{"id":4871,"date":"2016-05-18T11:49:00","date_gmt":"2016-05-18T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-2-3\/"},"modified":"2023-03-22T15:21:08","modified_gmt":"2023-03-22T09:51:08","slug":"ncert-solutions-for-class-10-maths-exercise-2-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 2.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#_NCERT_Solutions_for_Class_10_Maths_Polynomials\" >\u00a0NCERT Solutions for Class 10 Maths\u00a0Polynomials<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#2_Check_whether_the_first_polynomial_is_a_factor_of_the_second_polynomial_by_dividing_the_second_polynomial_by_the_first_polynomial\" >2. Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#3_Obtain_all_other_zeroes_of_if_two_of_its_zeroes_are_and\" >3. Obtain all other zeroes of if two of its zeroes are and .<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#4_On_dividing_by_a_polynomial_gx_the_quotient_and_remainder_were_x-2_and_-2x4_respectively_Find_gx\" >4. On dividing by a polynomial g(x), the quotient and remainder were (x-2) and (-2x+4) respectively. Find g(x).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#5_Give_examples_of_polynomials_px_gx_qx_and_rx_which_satisfy_the_division_algorithm_and\" >5. Give examples of polynomials p(x), g(x), q(x) and r(x), which satisfy the division algorithm and<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#NCERT_Solutions_for_Class_10_Maths_Exercise_23\" >NCERT Solutions for Class 10 Maths Exercise 2.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Maths Exercise 2.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 10\u00a0Maths Polynomials\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-polynomials\/1204\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 2.3\" width=\"184\" height=\"227\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"_NCERT_Solutions_for_Class_10_Maths_Polynomials\"><\/span>\u00a0NCERT Solutions for Class 10 Maths\u00a0Polynomials<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: justify;\"><strong>1. Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in each of the following.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(i)<img decoding=\"async\" style=\"height: 26px; width: 164px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image001.png\" \/>, <img decoding=\"async\" style=\"height: 26px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image002.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<img decoding=\"async\" style=\"height: 26px; width: 164px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image003.png\" \/>, <img decoding=\"async\" style=\"height: 26px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image004.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<img decoding=\"async\" style=\"height: 26px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image005.png\" \/>, <img decoding=\"async\" style=\"height: 26px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image006.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" style=\"height: 160px; width: 161px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image007.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\">Therefore, quotient = x \u2013 3 and Remainder = 7x \u2013 9<\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong> <img decoding=\"async\" style=\"height: 214px; width: 210px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image008.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\">Therefore, quotient = <img decoding=\"async\" style=\"height: 22px; width: 70px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image009.png\" \/>and, Remainder = 8<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong> <img decoding=\"async\" style=\"height: 163px; width: 172px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image010.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\">Therefore, quotient = <img decoding=\"async\" style=\"height: 22px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image011.png\" \/>and, Remainder = \u22125<em>x <\/em>+ 10<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 2.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Check_whether_the_first_polynomial_is_a_factor_of_the_second_polynomial_by_dividing_the_second_polynomial_by_the_first_polynomial\"><\/span><strong>2. Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) <img decoding=\"async\" style=\"height: 24px; width: 189px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image012.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <img decoding=\"async\" style=\"height: 24px; width: 226px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image013.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <img decoding=\"async\" style=\"height: 24px; width: 209px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image014.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong> Ans. (i)<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 216px; width: 203px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image016.png\" \/>Remainder = 0<\/p>\n<p style=\"text-align: justify;\">Hence first polynomial is a factor of second polynomial.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 216px; width: 237px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image016.png\" \/> Remainder = 0<\/p>\n<p style=\"text-align: justify;\">Hence first polynomial is a factor of second polynomial.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 185px; width: 211px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image016.png\" \/> Remainder \u22600<\/p>\n<p style=\"text-align: justify;\">Hence first polynomial is not factor of second polynomial.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 2.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_Obtain_all_other_zeroes_of_if_two_of_its_zeroes_are_and\"><\/span><strong>3. Obtain all other zeroes of <img decoding=\"async\" style=\"height: 29px; width: 180px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image019.png\" \/>if two of its zeroes are <img decoding=\"async\" style=\"height: 47px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image020.png\" \/>and <img decoding=\"async\" style=\"height: 47px; width: 38px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image021.png\" \/>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Two zeroes of <img decoding=\"async\" style=\"height: 29px; width: 173px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image022.png\" \/>are <img decoding=\"async\" style=\"height: 47px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image020.png\" \/>and <img decoding=\"async\" style=\"height: 47px; width: 38px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image021.png\" \/> which means that <img decoding=\"async\" style=\"height: 53px; width: 180px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image023.png\" \/> is a factor of <img decoding=\"async\" style=\"height: 29px; width: 173px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image022.png\" \/>.