{"id":4738,"date":"2016-05-18T09:49:00","date_gmt":"2016-05-18T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-2\/"},"modified":"2018-06-27T11:00:45","modified_gmt":"2018-06-27T05:30:45","slug":"ncert-solutions-for-class-8-maths-exercise-11-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Exercise 11.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#NCERT_Solutions_for_Class_8_Maths_Mensuration\" >NCERT Solutions for Class 8 Maths Mensuration<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#Class_%E2%80%93VIII_Mathematics_Ex_112\" >Class \u2013VIII Mathematics (Ex. 11.2)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#NCERT_SOLUTION\" >NCERT SOLUTION<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#1The_shape_of_the_top_surface_of_a_table_is_a_trapezium_Find_its_area_if_its_parallel_sides_are_1_m_and_12_m_and_perpendicular_distance_between_them_is_08_m\" >1.The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#2_The_area_of_a_trapezium_is_34_and_the_length_of_one_of_the_parallel_sides_is_10_cm_and_its_height_is_4_cm\" >2. The area of a trapezium is 34 and the length of one of the parallel sides is 10 cm and its height is 4 cm.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#3_Length_of_the_fence_of_a_trapezium_shaped_field_ABCD_is_120_m_If_BC_48_m_CD_17_m_and_AD_40_m_find_the_area_of_this_field_Side_AB_is_perpendicular_to_the_parallel_sides_AD_and_BC\" >3. Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#4_The_diagonal_of_a_quadrilateral_shaped_field_is_24_m_and_the_perpendiculars_dropped_on_it_from_the_remaining_opposite_vertices_are_8_m_and_13_m_Find_the_area_of_the_field\" >4. The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#5_The_diagonals_of_a_rhombus_are_75_cm_and_12_cm_Find_its_area\" >5. The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#6_Find_the_area_of_a_rhombus_whose_side_is_6_cm_and_whose_altitude_is_4_cm_If_one_of_the_diagonals_is_8_cm_long_find_the_length_of_the_other_diagonal\" >6. Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of the diagonals is 8 cm long, find the length of the other diagonal.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#7_The_floor_of_a_building_consists_of_3000_tiles_which_are_rhombus_shaped_and_each_of_its_diagonals_are_45_cm_and_30_cm_in_length_Find_the_total_cost_of_polishing_the_floor_if_the_cost_per_is_4\" >7. The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per is ` 4.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#8_Mohan_wants_to_buy_a_trapezium_shaped_field_Its_side_along_the_river_is_parallel_to_and_twice_the_sidealong_the_road_If_the_area_of_this_field_is_10500_m2_and_the_perpendicular_distance_between_the_two_parallel_sides_is_100_m_find_the_length_of_the_side_along_the_river\" >8. Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the sidealong the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#9_Top_surface_of_a_raised_platform_is_in_the_shape_of_a_regular_octagon_as_shown_in_the_figure_Find_the_area_of_the_octagonal_surface\" >9. Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#10_There_is_a_pentagonal_shaped_park_as_shown_in_the_figure\" >10. There is a pentagonal shaped park as shown in the figure.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#Find_the_area_of_this_park_using_both_ways_Can_you_suggest_some_other_way_of_finding_its_area\" >Find the area of this park using both ways. Can you suggest some other way of finding its area?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#11_Diagram_of_the_adjacent_picture_frame_has_outer_dimensions_24_cm_28_cm_and_inner_dimensions_16_cm_20_cm_Find_the_area_of_each_section_of_theframe_if_the_width_of_each_section_is_same\" >11. Diagram of the adjacent picture frame has outer dimensions = 24 cm \u00a028 cm and inner dimensions 16 cm \u00a020 cm. Find the area of each section of theframe, if the width of each section is same.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#NCERT_Solutions_for_Class_8_Maths_Exercise_112\" >NCERT Solutions for Class 8 Maths Exercise 11.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-11-2\/#CBSE_app_for_Class_8\" >CBSE app for Class 8<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 8 Maths Exercise 11.2 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>CERT solutions for Class 8 Maths\u00a0Mensuration\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-08-mathematics-mensuration\/1460\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/08_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 8 Maths Exercise 11.2\" width=\"160\" height=\"201\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Mensuration\"><\/span>NCERT Solutions for Class 8 Maths Mensuration<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VIII_Mathematics_Ex_112\"><\/span><strong>Class \u2013VIII Mathematics (Ex. 11.2)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"NCERT_SOLUTION\"><\/span><strong>NCERT SOLUTION<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1The_shape_of_the_top_surface_of_a_table_is_a_trapezium_Find_its_area_if_its_parallel_sides_are_1_m_and_12_m_and_perpendicular_distance_between_them_is_08_m\"><\/span><strong>1.The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 152px; width: 274px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image001.png\" \/><\/p>\n<p><strong>Ans.<\/strong> Here one parallel side of the trapezium <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image002.png\" \/>\u00a0= 1 m<\/p>\n<p>And second side <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image003.png\" \/>\u00a0= 1.2 m and<\/p>\n<p>height <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image004.png\" \/>\u00a0= 0.8 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Area of top surface of the table<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/>\u00a0= <img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image007.