{"id":4941,"date":"2016-05-19T09:49:00","date_gmt":"2016-05-19T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/"},"modified":"2018-06-04T15:00:00","modified_gmt":"2018-06-04T09:30:00","slug":"ncert-solutions-class-10-maths-exercise-9-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 9.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#NCERT_Solutions_for_Class_10_Maths_Some_Applications_of_Trigonometry\" >NCERT Solutions for Class 10 Maths Some Applications of Trigonometry<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#1_A_circus_artist_is_climbing_a_20_m_long_rope_which_is_tightly_stretched_and_tied_from_the_top_of_a_vertical_pole_to_the_ground_Find_the_height_of_the_pole_if_the_angle_made_by_the_rope_with_the_ground_level_is_see_figure\" >1. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is  (see figure).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#2_A_tree_breaks_due_to_storm_and_the_broken_part_bends_so_that_the_top_of_the_tree_touches_the_ground_making_an_angle_with_it_The_distance_between_the_foot_of_the_tree_to_the_point_where_the_top_touches_the_ground_is_8_m_Find_the_height_of_the_tree\" >2. A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle  with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#3_A_contractor_plans_to_install_two_slides_for_the_children_to_play_in_a_park_For_the_children_below_the_age_of_5_years_she_prefers_to_have_a_slide_whose_top_is_at_a_height_of_15_m_and_is_inclined_at_an_angle_of_to_the_ground_whereas_for_elder_children_she_wants_to_have_a_steep_slide_at_a_height_of_3_m_and_inclined_at_an_angle_of_to_the_ground_What_should_be_the_length_of_the_slide_in_each_case\" >3. A contractor plans to install two slides for the children to play in a park. For the children below the age of 5 years, she prefers to have a slide whose top is at a height of 1.5 m and is inclined at an angle of  to the ground, whereas for elder children, she wants to have a steep slide at a height of 3 m and inclined at an angle of  to the ground. What should be the length of the slide in each case?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#4_The_angle_of_elevation_of_the_top_of_a_tower_from_a_point_on_the_ground_which_is_30_m_away_from_the_foot_of_the_lower_is_Find_the_height_of_the_tower\" >4. The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the lower is . Find the height of the tower.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#5_A_kite_is_flying_at_a_height_of_60_m_above_the_ground_The_string_attached_to_the_kite_is_temporarily_tied_to_a_point_on_the_ground_The_inclination_of_the_string_with_the_ground_is_Find_the_length_of_the_string_assuming_that_there_is_no_slack_in_the_string\" >5. A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is  Find the length of the string, assuming that there is no slack in the string.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#6_A_15_m_tall_boy_is_standing_at_some_distance_from_a_30_m_tall_building_The_angle_of_elevation_from_his_eyes_to_the_top_of_the_building_increases_from_to_as_he_walks_towards_the_building_Find_the_distance_he_walked_towards_the_building\" >6. A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from  to  as he walks towards the building. Find the distance he walked towards the building.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#7_From_a_point_on_the_ground_the_angles_of_elevation_of_the_bottom_and_the_top_of_a_transmission_tower_fixed_at_the_top_of_a_20_m_high_building_are_and_respectively_Find_the_height_of_the_tower\" >7. From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are  and  respectively. Find the height of the tower.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#8_A_statue_16_m_tall_stands_on_the_top_of_a_postal_From_a_point_on_the_ground_the_angle_of_elevation_of_the_top_of_the_statue_is_and_from_the_same_point_the_angle_of_elevation_of_the_top_of_the_pedestal_is_Find_the_height_of_the_pedestal\" >8. A statue, 1.6 m tall, stands on the top of a postal. From a point on the ground, the angle of elevation of the top of the statue is  and from the same point the angle of elevation of the top of the pedestal is  Find the height of the pedestal.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#9_The_angle_of_elevation_of_the_top_of_a_building_from_the_foot_of_the_tower_is_and_the_angle_of_elevation_of_the_top_of_the_tower_from_the_foot_of_the_building_is_If_the_tower_is_50_m_high_find_the_height_of_the_building\" >9. The angle of elevation of the top of a building from the foot of the tower is  and the angle of elevation of the top of the tower from the foot of the building is  If the tower is 50 m high, find the height of the building.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#NCERT_Solutions_for_Class_10_Maths_Exercise_91\" >NCERT Solutions for Class 10 Maths Exercise 9.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#10_Two_poles_of_equal_heights_are_standing_opposite_each_other_on_either_side_of_the_road_which_is_80_m_wide_From_a_point_between_them_on_the_road_the_angles_of_elevation_of_the_top_of_the_poles_are_and_respectively_Find_the_height_of_the_poles_and_the_distances_of_the_point_from_the_poles\" >10. Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are  and  respectively. Find the height of the poles and the distances of the point from the poles.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#11_A_TV_tower_stands_vertically_on_a_bank_of_a_canal_From_a_point_on_the_other_bank_directly_opposite_the_tower_the_angle_of_elevation_of_the_top_of_the_tower_is_From_another_point_20_m_away_from_this_point_on_the_line_joining_this_point_to_the_foot_of_the_tower_the_angle_of_elevation_of_the_top_of_the_tower_is_see_figure_Find_the_height_of_the_tower_and_the_width_of_the_canal\" >11. A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is  From another point 20 m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is  (see figure). Find the height of the tower and the width of the canal.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#12_From_the_top_of_a_7_m_high_building_the_angle_of_elevation_of_the_top_of_a_cable_tower_is_and_the_angle_of_depression_of_its_foot_is_Determine_the_height_of_the_tower\" >12. From the top of a 7 m high building, the angle of elevation of the top of a cable tower is  and the angle of depression of its foot is  Determine the height of the tower.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#13_As_observed_from_the_top_of_a_75_m_high_lighthouse_from_the_sea-level_the_angles_of_depression_of_two_ships_are_and_If_one_ship_is_exactly_behind_the_other_on_the_same_side_of_the_lighthouse_find_the_distance_between_two_ships\" >13. As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are  and  If one ship is exactly behind the other on the same side of the lighthouse, find the distance between two ships.