{"id":4913,"date":"2016-05-19T09:49:00","date_gmt":"2016-05-19T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-3-2\/"},"modified":"2023-03-22T15:16:39","modified_gmt":"2023-03-22T09:46:39","slug":"ncert-solutions-for-class-10-maths-exercise-3-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 3.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#_NCERT_Solutions_for_Class_10_Maths_Pair_of_Linear_Equations_in_Two_Variables\" >\u00a0NCERT Solutions for Class 10 Maths\u00a0Pair of Linear Equations in Two Variables<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#2_On_comparing_the_ratios_find_out_whether_the_lines_representing_the_following_pairs_of_linear_equations_intersect_at_a_point_are_parallel_or_coincident\" >2. On comparing the ratios , find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#3_On_comparing_the_ratios_find_out_whether_the_following_pair_of_linear_equations_are_consistent_or_inconsistent\" >3. On comparing the ratios , find out whether the following pair of linear equations are consistent, or inconsistent.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#4_Which_of_the_following_pairs_of_linear_equations_are_consistentinconsistent_If_consistent_obtain_the_solution_graphically\" >4. Which of the following pairs of linear equations are consistent\/inconsistent? If consistent, obtain the solution graphically:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#5_Half_the_perimeter_of_a_rectangle_garden_whose_length_is_4_m_more_than_its_width_is_36_m_Find_the_dimensions_of_the_garden\" >5. Half the perimeter of a rectangle garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#6_Given_the_linear_equation_2x_3y_%E2%80%93_8_0_write_another_linear_equation_in_two_variables_such_that_the_geometrical_representation_of_the_pair_so_formed_is\" >6. Given the linear equation (2x + 3y \u2013 8 = 0), write another linear equation in two variables such that the geometrical representation of the pair so formed is:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#7_Draw_the_graphs_of_the_equations_x_%E2%80%93_y_1_0_and_3x_2y_%E2%80%93_12_0_Determine_the_coordinates_of_the_vertices_of_the_triangle_formed_by_these_lines_and_the_x-axis_and_shade_the_triangular_region\" >7. Draw the graphs of the equations x \u2013 y + 1 = 0 and 3x + 2y \u2013 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#NCERT_Solutions_for_Class_10_Maths_Exercise_32\" >NCERT Solutions for Class 10 Maths Exercise 3.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Maths Exercise 3.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Pair of Linear Quations in Two Variables\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-pair-of-linear-equations-in-two-variables\/1205\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 3.2\" width=\"168\" height=\"207\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"_NCERT_Solutions_for_Class_10_Maths_Pair_of_Linear_Equations_in_Two_Variables\"><\/span>\u00a0NCERT Solutions for Class 10 Maths\u00a0Pair of Linear Equations in Two Variables<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><strong>1. Form the pair of linear equations in the following problems, and find their solutions graphically. <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(i) 10 students of class X took part in a mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) 5 pencils and 7 pens together cost Rs 50, whereas 7 pencils and 5 pens together cost Rs. 46. Find the cost of one pencil and that of one pen.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i) <\/strong>Let number of boys who took part in the quiz = x<\/p>\n<p style=\"text-align: justify;\">Let number of girls who took part in the quiz = y<\/p>\n<p style=\"text-align: justify;\"><strong>According to given conditions, we have<\/strong><\/p>\n<p style=\"text-align: justify;\"><em>x <\/em>+ <em>y <\/em>= 10\u2026 <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\">And, <em>y <\/em>= <em>x <\/em>+ 4<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>\u2013 <em>y <\/em>= \u22124 \u2026 <strong>(2)<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 298\" style=\"height: 181px; width: 231px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image001.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation x + y = 10, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 1\" style=\"height: 49px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image002.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation x \u2013 y = \u20134, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 2\" style=\"height: 48px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image003.png\" \/><\/p>\n<p style=\"text-align: justify;\">We plot the points for both of the equations to find the solution.<\/p>\n<p style=\"text-align: justify;\">We can clearly see that the intersection point of two lines is <strong>(3, 7).<\/strong><\/p>\n<p style=\"text-align: justify;\">Therefore, number of boys who took park in the quiz = 3 and, number of girls who took part in the quiz = 7.