{"id":4915,"date":"2016-05-19T09:49:00","date_gmt":"2016-05-19T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-3-3\/"},"modified":"2023-03-22T15:17:31","modified_gmt":"2023-03-22T09:47:31","slug":"ncert-solutions-for-class-10-maths-exercise-3-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 3.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#_NCERT_Solutions_for_Class_10_Maths_Pair_of_Linear_Equations_in_Two_Variables\" >\u00a0NCERT Solutions for Class 10 Maths\u00a0Pair of Linear Equations in Two Variables<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#2_Solve_2x_3y_11_and_2x_%E2%88%92_4y_%E2%88%9224_and_hence_find_the_value_of_%E2%80%98m_for_which\" >2. Solve 2x + 3y = 11 and 2x \u2212 4y = \u221224 and hence find the value of &#8216;m&#8217; for which<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#3_Form_a_pair_of_linear_equations_for_the_following_problems_and_find_their_solution_by_substitution_method\" >3. Form a pair of linear equations for the following problems and find their solution by substitution method.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#NCERT_Solutions_for_Class_10_Maths_Exercise_33\" >NCERT Solutions for Class 10 Maths Exercise 3.3<\/a><ul class='ez-toc-list-level-5' ><li class='ez-toc-heading-level-5'><ul class='ez-toc-list-level-5' ><li class='ez-toc-heading-level-5'><ul class='ez-toc-list-level-5' ><li class='ez-toc-heading-level-5'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#_Download_CBSE_Question_Paper_2018\" >\u00a0Download CBSE Question Paper 2018<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Maths Exercise 3.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Pair of Linear Equations in Two Variables\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-pair-of-linear-equations-in-two-variables\/1205\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 3.3\" width=\"180\" height=\"221\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"_NCERT_Solutions_for_Class_10_Maths_Pair_of_Linear_Equations_in_Two_Variables\"><\/span>\u00a0NCERT Solutions for Class 10 Maths\u00a0Pair of Linear Equations in Two Variables<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><strong>1. Solve the following pair of linear equations by the substitution method.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(i) <em>x <\/em>+ <em>y <\/em>= 14<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em>x <\/em>\u2013 <em>y <\/em>= 4<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <em>s <\/em>\u2013 <em>t <\/em>= 3<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em><img decoding=\"async\" style=\"height: 42px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image001.png\" \/><\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<em> 3x \u2013 y = 3<\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em>9x \u2212 3y = 9<\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iv)<em>0.2x + 0.3y = 1.3<\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em>0.4x + 0.5y = 2.3<\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(v)<em> <img decoding=\"async\" style=\"height: 25px; width: 98px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image002.png\" \/><\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em><img decoding=\"async\" style=\"height: 25px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image003.png\" \/><\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(vi)<em> <img decoding=\"async\" style=\"height: 42px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image004.png\" \/><\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em><img decoding=\"async\" style=\"height: 42px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image005.png\" \/> <\/em><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> <em>x <\/em>+ <em>y <\/em>= 14 \u2026(1)<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>\u2013 <em>y <\/em>= 4 \u2026 (2)<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= 4 + <em>y<\/em> from equation (2)<\/p>\n<p style=\"text-align: justify;\">Putting this in equation (1), we get<\/p>\n<p style=\"text-align: justify;\">4 + <em>y <\/em>+ <em>y <\/em>= 14<\/p>\n<p style=\"text-align: justify;\">\u21d2 2<em>y <\/em>= 10\u21d2 <em>y <\/em>= 5<\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 5 = 14<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= 14 \u2013 5 = 9<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>x <\/em>= 9 and <em>y <\/em>= 5<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> <em>s <\/em>\u2013 <em>t <\/em>= 3 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image001.png\" \/> \u2026<\/em>(2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that <em>s <\/em>= 3 + <em>t<\/em><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (2), we get<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image006.png\" \/> <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image007.png\" \/><\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 5<em>t <\/em>+ 6 = 36<\/p>\n<p style=\"text-align: justify;\">\u21d2 5<em>t <\/em>= 30\u21d2 <em>t <\/em>= 6<\/p>\n<p style=\"text-align: justify;\">Putting value of t in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><em>s <\/em>\u2013 6 = 3\u21d2 <em>s <\/em>= 3 + 6 = 9<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>t <\/em>= 6 and <em>s <\/em>= 9<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> 3<em>x <\/em>\u2013 <em>y <\/em>= 3 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">9<em>x <\/em>\u2212 3<em>y <\/em>= 9 \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Comparing equation 3<em>x <\/em>\u2013 <em>y <\/em>= 3 with <img decoding=\"async\" style=\"height: 24px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image008.png\" \/> and equation 9<em>x <\/em>\u2212 3<em>y <\/em>= 9 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image009.