{"id":4864,"date":"2016-05-18T11:49:00","date_gmt":"2016-05-18T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/"},"modified":"2023-03-22T15:20:43","modified_gmt":"2023-03-22T09:50:43","slug":"ncert-solutions-class-10-maths-exercise-1-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/","title":{"rendered":"NCERT Solutions class-10 Maths Exercise 1.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#NCERT_Solutions_for_Class_10_Maths_Real_Numbers\" >NCERT Solutions for Class 10 Maths Real Numbers<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#1_Prove_that_is_irrational\" >1. Prove that is irrational.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#2_Prove_that_3_2_is_irrational\" >2. Prove that (3 + 2) is irrational.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#3_Prove_that_the_following_are_irrationals\" >3. Prove that the following are irrationals.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#NCERT_Solutions_class-10_Maths_Exercise_13\" >NCERT Solutions class-10 Maths Exercise 1.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions class-10 Maths Exercise 1.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 10\u00a0Maths\u00a0Real Numbers\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-real-numbers\/1203\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions class-10 Maths Exercise 1.3\" width=\"171\" height=\"210\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Real_Numbers\"><\/span>NCERT Solutions for Class 10 Maths Real Numbers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"1_Prove_that_is_irrational\"><\/span><strong>1. Prove that <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>is irrational.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let us prove <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>irrational by contradiction.<\/p>\n<p style=\"text-align: justify;\">Let us suppose that <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>is rational. It means that we have co-prime integers <strong><em>a<\/em> and <em>b<\/em> <\/strong>(<em>b <\/em>\u2260 0) such that <img decoding=\"async\" style=\"height: 42px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image002.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em>b<\/em><img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>=<em>a<\/em><\/p>\n<p style=\"text-align: justify;\">Squaring both sides, we get<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image003.png\" \/><img decoding=\"async\" style=\"height: 22px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image004.png\" \/>\u2026 <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\">It means that 5 is factor of <img decoding=\"async\" style=\"height: 22px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image005.png\" \/><\/p>\n<p style=\"text-align: justify;\">Hence, <strong>5 is also factor of<\/strong> <strong><em>a<\/em><\/strong> by Theorem. \u2026 <strong>(2)<\/strong><\/p>\n<p style=\"text-align: justify;\">If, <strong>5 is factor of <em>a<\/em><\/strong>, it means that we can write <strong><em>a<\/em> = 5<em>c<\/em><\/strong> for some integer <strong><em>c<\/em><\/strong>.<\/p>\n<p style=\"text-align: justify;\">Substituting value of <strong><em>a<\/em> <\/strong>in <strong>(1)<\/strong>,<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 156px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\">It means that 5 is factor of <img decoding=\"async\" style=\"height: 22px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image007.png\" \/>.<\/p>\n<p style=\"text-align: justify;\">Hence, <strong>5 is also factor of <em>b<\/em><\/strong> by Theorem. \u2026 <strong>(3)<\/strong><\/p>\n<p style=\"text-align: justify;\">From <strong>(2)<\/strong> and <strong>(3)<\/strong>, we can say that <strong>5<\/strong> is factor of both <strong><em>a<\/em> and <em>b<\/em><\/strong>.<\/p>\n<p style=\"text-align: justify;\">But, <strong><em>a<\/em> and <em>b<\/em><\/strong> are <strong>co-prime<\/strong>.<\/p>\n<p style=\"text-align: justify;\">Therefore, our assumption was wrong. <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/> cannot be rational. Hence, it is irrational.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions class-10 Maths Exercise 1.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Prove_that_3_2_is_irrational\"><\/span><strong>2. Prove that (3 + 2<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>) is irrational.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>We will prove this by contradiction.<\/p>\n<p style=\"text-align: justify;\">Let us suppose that (3+2<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>) is rational.<\/p>\n<p style=\"text-align: justify;\">It means that we have co-prime integers <strong><em>a<\/em> and <em>b<\/em> <\/strong>(<em>b <\/em>\u2260 0) such that<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image008.png\" \/><\/em> \u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image009.png\" \/><\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image010.png\" \/><\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image011.png\" \/>\u2026 <\/em> <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em>a<\/em> and <em>b<\/em><\/strong> are integers.<\/p>\n<p style=\"text-align: justify;\">It means<strong> L.H.S<\/strong> of <strong>(1)<\/strong> is rational but we know that <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/> is irrational. It is not possible. Therefore, our supposition is wrong. (3+2<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>) cannot be rational.<\/p>\n<p style=\"text-align: justify;\">Hence, (3+2<img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/>) is irrational.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions class-10 Maths Exercise 1.3<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_Prove_that_the_following_are_irrationals\"><\/span><strong>3. Prove that the following are irrationals.