{"id":4862,"date":"2016-05-18T11:49:00","date_gmt":"2016-05-18T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/"},"modified":"2023-03-22T15:20:36","modified_gmt":"2023-03-22T09:50:36","slug":"ncert-solutions-class-10-maths-exercise-1-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Exercise 1.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#_NCERT_Solutions_for_Class_10_Maths_Real_Numbers\" >\u00a0NCERT Solutions for Class 10 Maths Real Numbers<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#1_Express_each_number_as_product_of_its_prime_factors\" >1. Express each number as product of its prime factors:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#2_Find_the_LCM_and_HCF_of_the_following_pairs_of_integers_and_verify_that_product_of_the_two_numbers\" >2. Find the LCM and HCF of the following pairs of integers and verify that product of the two numbers.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#3_Find_the_LCM_and_HCF_of_the_following_integers_by_applying_the_prime_factorisation_method\" >3. Find the LCM and HCF of the following integers by applying the prime factorisation method.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#4_Given_that_HCF_306_657_9_find_LCM_306_657\" >4. Given that HCF (306, 657) = 9, find LCM (306, 657).<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#5_Check_whether_6n_can_end_with_the_digit_0_for_any_natural_number_n\" >5. Check whether 6n can end with the digit 0 for any natural number n.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#6_Explain_why_and_are_composite_numbers\" >6. Explain why and are composite numbers.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#7_There_is_a_circular_path_around_a_sports_field_Sonia_takes_18_minutes_to_drive_one_round_of_the_field_while_Ravi_takes_12_minutes_for_the_same_Suppose_they_both_start_at_the_same_point_and_at_the_same_time_and_go_in_the_same_direction_After_how_many_minutes_will_they_meet_again_at_the_starting_point\" >7. There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#NCERT_Solutions_for_Class_10_Maths_Exercise_12\" >NCERT Solutions for Class 10 Maths Exercise 1.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-10-maths-exercise-1-2\/#CBSE_app_for_Class_10\" >CBSE app for Class 10<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Maths Exercise 1.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 10\u00a0Maths\u00a0Real Numbers\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-mathematics-real-numbers\/1203\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Maths%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Maths Exercise 1.2\" width=\"180\" height=\"222\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"_NCERT_Solutions_for_Class_10_Maths_Real_Numbers\"><\/span>\u00a0NCERT Solutions for Class 10 Maths Real Numbers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"1_Express_each_number_as_product_of_its_prime_factors\"><\/span><strong>1. Express each number as product of its prime factors:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) 140<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) 156<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) 3825 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iv) 5005<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(v) 7429<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> 140 = <img decoding=\"async\" style=\"height: 19px; width: 73px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image001.png\" \/><img decoding=\"async\" style=\"height: 22px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image002.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> 156 = <img decoding=\"async\" style=\"height: 19px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image003.png\" \/>= <img decoding=\"async\" style=\"height: 22px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image004.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> 3825 = <img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image005.png\" \/>= <img decoding=\"async\" style=\"height: 22px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(iv)<\/strong> 5005 = <img decoding=\"async\" style=\"height: 19px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image007.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(v)<\/strong> 7429 = <img decoding=\"async\" style=\"height: 19px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image008.png\" \/><\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Find_the_LCM_and_HCF_of_the_following_pairs_of_integers_and_verify_that_product_of_the_two_numbers\"><\/span><strong>2. Find the LCM and HCF of the following pairs of integers and verify that <img decoding=\"async\" style=\"height: 19px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image009.png\" \/>product of the two numbers.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) 26 and 91 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) 510 and 92 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) 336 and 54<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> 26 and 91<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image010.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = 13<\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 19px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image012.png\" \/>= 182<\/p>\n<p style=\"text-align: justify;\">Product of two numbers 26 and 91 <img decoding=\"async\" style=\"height: 19px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image013.png\" \/>= 2366<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 152px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image014.png\" \/>= 2366<\/p>\n<p style=\"text-align: justify;\">Hence, product of two numbers = <strong><img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image015.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> 510 and 92<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image016.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image017.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = 2<\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 19px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image018.png\" \/>= 23460<\/p>\n<p style=\"text-align: justify;\">Product of two numbers 510 and 92 = <img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image019.png\" \/>= 46920<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image020.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image021.png\" \/>= 46920<\/p>\n<p style=\"text-align: justify;\">Hence, product of two numbers = <img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> 336 and 54<\/p>\n<p style=\"text-align: justify;\">336= <img decoding=\"async\" style=\"height: 19px; width: 161px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image022.png\" \/><img decoding=\"async\" style=\"height: 22px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">54 = <img decoding=\"async\" style=\"height: 22px; width: 172px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image024.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = <img decoding=\"async\" style=\"height: 19px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image025.png\" \/><\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 22px; width: 76px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image026.png\" \/>= 3024<\/p>\n<p style=\"text-align: justify;\">Product of two numbers 336 and 54 = <img decoding=\"async\" style=\"height: 19px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image027.png\" \/>= 18144<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 186px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image028.png\" \/>= 18144<\/p>\n<p style=\"text-align: justify;\">Hence, product of two numbers = <img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image015.png\" \/><\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_Find_the_LCM_and_HCF_of_the_following_integers_by_applying_the_prime_factorisation_method\"><\/span><strong>3. Find the LCM and HCF of the following integers by applying the prime factorisation method.