_to_Circles_Exercise_122\" >Area Related to Circles Exercise 12.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#Area_Related_to_Circles_Exercise_123\" >Area Related to Circles Exercise 12.3<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/#CBSE_Guide_App_for_Class_10\" >CBSE Guide App for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>12.3 class 10 maths NCERT Solutions are available in PDF format for free download. The <a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths\/\">NCERT Solutions for Class 10 Maths<\/a> Exercise 12.3 are also available on myCBSEguide&#8217;s student dashboard for free download. The NCERT chapter-wise questions and answers are very helpful for the CBSE board exam. CBSE recommends NCERT books and most of the questions in the CBSE exam are asked from NCERT textbooks. Class 10 Maths chapter-wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT Solutions for Maths <\/strong><strong>Area Related to Circles<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-area-related-to-circles\/1212\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 12.3\" width=\"173\" height=\"213\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_123_Area_Related_to_Circles\"><\/span>NCERT Solutions for Class 10 Maths 12.3 (Area Related to Circles)<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><strong>Unless stated otherwise, take <img decoding=\"async\" style=\"height: 41px; width: 53px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image001.png\" \/> <\/strong><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_1_of_123_class_10_Maths\"><\/span>Q. 1 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>1. Find the area of the shaded region in figure, if PQ = 24 cm, PR = 7 cm and O is the centre of the circle.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1035\" style=\"height: 138px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image002.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image003.png\" \/>RPQ = <img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image004.png\" \/>[Angle in semi-circle is <img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image004.png\" \/>]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 29px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image007.png\" \/> = 49 + 576 = 625<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/>RQ = 25 cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> Diameter of the circle = 25 cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> Radius of the circle = <img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image009.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\">Area of the semicircle = <img decoding=\"async\" style=\"height: 41px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image011.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 66px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\">Area of right triangle RPQ = <img decoding=\"async\" style=\"height: 42px; width: 70px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image013.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image014.png\" \/> = <img decoding=\"async\" style=\"height: 22px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">Area of shaded region = Area of semicircle \u2013 Area of right triangle RPQ<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 164px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image016.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 66px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image017.png\" \/><\/p>\n<hr \/>\n<h3><span class=\"ez-toc-section\" id=\"Q_2_of_123_class_10_Maths\"><\/span>Q. 2 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>2. Find the area of the shaded region in figure, if radii of the two concentric circles with centre O are 7 cm and 14 cm respectively and <\/strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image003.png\" \/><strong>AOC = <\/strong><img decoding=\"async\" style=\"height: 19px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1038\" style=\"height: 135px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image019.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region = Area of sector OAC \u2013 Area of sector OBD<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 229px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image020.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 159px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image021.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image022.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image024.png\" \/><\/p>\n<hr \/>\n<h3><span class=\"ez-toc-section\" id=\"Q_3_of_123_class_10_Maths\"><\/span>Q. 3 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>3. Find the area of the shaded region in figure, if ABCD is a square of side 14 cm and APD and BPC are semicircles.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1041\" style=\"height: 167px; width: 151px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image025.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 176px; width: 158px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image026.png\" \/><\/p>\n<p style=\"text-align: justify;\">= Area of square ABCD \u2013 (Area of semicircle APD + Area of semicircle BPC)<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 53px; width: 254px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image028.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 196 \u2013 154 = <img decoding=\"async\" style=\"height: 22px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image029.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_4_of_123_class_10_Maths\"><\/span>Q. 4 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>4. Find the area of the shaded region in figure, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as centre.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1044\" style=\"height: 162px; width: 137px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image030.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region<\/p>\n<p style=\"text-align: justify;\">= Area of circle + Area of equilateral triangle OAB \u2013 Area common to the circle and the triangle<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 211px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 24px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image032.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 24px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image033.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image034.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 121px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image035.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_5_of_123_class_10_Maths\"><\/span>Q. 5 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>5. From each corner of a square of side 4 cm a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown in figure. Find the area of the remaining portion of the figure.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1047\" style=\"height: 124px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image036.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of remaining portion of the square<\/p>\n<p style=\"text-align: justify;\">= Area of square \u2013 (4 <img decoding=\"async\" style=\"height: 14px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image037.png\" \/> Area of a quadrant + Area of a circle)<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 53px; width: 260px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image038.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image039.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 50px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image040.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_6_of_123_class_10_Maths\"><\/span>Q. 6 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>6. In a circular table cover of radius 32 cm, a design is formed leaving an equilateral triangle ABC in the middle as shown in figure. Find the area of the design (shaded region).<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1050\" style=\"height: 161px; width: 151px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image041.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of design = Area of circular table cover \u2013 Area of the equilateral triangle ABC<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 180px; width: 210px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image042.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image043.png\" \/>\u2026\u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image044.png\" \/> G is the centroid of the equilateral triangle.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> radius of the circumscribed circle = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image045.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\">According to the question, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image046.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image047.png\" \/> = 48 cm<\/p>\n<p style=\"text-align: justify;\">Now, <img decoding=\"async\" style=\"height: 49px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image048.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image049.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image051.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image052.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 48px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image053.png\" \/> = 3072<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image054.