{"id":4741,"date":"2016-05-18T09:49:00","date_gmt":"2016-05-18T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-3\/"},"modified":"2018-06-27T11:20:10","modified_gmt":"2018-06-27T05:50:10","slug":"ncert-solutions-for-class-8-maths-exercise-11-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Exercise 11.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#NCERT_Solutions_for_Class_8_Maths_Mensuration\" >NCERT Solutions for Class 8 Maths Mensuration<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#Class_%E2%80%93VIII_Mathematics_Ex_113\" >Class \u2013VIII Mathematics (Ex. 11.3)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#NCERT_SOLUTION\" >NCERT SOLUTION<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#1_There_are_two_cuboidal_boxes_as_shown_in_the_adjoining_figure_Which_box_requires_the_lesser_amount_of_material_to_make\" >1. There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#2_A_suitcase_with_measures_80_cm_48_cm_24_cm_is_to_be_covered_with_a_tarpaulin_cloth_How_many_meters_of_tarpaulin_of_width_96_cm_is_required_to_cover_100_such_suitcases\" >2. A suitcase with measures 80 cm \u00a048 cm \u00a024 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#3_Find_the_side_of_a_cube_whose_surface_area_id_600\" >3. Find the side of a cube whose surface area id 600.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#4_Rukshar_painted_the_outside_of_the_cabinet_of_measure_1_m_2_m_15_m_How_much_surface_area_did_she_cover_if_she_painted_all_except_the_bottom_of_the_cabinet\" >4. Rukshar painted the outside of the cabinet of measure 1 m 2 m \u00a01.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#5_Daniel_is_paining_the_walls_and_ceiling_of_a_cuboidal_hall_with_length_breadth_and_height_of_15_m_10_m_and_7_m_respectively_From_each_can_of_paint_100_of_area_is_painted_How_many_cans_of_paint_will_she_need_to_paint_the_room\" >5. Daniel is paining the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 of area is painted. How many cans of paint will she need to paint the room?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#6_Describe_how_the_two_figures_below_are_alike_and_how_they_are_different_Which_box_has_larger_lateral_surface_area\" >6. Describe how the two figures below are alike and how they are different. Which box has larger lateral surface area?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#7_A_closed_cylindrical_tank_of_radius_7_m_and_height_3_m_is_made_from_a_sheet_of_metal_How_much_sheet_of_metal_is_required\" >7. A closed cylindrical tank of radius 7 m and height 3 m is made from a sheet of metal. How much sheet of metal is required?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#8_The_lateral_surface_area_of_a_hollow_cylinder_is_4224_It_is_cut_along_its_height_and_formed_a_rectangular_sheet_of_width_33_cm_Find_the_perimeter_of_rectangular_sheet\" >8. The lateral surface area of a hollow cylinder is 4224. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#9_A_road_roller_takes_750_complete_revolutions_to_move_once_over_to_level_a_road_Find_the_area_of_the_road_if_the_diameter_of_a_road_roller_is_84_cm_and_length_1_m\" >9. A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length 1 m.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#10_A_company_packages_its_milk_powder_in_cylindrical_container_whose_base_has_a_diameter_of_14_cm_and_height_20_cm_Company_places_a_label_around_the_surface_of_the_container_as_shown_in_figure_If_the_label_is_placed_2_cm_from_top_and_bottom_what_is_the_area_of_the_label\" >10. A company packages its milk powder in cylindrical container whose base has a diameter of 14 cm and height 20 cm. Company places a label around the surface of the container (as shown in figure). If the label is placed 2 cm from top and bottom, what is the area of the label?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#NCERT_Solutions_for_Class_8_Maths_Exercise_113\" >NCERT Solutions for Class 8 Maths Exercise 11.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/#CBSE_app_for_Class_8\" >CBSE app for Class 8<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 8 Maths Exercise 11.3 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 8 Maths\u00a0Mensuration\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-08-mathematics-mensuration\/1460\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/08_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 8 Maths Exercise 11.3\" width=\"159\" height=\"200\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Mensuration\"><\/span>NCERT Solutions for Class 8 Maths Mensuration<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VIII_Mathematics_Ex_113\"><\/span><strong>Class \u2013VIII Mathematics (Ex. 11.3)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"NCERT_SOLUTION\"><\/span><strong>NCERT SOLUTION<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1_There_are_two_cuboidal_boxes_as_shown_in_the_adjoining_figure_Which_box_requires_the_lesser_amount_of_material_to_make\"><\/span><strong>1. There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 86px; width: 216px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image001.png\" \/><\/p>\n<p><strong>Ans. (a)<\/strong> Given: Length of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image002.png\" \/>\u00a0= 60 cm<\/p>\n<p>Breadth of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image003.png\" \/>\u00a0= 40 cm<\/p>\n<p>Height of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 50 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Total surface area of cuboidal