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get <img decoding=\"async\" style=\"height: 24px; width: 166px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image010.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\">Here <img decoding=\"async\" style=\"height: 45px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, we have infinite many solutions for x and y<\/p>\n<p style=\"text-align: justify;\"><strong>(iv)<\/strong> 0.2<em>x <\/em>+ 0.3<em>y <\/em>= 1.3 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">0.4<em>x <\/em>+ 0.5<em>y <\/em>= 2.3 \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\">0.2<em>x <\/em>= 1.3 \u2212 0.3<em>y<\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= <img decoding=\"async\" style=\"height: 42px; width: 68px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image013.png\" \/><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (2), we get<\/p>\n<p style=\"text-align: justify;\">0.4 <img decoding=\"async\" style=\"height: 45px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image014.png\" \/>+ 0.5<em>y <\/em>= 2.3<\/p>\n<p style=\"text-align: justify;\">\u21d2 2.6 \u2212 0.6<em>y <\/em>+ 0.5<em>y <\/em>= 2.3<\/p>\n<p style=\"text-align: justify;\">\u21d2 \u22120.1<em>y <\/em>= \u22120.3 \u21d2 <em>y <\/em>= 3<\/p>\n<p style=\"text-align: justify;\">Putting value of y in (1), we get<\/p>\n<p style=\"text-align: justify;\">0.2<em>x <\/em>+ 0.3 (3) = 1.3<\/p>\n<p style=\"text-align: justify;\">\u21d2 0.2<em>x <\/em>+ 0.9 = 1.3<\/p>\n<p style=\"text-align: justify;\">\u21d2 0.2<em>x <\/em>= 0.4 \u21d2 <em>x <\/em>= 2<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>x <\/em>= 2 and <em>y <\/em>= 3<\/p>\n<p style=\"text-align: justify;\"><strong>(v)<\/strong> <em><img decoding=\"async\" style=\"height: 25px; width: 98px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image002.png\" \/><\/em> \u2026\u2026\u2026.(1)<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 25px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image003.png\" \/> <\/em>\u2026\u2026\u2026.(2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= <img decoding=\"async\" style=\"height: 48px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image015.png\" \/><\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<p style=\"text-align: justify;\">Putting this in equation (2), we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 53px; width: 145px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image016.png\" \/>\u21d2 <img decoding=\"async\" style=\"height: 44px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 48px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image018.png\" \/>\u21d2 <em>y <\/em>= 0<\/p>\n<p style=\"text-align: justify;\">Putting value of y in (1), we get <em>x <\/em>= 0<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>x <\/em>= 0 and <em>y <\/em>= 0<\/p>\n<p style=\"text-align: justify;\"><strong>(vi)<\/strong> <img decoding=\"async\" style=\"height: 42px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image004.png\" \/> \u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image005.png\" \/> \u2026 (2<em>)<\/em><\/p>\n<p style=\"text-align: justify;\">Using equation (2), we can say that<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= <img decoding=\"async\" style=\"height: 45px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image019.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= <img decoding=\"async\" style=\"height: 42px; width: 54px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image020.png\" \/><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 45px; width: 154px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image021.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 123px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image022.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 149px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 111px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image024.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image025.png\" \/> \u21d2 <em>y <\/em>= 3<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (2), we get<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image026.png\" \/> <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 179px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image027.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image028.