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#14_A_12_m_tall_girl_spots_a_balloon_moving_with_the_wind_in_a_horizontal_line_at_a_height_of_882_m_from_the_ground_The_angle_of_elevation_of_the_balloon_from_the_eyes_of_the_girl_at_any_distant_is_After_some_time_the_angle_of_elevation_reduces_to_see_figure_Find_the_distance_travelled_by_the_balloon_during_the_interval\" >14. A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground. The angle of elevation of the balloon from the eyes of the girl at any distant is  After some time, the angle of elevation reduces to  (see figure). Find the distance travelled by the balloon during the interval.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#15_A_straight_highway_leads_to_the_foot_of_a_tower_A_man_standing_at_the_top_of_the_tower_observes_a_car_at_an_angle_of_depression_of_which_is_approaching_the_foot_of_the_tower_with_a_uniform_speed_Six_seconds_later_the_angle_of_depression_of_the_car_is_found_to_be_Find_the_time_taken_by_the_car_to_reach_the_foot_of_the_tower_from_this_point\" >15. A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of , which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be  Find the time taken by the car to reach the foot of the tower from this point.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#16_The_angles_of_elevation_of_the_top_of_a_tower_from_two_points_at_a_distance_of_4_m_and_9_m_from_the_base_of_the_tower_and_in_the_same_straight_line_with_it_are_complementary_Prove_that_the_height_of_the_tower_is_6_m\" >16. The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#NCERT_Solutions_for_Class_10_Maths_Exercise_91-2\" >NCERT Solutions for Class 10 Maths Exercise 9.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<div class=\"addtoany_share_save_container addtoany_content addtoany_content_top\">\n<div class=\"a2a_kit a2a_kit_size_50 addtoany_list\" data-a2a-url=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-8-1\/\" data-a2a-title=\"NCERT Solutions for Class 10 Maths Exercise 8.1\">NCERT Solutions for Class 10 Maths Exercise 9.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/div>\n<\/div>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0<\/strong><strong>Applications of Trigonometry\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-some-applications-of-trigonometry\/2092\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 9.1\" width=\"171\" height=\"211\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Some_Applications_of_Trigonometry\"><\/span>NCERT Solutions for Class 10 Maths Some Applications of Trigonometry<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"1_A_circus_artist_is_climbing_a_20_m_long_rope_which_is_tightly_stretched_and_tied_from_the_top_of_a_vertical_pole_to_the_ground_Find_the_height_of_the_pole_if_the_angle_made_by_the_rope_with_the_ground_level_is_see_figure\"><\/span><strong>1. A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> (see figure). <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 1\" style=\"height: 137px; width: 168px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image002.jpg\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image003.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image005.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AB = 10 m<\/p>\n<p style=\"text-align: justify;\">Hence, the height of the pole is 10 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_A_tree_breaks_due_to_storm_and_the_broken_part_bends_so_that_the_top_of_the_tree_touches_the_ground_making_an_angle_with_it_The_distance_between_the_foot_of_the_tree_to_the_point_where_the_top_touches_the_ground_is_8_m_Find_the_height_of_the_tree\"><\/span><strong>2. A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 258px; width: 212px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image007.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image008.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image009.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Again, <img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AB = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image012.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/>Height of the tree = AB + AC<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 41px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image014.png\" \/> = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 44px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image016.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image017.png\" \/> m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_A_contractor_plans_to_install_two_slides_for_the_children_to_play_in_a_park_For_the_children_below_the_age_of_5_years_she_prefers_to_have_a_slide_whose_top_is_at_a_height_of_15_m_and_is_inclined_at_an_angle_of_to_the_ground_whereas_for_elder_children_she_wants_to_have_a_steep_slide_at_a_height_of_3_m_and_inclined_at_an_angle_of_to_the_ground_What_should_be_the_length_of_the_slide_in_each_case\"><\/span><strong>3. A contractor plans to install two slides for the children to play in a park. For the children below the age of 5 years, she prefers to have a slide whose top is at a height of 1.5 m and is inclined at an angle of <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> to the ground, whereas for elder children, she wants to have a steep slide at a height of 3 m and inclined at an angle of <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> to the ground. What should be the length of the slide in each case?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image003.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 128px; width: 226px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image019.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image020.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AC = 3 m<\/p>\n<p style=\"text-align: justify;\">In right triangle PQR,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image021.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 196px; width: 138px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image022.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> PR = <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image024.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence, the lengths of the slides are 3 m and <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image024.png\" \/> m respectively.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_The_angle_of_elevation_of_the_top_of_a_tower_from_a_point_on_the_ground_which_is_30_m_away_from_the_foot_of_the_lower_is_Find_the_height_of_the_tower\"><\/span><strong>4. The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the lower is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong>. Find the height of the tower.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 154px; width: 358px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image026.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 264px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AB = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image028.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image029.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image030.png\" \/> m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_A_kite_is_flying_at_a_height_of_60_m_above_the_ground_The_string_attached_to_the_kite_is_temporarily_tied_to_a_point_on_the_ground_The_inclination_of_the_string_with_the_ground_is_Find_the_length_of_the_string_assuming_that_there_is_no_slack_in_the_string\"><\/span><strong>5. A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image031.png\" \/><strong> Find the length of the string, assuming that there is no slack in the string.