box<\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image006.png\" \/>]\n<p>= 2 (60 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a040 + 40 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a050 + 50 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>60)<\/p>\n<p>= 2 (2400 + 2000 + 3000<\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a07400 = 14800 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p><strong>(b)<\/strong> Given: Length of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image002.png\" \/><\/p>\n<p>= 50 cm<\/p>\n<p>Breadth of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image003.png\" \/>\u00a0= 50 cm<\/p>\n<p>Height of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 50 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Total surface area of cuboidal box<\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image006.png\" \/><\/p>\n<p>= 2 (50 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a050 + 50 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a050 + 50 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a050)<\/p>\n<p>= 2 (2500 + 2500 + 2500)<\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a07500 = 15000 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p>Hence cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image009.png\" \/>\u00a0requires the lesser amount of materal to make, since surface area of box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image009.png\" \/>\u00a0is less than that of box <img decoding=\"async\" style=\"height: 27px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image010.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"2_A_suitcase_with_measures_80_cm_48_cm_24_cm_is_to_be_covered_with_a_tarpaulin_cloth_How_many_meters_of_tarpaulin_of_width_96_cm_is_required_to_cover_100_such_suitcases\"><\/span><strong>2. A suitcase with measures 80 cm <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a048 cm <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a024 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Given: Length of suitcase box <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image002.png\" \/>= 80 cm, Breadth of suitcase box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image003.png\" \/>\u00a0= 48 cm<\/p>\n<p>And Height of cuboidal box <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 24 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Total surface area of suitcase box<\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image006.png\" \/><\/p>\n<p>= 2 (80 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a048 + 48 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a024 + 24 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a080)<\/p>\n<p>= 2 (3840 + 1152 + 1920)<\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a06912 = 13824 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p>Area of Tarpaulin cloth = Surface area of suitcase<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image012.png\" \/>\u00a0= 13824<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 92px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image013.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image014.png\" \/>\u00a0= 144 cm<\/p>\n<p>Required tarpaulin for 100 suitcases<\/p>\n<p>= 144 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a0100 = 14400 cm = 144 m<\/p>\n<p>Hence tarpaulin cloth required to cover 100 suitcases is 144 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_Find_the_side_of_a_cube_whose_surface_area_id_600\"><\/span><strong>3. Find the side of a cube whose surface area id 600<img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image015.png\" \/>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Here Surface area of cube = 600 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 21px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image016.png\" \/>\u00a0= 600<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 21px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image017.png\" \/>\u00a0= 100<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 9px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image018.png\" \/>\u00a0= 10 cm<\/p>\n<p>Hence the side of cube is 10 cm<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"4_Rukshar_painted_the_outside_of_the_cabinet_of_measure_1_m_2_m_15_m_How_much_surface_area_did_she_cover_if_she_painted_all_except_the_bottom_of_the_cabinet\"><\/span><strong>4. Rukshar painted the outside of the cabinet of measure 1 m <\/strong><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/><strong>2 m <\/strong><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/><strong>\u00a01.5 m. How much surface area did she cover if she painted all except the bottom of the cabinet?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 108px; width: 188px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image019.png\" \/><\/p>\n<p><strong>Ans.