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 x = 2<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>x <\/em>= 2 and <em>y <\/em>= 3<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Solve_2x_3y_11_and_2x_%E2%88%92_4y_%E2%88%9224_and_hence_find_the_value_of_%E2%80%98m_for_which\"><\/span><strong>2. Solve 2<em>x <\/em>+ 3<em>y <\/em>= 11 and 2<em>x <\/em>\u2212 4<em>y <\/em>= \u221224 and hence find the value of &#8216;m&#8217; for which<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong> <em>y <\/em>= <em>mx <\/em>+ 3. <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>2<em>x <\/em>+ 3<em>y <\/em>= 11 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">2<em>x <\/em>\u2212 4<em>y <\/em>= \u221224 \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Using equation (2), we can say that<\/p>\n<p style=\"text-align: justify;\">2<em>x <\/em>= \u221224 + 4<em>y<\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= \u221212 + 2<em>y<\/em><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (1), we get<\/p>\n<p style=\"text-align: justify;\">2 (\u221212 + 2<em>y<\/em>) + 3<em>y <\/em>= 11<\/p>\n<p style=\"text-align: justify;\">\u21d2 \u221224 + 4<em>y <\/em>+ 3<em>y <\/em>= 11<\/p>\n<p style=\"text-align: justify;\">\u21d2 7<em>y <\/em>= 35 \u21d2 <em>y <\/em>= 5<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (1), we get<\/p>\n<p style=\"text-align: justify;\">2<em>x <\/em>+ 3 (5) = 11<\/p>\n<p style=\"text-align: justify;\">\u21d2 2<em>x <\/em>+ 15 = 11<\/p>\n<p style=\"text-align: justify;\">\u21d2 2<em>x <\/em>= 11 \u2013 15 = \u22124\u21d2 <em>x <\/em>= \u22122<\/p>\n<p style=\"text-align: justify;\">Therefore, <em>x <\/em>= \u22122 and <em>y <\/em>= 5<\/p>\n<p style=\"text-align: justify;\">Putting values of x and y in <em>y <\/em>= <em>mx <\/em>+ 3, we get<\/p>\n<p style=\"text-align: justify;\">5 = <em>m <\/em>(\u22122) + 3<\/p>\n<p style=\"text-align: justify;\">\u21d2 5 = \u22122<em>m <\/em>+ 3<\/p>\n<p style=\"text-align: justify;\">\u21d2 \u22122<em>m <\/em>= 2 \u21d2 <em>m <\/em>= \u22121<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_Form_a_pair_of_linear_equations_for_the_following_problems_and_find_their_solution_by_substitution_method\"><\/span><strong>3. Form a pair of linear equations for the following problems and find their solution by substitution method.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) The difference between two numbers is 26 and one number is three times the other. Find them.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) The larger of two supplementary angles exceeds the smaller by 18 degrees. Find them.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii)The coach of a cricket team buys 7 bats and 6 balls for Rs 3800. Later, she buys 3 bats and 5 balls for Rs 1750. Find the cost of each bat and each ball.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iv) The taxi charges in a city consist of a fixed charge together with the charge for the distance covered. For a distance of 10 km, the charge paid is Rs 105 and for a journey of 15 km, the charge paid is Rs 155. What are the fixed charges and the charge per km? How much does a person have to pay for travelling a distance of 25 km?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(v) A fraction becomes <img decoding=\"async\" style=\"height: 42px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image029.png\" \/>, if 2 is added to both the numerator and the denominator. If, 3 is added to both the numerator and denominator it becomes <img decoding=\"async\" style=\"height: 42px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image030.png\" \/>. Find the fraction.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(vi) Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob&#8217;s age was seven times that of his son. What are their present ages?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> Let first number be x and second number be y.<\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>\u2013 <em>y <\/em>= 26 (assuming x &gt; y) \u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= 3<em>y<\/em>(x &gt; y)\u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Putting equation (2) in (1), we get<\/p>\n<p style=\"text-align: justify;\">3<em>y <\/em>\u2013 <em>y <\/em>= 26<\/p>\n<p style=\"text-align: justify;\">\u21d2 2<em>y <\/em>= 26<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>y <\/em>= 13<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (2), we get<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= 3<em>y <\/em>= <img decoding=\"async\" style=\"height: 19px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, two numbers are 13 and 39.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> Let smaller angle =<em>x <\/em>and let larger angle =<em>y<\/em><\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\"><em>y <\/em>= <em>x <\/em>+ 18 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">Also, <img decoding=\"async\" style=\"height: 24px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image032.png\" \/>(Sum of supplementary angles) \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Putting (1) in equation (2), we get<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ <em>x <\/em>+ 18 = 180<\/p>\n<p style=\"text-align: justify;\">\u21d2 2<em>x <\/em>= 180 \u2013 18 = 162<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 22px; width: 53px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\">Putting value of x in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><em>y <\/em>= <em>x <\/em>+ 18 = 81 + 18 = <img decoding=\"async\" style=\"height: 22px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image034.