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image032.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AC = <img decoding=\"async\" style=\"height: 23px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image034.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence the length of the string is <img decoding=\"async\" style=\"height: 23px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image034.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_A_15_m_tall_boy_is_standing_at_some_distance_from_a_30_m_tall_building_The_angle_of_elevation_from_his_eyes_to_the_top_of_the_building_increases_from_to_as_he_walks_towards_the_building_Find_the_distance_he_walked_towards_the_building\"><\/span><strong>6. A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> to <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> as he walks towards the building. Find the distance he walked towards the building.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>AB = 30 m and PR = 1.5 m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 178px; width: 252px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image035.png\" \/><\/p>\n<p style=\"text-align: justify;\">AC = AB \u2013 BC<\/p>\n<p style=\"text-align: justify;\">= AB \u2013 PR<\/p>\n<p style=\"text-align: justify;\">= 30 \u2013 1.5<\/p>\n<p style=\"text-align: justify;\">= 28.5 m<\/p>\n<p style=\"text-align: justify;\">In right triangle ACQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image036.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image037.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> QC = <img decoding=\"async\" style=\"height: 41px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image038.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">In right triangle ACP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image039.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 43px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image040.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 60px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image041.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 45px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image042.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image043.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 24px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image044.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> PQ = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image045.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> PQ = <img decoding=\"async\" style=\"height: 44px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image046.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image047.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence, the walked towards the building is <img decoding=\"async\" style=\"height: 23px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image047.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_From_a_point_on_the_ground_the_angles_of_elevation_of_the_bottom_and_the_top_of_a_transmission_tower_fixed_at_the_top_of_a_20_m_high_building_are_and_respectively_Find_the_height_of_the_tower\"><\/span><strong>7. From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image048.png\" \/><strong> and <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> respectively. Find the height of the tower.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let the height of the tower be <img decoding=\"async\" style=\"height: 17px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image049.png\" \/> m. Then, in right triangle CBP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 288px; width: 320px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image051.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image052.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 75px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image053.png\" \/> \u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image054.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image055.png\" \/> <img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> BP = 20 m<\/p>\n<p style=\"text-align: justify;\">Putting this value in eq. (i), we get,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 23px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image056.png\" \/> = <img decoding=\"async\" style=\"height: 39px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image057.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 23px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image058.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 23px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image059.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 31px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image060.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/>The height of the tower is <img decoding=\"async\" style=\"height: 31px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image061.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"8_A_statue_16_m_tall_stands_on_the_top_of_a_postal_From_a_point_on_the_ground_the_angle_of_elevation_of_the_top_of_the_statue_is_and_from_the_same_point_the_angle_of_elevation_of_the_top_of_the_pedestal_is_Find_the_height_of_the_pedestal\"><\/span><strong>8. A statue, 1.6 m tall, stands on the top of a postal. From a point on the ground, the angle of elevation of the top of the statue is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> and from the same point the angle of elevation of the top of the pedestal is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image062.png\" \/><strong> Find the height of the pedestal.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let the height of the pedestal be <img decoding=\"async\" style=\"height: 17px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image049.png\" \/> m.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/>BC = <img decoding=\"async\" style=\"height: 17px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image049.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">In right triangle ACP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 288px; width: 316px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image063.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image064.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image065.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image066.png\" \/> \u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle BCP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image067.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image068.png\" \/> <img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> PC = <img decoding=\"async\" style=\"height: 17px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image049.