<\/strong> Here, Length of cabinet <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image002.png\" \/>\u00a0= 2 m, Breadth of cabinet <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image003.png\" \/>\u00a0= 1 m<\/p>\n<p>And Height of cabinet <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 1.5 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Surface area of cabinet = <img decoding=\"async\" style=\"height: 27px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image020.png\" \/><\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a01 + 2 (1 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a01.5 + 1.5 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a02)<\/p>\n<p>= 2 + 2 (1.5 + 3.0)<\/p>\n<p>= 2 + 9.0<\/p>\n<p>= 11 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/><\/p>\n<p>Hence required surface area of cabinet is 11<img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5_Daniel_is_paining_the_walls_and_ceiling_of_a_cuboidal_hall_with_length_breadth_and_height_of_15_m_10_m_and_7_m_respectively_From_each_can_of_paint_100_of_area_is_painted_How_many_cans_of_paint_will_she_need_to_paint_the_room\"><\/span><strong>5. Daniel is paining the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 <img decoding=\"async\" style=\"height: 20px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image022.png\" \/>of area is painted. How many cans of paint will she need to paint the room?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Here, Length of wall <img decoding=\"async\" style=\"height: 27px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image002.png\" \/>\u00a0= 15 m, Breadth of wall <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image003.png\" \/>\u00a0= 10 m<\/p>\n<p>And Height of wall <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 7 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Total Surface area of classroom<\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image020.png\" \/><\/p>\n<p>= 15 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a010 + 2 (10 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a07 + 7 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>15)<\/p>\n<p>= 150 + 2 (70 + 105)<\/p>\n<p>= 150 + 350<\/p>\n<p>= 500 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/><\/p>\n<p>Now Required number of cans<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 151px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image023.png\" \/>\u00a0= 5 cans<\/p>\n<p>Hence 5 cans are required to paint the room.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"6_Describe_how_the_two_figures_below_are_alike_and_how_they_are_different_Which_box_has_larger_lateral_surface_area\"><\/span><strong>6. Describe how the two figures below are alike and how they are different. Which box has larger lateral surface area?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 69\" style=\"height: 130px; width: 277px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image024.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: Diameter of cylinder = 7 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Radius\u00a0 of cylinder <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image025.png\" \/>\u00a0= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image026.png\" \/>\u00a0cm<\/p>\n<p>And Height of cylinder <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 7 cm<\/p>\n<p>Lateral surface area of cylinder = <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image027.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image028.png\" \/><\/p>\n<p>= 154 cm<sup>2<\/sup><\/p>\n<p>Now lateral surface area of cube<\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image029.png\" \/>\u00a0= 4 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a049 = 196 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p>Hence the cube has larger lateral surface area.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7_A_closed_cylindrical_tank_of_radius_7_m_and_height_3_m_is_made_from_a_sheet_of_metal_How_much_sheet_of_metal_is_required\"><\/span><strong>7. A closed cylindrical tank of radius 7 m and height 3 m is made from a sheet of metal. How much sheet of metal is required? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong><img decoding=\"async\" id=\"Picture 72\" style=\"height: 121px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image030.jpg\" \/><\/strong><\/p>\n<p><strong>Ans.<\/strong> Given: Radius of cylindrical tank <img decoding=\"async\" style=\"height: 27px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image025.png\" \/>\u00a0= 7 m<\/p>\n<p>Height of cylindrical tank <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 3 m<\/p>\n<p>Total surface area of cylindrical tank<\/p>\n<p>= <img decoding=\"async\" style=\"height: 27px; width: 75px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image031.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image032.png\" \/><\/p>\n<p>= 44 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a010 = 440 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/><\/p>\n<p>Hence 440 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/>\u00a0metal sheet is required.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_The_lateral_surface_area_of_a_hollow_cylinder_is_4224_It_is_cut_along_its_height_and_formed_a_rectangular_sheet_of_width_33_cm_Find_the_perimeter_of_rectangular_sheet\"><\/span><strong>8. The lateral surface area of a hollow cylinder is 4224<img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image015.png\" \/>. It is cut along its height and formed a rectangular sheet of width 33 cm. Find the perimeter of rectangular sheet?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Given: Lateral surface area of hollow cylinder = 4224 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p>And Height of hollow cylinder = 33 cm<\/p>\n<p>Curved surface area of hollow cylinder = <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image027.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a04224 = <img decoding=\"async\" style=\"height: 41px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image033.