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, two angles are <img decoding=\"async\" style=\"height: 22px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image035.png\" \/>.<\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> Let cost of each bat = Rs x and let cost of each ball = Rs y<\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\">7<em>x <\/em>+ 6<em>y <\/em>= 3800 \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">And,3<em>x <\/em>+ 5<em>y <\/em>= 1750 \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\">7<em>x <\/em>= 3800 \u2212 6<em>y <\/em>\u21d2 <em>x <\/em>= <img decoding=\"async\" style=\"height: 42px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image036.png\" \/><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (2), we get<\/p>\n<p style=\"text-align: justify;\">3 <img decoding=\"async\" style=\"height: 45px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image037.png\" \/>+ 5<em>y <\/em>= 1750<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 45px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image038.png\" \/>+ 5<em>y <\/em>= 1750<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image039.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 179px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image040.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 17<em>y <\/em>= 850 \u21d2 <em>y <\/em>= 50<\/p>\n<p style=\"text-align: justify;\">Putting value of y in (2), we get<\/p>\n<p style=\"text-align: justify;\">3<em>x <\/em>+ 250 = 1750<\/p>\n<p style=\"text-align: justify;\">\u21d2 3<em>x <\/em>= 1500 \u21d2 <em>x <\/em>= 500<\/p>\n<p style=\"text-align: justify;\">Therefore, cost of each bat = Rs 500 and cost of each ball = Rs 50<\/p>\n<p style=\"text-align: justify;\"><strong>(iv)<\/strong> Let fixed charge = Rs x and let charge for every km = Rs y<\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 10<em>y <\/em>= 105\u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 15<em>y <\/em>= 155\u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>= 105 \u2212 10<em>y<\/em><\/p>\n<p style=\"text-align: justify;\">Putting this in equation (2), we get<\/p>\n<p style=\"text-align: justify;\">105 \u2212 10<em>y <\/em>+ 15<em>y <\/em>= 155<\/p>\n<p style=\"text-align: justify;\">\u21d2 5<em>y <\/em>= 50 \u21d2 <em>y <\/em>= 10<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 10 (10) = 105<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= 105 \u2013 100 = 5<\/p>\n<p style=\"text-align: justify;\">Therefore, fixed charge = Rs 5 and charge per km = Rs 10<\/p>\n<p style=\"text-align: justify;\">To travel distance of 25 Km, person will have to pay = Rs (x + 25y)<\/p>\n<p style=\"text-align: justify;\">= Rs (5 + 25 \u00d7 10)<\/p>\n<p style=\"text-align: justify;\">= Rs (5 + 250) = Rs 255<\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<p style=\"text-align: justify;\"><strong>(v)<\/strong> Let numerator = x and let denominator = y<\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 44px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image041.png\" \/><\/em>\u2026 (1)<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 44px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image042.png\" \/><\/em>\u2026 (2)<\/p>\n<p style=\"text-align: justify;\">Using equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\">11 (<em>x <\/em>+ 2) = 9<em>y <\/em>+ 18<\/p>\n<p style=\"text-align: justify;\">\u21d2 11<em>x <\/em>+ 22 = 9<em>y <\/em>+ 18<\/p>\n<p style=\"text-align: justify;\">\u21d2 11<em>x <\/em>= 9<em>y <\/em>\u2013 4<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= <img decoding=\"async\" style=\"height: 42px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image043.png\" \/><\/p>\n<p style=\"text-align: justify;\">Putting value of x in equation (2), we get<\/p>\n<p style=\"text-align: justify;\">6 <img decoding=\"async\" style=\"height: 45px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image044.png\" \/> = 5 (<em>y <\/em>+ 3)<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image045.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image046.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 150px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image047.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>y <\/em>= 9<\/p>\n<p style=\"text-align: justify;\">Putting value of y in (1), we get<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image048.png\" \/> <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>+ 2 = 9 \u21d2 <em>x <\/em>= 7<\/p>\n<p style=\"text-align: justify;\">Therefore, fraction =<img decoding=\"async\" style=\"height: 44px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image049.