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) <img decoding=\"async\" style=\"height: 44px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image012.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image013.png\" \/> <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <img decoding=\"async\" style=\"height: 23px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image014.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i) <\/strong>We can prove <strong><img decoding=\"async\" style=\"height: 44px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image012.png\" \/><\/strong>irrational by contradiction.<\/p>\n<p style=\"text-align: justify;\">Let us suppose that <strong><img decoding=\"async\" style=\"height: 44px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image012.png\" \/><\/strong> is rational.<\/p>\n<p style=\"text-align: justify;\">It means we have some co-prime integers <em>a<\/em> and <em>b<\/em> (<em>b <\/em>\u2260 0) such that<\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" style=\"height: 44px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image012.png\" \/><\/strong>=<em>ab <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image015.png\" \/> \u2026 <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>R.H.S<\/strong> of<strong> (1)<\/strong> is rational but we know that <img decoding=\"async\" style=\"height: 23px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image016.png\" \/> is irrational.<\/p>\n<p style=\"text-align: justify;\">It is not possible which means our supposition is wrong.<\/p>\n<p style=\"text-align: justify;\">Therefore, <strong><img decoding=\"async\" style=\"height: 44px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image012.png\" \/><\/strong> cannot be rational.<\/p>\n<p style=\"text-align: justify;\">Hence, it is irrational.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <\/strong>We can prove <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image013.png\" \/> irrational by contradiction.<\/p>\n<p style=\"text-align: justify;\">Let us suppose that <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image013.png\" \/> is rational.<\/p>\n<p style=\"text-align: justify;\">It means we have some co-prime integers <em>a<\/em> and <em>b<\/em> (<em>b <\/em>\u2260 0) such that<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\">\u21d2 <img decoding=\"async\" style=\"height: 42px; width: 58px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image018.png\" \/> \u2026 <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>R.H.S<\/strong> of<strong> (1)<\/strong> is rational but we know that <img decoding=\"async\" style=\"height: 24px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image001.png\" \/> is irrational.<\/p>\n<p style=\"text-align: justify;\">It is not possible which means our supposition is wrong.<\/p>\n<p style=\"text-align: justify;\">Therefore, <img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image013.png\" \/> cannot be rational.<\/p>\n<p style=\"text-align: justify;\">Hence, it is irrational.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <\/strong>We will prove <img decoding=\"async\" style=\"height: 23px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image014.png\" \/> irrational by contradiction.<\/p>\n<p style=\"text-align: justify;\">Let us suppose that (<img decoding=\"async\" style=\"height: 23px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image014.png\" \/>) is rational.<\/p>\n<p style=\"text-align: justify;\">It means that we have co-prime integers <strong><em>a<\/em> and <em>b<\/em> <\/strong>(<em>b <\/em>\u2260 0) such that<\/p>\n<p style=\"text-align: justify;\"><em><img decoding=\"async\" style=\"height: 42px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image019.png\" \/> <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image020.png\" \/> <\/em><\/p>\n<p style=\"text-align: justify;\">\u21d2 <em><img decoding=\"async\" style=\"height: 42px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image021.png\" \/> \u2026<\/em> <strong>(1)<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong><em>a<\/em> and <em>b<\/em><\/strong> are integers.<\/p>\n<p style=\"text-align: justify;\">It means<strong> L.H.S<\/strong> of <strong>(1)<\/strong> is rational but we know that <img decoding=\"async\" style=\"height: 23px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image016.png\" \/>is irrational. It is not possible.<\/p>\n<p style=\"text-align: justify;\">Therefore, our supposition is wrong. (<img decoding=\"async\" style=\"height: 23px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image014.png\" \/>) cannot be rational.<\/p>\n<p style=\"text-align: justify;\">Hence, (<img decoding=\"async\" style=\"height: 23px; width: 47px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.3\/image014.png\" \/>) is irrational.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_class-10_Maths_Exercise_13\"><\/span>NCERT Solutions class-10 Maths Exercise 1.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions class-10 Maths Exercise 1.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths &#8230; <a title=\"NCERT Solutions class-10 Maths Exercise 1.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-3\/\" aria-label=\"More on NCERT Solutions class-10 Maths Exercise 1.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":30024,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1347,281],"tags":[1042,283,438,321,1485,216],"class_list":["post-4864","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics","category-ncert-solutions","tag-cbse-class-10-mathematics","tag-cbse-study-material","tag-class-10","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions class-10 Maths Exercise 1.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions class-10 Maths Exercise 1.3 in PDF format for free download. 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