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image069.png\" \/> [From eq. (i)]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 23px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image070.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 31px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image071.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image072.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 59px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image073.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image074.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 48px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image075.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 31px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image076.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence, the height of the pedestal is <img decoding=\"async\" style=\"height: 31px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image077.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"9_The_angle_of_elevation_of_the_top_of_a_building_from_the_foot_of_the_tower_is_and_the_angle_of_elevation_of_the_top_of_the_tower_from_the_foot_of_the_building_is_If_the_tower_is_50_m_high_find_the_height_of_the_building\"><\/span><strong>9. The angle of elevation of the top of a building from the foot of the tower is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> and the angle of elevation of the top of the tower from the foot of the building is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image031.png\" \/><strong> If the tower is 50 m high, find the height of the building.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let the height of the building be <img decoding=\"async\" style=\"height: 17px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image049.png\" \/> m.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 12\" style=\"height: 284px; width: 252px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image078.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image079.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image080.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> BQ = <img decoding=\"async\" style=\"height: 41px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image081.png\" \/> m\u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image082.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image083.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> BQ = <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image084.png\" \/> m\u2026\u2026\u2026.(ii)<\/p>\n<p style=\"text-align: justify;\">From eq. (i) and (ii),<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image085.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 39px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image086.png\" \/> m<\/p>\n<hr \/>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_91\"><\/span>NCERT Solutions for Class 10 Maths Exercise 9.1<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"10_Two_poles_of_equal_heights_are_standing_opposite_each_other_on_either_side_of_the_road_which_is_80_m_wide_From_a_point_between_them_on_the_road_the_angles_of_elevation_of_the_top_of_the_poles_are_and_respectively_Find_the_height_of_the_poles_and_the_distances_of_the_point_from_the_poles\"><\/span><strong>10. Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> and <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> respectively. Find the height of the poles and the distances of the point from the poles.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle PRQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 13\" style=\"height: 149px; width: 329px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image087.jpg\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image088.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image089.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> H = <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image084.png\" \/> m\u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABR,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image090.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image091.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image092.png\" \/>[From eq. (i)]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 17px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image093.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 17px; width: 48px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image094.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 17px; width: 41px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image095.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/>H = <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image084.png\" \/> = <img decoding=\"async\" style=\"height: 23px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image096.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Also, BR = <img decoding=\"async\" style=\"height: 17px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image097.png\" \/> = 80 \u2013 20 = 60 m<\/p>\n<p style=\"text-align: justify;\">Hence the heights of the poles are <img decoding=\"async\" style=\"height: 23px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image096.png\" \/> m each and the distances of the point from poles are 20 m and 60 m respectively.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"11_A_TV_tower_stands_vertically_on_a_bank_of_a_canal_From_a_point_on_the_other_bank_directly_opposite_the_tower_the_angle_of_elevation_of_the_top_of_the_tower_is_From_another_point_20_m_away_from_this_point_on_the_line_joining_this_point_to_the_foot_of_the_tower_the_angle_of_elevation_of_the_top_of_the_tower_is_see_figure_Find_the_height_of_the_tower_and_the_width_of_the_canal\"><\/span><strong>11. A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image031.png\" \/><strong> From another point 20 m away from this point on the line joining this point to the foot of the tower, the angle of elevation of the top of the tower is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> (see figure). Find the height of the tower and the width of the canal. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 192px; width: 272px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image098.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image099.png\" \/><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image100.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AB = <img decoding=\"async\" style=\"height: 23px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image101.png\" \/> m\u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABD,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image102.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image103.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image104.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AB = <img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image105.png\" \/> m\u2026\u2026\u2026.(ii)<\/p>\n<p style=\"text-align: justify;\">From eq. (i) and (ii),<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 23px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image101.png\" \/> =<img decoding=\"async\" style=\"height: 41px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image105.