{"id":4735,"date":"2016-05-18T08:49:00","date_gmt":"2016-05-18T03:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/"},"modified":"2018-06-27T10:55:22","modified_gmt":"2018-06-27T05:25:22","slug":"ncert-solutions-class-8-maths-exercise-11-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Exercise 11.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#NCERT_Solutions_for_Class_8_Maths_Mensuration\" >NCERT Solutions for Class 8 Maths Mensuration<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#Class_%E2%80%93VIII_Mathematics_Ex_111\" >Class \u2013VIII Mathematics (Ex. 11.1)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#NCERT_SOLUTION\" >NCERT SOLUTION<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#1_A_square_and_a_rectangular_field_with_measurements_as_given_in_the_figure_have_the_same_perimeter\" >1. A square and a rectangular field with measurements as given in the figure have the same perimeter.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#2_Mrs_Kaushik_has_a_square_plot_with_the_measurement_as_shown_in_the_figure_She_wants_to_construct_a_house_in_the_middle_of_the_plot_A_garden_is_developed_around_the_house_Find_the_total_cost_of_developing_a_garden_around_the_house_at_the_rate_of_55\" >2. Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ` 55<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#3_The_shape_of_a_garden_is_rectangular_in_the_middle_and_semi-circular_at_the_ends_as_shown_in_the_diagram_Find_the_area_and_the_perimeter_of_this_garden_Length_of_rectangle_is_20_%E2%80%93_35_35_meters\" >3. The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20 \u2013 (3.5 + 3.5 meters]<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#4_A_flooring_tile_has_the_shape_of_a_parallelogram_whose_base_is_24_cm_and_the_corresponding_height_is_10_cm_How_many_such_tiles_are_required_to_cover_a_floor_of_area_1080_If_required_you_can_split_the_tiles_in_whatever_way_you_want_to_fill_up_the_corners\" >4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080? [If required you can split the tiles in whatever way you want to fill up the corners]<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#5_An_ant_is_moving_around_a_few_food_pieces_of_different_shapes_scattered_on_the_floor_For_which_food-piece_would_the_ant_have_to_take_a_longer_round_Remember_circumference_of_a_circle_can_be_obtained_by_using_the_expression_where_is_the_radius_of_the_circle\" >5. An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, circumference of a circle can be obtained by using the expression where \u00a0is the radius of the circle.<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#NCERT_Solutions_for_Class_8_Maths_Exercise_111\" >NCERT Solutions for Class 8 Maths Exercise 11.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/#CBSE_app_for_Class_8\" >CBSE app for Class 8<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 8 Maths Exercise 11.1 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 8 Maths\u00a0Mensuration <a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-08-mathematics-mensuration\/1460\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/08_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 8 Maths Exercise 11.1\" width=\"166\" height=\"208\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Mensuration\"><\/span>NCERT Solutions for Class 8 Maths Mensuration<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<div>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VIII_Mathematics_Ex_111\"><\/span><strong>Class \u2013VIII Mathematics (Ex. 11.1)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"NCERT_SOLUTION\"><\/span><strong>NCERT SOLUTION<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1_A_square_and_a_rectangular_field_with_measurements_as_given_in_the_figure_have_the_same_perimeter\"><\/span><strong>1. A square and a rectangular field with measurements as given in the figure have the same perimeter. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Which field has a larger area?<\/strong><\/p>\n<p><img decoding=\"async\" id=\"Picture 3\" style=\"height: 99px; width: 219px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image001.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: The side of a square = 60 m<\/p>\n<p>And the length of rectangular field = 80 m<\/p>\n<p>According to question,<\/p>\n<p>Perimeter of rectangular field<\/p>\n<p>= Perimeter of square field<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 27px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image003.png\" \/>=\u00a0 4 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a0side<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 27px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image005.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image006.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 97px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image007.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 52px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image008.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image002.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 19px; width: 45px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image009.png\" \/>m<\/p>\n<p>Now Area of Square field<\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image010.