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <\/strong>Let cost of one pencil = Rs x and Let cost of one pen = Rs y<\/p>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<p style=\"text-align: justify;\"><strong>According to given conditions, we have<\/strong><\/p>\n<p style=\"text-align: justify;\">5<em>x <\/em>+ 7<em>y <\/em>= 50\u2026 <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 158px; width: 244px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image004.png\" \/><\/p>\n<p style=\"text-align: justify;\">7<em>x <\/em>+ 5<em>y <\/em>= 46\u2026 <strong>(2)<\/strong><\/p>\n<p style=\"text-align: justify;\">For equation 5x + 7y = 50, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 3\" style=\"height: 50px; width: 90px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image005.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation 7x + 5y = 46, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 4\" style=\"height: 48px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\">We can clearly see that the intersection point of two lines is <strong>(3, 5).<\/strong><\/p>\n<p style=\"text-align: justify;\">Therefore, cost of pencil = Rs 3 and, cost of pen = Rs 5<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_On_comparing_the_ratios_find_out_whether_the_lines_representing_the_following_pairs_of_linear_equations_intersect_at_a_point_are_parallel_or_coincident\"><\/span><strong>2. On comparing the ratios <img decoding=\"async\" style=\"height: 45px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image007.png\" \/>, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong> (i) 5<em>x <\/em>\u2212 4<em>y <\/em>+ 8 = 0 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)9<em>x <\/em>+ 3<em>y <\/em>+ 12 = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>7<em>x <\/em>+ 6<em>y <\/em>\u2013 9 = 018<em>x <\/em>+ 6<em>y <\/em>+ 24 = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) 6<em>x <\/em>\u2212 3<em>y <\/em>+ 10 = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>2<em>x <\/em>\u2013 <em>y <\/em>+ 9 = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> 5<em>x <\/em>\u2212 4<em>y <\/em>+ 8 = 0, 7<em>x <\/em>+ 6<em>y <\/em>\u2013 9 = 0<\/p>\n<p style=\"text-align: justify;\">Comparing equation 5<em>x <\/em>\u2212 4<em>y <\/em>+ 8 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 7<em>x <\/em>+ 6<em>y <\/em>\u2013 9 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image009.png\" \/><\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image010.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image011.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image012.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 48px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image013.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image014.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">We have <img decoding=\"async\" style=\"height: 45px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image016.png\" \/>because <img decoding=\"async\" style=\"height: 42px; width: 53px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\">Hence, lines have unique solution which means they intersect at one point.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> 9<em>x <\/em>+ 3<em>y <\/em>+ 12 = 0, 18<em>x <\/em>+ 6<em>y <\/em>+ 24 = 0<\/p>\n<p style=\"text-align: justify;\">Comparing equation 9<em>x <\/em>+ 3<em>y <\/em>+ 12 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 18<em>x <\/em>+ 6<em>y <\/em>+ 24 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image019.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image020.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image021.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 54px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image022.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image014.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">We have <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image024.png\" \/> because <img decoding=\"async\" style=\"height: 42px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\">Hence, lines are coincident.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> 6<em>x <\/em>\u2212 3<em>y <\/em>+ 10 = 0, 2<em>x <\/em>\u2013 <em>y <\/em>+ 9 = 0<\/p>\n<p style=\"text-align: justify;\">Comparing equation 6<em>x <\/em>\u2212 3<em>y <\/em>+ 10 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 2<em>x <\/em>\u2013 <em>y <\/em>+ 9 = 0 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image026.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image027.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image028.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 48px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image029.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image030.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\">We have <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image032.png\" \/> because <img decoding=\"async\" style=\"height: 42px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\">Hence, lines are parallel to each other.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_On_comparing_the_ratios_find_out_whether_the_following_pair_of_linear_equations_are_consistent_or_inconsistent\"><\/span><strong>3. On comparing the ratios <img decoding=\"async\" style=\"height: 45px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image007.png\" \/>, find out whether the following pair of linear equations are consistent, or inconsistent.