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) 12, 15 and 21 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) 17, 23 and 29 <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) 8, 9 and 25<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> 12, 15 and 21<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image029.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image030.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = 3<\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 22px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image032.png\" \/>= 420<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> 17, 23 and 29<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image034.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image035.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = 1<\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image036.png\" \/>= 11339<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> 8, 9 and 25<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 148px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image037.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image038.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image039.png\" \/><\/p>\n<p style=\"text-align: justify;\">HCF = 1<\/p>\n<p style=\"text-align: justify;\">LCM = <img decoding=\"async\" style=\"height: 22px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image040.png\" \/>= 1800<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 1.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_Given_that_HCF_306_657_9_find_LCM_306_657\"><\/span><strong>4. Given that HCF (306, 657) = 9, find LCM (306, 657).<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>HCF (306, 657) = 9<\/p>\n<p style=\"text-align: justify;\">We know that, LCM \u00d7 HCF = Product of two numbers<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 189px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image041.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 203px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image042.png\" \/><\/p>\n<p style=\"text-align: justify;\">LCM = 22338<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 1.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_Check_whether_6n_can_end_with_the_digit_0_for_any_natural_number_n\"><\/span><strong>5. Check whether 6<em><sup>n<\/sup><\/em> can end with the digit 0 for any natural number <em>n<\/em>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>If any number ends with the digit 0, it should be divisible by 10.<\/p>\n<p style=\"text-align: justify;\">In other words, it will also be divisible by 2 and 5 as <img decoding=\"async\" style=\"height: 19px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image043.png\" \/><\/p>\n<p style=\"text-align: justify;\">Prime factorisation of <img decoding=\"async\" style=\"height: 29px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image044.png\" \/><\/p>\n<p style=\"text-align: justify;\">It can be observed that 5 is not in the prime factorisation of<img decoding=\"async\" style=\"height: 22px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image045.png\" \/>.<\/p>\n<p style=\"text-align: justify;\">Hence, for any value of <em>n<\/em>,<img decoding=\"async\" style=\"height: 22px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image045.png\" \/> will not be divisible by 5.<\/p>\n<p style=\"text-align: justify;\">Therefore,<img decoding=\"async\" style=\"height: 22px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image045.png\" \/> cannot end with the digit 0 for any natural number <em>n<\/em>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 1.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_Explain_why_and_are_composite_numbers\"><\/span><strong>6. Explain why <img decoding=\"async\" style=\"height: 19px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image046.png\" \/>and <img decoding=\"async\" style=\"height: 19px; width: 156px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image047.png\" \/>are composite numbers.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Numbers are of two types &#8211; prime and composite.<\/p>\n<p style=\"text-align: justify;\">Prime numbers can be divided by 1 and only itself, whereas composite numbers have factors other than 1 and itself.<\/p>\n<p style=\"text-align: justify;\">It can be observed that<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image048.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 26px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image049.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 26px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image050.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 19px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image051.png\" \/><\/p>\n<p style=\"text-align: justify;\">The given expression has 6 and 13 as its factors.<\/p>\n<p style=\"text-align: justify;\">Therefore, it is a composite number.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 152px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image052.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 26px; width: 163px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image053.png\" \/><\/p>\n<p style=\"text-align: justify;\">= <img decoding=\"async\" style=\"height: 26px; width: 110px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image054.png\" \/>= <img decoding=\"async\" style=\"height: 19px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image055.png\" \/><\/p>\n<p style=\"text-align: justify;\">1009 cannot be factorized further<\/p>\n<p style=\"text-align: justify;\">Therefore, the given expression has 5 and 1009 as its factors.<\/p>\n<p style=\"text-align: justify;\">Hence, it is a composite number.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Maths Exercise 1.2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_There_is_a_circular_path_around_a_sports_field_Sonia_takes_18_minutes_to_drive_one_round_of_the_field_while_Ravi_takes_12_minutes_for_the_same_Suppose_they_both_start_at_the_same_point_and_at_the_same_time_and_go_in_the_same_direction_After_how_many_minutes_will_they_meet_again_at_the_starting_point\"><\/span><strong>7. There is a circular path around a sports field. Sonia takes 18 minutes to drive one round of the field, while Ravi takes 12 minutes for the same. Suppose they both start at the same point and at the same time, and go in the same direction. After how many minutes will they meet again at the starting point?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>It can be observed that Ravi takes lesser time than Sonia for completing 1 round of the circular path. As they are going in the same direction, they will meet again at the same time when Ravi will have completed 1 round of that circular path with respect to Sonia. And the total time taken for completing this 1 round of circular path will be the LCM of time taken by Sonia and Ravi for completing 1 round of circular path respectively i.e., LCM of 18 minutes and 12 minutes.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 90px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image056.png\" \/>And, <img decoding=\"async\" style=\"height: 19px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image057.png\" \/><\/p>\n<p style=\"text-align: justify;\">LCM of 12 and <img decoding=\"async\" style=\"height: 19px; width: 144px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/mathematics\/ch01\/Ex1.2\/image058.png\" \/>= 36<\/p>\n<p style=\"text-align: justify;\">Therefore, Ravi and Sonia will meet together at the starting point after 36 minutes.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Maths_Exercise_12\"><\/span>NCERT Solutions for Class 10 Maths Exercise 1.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_10\"><\/span>CBSE app for Class 10<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Exercise 1.2 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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