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(vi)<\/strong> Let present age of Jacob = x years<\/p>\n<p style=\"text-align: justify;\">Let present age of Jacob\u2019s son = y years<\/p>\n<p style=\"text-align: justify;\">According to given conditions, we have<\/p>\n<p style=\"text-align: justify;\">(<em>x <\/em>+ 5) = 3 (<em>y <\/em>+ 5) \u2026 (1)<\/p>\n<p style=\"text-align: justify;\">And, (<em>x <\/em>\u2212 5) = 7 (<em>y <\/em>\u2212 5) \u2026 (2)<\/p>\n<p style=\"text-align: justify;\">From equation (1), we can say that<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 5 = 3<em>y <\/em>+ 15<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= 10 + 3<em>y<\/em><\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.3<\/p>\n<p style=\"text-align: justify;\">Putting value of x in equation (2) we get<\/p>\n<p style=\"text-align: justify;\">10 + 3<em>y <\/em>\u2013 5 = 7<em>y <\/em>\u2212 35<\/p>\n<p style=\"text-align: justify;\">\u21d2 \u22124<em>y <\/em>= \u221240<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>y <\/em>= 10 years<\/p>\n<p style=\"text-align: justify;\">Putting value of y in equation (1), we get<\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ 5 = 3 (10 + 5) = <img decoding=\"async\" style=\"height: 19px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.3\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>= 45 \u2013 5 = 40 years<\/p>\n<p style=\"text-align: justify;\">Therefore, present age of Jacob = 40 years and, present age of Jacob\u2019s son = 10 years<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_33\"><\/span>NCERT Solutions for Class 10 Maths Exercise 3.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h5 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"_Download_CBSE_Question_Paper_2018\"><\/span><b><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/blog\/cbse-question-paper-2018-for-class-10-12\/\">\u00a0Download CBSE Question Paper 2018<\/a><\/strong><\/b><span class=\"ez-toc-section-end\"><\/span><\/h5>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 3.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 3.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 3.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":30000,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4915","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide\" \/>\n<meta property=\"og:description\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\" \/>\n<meta property=\"og:site_name\" content=\"myCBSEguide\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/mycbseguide\/\" \/>\n<meta property=\"article:published_time\" content=\"2016-05-19T04:19:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-03-22T09:47:31+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1\" \/>\n\t<meta property=\"og:image:height\" content=\"1\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"myCBSEguide\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:site\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"myCBSEguide\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\"},\"author\":{\"name\":\"myCBSEguide\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65\"},\"headline\":\"NCERT Solutions for Class 10 Maths Exercise 3.3\",\"datePublished\":\"2016-05-19T04:19:00+00:00\",\"dateModified\":\"2023-03-22T09:47:31+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\"},\"wordCount\":1171,\"commentCount\":32,\"publisher\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"keywords\":[\"CBSE Class 10 Mathematics\",\"CBSE Study Material\",\"Class 10\",\"Mathematics\",\"maths\",\"NCERT Solutions\"],\"articleSection\":[\"Mathematics\",\"NCERT Solutions\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\",\"url\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\",\"name\":\"NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide\",\"isPartOf\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"datePublished\":\"2016-05-19T04:19:00+00:00\",\"dateModified\":\"2023-03-22T09:47:31+00:00\",\"description\":\"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics\",\"breadcrumb\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage\",\"url\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"contentUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"caption\":\"NCERT Solutions for Class 10 Maths Exercise 3.3\"},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mycbseguide.com\/blog\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions\",\"item\":\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/\"},{\"@type\":\"ListItem\",\"position\":3,\"name\":\"NCERT Solutions for Class 10 Maths Exercise 