{"id":4948,"date":"2016-05-19T09:49:00","date_gmt":"2016-05-19T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-11-1\/"},"modified":"2023-03-22T15:17:38","modified_gmt":"2023-03-22T09:47:38","slug":"ncert-solutions-for-class-10-maths-exercise-11-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 11.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#NCERT_Solutions_for_Class_10_Maths_Constructions\" >NCERT Solutions for Class 10 Maths\u00a0Constructions<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#n_each_of_the_following_give_the_justification_of_the_construction_also\" >n each of the following, give the justification of the construction also:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#2_Construct_a_triangle_of_sides_4_cm_5_cm_and_6_cm_and_then_a_triangle_similar_to_it_whose_sides_are_of_the_corresponding_sides_of_the_first_triangle\" >2. Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are  of the corresponding sides of the first triangle.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#3_Construct_a_triangle_with_sides_6_cm_6_cm_and_7_cm_and_then_another_triangle_whose_sides_are_of_the_corresponding_sides_of_the_first_triangle\" >3. Construct a triangle with sides 6 cm, 6 cm and 7 cm and then another triangle whose sides are  of the corresponding sides of the first triangle.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#4_Construct_an_isosceles_triangle_whose_base_is_8_cm_and_altitude_4_cm_and_then_another_triangle_whose_sides_are_times_the_corresponding_sides_of_the_isosceles_triangle\" >4. Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are  times the corresponding sides of the isosceles triangle.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#5_Draw_a_triangle_ABC_with_side_BC_6_cm_AB_5_cm_and_ABC_Then_construct_a_triangle_whose_sides_are_of_the_corresponding_sides_of_triangle_ABC\" >5. Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and ABC =  Then construct a triangle whose sides are  of the corresponding sides of triangle ABC.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#6_Draw_a_triangle_ABC_with_side_BC_7_cm_B_A_Then_construct_a_triangle_whose_sides_are_times_the_corresponding_sides_of_ABC\" >6. Draw a triangle ABC with side BC = 7 cm, B = A =  Then construct a triangle whose sides are  times the corresponding sides of ABC.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#7_Draw_a_right_triangle_in_which_the_sides_other_than_hypotenuse_are_of_lengths_4_cm_and_3_cm_Then_construct_another_triangle_whose_sides_are_times_the_corresponding_sides_of_the_given_triangle\" >7. Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are  times the corresponding sides of the given triangle.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#NCERT_Solutions_for_Class_10_Maths_Exercise_111\" >NCERT Solutions for Class 10 Maths Exercise 11.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Maths Exercise 11.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths Constructions<\/strong><strong>\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-constructions\/1211\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 11.1\" width=\"180\" height=\"222\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Constructions\"><\/span>NCERT Solutions for Class 10 Maths\u00a0Constructions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"n_each_of_the_following_give_the_justification_of_the_construction_also\"><\/span><strong>n each of the following, give the justification of the construction also:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>1. Draw a line segment of length 7.6 cm and divide it in the ratio 5: 8. Measure the two parts.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. Given<\/strong>: A line segment of length 7.6 cm.<\/p>\n<p style=\"text-align: justify;\"><strong>To construct<\/strong>: To divide it in the ration 5: 8 and to measure the two parts.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1\" style=\"height: 168px; width: 271px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image001.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>From any ray AX, making an acute angle with AB.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>Locate 13 (=5 + 8) points <img decoding=\"async\" style=\"height: 24px; width: 348px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image002.png\" \/>on AX such that<img decoding=\"async\" style=\"height: 24px; width: 649px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image003.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Join<img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image004.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Through the point<img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image005.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 34px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image006.png\" \/>intersecting AB at the point C.<\/p>\n<p style=\"text-align: justify;\">Then, AC: CB = 5: 8<\/p>\n<p style=\"text-align: justify;\">On measurement, AC = 3.1 cm, CB = 4.5 cm<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image008.png\" \/>[By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 45px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image011.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/>AC: CB = 5: 8<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Construct_a_triangle_of_sides_4_cm_5_cm_and_6_cm_and_then_a_triangle_similar_to_it_whose_sides_are_of_the_corresponding_sides_of_the_first_triangle\"><\/span><strong>2. Construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image014.png\" \/><strong> of the corresponding sides of the first triangle.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct a triangle of sides 4 cm, 5 cm and 6 cm and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image014.png\" \/> of the corresponding sides of the first triangle.<\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 2\" style=\"height: 186px; width: 200px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image015.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw a triangle ABC of sides 4 cm, 5 cm and 6 cm.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Locate 3 points <img decoding=\"async\" style=\"height: 24px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image016.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image017.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image019.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/>intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image020.png\" \/> [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 45px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image021.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image022.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image024.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image026.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image028.png\" \/> \u2026\u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>CA<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/> C\u2019A\u2019 [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>BC\u2019A\u2019 <img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>BCA [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image032.png\" \/> [From eq. (i)]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 11.