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image008.png\" \/>\u00a0= 0.88 m<sup>2<\/sup><\/p>\n<p>Hence surface area of the table is 0.88 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"2_The_area_of_a_trapezium_is_34_and_the_length_of_one_of_the_parallel_sides_is_10_cm_and_its_height_is_4_cm\"><\/span><strong>2. The area of a trapezium is 34 <img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image010.png\" \/>and the length of one of the parallel sides is 10 cm and its height is 4 cm. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 30\" style=\"height: 72px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image011.jpg\" \/><\/p>\n<p><strong>Find the length of the other parallel side.<\/strong><\/p>\n<p><strong>Ans.<\/strong> Let the length of the other parallel side be <img decoding=\"async\" style=\"height: 19px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image012.png\" \/><\/p>\n<p>Length of one parallel side <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image002.png\" \/>\u00a0= 10 am and height <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image004.png\" \/>\u00a0= 4 cm<\/p>\n<p>Area of trapezium = <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image014.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 27px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image015.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image016.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image017.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image018.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image019.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/><strong>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 37px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image020.png\" \/><\/strong><\/p>\n<p>Hence another required parallel<\/p>\n<p>side is 7 cm.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"3_Length_of_the_fence_of_a_trapezium_shaped_field_ABCD_is_120_m_If_BC_48_m_CD_17_m_and_AD_40_m_find_the_area_of_this_field_Side_AB_is_perpendicular_to_the_parallel_sides_AD_and_BC\"><\/span><strong>3. Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 36\" style=\"height: 106px; width: 160px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image021.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: BC = 48 m, CD = 17 m,<\/p>\n<p>AD = 40 m and perimeter = 120 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image022.png\" \/>\u00a0Perimeter of trapezium ABCD<\/p>\n<p>= AB + BC + CD + DA<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0120 = AB + 48 + 17 + 40<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0120 = AB = 105<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0AB = 120 \u2013 105 = 15 m<\/p>\n<p>Now Area of the field<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 135px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image023.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image024.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image025.png\" \/><\/p>\n<p>= 660 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<p>Hence area of the field ABCD is 660<img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_The_diagonal_of_a_quadrilateral_shaped_field_is_24_m_and_the_perpendiculars_dropped_on_it_from_the_remaining_opposite_vertices_are_8_m_and_13_m_Find_the_area_of_the_field\"><\/span><strong>4. The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 33\" style=\"height: 114px; width: 175px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image026.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Here <img decoding=\"async\" style=\"height: 24px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image027.png\" \/>\u00a0= 13 m, <img decoding=\"async\" style=\"height: 24px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image028.png\" \/>\u00a0= 8 m and<\/p>\n<p>AC = 24 m<\/p>\n<p>Area of quadrilateral ABCD<\/p>\n<p>= Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image029.png\" \/>ABC + Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image029.png\" \/>ADC<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 109px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image030.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image031.png\" \/><\/p>\n<p>=<img decoding=\"async\" style=\"height: 41px; width: 185px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image032.png\" \/><\/p>\n<p>=252 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<p>Hence required area of the field<\/p>\n<p>is 252 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"5_The_diagonals_of_a_rhombus_are_75_cm_and_12_cm_Find_its_area\"><\/span><strong>5. The diagonals of a rhombus are 7.5 cm and 12 cm. Find its area.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Given: <img decoding=\"async\" style=\"height: 24px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image033.png\" \/>\u00a0=7.5 cm and <img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image034.png\" \/>\u00a0= 12 cm<\/p>\n<p>We know that,<\/p>\n<p>Area of rhombus = <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image035.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 75px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image036.png\" \/><\/p>\n<p>= 45 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p>Hence area of rhombus is 45 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/>.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"6_Find_the_area_of_a_rhombus_whose_side_is_6_cm_and_whose_altitude_is_4_cm_If_one_of_the_diagonals_is_8_cm_long_find_the_length_of_the_other_diagonal\"><\/span><strong>6. Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of the diagonals is 8 cm long, find the length of the other diagonal.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Since rhombus is also a kind of parallelogram.