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong> (i) 3<em>x <\/em>+ 2<em>y <\/em>= 5, 2<em>x <\/em>\u2212 3<em>y <\/em>= 8<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) 2<em>x <\/em>\u2212 3<em>y <\/em>= 7, 4<em>x <\/em>\u2212 6<em>y <\/em>= 9<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <\/strong><img decoding=\"async\" style=\"height: 42px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image042.png\" \/> 9<em>x <\/em>\u2212 10<em>y <\/em>= 14<\/p>\n<p style=\"text-align: justify;\"><strong>(iv) <\/strong>5<em>x <\/em>\u2212 3<em>y <\/em>= 11, \u221210<em>x <\/em>+ 6<em>y <\/em>= \u221222<\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> 3<em>x <\/em>+ 2<em>y <\/em>= 5, 2<em>x <\/em>\u2212 3<em>y <\/em>= 7<\/p>\n<p style=\"text-align: justify;\">Comparing equation 3<em>x <\/em>+ 2<em>y <\/em>= 5 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 2<em>x <\/em>\u2212 3<em>y <\/em>= 7 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 141px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image035.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 172px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image036.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 45px; width: 48px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image037.png\" \/> and <img decoding=\"async\" style=\"height: 45px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image038.png\" \/><\/p>\n<p style=\"text-align: justify;\">Here <img decoding=\"async\" style=\"height: 45px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image016.png\" \/>which means equations have unique solution.<\/p>\n<p style=\"text-align: justify;\">Hence they are consistent.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> 2<em>x <\/em>\u2212 3<em>y <\/em>= 8, 4<em>x <\/em>\u2212 6<em>y <\/em>= 9<\/p>\n<p style=\"text-align: justify;\">Comparing equation 2<em>x <\/em>\u2212 3<em>y <\/em>= 8 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 4<em>x <\/em>\u2212 6<em>y <\/em>= 9 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image039.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 173px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image040.png\" \/><\/p>\n<p style=\"text-align: justify;\">Here <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image032.png\" \/>because <img decoding=\"async\" style=\"height: 42px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image041.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, equations have no solution because they are parallel.<\/p>\n<p style=\"text-align: justify;\">Hence, they are inconsistent.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> <img decoding=\"async\" style=\"height: 42px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image042.png\" \/> 9<em>x <\/em>\u2212 10<em>y <\/em>= 14<\/p>\n<p style=\"text-align: justify;\">Comparing equation <img decoding=\"async\" style=\"height: 42px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image034.png\" \/>with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and 9<em>x <\/em>\u2212 10<em>y <\/em>= 14 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 42px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image043.png\" \/>, <img decoding=\"async\" style=\"height: 42px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image044.png\" \/>, <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image045.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 138px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image046.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 64px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image047.png\" \/> and <img decoding=\"async\" style=\"height: 64px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image048.png\" \/><\/p>\n<p style=\"text-align: justify;\">Here <img decoding=\"async\" style=\"height: 45px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image016.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, equations have unique solution.<\/p>\n<p style=\"text-align: justify;\">Hence, they are consistent.<\/p>\n<p style=\"text-align: justify;\"><strong>(iv)<\/strong> 5<em>x <\/em>\u2212 3<em>y <\/em>= 11, \u221210<em>x <\/em>+ 6<em>y <\/em>= \u221222<\/p>\n<p style=\"text-align: justify;\">Comparing equation 5<em>x <\/em>\u2212 3<em>y <\/em>= 11 with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/> and \u221210<em>x <\/em>+ 6<em>y <\/em>= \u221222 with <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get, <img decoding=\"async\" style=\"height: 24px; width: 175px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image049.png\" \/><img decoding=\"async\" style=\"height: 24px; width: 173px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 45px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image051.png\" \/> <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image052.png\" \/> and <img decoding=\"async\" style=\"height: 45px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image053.png\" \/><\/p>\n<p style=\"text-align: justify;\">Here <img decoding=\"async\" style=\"height: 45px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image054.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, the lines have infinite many solutions.<\/p>\n<p style=\"text-align: justify;\">Hence, they are consistent.