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> 3BC = BC + 20<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> BC = 10 m<\/p>\n<p style=\"text-align: justify;\">From eq. (i), AB = <img decoding=\"async\" style=\"height: 23px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image030.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence height of the tower is <img decoding=\"async\" style=\"height: 23px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image030.png\" \/> m and the width of the canal is 10 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"12_From_the_top_of_a_7_m_high_building_the_angle_of_elevation_of_the_top_of_a_cable_tower_is_and_the_angle_of_depression_of_its_foot_is_Determine_the_height_of_the_tower\"><\/span><strong>12. From the top of a 7 m high building, the angle of elevation of the top of a cable tower is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image018.png\" \/><strong> and the angle of depression of its foot is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image062.png\" \/><strong> Determine the height of the tower.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABD,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image106.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 17\" style=\"height: 367px; width: 231px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image107.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image108.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> BD = 7 m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> AE = 7 m<\/p>\n<p style=\"text-align: justify;\">In right triangle AEC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 39px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image109.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/><img decoding=\"async\" style=\"height: 39px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image110.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 15px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image004.png\" \/> CE = <img decoding=\"async\" style=\"height: 23px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image111.png\" \/> m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image013.png\" \/>CD = CE + ED<\/p>\n<p style=\"text-align: justify;\">= CE + AB<\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 23px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image112.png\" \/> = <img decoding=\"async\" style=\"height: 31px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image113.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence height of the tower is <img decoding=\"async\" style=\"height: 31px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image113.png\" \/>m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"13_As_observed_from_the_top_of_a_75_m_high_lighthouse_from_the_sea-level_the_angles_of_depression_of_two_ships_are_and_If_one_ship_is_exactly_behind_the_other_on_the_same_side_of_the_lighthouse_find_the_distance_between_two_ships\"><\/span><strong>13. As observed from the top of a 75 m high lighthouse from the sea-level, the angles of depression of two ships are <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> and <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image062.png\" \/><strong> If one ship is exactly behind the other on the same side of the lighthouse, find the distance between two ships.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 178px; width: 334px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image114.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 44px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image115.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/><img decoding=\"async\" style=\"height: 44px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image117.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BQ = 75 m\u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image118.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image119.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image120.png\" \/> [From eq. (i)]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> 75 + QP = <img decoding=\"async\" style=\"height: 24px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image121.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> QP = <img decoding=\"async\" style=\"height: 32px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image122.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence the distance between the two ships is <img decoding=\"async\" style=\"height: 32px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image122.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"14_A_12_m_tall_girl_spots_a_balloon_moving_with_the_wind_in_a_horizontal_line_at_a_height_of_882_m_from_the_ground_The_angle_of_elevation_of_the_balloon_from_the_eyes_of_the_girl_at_any_distant_is_After_some_time_the_angle_of_elevation_reduces_to_see_figure_Find_the_distance_travelled_by_the_balloon_during_the_interval\"><\/span><strong>14. A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground. The angle of elevation of the balloon from the eyes of the girl at any distant is <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image031.png\" \/><strong> After some time, the angle of elevation reduces to <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong> (see figure). Find the distance travelled by the balloon during the interval. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 176px; width: 290px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image123.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image124.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 198px; width: 306px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image125.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image126.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BC = <img decoding=\"async\" style=\"height: 44px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image127.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">In right triangle PQC,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 44px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image128.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image129.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 64px; width: 111px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image130.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 49px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image131.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 25px; width: 140px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image132.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 25px; width: 140px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image133.png\" \/> = 176.4<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BQ = <img decoding=\"async\" style=\"height: 44px; width: 41px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image134.png\" \/> = <img decoding=\"async\" style=\"height: 48px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image135.