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Area of rhombus<\/p>\n<p>= Base <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>Altitude<\/p>\n<p>= 6 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a04 = 24 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p>Also Area of rhombus = <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image039.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a024 = <img decoding=\"async\" style=\"height: 41px; width: 61px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image040.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 24px; width: 59px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image041.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image042.png\" \/>\u00a0= 6 cm<\/p>\n<p>Hence the length of the other<\/p>\n<p>diagonal is 6 cm.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7_The_floor_of_a_building_consists_of_3000_tiles_which_are_rhombus_shaped_and_each_of_its_diagonals_are_45_cm_and_30_cm_in_length_Find_the_total_cost_of_polishing_the_floor_if_the_cost_per_is_4\"><\/span><strong>7. The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per <img decoding=\"async\" style=\"height: 20px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image043.png\" \/>is ` 4.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Here, <img decoding=\"async\" style=\"height: 24px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image033.png\" \/>\u00a0= 45 cm and <img decoding=\"async\" style=\"height: 24px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image034.png\" \/>\u00a0= 30 cm<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image022.png\" \/>\u00a0Area of one tile = <img decoding=\"async\" style=\"height: 41px; width: 44px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image039.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image044.png\" \/>\u00a0= 675 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Area of 3000 tiles<\/p>\n<p>= 675 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a03000 = 2025000 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p>=<img decoding=\"async\" style=\"height: 41px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image045.png\" \/><\/p>\n<p>= 202.50 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><img decoding=\"async\" style=\"height: 29px; width: 156px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image046.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image022.png\" \/>\u00a0Cost of polishing the floor per<\/p>\n<p>sq. meter = 4<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Cost of polishing the floor per 202.50 sq. meter = 4 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a0202.50 =\u00a0 810<\/p>\n<p>Hence the total cost of polishing the floor is 810.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_Mohan_wants_to_buy_a_trapezium_shaped_field_Its_side_along_the_river_is_parallel_to_and_twice_the_sidealong_the_road_If_the_area_of_this_field_is_10500_m2_and_the_perpendicular_distance_between_the_two_parallel_sides_is_100_m_find_the_length_of_the_side_along_the_river\"><\/span><strong>8. Mohan wants to buy a trapezium shaped field. Its side along the river is parallel to and twice the sidealong the road. If the area of this field is 10500 m<sup>2<\/sup> and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 148px; width: 202px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image047.png\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: Perpendicular distance <img decoding=\"async\" style=\"height: 27px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image004.png\" \/><\/p>\n<p>= 100 m<\/p>\n<p>Area of the trapezium shaped field<\/p>\n<p>= 10500 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<p>Let side along the road be <img decoding=\"async\" style=\"height: 15px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image048.png\" \/>\u00a0m and side along the river = <img decoding=\"async\" style=\"height: 19px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image049.png\" \/>\u00a0m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Area of the trapezium field<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/>10500 = <img decoding=\"async\" style=\"height: 41px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image050.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 103px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image051.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image052.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/><img decoding=\"async\" style=\"height: 41px; width: 69px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image053.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image013.png\" \/><img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image054.png\" \/>m<\/p>\n<p>Hence the side along the river = <img decoding=\"async\" style=\"height: 19px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image049.png\" \/><\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a070 = 140 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"9_Top_surface_of_a_raised_platform_is_in_the_shape_of_a_regular_octagon_as_shown_in_the_figure_Find_the_area_of_the_octagonal_surface\"><\/span><strong>9. Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong><img decoding=\"async\" id=\"Picture 45\" style=\"height: 118px; width: 158px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image055.jpg\" \/><\/strong><\/p>\n<p><strong>Ans.<\/strong> Given: Octagon having eight equal sides, each 5 m.<\/p>\n<p>Construction:\u00a0 Divided the octagon in 3 figures, two trapeziums whose parallel and perpendicular sides are 11 m and 4 m respectively and third figure is rectangle having length and breadth 11 m and 5 m respectively.