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_Construct_a_triangle_with_sides_6_cm_6_cm_and_7_cm_and_then_another_triangle_whose_sides_are_of_the_corresponding_sides_of_the_first_triangle\"><\/span><strong>3. Construct a triangle with sides 6 cm, 6 cm and 7 cm and then another triangle whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image033.png\" \/><strong> of the corresponding sides of the first triangle.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct a triangle of sides 5 cm, 6 cm and 7 cm and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image033.png\" \/> of the corresponding sides of the first triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction: <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 3\" style=\"height: 216px; width: 205px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image034.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw a triangle ABC of sides 5 cm, 6 cm and 7 cm.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Locate 7 points <img decoding=\"async\" style=\"height: 24px; width: 191px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image035.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 331px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image036.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image037.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image038.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image037.png\" \/>intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>C\u2019A\u2019<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/>CA [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>ABC<img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>A\u2019BC\u2019 [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image039.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image040.png\" \/>[By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image041.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image042.png\" \/> [AA similarity]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image043.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image044.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image045.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image046.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 11.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_Construct_an_isosceles_triangle_whose_base_is_8_cm_and_altitude_4_cm_and_then_another_triangle_whose_sides_are_times_the_corresponding_sides_of_the_isosceles_triangle\"><\/span><strong>4. Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image047.png\" \/><strong> times the corresponding sides of the isosceles triangle.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 45px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image048.png\" \/> of the corresponding sides of the first triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction: <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1023\" style=\"height: 200px; width: 186px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image049.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw BC = 8 cm<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>Draw perpendicular bisector of BC. Let it meets BC at D.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Mark a point A on the perpendicular bisector such that AD = 4 cm.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join AB and AC. Thus <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>ABC is the required isosceles triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(f) <\/strong>Locate 3 points <img decoding=\"async\" style=\"height: 24px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image016.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image017.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(g) <\/strong> Join <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image050.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image051.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image050.png\" \/>intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(h) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>C\u2019A\u2019<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/>CA [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>ABC<img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>A\u2019BC\u2019 [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image039.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image052.png\" \/>[By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 54px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image053.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image054.png\" \/> [AA similarity]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image055.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image056.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image057.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 11.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_Draw_a_triangle_ABC_with_side_BC_6_cm_AB_5_cm_and_ABC_Then_construct_a_triangle_whose_sides_are_of_the_corresponding_sides_of_triangle_ABC\"><\/span><strong>5. Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and <\/strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/><strong>ABC = <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image059.png\" \/><strong> Then construct a triangle whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image060.png\" \/><strong> of the corresponding sides of triangle ABC.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct a triangle ABC with side BC = 6 cm, AB = 5 cm and <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>ABC = <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image061.png\" \/> and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image060.png\" \/> of the corresponding sides of the first triangle ABC.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 1026\" style=\"height: 173px; width: 189px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image062.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw a triangle ABC with side BC = 6 cm, AB = 5 cm and <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>ABC = <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image061.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Locate 4 points <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image063.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 178px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image064.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image065.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image051.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image065.png\" \/> intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image066.png\" \/>[By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 45px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image067.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image068.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image069.png\" \/> \u2026\u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>CA<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/> C\u2019A\u2019 [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>BC\u2019A\u2019 <img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>BCA [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image070.png\" \/> [From eq. (i)]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 11.