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 24px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image136.png\" \/> = <img decoding=\"async\" style=\"height: 45px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image137.png\" \/> = <img decoding=\"async\" style=\"height: 45px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image138.png\" \/> m<\/p>\n<p style=\"text-align: justify;\">Hence the distance travelled by the balloon during the interval is <img decoding=\"async\" style=\"height: 45px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image138.png\" \/> m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"15_A_straight_highway_leads_to_the_foot_of_a_tower_A_man_standing_at_the_top_of_the_tower_observes_a_car_at_an_angle_of_depression_of_which_is_approaching_the_foot_of_the_tower_with_a_uniform_speed_Six_seconds_later_the_angle_of_depression_of_the_car_is_found_to_be_Find_the_time_taken_by_the_car_to_reach_the_foot_of_the_tower_from_this_point\"><\/span><strong>15. A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of <\/strong><img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image001.png\" \/><strong>, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be <\/strong><img decoding=\"async\" style=\"height: 21px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image031.png\" \/><strong> Find the time taken by the car to reach the foot of the tower from this point.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In right triangle ABP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image118.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 200px; width: 332px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image139.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/><img decoding=\"async\" style=\"height: 44px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image140.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BP = AB<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image141.png\" \/> \u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 44px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image142.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image143.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BQ = <img decoding=\"async\" style=\"height: 44px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image144.png\" \/> \u2026\u2026\u2026.(ii)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image145.png\" \/>PQ = BP \u2013 BQ<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image146.png\" \/>PQ = AB<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image141.png\" \/> <img decoding=\"async\" style=\"height: 11px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image147.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image144.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 44px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image148.png\" \/> = <img decoding=\"async\" style=\"height: 44px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image149.png\" \/> = 2BQ [From eq. (ii)]\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> BQ = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image150.png\" \/> PQ<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image145.png\" \/> Time taken by the car to travel a distance PQ = 6 seconds.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image146.png\" \/> Time taken by the car to travel a distance BQ, i.e. <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image150.png\" \/> PQ = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image150.png\" \/> x 6 = 3 seconds.<\/p>\n<p style=\"text-align: justify;\">Hence, the further time taken by the car to reach the foot of the tower is 3 seconds.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 9.1<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"16_The_angles_of_elevation_of_the_top_of_a_tower_from_two_points_at_a_distance_of_4_m_and_9_m_from_the_base_of_the_tower_and_in_the_same_straight_line_with_it_are_complementary_Prove_that_the_height_of_the_tower_is_6_m\"><\/span><strong>16. The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6 m.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image151.png\" \/>APB = <img decoding=\"async\" style=\"height: 19px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image152.png\" \/><\/p>\n<p style=\"text-align: justify;\">Then, <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image151.png\" \/>AQB = <img decoding=\"async\" style=\"height: 29px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image153.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 222px; width: 204px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image154.png\" \/><\/p>\n<p style=\"text-align: justify;\">[<img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image151.png\" \/>APB and <img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image151.png\" \/>AQB are complementary]\n<p style=\"text-align: justify;\">In right triangle ABP,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image155.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image156.png\" \/> \u2026\u2026\u2026.(i)<\/p>\n<p style=\"text-align: justify;\">In right triangle ABQ,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 29px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image157.png\" \/> = <img decoding=\"async\" style=\"height: 44px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image158.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 41px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image159.png\" \/> \u2026\u2026\u2026.(ii)<\/p>\n<p style=\"text-align: justify;\">Multiplying eq. (i) and eq. (ii),<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 41px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image160.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> <img decoding=\"async\" style=\"height: 44px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image161.png\" \/><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> AB<sup>2<\/sup> = 36<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch09\/Ex9.1\/image116.png\" \/> AB = 6 m<\/p>\n<p style=\"text-align: justify;\">Hence, the height of the tower is 6 m.<\/p>\n<p style=\"text-align: justify;\">Proved.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_91-2\"><\/span>NCERT Solutions for Class 10 Maths Exercise 9.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<strong><a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\">the best app for CBSE\u00a0<\/a><\/strong><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 9.1 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 9.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-9-1\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 9.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[281],"tags":[283,438,321,1485,216],"class_list":["post-4941","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ncert-solutions","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Exercise 9.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 9.1 in PDF format for free download. 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