<\/p>\n<p style=\"text-align: justify;\">Applying Division Algorithm to find more factors we get:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 234px; width: 224px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image024.png\" \/><\/p>\n<p style=\"text-align: justify;\">We have <img decoding=\"async\" style=\"height: 26px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 29px; width: 172px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image026.png\" \/><\/p>\n<p style=\"text-align: justify;\">= (<img decoding=\"async\" style=\"height: 42px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image027.png\" \/><img decoding=\"async\" style=\"height: 29px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image028.png\" \/>)<\/p>\n<p style=\"text-align: justify;\">= (<img decoding=\"async\" style=\"height: 42px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image027.png\" \/>)3<img decoding=\"async\" style=\"height: 29px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image029.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 3(<img decoding=\"async\" style=\"height: 42px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image027.png\" \/>)<img decoding=\"async\" style=\"height: 29px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image030.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 3(<img decoding=\"async\" style=\"height: 42px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image027.png\" \/>)(<em>x<\/em>+1)(<em>x<\/em>+1)<\/p>\n<p style=\"text-align: justify;\">Therefore, other two zeroes of <img decoding=\"async\" style=\"height: 29px; width: 173px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image022.png\" \/>are \u22121 and \u22121.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 2.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_On_dividing_by_a_polynomial_gx_the_quotient_and_remainder_were_x-2_and_-2x4_respectively_Find_gx\"><\/span><strong>4. On dividing <img decoding=\"async\" style=\"height: 29px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image031.png\" \/>by a polynomial g(x), the quotient and remainder were (x-2) and (-2x+4) respectively. Find g(x).<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let<img decoding=\"async\" style=\"height: 26px; width: 156px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image032.png\" \/>, q(x) = (x \u2013 2) and r(x) = (\u20132x+4)<\/p>\n<p style=\"text-align: justify;\">According to Polynomial Division Algorithm, we have<\/p>\n<p style=\"text-align: justify;\">p(x) = g(x).q(x) + r(x)<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 22px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image033.png\" \/>= <em>g<\/em>(<em>x<\/em>).(<em>x<\/em>\u22122)\u22122<em>x<\/em>+4<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 22px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image034.png\" \/>\u22124 = <em>g<\/em>(<em>x<\/em>).(<em>x<\/em>\u22122)<\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 22px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image035.png\" \/>= <em>g<\/em>(<em>x<\/em>).(<em>x<\/em>\u22122)<\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>g<\/em>(<em>x<\/em>) = <img decoding=\"async\" style=\"height: 44px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image036.png\" \/><\/p>\n<p style=\"text-align: justify;\">So, Dividing <img decoding=\"async\" style=\"height: 29px; width: 121px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image037.png\" \/>by (<em>x<\/em>\u22122), we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 189px; width: 137px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image038.png\" \/><\/p>\n<p style=\"text-align: justify;\">Therefore, we have <em>g<\/em>(<em>x<\/em>) = <img decoding=\"async\" style=\"height: 44px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image036.png\" \/><img decoding=\"async\" style=\"height: 22px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image039.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 2.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_Give_examples_of_polynomials_px_gx_qx_and_rx_which_satisfy_the_division_algorithm_and\"><\/span><strong>5. Give examples of polynomials p(x), g(x), q(x) and r(x), which satisfy the division algorithm and <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) deg p(x) = deg q(x) <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) deg q(x) = deg r(x)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) deg r(x) = 0<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> Let <img decoding=\"async\" style=\"height: 26px; width: 140px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image040.png\" \/>, g(x) = 3<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 208px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image041.png\" \/><br \/>\nSo, we can see in this example that deg p(x) = deg q(x) = 2<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> Let <img decoding=\"async\" style=\"height: 26px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image042.png\" \/>and <img decoding=\"async\" style=\"height: 26px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image043.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 104px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image044.png\" \/><\/p>\n<p style=\"text-align: justify;\">We can see in this example that deg q(x) = deg r(x) = 1<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> Let<img decoding=\"async\" style=\"height: 26px; width: 127px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image045.png\" \/>, g(x) = <em>x<\/em>+3<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 155px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch02\/Ex2.3\/image046.png\" \/><\/p>\n<p style=\"text-align: justify;\">We can see in this example that deg r(x) = 0<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_23\"><\/span>NCERT Solutions for Class 10 Maths Exercise 2.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 2.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 10 Maths Exercise 2.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-3\/\" aria-label=\"More on NCERT Solutions for Class 10 Maths Exercise 2.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":30027,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4871","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Exercise 2.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 2.3 in PDF format for free download. 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