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_Draw_a_triangle_ABC_with_side_BC_7_cm_B_A_Then_construct_a_triangle_whose_sides_are_times_the_corresponding_sides_of_ABC\"><\/span><strong>6. Draw a triangle ABC with side BC = 7 cm, <\/strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/><strong>B = <\/strong><img decoding=\"async\" style=\"height: 24px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image071.png\" \/><strong>A = <\/strong><img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image072.png\" \/><strong> Then construct a triangle whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image073.png\" \/><strong> times the corresponding sides of <\/strong><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/><strong>ABC.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct a triangle ABC with side BC = 7 cm, <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>B = <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image074.png\" \/> and <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>C = <img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image075.png\" \/> and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image073.png\" \/> of the corresponding sides of the first triangle ABC.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction:<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 7\" style=\"height: 193px; width: 208px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image076.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw a triangle ABC with side BC = 7 cm, <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>B = <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image074.png\" \/> and <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image058.png\" \/>C = <img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image075.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Locate 4 points <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image063.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 178px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image064.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image077.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/>intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image078.png\" \/> [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image079.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image080.png\" \/> [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 45px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image081.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image082.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image083.png\" \/> \u2026\u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>CA<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/> C\u2019A\u2019 [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>BC\u2019A\u2019 <img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>BCA [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image084.png\" \/> [From eq. (i)]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 11.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_Draw_a_right_triangle_in_which_the_sides_other_than_hypotenuse_are_of_lengths_4_cm_and_3_cm_Then_construct_another_triangle_whose_sides_are_times_the_corresponding_sides_of_the_given_triangle\"><\/span><strong>7. Draw a right triangle in which the sides (other than hypotenuse) are of lengths 4 cm and 3 cm. Then construct another triangle whose sides are <\/strong><img decoding=\"async\" style=\"height: 41px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image085.png\" \/><strong> times the corresponding sides of the given triangle.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. To construct<\/strong>: To construct a right triangle in which sides (other than hypotenuse) are of lengths 4 cm and 3 cm and then a triangle similar to it whose sides are <img decoding=\"async\" style=\"height: 41px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image085.png\" \/> of the corresponding sides of the first triangle ABC.<\/p>\n<p style=\"text-align: justify;\"><strong>Steps of construction<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 8\" style=\"height: 297px; width: 278px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image086.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(a) <\/strong>Draw a right triangle in which sides (other than hypotenuse) are of lengths 4 cm and 3 cm.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>From any ray BX, making an acute angle with BC on the side opposite to the vertex A.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Locate 5 points <img decoding=\"async\" style=\"height: 24px; width: 139px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image087.png\" \/>on BX such that<img decoding=\"async\" style=\"height: 24px; width: 229px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image088.png\" \/>.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Join <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/>and draw a line through the point<img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image089.png\" \/>, draw a line parallel to <img decoding=\"async\" style=\"height: 24px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image018.png\" \/> intersecting BC at the point C\u2019.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Draw a line through C\u2019 parallel to the line CA to intersect BA at A\u2019.<\/p>\n<p style=\"text-align: justify;\">Then, A\u2019BC\u2019 is the required triangle.<\/p>\n<p style=\"text-align: justify;\"><strong>Justification<\/strong>:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image090.png\" \/> [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 54px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image091.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image080.png\" \/> [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 45px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image092.png\" \/><\/p>\n<p style=\"text-align: justify;\">[By Basic Proportionality Theorem]\n<p style=\"text-align: justify;\">But <img decoding=\"async\" style=\"height: 45px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image093.png\" \/> [By construction]\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image094.png\" \/> \u2026\u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image007.png\" \/>CA<img decoding=\"async\" style=\"height: 21px; width: 11px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image029.png\" \/> C\u2019A\u2019 [By construction]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/><img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image030.png\" \/>BC\u2019A\u2019 <img decoding=\"async\" style=\"height: 17px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image031.png\" \/>BCA [AA similarity]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image009.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch11\/Ex11.1\/image095.png\" \/> [From eq. (i)]\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_111\"><\/span>NCERT Solutions for Class 10 Maths Exercise 11.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<strong><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\">the best app for CBSE\u00a0<\/a><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 11.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 11.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-11-1\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 11.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":30001,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4948","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Exercise 11.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 11.1 in PDF format for free download. 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