<\/p>\n<p><img decoding=\"async\" style=\"float: left; height: 129px; width: 179px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image056.jpg\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>Now\u00a0 Area of two trapeziums = 2 x <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/><\/p>\n<p>= 2 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 41px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image057.png\" \/>= 4 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a016 = 64 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<p>And Area of rectangle = length <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a0breadth<\/p>\n<p>= 11 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a05 = 55 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Total area of octagon = 64 + 55<\/p>\n<p>= 119 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"10_There_is_a_pentagonal_shaped_park_as_shown_in_the_figure\"><\/span><strong>10. There is a pentagonal shaped park as shown in the figure.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>For finding its are a Jyoti and Kavita divided it in two different ways.<\/strong><\/p>\n<p><img decoding=\"async\" style=\"height: 110px; width: 272px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image058.png\" \/><\/p>\n<h6><span class=\"ez-toc-section\" id=\"Find_the_area_of_this_park_using_both_ways_Can_you_suggest_some_other_way_of_finding_its_area\"><\/span><strong>Find the area of this park using both ways. Can you suggest some other way of finding its area?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> First way:\u00a0 By Jyoti\u2019s diagram,<\/p>\n<p>Area of pentagon = Area of trapezium ABCP + Area of trapezium AEDP<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0(AP + BC) x CP + <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0(ED + AP) <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a0DP\u00a0\u00a0\u00a0\u00a0\u00a0 = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0(30 + 15 ) x CP + <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0(15 + 30) <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a0DP<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0(30 + 15) (CP + DP)<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a045 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>CD<\/p>\n<p><img decoding=\"async\" style=\"height: 41px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image060.png\" \/><\/p>\n<p>=337.5 m<sup>2<\/sup><\/p>\n<p>Second way:<\/p>\n<p>By Kavita\u2019s diagram<\/p>\n<p>Here, a perpendicular AM drawn to BE.<\/p>\n<p>AM = 30 \u2013 15 = 15 m<\/p>\n<p>Area of pentagon<\/p>\n<p>= Area of <img decoding=\"async\" style=\"height: 17px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image029.png\" \/>ABE + Area of square BCDE<\/p>\n<p><img decoding=\"async\" id=\"Picture 1563\" style=\"height: 172px; width: 158px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image061.png\" \/><\/p>\n<p>=<img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image059.png\" \/><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>15<img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>15+15<img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>15m<\/p>\n<p>= 112.5 + 225.0<\/p>\n<p>= 337.5 m<sup>2<\/sup><\/p>\n<p>Hence total area of pentagon shaped<\/p>\n<p>park = 337.5<img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image009.png\" \/>.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"11_Diagram_of_the_adjacent_picture_frame_has_outer_dimensions_24_cm_28_cm_and_inner_dimensions_16_cm_20_cm_Find_the_area_of_each_section_of_theframe_if_the_width_of_each_section_is_same\"><\/span><strong>11. Diagram of the adjacent picture frame has outer dimensions = 24 cm <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a028 cm and inner dimensions 16 cm <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image038.png\" \/>\u00a020 cm. Find the area of each section of theframe, if the width of each section is same.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 60\" style=\"height: 147px; width: 149px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image062.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Here two of given figures (I) and (II) are similar in dimensions.<\/p>\n<p>And also figures (III) and (IV) are similar in dimensions.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image005.png\" \/>\u00a0Area of figure (I) = Area of trapezium<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image063.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image064.png\" \/><\/p>\n<p>= 96 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p>Also Area of figure (II) = 96 cm<sup>2<\/sup><\/p>\n<p>Now Area of figure (III)<\/p>\n<p>= Area of trapezium = <img decoding=\"async\" style=\"height: 41px; width: 81px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image006.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image065.png\" \/>\u00a0= <img decoding=\"async\" style=\"height: 41px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image066.png\" \/>\u00a0= 80 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<p>Also Area of figure (IV) = 80 <img decoding=\"async\" style=\"height: 21px; width: 29px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_2\/image037.png\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Exercise_112\"><\/span>NCERT Solutions for Class 8 Maths Exercise 11.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 8\u00a0Mathematics PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 8\u00a0Mathematics includes text book solutions from Class 8 Maths Book . NCERT Solutions for CBSE Class 8 Maths have total 16 chapters. 8 Maths NCERT Solutions in PDF for free Download on our website. Ncert class 8 solutions PDF and Maths ncert class 8 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_8\"><\/span>CBSE app for Class 8<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 8 Social Science, Computer Science, Home Science,Hindi ,English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 8 Maths Exercise 11.2 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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