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_Which_of_the_following_pairs_of_linear_equations_are_consistentinconsistent_If_consistent_obtain_the_solution_graphically\"><\/span><strong>4. Which of the following pairs of linear equations are consistent\/inconsistent? If consistent, obtain the solution graphically:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) <em>x <\/em>+ <em>y <\/em>= 5, 2<em>x <\/em>+ 2<em>y <\/em>= 10<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <em>x <\/em>\u2013 <em>y <\/em>= 8, 3<em>x <\/em>\u2212 3<em>y <\/em>= 16<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) 2<em>x <\/em>+ <em>y <\/em>= 6, 4<em>x <\/em>\u2212 2<em>y <\/em>= 4<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iv) 2<em>x <\/em>\u2212 2<em>y <\/em>\u2013 2 = 0, 4<em>x <\/em>\u2212 4<em>y <\/em>\u2013 5 = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> <em>x <\/em>+ <em>y <\/em>= 5, 2<em>x <\/em>+ 2<em>y <\/em>= 10<\/p>\n<p style=\"text-align: justify;\">For equation x + y \u2013 5 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 5\" style=\"height: 47px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image055.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation 2x + 2y \u2013 10 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 6\" style=\"height: 48px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image056.png\" \/><\/p>\n<p style=\"text-align: justify;\">We can see that both of the lines coincide. Hence, there are infinite many solutions. Any point which lies on one line also lies on the other. Hence, by using equation (<em>x <\/em>+ <em>y <\/em>\u2013 5 = 0), we can say that <em>x <\/em>= 5 \u2212 <em>y<\/em><\/p>\n<p style=\"text-align: justify;\">We can assume any random values for y and can find the corresponding value of x using the above equation. All such points will lie on both lines and there will be infinite number of such points.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 164px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image057.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> <em>x <\/em>\u2013 <em>y <\/em>= 8, 3<em>x <\/em>\u2212 3<em>y <\/em>= 16<\/p>\n<p style=\"text-align: justify;\">For x \u2013 y = 8, the coordinates are:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 7\" style=\"height: 57px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image058.png\" \/><\/p>\n<p style=\"text-align: justify;\">And for 3x \u2013 3y = 16, the coordinates<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 8\" style=\"height: 102px; width: 148px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image059.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 307\" style=\"height: 319px; width: 233px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image060.png\" \/><\/p>\n<p style=\"text-align: justify;\">Plotting these points on the graph, it is clear that both lines are parallel. So the two lines have no common point. Hence the given equations have no solution and lines are inconsistent.<\/p>\n<p style=\"text-align: justify;\"><strong> (iii)<\/strong> 2<em>x <\/em>+ <em>y <\/em>= 6, 4<em>x <\/em>\u2212 2<em>y <\/em>= 4<\/p>\n<p style=\"text-align: justify;\">For equation 2x + y \u2013 6 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 9\" style=\"height: 48px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image061.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation 4x \u2013 2y \u2013 4 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 10\" style=\"height: 48px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image062.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 15\" style=\"height: 292px; width: 234px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image063.png\" \/><\/p>\n<p style=\"text-align: justify;\">We can clearly see that lines are intersecting at (2, 2) which is the solution.<\/p>\n<p style=\"text-align: justify;\">Hence x = 2 and y = 2 and lines are consistent.<\/p>\n<p style=\"text-align: justify;\"><strong> (iv)<\/strong> 2<em>x <\/em>\u2212 2<em>y <\/em>\u2013 2 = 0, 4<em>x <\/em>\u2212 4<em>y <\/em>\u2013 5 = 0<\/p>\n<p style=\"text-align: justify;\">For 2x \u2013 2y \u2013 2 = 0, the coordinates are:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 11\" style=\"height: 57px; width: 142px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image064.png\" \/><\/p>\n<p style=\"text-align: justify;\">And for 4x \u2013 4y \u2013 5 = 0, the coordinates<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 12\" style=\"height: 99px; width: 142px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image065.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 313\" style=\"height: 244px; width: 206px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image066.jpg\" \/><\/p>\n<p style=\"text-align: justify;\">Plotting these points on the graph, it is clear that both lines are parallel. So the two lines have no common point. Hence the given equations have no solution and lines are inconsistent.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_Half_the_perimeter_of_a_rectangle_garden_whose_length_is_4_m_more_than_its_width_is_36_m_Find_the_dimensions_of_the_garden\"><\/span><strong>5. Half the perimeter of a rectangle garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let length of rectangular garden = x metres<\/p>\n<p style=\"text-align: justify;\">Let width of rectangular garden = y metres<\/p>\n<p style=\"text-align: justify;\">According to given conditions, perimeter = 36 m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image067.png\" \/>x + y = 36 \u2026\u2026(i)<\/p>\n<p style=\"text-align: justify;\">And x = y + 4<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>x <\/em>\u2013 <em>y <\/em>= 4\u2026\u2026..