{"id":4866,"date":"2016-05-18T11:49:00","date_gmt":"2016-05-18T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-2-2\/"},"modified":"2023-03-22T15:20:55","modified_gmt":"2023-03-22T09:50:55","slug":"ncert-solutions-for-class-10-maths-exercise-2-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths-exercise-2-2\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 2.2"},"content":{"rendered":"

NCERT Solutions for Class 10 Maths Exercise 2.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n

NCERT solutions for Class 10\u00a0Maths Polynomials\u00a0Download as PDF<\/a><\/strong><\/p>\n

\"NCERT<\/p>\n

\u00a0NCERT Solutions for Class 10 Maths\u00a0Polynomials<\/h2>\n

1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeros and the coefficients. <\/strong><\/p>\n

(i) <\/strong><\/p>\n

(ii) <\/strong><\/p>\n

(iii) <\/strong><\/p>\n

(iv) <\/strong><\/p>\n

(v) <\/strong><\/p>\n

(vi) <\/strong><\/p>\n

Ans. (i) <\/strong><\/p>\n

Comparing given polynomial with general form ,<\/p>\n

We get a = 1, b = -2 and c = -8<\/p>\n

We have, <\/p>\n

<\/p>\n

= x<\/em>(x<\/em>\u22124)+2(x<\/em>\u22124) = (x<\/em>\u22124)(x<\/em>+2)<\/p>\n

Equating this equal to 0 will find values of 2 zeroes of this polynomial.<\/p>\n

(x<\/em>\u22124)(x<\/em>+2) = 0<\/p>\n

\u21d2 x <\/em>= 4, \u22122 are two zeroes.<\/p>\n

Sum of zeroes = 4 \u2013 2 = 2 = <\/p>\n

= <\/p>\n

Product of zeroes = 4 \u00d7 \u22122 = \u22128<\/p>\n

= <\/p>\n

(ii) <\/strong><\/p>\n

Here, a = 4, b = -4 and c = 1<\/p>\n

We have, <\/p>\n

=<\/p>\n

=2s<\/em>(2s<\/em>\u22121)\u22121(2s<\/em>\u22121)
\n= (2s<\/em>\u22121)(2s<\/em>\u22121)<\/p>\n

Equating this equal to 0 will find values of 2 zeroes of this polynomial.<\/p>\n

\u21d2 (2s<\/em>\u22121)(2s<\/em>\u22121) = 0<\/p>\n

\u21d2 s <\/em>= <\/p>\n

Therefore, two zeroes of this polynomial are <\/p>\n

Sum of zeroes = = 1 = <\/p>\n

= <\/p>\n

Product of Zeroes = <\/p>\n

<\/p>\n

(iii) <\/strong><\/p>\n

Here, a = 6, b = -7 and c = -3<\/p>\n

We have, <\/p>\n

<\/p>\n

<\/p>\n

= 3x<\/em>(2x<\/em>\u22123)+1(2x<\/em>\u22123) = (2x<\/em>\u22123)(3x<\/em>+1)<\/p>\n

Equating this equal to 0 will find values of 2 zeroes of this polynomial.<\/p>\n

\u21d2 (2x<\/em>\u22123)(3x<\/em>+1) = 0<\/p>\n

\u21d2 x <\/em>= <\/p>\n

Therefore, two zeroes of this polynomial are <\/p>\n

Sum of zeroes = <\/p>\n

<\/p>\n

Product of Zeroes = <\/p>\n

(iv) <\/strong><\/p>\n

Here, a = 4, b = 8 and c = 0<\/p>\n

<\/p>\n

Equating this equal to 0 will find values of 2 zeroes of this polynomial.<\/p>\n

\u21d2 4u<\/em>(u<\/em>+2) = 0<\/p>\n

\u21d2 u <\/em>= 0,\u22122<\/p>\n

NCERT Solutions for Class 10 Maths Exercise 2.2<\/p>\n

Therefore, two zeroes of this polynomial are 0, \u22122<\/p>\n

Sum of zeroes = 0\u22122 = \u22122 = <\/p>\n

= <\/p>\n

Product of Zeroes = 0<\/p>\n

= <\/p>\n

(v) <\/strong><\/p>\n

Here, a = 1, b = 0 and c = -15<\/p>\n

We have, \u21d2 \u21d2 t <\/em>= <\/p>\n

Therefore, two zeroes of this polynomial are <\/p>\n

Sum of zeroes = <\/p>\n

Product of Zeroes = <\/p>\n

<\/p>\n

(vi) <\/strong><\/p>\n

Here, a = 3, b = -1 and c = -4<\/p>\n

We have, = <\/p>\n

= x<\/em>(3x<\/em>\u22124)+1(3x<\/em>\u22124) = (3x<\/em>\u22124)(x<\/em>+1)<\/p>\n

Equating this equal to 0 will find values of 2 zeroes of this polynomial.<\/p>\n

\u21d2 (3x<\/em>\u22124)(x<\/em>+1) = 0<\/p>\n

\u21d2 x <\/em>= <\/p>\n

Therefore, two zeroes of this polynomial are <\/p>\n

Sum of zeroes = <\/p>\n

Product of Zeroes = <\/p>\n

\n

NCERT Solutions for Class 10 Maths Exercise 2.2<\/p>\n

2. Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.<\/strong><\/p>\n

(i) , \u22121 <\/strong><\/p>\n

(ii) , 13 <\/strong><\/p>\n

(iii) 0, <\/strong><\/p>\n

(iv) 1, 1 <\/strong><\/p>\n

(v) <\/strong><\/p>\n

(vi) 4, 1<\/strong><\/p>\n

Ans. (i) <\/strong>, \u22121<\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> are two zeroes of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2<\/em> = = <\/p>\n

\u03b1 <\/em>\u00d7 \u03b2 <\/em>= -1 = <\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions = <\/p>\n

(ii) <\/strong><\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> be two zeros of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2 <\/em>= = <\/p>\n

\u03b1 <\/em>\u00d7 \u03b2 <\/em>= which is equal to <\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions = <\/p>\n

(iii) <\/strong>0, <\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> be two zeros of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2 <\/em>= 0 = <\/p>\n

\u03b1 <\/em> \u03b2 <\/em>= = <\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions <\/p>\n

(iv) <\/strong>1, 1<\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> be two zeros of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2 <\/em>= 1 = <\/p>\n

\u03b1 <\/em> \u03b2 <\/em>= 1 =<\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions = <\/p>\n

(v) <\/strong> <\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> be two zeros of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2 <\/em>= = <\/p>\n

\u03b1 <\/em> \u03b2 <\/em>= = <\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions = <\/p>\n

(vi) <\/strong>4, 1<\/p>\n

Let quadratic polynomial be <\/p>\n

Let \u03b1<\/em> and \u03b2<\/em> be two zeros of above quadratic polynomial.<\/p>\n

\u03b1<\/em>+\u03b2 <\/em>= 4 = <\/p>\n

\u03b1 <\/em>\u00d7 \u03b2 <\/em>= 1 = <\/p>\n

<\/p>\n

Quadratic polynomial which satisfies above conditions <\/p>\n

NCERT Solutions for Class 10 Maths Exercise 2.2<\/h2>\n

NCERT Solutions for Class 10 Maths Exercise 2.2 PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n

CBSE app for Class 10<\/h2>\n

To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions for Class 10 Maths Exercise 2.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":30026,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4866","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"\nNCERT Solutions for Class 10 Maths Exercise 2.2 |<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Exercise 2.2 Class 10 Maths book solutions are available in PDF format for free download.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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