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> Required area = <img decoding=\"async\" style=\"height: 45px; width: 132px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image055.png\" \/>[From eq. (i)]\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 123px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image056.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image057.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_7_of_123_class_10_Maths\"><\/span>Q. 7 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>7. In figure ABCD is a square of side 14 cm. With centers A, B, C and D, four circles are drawn such that each circle touches externally two of the remaining three circles. Find the area of the shaded region.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1053\" style=\"height: 166px; width: 166px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image058.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region = Area of square \u2013 4 <img decoding=\"async\" style=\"height: 14px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image037.png\" \/> Area of sector<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 49px; width: 193px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image059.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image028.png\" \/> = 196 \u2013 154 = <img decoding=\"async\" style=\"height: 22px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image029.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_8_of_123_class_10_Maths\"><\/span>Q. 8 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>8. Figure depicts a racing track whose left and right ends are semicircular.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1056\" style=\"height: 80px; width: 258px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image060.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>The distance between the two inner parallel line segments is 60 m and they are each 106 m long. If the track is 10 m wide, find:<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(i) the distance around the track along its inner edge.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) the area of the track.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong>Distance around the track along its inner edge<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 48px; width: 243px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image061.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image062.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image063.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image064.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong>Area of track = <img decoding=\"async\" style=\"height: 45px; width: 365px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image065.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 212px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image066.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image067.png\" \/> = <img decoding=\"async\" style=\"height: 22px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image068.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_9_of_123_class_10_Maths\"><\/span>Q. 9 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>9. In figure, AB and CD are two diameters of a circle (with centre O) perpendicular to each other and OD is the diameter of the smaller circle. If OA = 7 cm, find the area of the shaded region.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1059\" style=\"height: 160px; width: 156px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image069.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region = Area of circle + Area of semicircle ACB \u2013 Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image070.png\" \/>ACB<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 49px; width: 271px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image071.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image072.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image073.png\" \/> = <img decoding=\"async\" style=\"height: 22px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image074.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_10_of_123_class_10_Maths\"><\/span>Q. 10 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>10. The area of an equilateral triangle ABC is<img decoding=\"async\" style=\"height: 22px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image075.png\" \/>. With each vertex of the triangle as centre, a circle is drawn with radius equal to half the length of the side of the triangle (see figure). Find the area of the shaded region. <\/strong><img decoding=\"async\" style=\"height: 32px; width: 223px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image076.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1062\" style=\"height: 171px; width: 179px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image077.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of equilateral triangle = <img decoding=\"async\" style=\"height: 45px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image078.png\" \/> = 17320.5<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/><img decoding=\"async\" style=\"height: 44px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image079.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image080.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 21px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image081.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 19px; width: 53px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image082.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\">Area of shaded region = Area of<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image070.png\" \/>ABC \u2013 <img decoding=\"async\" style=\"height: 53px; width: 161px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image083.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 17320.5 \u2013 15700 = <img decoding=\"async\" style=\"height: 22px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image084.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_11_of_123_class_10_Maths\"><\/span>Q. 11 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>11. On a square handkerchief, nine circular designs each of radius 7 cm are made (see figure). Find the area of the remaining portion of the handkerchief.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1065\" style=\"height: 164px; width: 172px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image085.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of remaining portion of handkerchief = Area of square ABCD \u2013 Area of 9 circular designs<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image086.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 1764 \u2013 1386 = <img decoding=\"async\" style=\"height: 22px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image087.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_12_of_123_class_10_Maths\"><\/span>Q. 12 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>12. In figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the: <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 993\" style=\"height: 128px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image088.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(i) quadrant OACB<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) shaded region<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong>Area of quadrant OACB = <img decoding=\"async\" style=\"height: 44px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image089.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image090.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image091.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> Area of shaded region = Area of quadrant OACB \u2013 Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image070.png\" \/>OBD<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image092.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image093.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image094.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image095.png\" \/> cm<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_13_of_123_class_10_Maths\"><\/span>Q. 13 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>13. In figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. <\/strong><img decoding=\"async\" style=\"height: 27px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image096.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 1071\" style=\"height: 113px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image097.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>OB = <img decoding=\"async\" style=\"height: 27px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image098.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 27px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image099.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 23px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image100.png\" \/>OA = <img decoding=\"async\" style=\"height: 23px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image101.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\">Area of shaded region = Area of quadrant OPBQ \u2013 Area of square OABC<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 44px; width: 192px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image102.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 129px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image103.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 19px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image104.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 22px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image105.