(ii)<\/p>\n<p style=\"text-align: justify;\">Adding eq. (i) and (ii),<\/p>\n<p style=\"text-align: justify;\">2x = 40<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image067.png\" \/> x = 20 m<\/p>\n<p style=\"text-align: justify;\">Subtracting eq. (ii) from eq. (i),<\/p>\n<p style=\"text-align: justify;\">2y = 32<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image067.png\" \/> y = 16 m<\/p>\n<p style=\"text-align: justify;\">Hence, length = 20 m and width = 16 m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_Given_the_linear_equation_2x_3y_%E2%80%93_8_0_write_another_linear_equation_in_two_variables_such_that_the_geometrical_representation_of_the_pair_so_formed_is\"><\/span><strong>6. Given the linear equation (2x + 3y \u2013 8 = 0), write another linear equation in two variables such that the geometrical representation of the pair so formed is: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) Intersecting lines <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) Parallel lines<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) Coincident lines<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> Let the second line be equal to <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\">Comparing given line <strong>2x + 3y \u2013 8 = 0 <\/strong>with <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get <img decoding=\"async\" style=\"height: 24px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image068.png\" \/><\/p>\n<p style=\"text-align: justify;\">Two lines intersect with each other if <img decoding=\"async\" style=\"height: 45px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image069.png\" \/><\/p>\n<p style=\"text-align: justify;\">So, second equation can be <strong>x + 2y = 3<\/strong> because <img decoding=\"async\" style=\"height: 45px; width: 56px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image069.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <\/strong>Let the second line be equal to <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\">Comparing given line <strong>2x + 3y \u2013 8 = 0 w<\/strong>ith <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get <img decoding=\"async\" style=\"height: 24px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image068.png\" \/><\/p>\n<p style=\"text-align: justify;\">Two lines are parallel to each other if <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image032.png\" \/><\/p>\n<p style=\"text-align: justify;\">So, second equation can be <strong>2x + 3y \u2013 2 = 0<\/strong> because <img decoding=\"async\" style=\"height: 45px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image032.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <\/strong>Let the second line be equal to <img decoding=\"async\" style=\"height: 24px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\">Comparing given line <strong>2x + 3y \u2013 8 = 0 w<\/strong>ith <img decoding=\"async\" style=\"height: 24px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image008.png\" \/>,<\/p>\n<p style=\"text-align: justify;\">We get <img decoding=\"async\" style=\"height: 24px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image068.png\" \/><\/p>\n<p style=\"text-align: justify;\">Two lines are coincident if <img decoding=\"async\" style=\"height: 45px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image054.png\" \/><\/p>\n<p style=\"text-align: justify;\">So, second equation can be <strong>4x + 6y \u2013 16 = 0<\/strong> because <img decoding=\"async\" style=\"height: 45px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image054.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 3.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_Draw_the_graphs_of_the_equations_x_%E2%80%93_y_1_0_and_3x_2y_%E2%80%93_12_0_Determine_the_coordinates_of_the_vertices_of_the_triangle_formed_by_these_lines_and_the_x-axis_and_shade_the_triangular_region\"><\/span><strong>7. Draw the graphs of the equations x \u2013 y + 1 = 0 and 3x + 2y \u2013 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis, and shade the triangular region.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>For equation x \u2013 y + 1 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 13\" style=\"height: 46px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image070.png\" \/><\/p>\n<p style=\"text-align: justify;\">For equation 3x + 2y \u2013 12 = 0, we have following points which lie on the line<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 14\" style=\"height: 48px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image071.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 316\" style=\"height: 194px; width: 230px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch03\/Ex3.2\/image072.jpg\" \/><\/p>\n<p style=\"text-align: justify;\">We can see from the graphs that points of intersection of the lines with the x\u2013axis are (\u20131, 0), (2, 3) and (4, 0).<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_32\"><\/span>NCERT Solutions for Class 10 Maths Exercise 3.