3.3\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#website\",\"url\":\"https:\/\/mycbseguide.com\/blog\/\",\"name\":\"myCBSEguide\",\"description\":\"\",\"publisher\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mycbseguide.com\/blog\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"en-US\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\",\"name\":\"myCBSEguide\",\"url\":\"https:\/\/mycbseguide.com\/blog\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png\",\"contentUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png\",\"width\":180,\"height\":180,\"caption\":\"myCBSEguide\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/\"},\"sameAs\":[\"https:\/\/www.facebook.com\/mycbseguide\/\",\"https:\/\/x.com\/mycbseguide\",\"https:\/\/www.linkedin.com\/company\/mycbseguide\/\",\"http:\/\/in.pinterest.com\/mycbseguide\/\",\"https:\/\/www.youtube.com\/channel\/UCxuqSnnygFzwJG0pwogCNEQ\"]},{\"@type\":\"Person\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65\",\"name\":\"myCBSEguide\",\"sameAs\":[\"http:\/\/mycbseguide.com\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide","description":"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide","og_description":"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics","og_url":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/","og_site_name":"myCBSEguide","article_publisher":"https:\/\/www.facebook.com\/mycbseguide\/","article_published_time":"2016-05-19T04:19:00+00:00","article_modified_time":"2023-03-22T09:47:31+00:00","og_image":[{"url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","width":1,"height":1,"type":"image\/jpeg"}],"author":"myCBSEguide","twitter_card":"summary_large_image","twitter_creator":"@mycbseguide","twitter_site":"@mycbseguide","twitter_misc":{"Written by":"myCBSEguide","Est. reading time":"6 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#article","isPartOf":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/"},"author":{"name":"myCBSEguide","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65"},"headline":"NCERT Solutions for Class 10 Maths Exercise 3.3","datePublished":"2016-05-19T04:19:00+00:00","dateModified":"2023-03-22T09:47:31+00:00","mainEntityOfPage":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/"},"wordCount":1171,"commentCount":32,"publisher":{"@id":"https:\/\/mycbseguide.com\/blog\/#organization"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage"},"thumbnailUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","keywords":["CBSE Class 10 Mathematics","CBSE Study Material","Class 10","Mathematics","maths","NCERT Solutions"],"articleSection":["Mathematics","NCERT Solutions"],"inLanguage":"en-US"},{"@type":"WebPage","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/","url":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/","name":"NCERT Solutions for Class 10 Maths Exercise 3.3 | myCBSEguide","isPartOf":{"@id":"https:\/\/mycbseguide.com\/blog\/#website"},"primaryImageOfPage":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage"},"thumbnailUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","datePublished":"2016-05-19T04:19:00+00:00","dateModified":"2023-03-22T09:47:31+00:00","description":"NCERT Solutions for Class 10 Maths Exercise 3.3 in PDF format for free download. NCERT Solutions Class 10 Mathematics","breadcrumb":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#primaryimage","url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","contentUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","caption":"NCERT Solutions for Class 10 Maths Exercise 3.3"},{"@type":"BreadcrumbList","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-3\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mycbseguide.com\/blog\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions","item":"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/"},{"@type":"ListItem","position":3,"name":"NCERT Solutions for Class 10 Maths Exercise 3.3"}]},{"@type":"WebSite","@id":"https:\/\/mycbseguide.com\/blog\/#website","url":"https:\/\/mycbseguide.com\/blog\/","name":"myCBSEguide","description":"","publisher":{"@id":"https:\/\/mycbseguide.com\/blog\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mycbseguide.com\/blog\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"en-US"},{"@type":"Organization","@id":"https:\/\/mycbseguide.com\/blog\/#organization","name":"myCBSEguide","url":"https:\/\/mycbseguide.com\/blog\/","logo":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/","url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png","contentUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png","width":180,"height":180,"caption":"myCBSEguide"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.facebook.com\/mycbseguide\/","https:\/\/x.com\/mycbseguide","https:\/\/www.linkedin.com\/company\/mycbseguide\/","http:\/\/in.pinterest.com\/mycbseguide\/","https:\/\/www.youtube.com\/channel\/UCxuqSnnygFzwJG0pwogCNEQ"]},{"@type":"Person","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65","name":"myCBSEguide","sameAs":["http:\/\/mycbseguide.com"]}]}},"_links":{"self":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4915","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/comments?post=4915"}],"version-history":[{"count":5,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4915\/revisions"}],"predecessor-version":[{"id":18488,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4915\/revisions\/18488"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/media\/30000"}],"wp:attachment":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/media?parent=4915"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/categories?post=4915"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/tags?post=4915"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}