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image011.png\" \/>\u00a0= 3600 m<sup>2<\/sup><\/p>\n<p>And Area of Rectangular field<\/p>\n<p>= length <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a0breadth = 80 <strong><img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/><\/strong>\u00a040<\/p>\n<p>= 3200 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image012.png\" \/><\/p>\n<p>Hence, area of square field is larger.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"2_Mrs_Kaushik_has_a_square_plot_with_the_measurement_as_shown_in_the_figure_She_wants_to_construct_a_house_in_the_middle_of_the_plot_A_garden_is_developed_around_the_house_Find_the_total_cost_of_developing_a_garden_around_the_house_at_the_rate_of_55\"><\/span><strong>2. Mrs. Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of ` 55 <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>per m<sup>2<\/sup>.<\/strong><\/p>\n<p><img decoding=\"async\" id=\"Picture 6\" style=\"height: 172px; width: 158px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image013.jpg\" \/><\/p>\n<p><strong>Ans.<\/strong>\u00a0 Side of a square plot = 25 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Area of square plot = <img decoding=\"async\" style=\"height: 29px; width: 51px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image010.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 29px; width: 39px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image015.png\" \/>\u00a0= 625 m<sup>2<\/sup><\/p>\n<p>Length of the house = 20 m and<\/p>\n<p><img decoding=\"async\" style=\"height: 158px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image016.png\" \/><\/p>\n<p>Breadth of the house = 15 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Area of the house = length <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a0breadth<\/p>\n<p>= 20 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a015 = 300 m<sup>2<\/sup><\/p>\n<p>Area of garden = Area of square plot<\/p>\n<p>\u2013 Area of house<\/p>\n<p>= 625 \u2013 300 = 325 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image017.png\" \/>\u00a0Cost of developing the garden per sq. m = ` 55<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Cost of developing the garden 325 sq. m = ` 55 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>325<\/p>\n<p>= ` 17,875<\/p>\n<p>Hence total cost of developing a garden around is ` 17,875.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_The_shape_of_a_garden_is_rectangular_in_the_middle_and_semi-circular_at_the_ends_as_shown_in_the_diagram_Find_the_area_and_the_perimeter_of_this_garden_Length_of_rectangle_is_20_%E2%80%93_35_35_meters\"><\/span><strong>3. The shape of a garden is rectangular in the middle and semi-circular at the ends as shown in the diagram. Find the area and the perimeter of this garden [Length of rectangle is 20 \u2013 (3.5 + 3.5 meters]<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"float: left; height: 100px; width: 258px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image018.png\" \/><\/p>\n<p><strong>Ans.<\/strong> Given: Total length = 20 m<\/p>\n<p>Diameter of semi circle = 7 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Radius of semi circle = <img decoding=\"async\" style=\"height: 41px; width: 16px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image019.png\" \/>\u00a0= 3.5 m<\/p>\n<p>Length of rectangular field<\/p>\n<p>= 20 \u2013 (3.5 + 3.5) = 20 \u2013 7 = 13 m<\/p>\n<p>Breadth of the rectangular field = 7 m<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Area of rectangular field = <img decoding=\"async\" style=\"height: 19px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image020.png\" \/><\/p>\n<p>= 13 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a07 = 91 <img decoding=\"async\" style=\"height: 20px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image012.png\" \/><\/p>\n<p>Area of two semi circles = <img decoding=\"async\" style=\"height: 41px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image021.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 131px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image022.png\" \/>\u00a0= 38.5 m<sup>2<\/sup><\/p>\n<p>Area of garden = 91 + 38.5 = 129.5 m<sup>2<\/sup><\/p>\n<p>Now Perimeter of two semi circles = <img decoding=\"async\" style=\"height: 41px; width: 129px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image023.png\" \/>\u00a0= 22 m<\/p>\n<p>And Perimeter of garden<\/p>\n<p>= 22 + 13 + 13<\/p>\n<p>= 48 m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_A_flooring_tile_has_the_shape_of_a_parallelogram_whose_base_is_24_cm_and_the_corresponding_height_is_10_cm_How_many_such_tiles_are_required_to_cover_a_floor_of_area_1080_If_required_you_can_split_the_tiles_in_whatever_way_you_want_to_fill_up_the_corners\"><\/span><strong>4. A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080<img decoding=\"async\" style=\"height: 20px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image024.png\" \/>? [If required you can split the tiles in whatever way you want to fill up the corners]<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans.<\/strong> Given: Base of flooring tile = 24 cm<\/p>\n<p>= 0.24 m<\/p>\n<p>Corresponding height of a flooring tile<\/p>\n<p>= 10 cm = 0.10 m<\/p>\n<p>Now Area of flooring tile<\/p>\n<p>= Base <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a0Altitude<\/p>\n<p>= 0.24 <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image004.png\" \/>\u00a00.10<\/p>\n<p>= 0.024 m<sup>2<\/sup><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Number of tiles required to cover the floor<\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image025.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 43px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image026.png\" \/><\/p>\n<p>= 45000 tiles<\/p>\n<p>Hence 45000 tiles are required to cover the floor.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 11.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5_An_ant_is_moving_around_a_few_food_pieces_of_different_shapes_scattered_on_the_floor_For_which_food-piece_would_the_ant_have_to_take_a_longer_round_Remember_circumference_of_a_circle_can_be_obtained_by_using_the_expression_where_is_the_radius_of_the_circle\"><\/span><strong>5. An ant is moving around a few food pieces of different shapes scattered on the floor. For which food-piece would the ant have to take a longer round? Remember, circumference of a circle can be obtained by using the expression <\/strong><strong><img decoding=\"async\" style=\"height: 21px; width: 57px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image027.png\" \/>where <img decoding=\"async\" style=\"height: 13px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image028.png\" \/>\u00a0is the radius of the circle.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" style=\"height: 86px; width: 276px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image029.png\" \/><\/p>\n<p><strong>Ans.<\/strong> <strong>(a)<\/strong> Radius = <img decoding=\"async\" style=\"height: 41px; width: 106px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image030.png\" \/><\/p>\n<p>= 1.4 cm<\/p>\n<p>Circumference of semi circle = <img decoding=\"async\" style=\"height: 15px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image031.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image032.png\" \/>\u00a0= 4.4 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 18\" style=\"height: 74px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image033.jpg\" \/><\/p>\n<p>Total distance covered by the ant<\/p>\n<p>= Circumference of semi circle + Diameter<\/p>\n<p>= 4.4 + 2.8 = 7.2 cm<\/p>\n<p><strong>(b)<\/strong> Diameter of semi circle = 2.8 cm<\/p>\n<p><img decoding=\"async\" style=\"float: left; height: 79px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image034.jpg\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Radius = <img decoding=\"async\" style=\"height: 41px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image035.png\" \/>\u00a0= 1.4 cm<\/p>\n<p>Circumference of semi circle = <img decoding=\"async\" style=\"height: 15px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image031.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image032.png\" \/>\u00a0= 4.4 cm<\/p>\n<p>Total distance covered by the ant<\/p>\n<p>= 1.5 + 2.8 + 1.5 + 4.4 = 10.2 cm<\/p>\n<p><strong>(c)<\/strong> Diameter of semi circle = 2.8 cm<\/p>\n<p><img decoding=\"async\" style=\"float: left; height: 132px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image036.jpg\" \/><\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image014.png\" \/>\u00a0Radius = <img decoding=\"async\" style=\"height: 41px; width: 105px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image035.png\" \/><\/p>\n<p>= 1.4 cm<\/p>\n<p>Circumference of semi circle = <img decoding=\"async\" style=\"height: 15px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image031.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 41px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/11_1\/image032.png\" \/>\u00a0= 4.4 cm<\/p>\n<p>Total distance covered by the ant<\/p>\n<p>= 2 + 2 + 4.4 = 8.4 cm<\/p>\n<p>Hence for figure (b) food piece, the ant would take a longer round.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Exercise_111\"><\/span>NCERT Solutions for Class 8 Maths Exercise 11.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 8\u00a0Mathematics PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 8\u00a0Mathematics includes text book solutions from Class 8 Maths Book . NCERT Solutions for CBSE Class 8 Maths have total 16 chapters. 8 Maths NCERT Solutions in PDF for free Download on our website. Ncert class 8 solutions PDF and Maths ncert class 8 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_8\"><\/span>CBSE app for Class 8<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 8 Social Science, Computer Science, Home Science,Hindi ,English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 8 Maths Exercise 11.1 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 &#8230; <a title=\"NCERT Solutions for Class 8 Maths Exercise 11.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-11-1\/\" aria-label=\"More on NCERT Solutions for Class 8 Maths Exercise 11.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1382,281],"tags":[283,1523,321,1485,216],"class_list":["post-4735","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-08","category-ncert-solutions","tag-cbse-study-material","tag-class-8","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 8 Maths Exercise 11.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 8 Maths Exercise 11.1 in PDF format for free download. 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