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 3.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 3.2\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 3.2\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":29994,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4913","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide\" \/>\n<meta property=\"og:description\" content=\"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\" \/>\n<meta property=\"og:site_name\" content=\"myCBSEguide\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/mycbseguide\/\" \/>\n<meta property=\"article:published_time\" content=\"2016-05-19T04:19:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2023-03-22T09:46:39+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\" \/>\n\t<meta property=\"og:image:width\" content=\"1\" \/>\n\t<meta property=\"og:image:height\" content=\"1\" \/>\n\t<meta property=\"og:image:type\" content=\"image\/jpeg\" \/>\n<meta name=\"author\" content=\"myCBSEguide\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:site\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"myCBSEguide\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"7 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\"},\"author\":{\"name\":\"myCBSEguide\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65\"},\"headline\":\"NCERT Solutions for Class 10 Maths Exercise 3.2\",\"datePublished\":\"2016-05-19T04:19:00+00:00\",\"dateModified\":\"2023-03-22T09:46:39+00:00\",\"mainEntityOfPage\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\"},\"wordCount\":1399,\"commentCount\":9,\"publisher\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"keywords\":[\"CBSE Class 10 Mathematics\",\"CBSE Study Material\",\"Class 10\",\"Mathematics\",\"maths\",\"NCERT Solutions\"],\"articleSection\":[\"Mathematics\",\"NCERT Solutions\"],\"inLanguage\":\"en-US\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\",\"url\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\",\"name\":\"NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide\",\"isPartOf\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#website\"},\"primaryImageOfPage\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage\"},\"thumbnailUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"datePublished\":\"2016-05-19T04:19:00+00:00\",\"dateModified\":\"2023-03-22T09:46:39+00:00\",\"description\":\"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics\",\"breadcrumb\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#breadcrumb\"},\"inLanguage\":\"en-US\",\"potentialAction\":[{\"@type\":\"ReadAction\",\"target\":[\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/\"]}]},{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage\",\"url\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"contentUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg\",\"caption\":\"NCERT Solutions for Class 10 Maths Exercise 3.2\"},{\"@type\":\"BreadcrumbList\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#breadcrumb\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Home\",\"item\":\"https:\/\/mycbseguide.com\/blog\/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"NCERT Solutions\",\"item\":\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/\"},{\"@type\":\"ListItem\",\"position\":3,\"name\":\"NCERT Solutions for Class 10 Maths Exercise 3.2\"}]},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#website\",\"url\":\"https:\/\/mycbseguide.com\/blog\/\",\"name\":\"myCBSEguide\",\"description\":\"\",\"publisher\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/mycbseguide.com\/blog\/?s={search_term_string}\"},\"query-input\":{\"@type\":\"PropertyValueSpecification\",\"valueRequired\":true,\"valueName\":\"search_term_string\"}}],\"inLanguage\":\"en-US\"},{\"@type\":\"Organization\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#organization\",\"name\":\"myCBSEguide\",\"url\":\"https:\/\/mycbseguide.com\/blog\/\",\"logo\":{\"@type\":\"ImageObject\",\"inLanguage\":\"en-US\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/\",\"url\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png\",\"contentUrl\":\"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png\",\"width\":180,\"height\":180,\"caption\":\"myCBSEguide\"},\"image\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/\"},\"sameAs\":[\"https:\/\/www.facebook.com\/mycbseguide\/\",\"https:\/\/x.com\/mycbseguide\",\"https:\/\/www.linkedin.com\/company\/mycbseguide\/\",\"http:\/\/in.pinterest.com\/mycbseguide\/\",\"https:\/\/www.youtube.com\/channel\/UCxuqSnnygFzwJG0pwogCNEQ\"]},{\"@type\":\"Person\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65\",\"name\":\"myCBSEguide\",\"sameAs\":[\"http:\/\/mycbseguide.com\"]}]}<\/script>\n<!