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image034.png\" \/>\u00a0= <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image035.png\" \/>\u00a0cm<\/p>\n<p>Now Length of rectangular sheet = <img decoding=\"async\" style=\"height: 19px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image036.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image011.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image037.png\" \/>\u00a0= 128 cm<\/p>\n<p>Perimeter of rectangular sheet = <img decoding=\"async\" style=\"height: 27px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image038.png\" \/><\/p>\n<p>= 2 (128 + 33) = 2 x 161 = 322 cm<\/p>\n<p>Hence perimeter of rectangular sheet is 322 cm.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"9_A_road_roller_takes_750_complete_revolutions_to_move_once_over_to_level_a_road_Find_the_area_of_the_road_if_the_diameter_of_a_road_roller_is_84_cm_and_length_1_m\"><\/span><strong>9. A road roller takes 750 complete revolutions to move once over to level a road. Find the area of the road if the diameter of a road roller is 84 cm and length 1 m.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 75\" style=\"height: 131px; width: 157px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image039.jpg\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>Ans.<\/strong> Given: Diameter of road roller = 84 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Radius of road roller <img decoding=\"async\" style=\"height: 41px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image040.png\" \/><\/p>\n<p>= 42 cm<\/p>\n<p>Length of road roller <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>\u00a0= 1 m = 100 cm<\/p>\n<p>Curved surface area of road roller = <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image027.png\" \/>\u00a0= <img decoding=\"async\" style=\"height: 41px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image041.png\" \/>\u00a0= 26400 cm<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Area covered by road roller in 750 revolutions = 26400 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image007.png\" \/>\u00a0750<\/p>\n<p>= 1,98,00,000<img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/><\/p>\n<p>= 1980 m<sup>2<\/sup> [<img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image042.png\" \/>\u00a01 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/>= 10,000<img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image008.png\" \/>]\n<p>Hence the area of the road is 1980<img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image021.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"10_A_company_packages_its_milk_powder_in_cylindrical_container_whose_base_has_a_diameter_of_14_cm_and_height_20_cm_Company_places_a_label_around_the_surface_of_the_container_as_shown_in_figure_If_the_label_is_placed_2_cm_from_top_and_bottom_what_is_the_area_of_the_label\"><\/span><strong>10. A company packages its milk powder in cylindrical container whose base has a diameter of 14 cm and height 20 cm. Company places a label around the surface of the container (as shown in figure). If the label is placed 2 cm from top and bottom, what is the area of the label?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 150px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image043.png\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: Diameter of cylindrical container = 14 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image005.png\" \/>\u00a0Radius of cylindrical container <img decoding=\"async\" style=\"height: 41px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image044.png\" \/>\u00a0= 7 cm<\/p>\n<p>Height of cylindrical container = 20 cm<\/p>\n<p>Height of the label <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image004.png\" \/>= 20 \u2013 2 \u2013 2<\/p>\n<p>= 16 cm<\/p>\n<p>Curved surface area of label = <img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image027.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_3\/image045.png\" \/>\u00a0= 704 cm<sup>2<\/sup><\/p>\n<p>Hence the area of the label of 704 cm<sup>2<\/sup>.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Exercise_113\"><\/span>NCERT Solutions for Class 8 Maths Exercise 11.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 8\u00a0Mathematics PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 8\u00a0Mathematics includes text book solutions from Class 8 Maths Book . NCERT Solutions for CBSE Class 8 Maths have total 16 chapters. 8 Maths NCERT Solutions in PDF for free Download on our website. Ncert class 8 solutions PDF and Maths ncert class 8 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_8\"><\/span>CBSE app for Class 8<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 8 Social Science, Computer Science, Home Science,Hindi ,English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 8 Maths Exercise 11.3 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 &#8230; <a title=\"NCERT Solutions for Class 8 Maths Exercise 11.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-3\/\" aria-label=\"More on NCERT Solutions for Class 8 Maths Exercise 11.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1382,281],"tags":[283,1523,321,1485,216],"class_list":["post-4741","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-08","category-ncert-solutions","tag-cbse-study-material","tag-class-8","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 8 Maths Exercise 11.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 8 Maths Exercise 11.3 in PDF format for free download. 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