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_14_of_123_class_10_Maths\"><\/span>Q. 14 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>14. AB and CD are respectively arcs of two concentric circles of radii 21 cm and 7 cm and centre O (see figure). If <\/strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image003.png\" \/><strong>AOB = <\/strong><img decoding=\"async\" style=\"height: 24px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image106.png\" \/><strong> find the area of the shaded region.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1074\" style=\"height: 180px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image107.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Area of shaded region = Area of sector OAB \u2013 Area of sector OCD<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 44px; width: 240px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image108.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 209px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image109.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image110.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image111.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image112.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image113.png\" \/> <img decoding=\"async\" style=\"height: 22px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image114.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_15_of_123_class_10_Maths\"><\/span>Q. 15 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>15. In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1077\" style=\"height: 123px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image115.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle BAC, <img decoding=\"async\" style=\"height: 22px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image116.png\" \/>[Pythagoras theorem]\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 997\" style=\"height: 122px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image117.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/><img decoding=\"async\" style=\"height: 29px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image118.png\" \/> = <img decoding=\"async\" style=\"height: 29px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image119.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> BC = <img decoding=\"async\" style=\"height: 23px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image120.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/>Radius of the semicircle = <img decoding=\"async\" style=\"height: 45px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image121.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> Required area = Area BPCQB<\/p>\n<p style=\"text-align: justify;\">= Area BCQB \u2013 Area BCPB<\/p>\n<p style=\"text-align: justify;\">= Area BCQB \u2013 (Area BACPB \u2013 Area <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image070.png\" \/>BAC)<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 312px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image122.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 209px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image123.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 154 \u2013 (154 \u2013 98) = <img decoding=\"async\" style=\"height: 22px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image124.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 12.3<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Q_16_of_123_class_10_Maths\"><\/span>Q. 16 of 12.3 class 10 Maths<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p style=\"text-align: justify;\"><strong>16. Calculate the area of the designed region in figure common between the two quadrants of circles of radius 8 cm each.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1080\" style=\"height: 149px; width: 191px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image125.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans.<\/strong> In right triangle ADC, <img decoding=\"async\" style=\"height: 22px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image126.png\" \/>[Pythagoras theorem]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/><img decoding=\"async\" style=\"height: 29px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image127.png\" \/> = <img decoding=\"async\" style=\"height: 29px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image128.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> AC = <img decoding=\"async\" style=\"height: 24px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image129.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image130.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 999\" style=\"height: 176px; width: 209px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image131.jpg\" \/><\/p>\n<p style=\"text-align: justify;\">Draw BM<img decoding=\"async\" style=\"height: 17px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image132.png\" \/>AC.<\/p>\n<p style=\"text-align: justify;\">Then AM = MC = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image133.png\" \/>AC = <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image134.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image135.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\">In right triangle AMB,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 20px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image136.png\" \/> [Pythagoras theorem]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 36px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image137.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> <img decoding=\"async\" style=\"height: 20px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image138.png\" \/>= 64 \u2013 32 = 32<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image008.png\" \/> BM = <img decoding=\"async\" style=\"height: 23px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image135.png\" \/> cm<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/>Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image070.png\" \/>ABC = <img decoding=\"async\" style=\"height: 42px; width: 90px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image139.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 45px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image140.png\" \/> = <img decoding=\"async\" style=\"height: 22px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image141.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> Half Area of shaded region<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 44px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image142.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image143.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 54px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image144.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image005.png\" \/> Area of designed region<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image145.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch12\/Ex12.3\/image146.png\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Chapter_12\"><\/span>NCERT Solutions for Class 10 Maths Chapter 12<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes textbook solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths NCERT class 10 PDF solutions with the latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<ul>\n<li>\n<h3><span class=\"ez-toc-section\" id=\"Area_Related_to_Circles_Exercise_121\"><\/span><a href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-1\/\" data-cke-saved-href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-1\/\">Area Related to Circles Exercise 12.1<\/a><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/li>\n<li>\n<h3><span class=\"ez-toc-section\" id=\"Area_Related_to_Circles_Exercise_122\"><\/span><a href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-2\/\" data-cke-saved-href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-2\/\">Area Related to Circles Exercise 12.2<\/a><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/li>\n<li>\n<h3><span class=\"ez-toc-section\" id=\"Area_Related_to_Circles_Exercise_123\"><\/span><a href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/\" data-cke-saved-href=\"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/\">Area Related to Circles Exercise 12.3<\/a><span class=\"ez-toc-section-end\"><\/span><\/h3>\n<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_Guide_App_for_Class_10\"><\/span>CBSE Guide App for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science, Hindi, English, and Social Science do check the myCBSEguide app or website. myCBSEguide provides sample papers with solutions, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Papers all are made available through <strong><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\">the best app for CBSE\u00a0<\/a><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>12.3 class 10 maths NCERT Solutions are available in PDF format for free download. The NCERT Solutions for Class 10 Maths Exercise 12.3 are also available on myCBSEguide&#8217;s student dashboard for free download. The NCERT chapter-wise questions and answers are very helpful for the CBSE board exam. CBSE recommends NCERT books and most of the &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 12.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-12-3\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 12.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":29760,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4953","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 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