-- \/ Yoast SEO plugin. -->","yoast_head_json":{"title":"NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide","description":"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics","robots":{"index":"index","follow":"follow","max-snippet":"max-snippet:-1","max-image-preview":"max-image-preview:large","max-video-preview":"max-video-preview:-1"},"canonical":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/","og_locale":"en_US","og_type":"article","og_title":"NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide","og_description":"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics","og_url":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/","og_site_name":"myCBSEguide","article_publisher":"https:\/\/www.facebook.com\/mycbseguide\/","article_published_time":"2016-05-19T04:19:00+00:00","article_modified_time":"2023-03-22T09:46:39+00:00","og_image":[{"url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","width":1,"height":1,"type":"image\/jpeg"}],"author":"myCBSEguide","twitter_card":"summary_large_image","twitter_creator":"@mycbseguide","twitter_site":"@mycbseguide","twitter_misc":{"Written by":"myCBSEguide","Est. reading time":"7 minutes"},"schema":{"@context":"https:\/\/schema.org","@graph":[{"@type":"Article","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#article","isPartOf":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/"},"author":{"name":"myCBSEguide","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65"},"headline":"NCERT Solutions for Class 10 Maths Exercise 3.2","datePublished":"2016-05-19T04:19:00+00:00","dateModified":"2023-03-22T09:46:39+00:00","mainEntityOfPage":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/"},"wordCount":1399,"commentCount":9,"publisher":{"@id":"https:\/\/mycbseguide.com\/blog\/#organization"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage"},"thumbnailUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","keywords":["CBSE Class 10 Mathematics","CBSE Study Material","Class 10","Mathematics","maths","NCERT Solutions"],"articleSection":["Mathematics","NCERT Solutions"],"inLanguage":"en-US"},{"@type":"WebPage","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/","url":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/","name":"NCERT Solutions for Class 10 Maths Exercise 3.2 | myCBSEguide","isPartOf":{"@id":"https:\/\/mycbseguide.com\/blog\/#website"},"primaryImageOfPage":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage"},"thumbnailUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","datePublished":"2016-05-19T04:19:00+00:00","dateModified":"2023-03-22T09:46:39+00:00","description":"NCERT Solutions for Class 10 Maths Exercise 3.2 in PDF format for free download. NCERT Solutions Class 10 Mathematics","breadcrumb":{"@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#breadcrumb"},"inLanguage":"en-US","potentialAction":[{"@type":"ReadAction","target":["https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/"]}]},{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#primaryimage","url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","contentUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/;https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10_maths_ncert_solutions.jpg","caption":"NCERT Solutions for Class 10 Maths Exercise 3.2"},{"@type":"BreadcrumbList","@id":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-3-2\/#breadcrumb","itemListElement":[{"@type":"ListItem","position":1,"name":"Home","item":"https:\/\/mycbseguide.com\/blog\/"},{"@type":"ListItem","position":2,"name":"NCERT Solutions","item":"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/"},{"@type":"ListItem","position":3,"name":"NCERT Solutions for Class 10 Maths Exercise 3.2"}]},{"@type":"WebSite","@id":"https:\/\/mycbseguide.com\/blog\/#website","url":"https:\/\/mycbseguide.com\/blog\/","name":"myCBSEguide","description":"","publisher":{"@id":"https:\/\/mycbseguide.com\/blog\/#organization"},"potentialAction":[{"@type":"SearchAction","target":{"@type":"EntryPoint","urlTemplate":"https:\/\/mycbseguide.com\/blog\/?s={search_term_string}"},"query-input":{"@type":"PropertyValueSpecification","valueRequired":true,"valueName":"search_term_string"}}],"inLanguage":"en-US"},{"@type":"Organization","@id":"https:\/\/mycbseguide.com\/blog\/#organization","name":"myCBSEguide","url":"https:\/\/mycbseguide.com\/blog\/","logo":{"@type":"ImageObject","inLanguage":"en-US","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/","url":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png","contentUrl":"https:\/\/mycbseguide.com\/blog\/wp-content\/uploads\/2016\/04\/books_square.png","width":180,"height":180,"caption":"myCBSEguide"},"image":{"@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/logo\/image\/"},"sameAs":["https:\/\/www.facebook.com\/mycbseguide\/","https:\/\/x.com\/mycbseguide","https:\/\/www.linkedin.com\/company\/mycbseguide\/","http:\/\/in.pinterest.com\/mycbseguide\/","https:\/\/www.youtube.com\/channel\/UCxuqSnnygFzwJG0pwogCNEQ"]},{"@type":"Person","@id":"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65","name":"myCBSEguide","sameAs":["http:\/\/mycbseguide.com"]}]}},"_links":{"self":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4913","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/comments?post=4913"}],"version-history":[{"count":3,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4913\/revisions"}],"predecessor-version":[{"id":16163,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/posts\/4913\/revisions\/16163"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/media\/29994"}],"wp:attachment":[{"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/media?parent=4913"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/categories?post=4913"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/mycbseguide.com\/blog\/wp-json\/wp\/v2\/tags?post=4913"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}