{"id":4700,"date":"2016-05-17T11:49:00","date_gmt":"2016-05-17T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-8-maths-exercise-6-4\/"},"modified":"2018-06-26T15:23:53","modified_gmt":"2018-06-26T09:53:53","slug":"ncert-solutions-for-class-8-maths-exercise-6-4","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Exercise 6.4"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#NCERT_Solutions_for_Class_8_Maths_Squares_and_Square_Roots\" >NCERT Solutions for Class 8 Maths\u00a0Squares and Square Roots<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#Class_%E2%80%93VIII_Mathematics_Ex_64\" >Class \u2013VIII Mathematics (Ex. 6.4)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#NCERT_SOLUTION\" >NCERT SOLUTION<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#1_Find_the_square_roots_of_each_of_the_following_numbers_by_Division_method\" >1. Find the square roots of each of the following numbers by Division method:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#2_Find_the_number_of_digits_in_the_square_root_of_each_of_the_following_numbers_without_any_calculation\" >2. Find the number of digits in the square root of each of the following numbers (without any calculation):<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#3_Find_the_square_root_of_the_following_decimal_numbers\" >3. Find the square root of the following decimal numbers:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#4_Find_the_least_number_which_must_be_subtracted_from_each_of_the_following_numbers_so_as_to_get_a_perfect_square_Also_find_the_square_root_of_the_perfect_square_so_obtained\" >4. Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#We_know_that_if_we_subtract_the_remainder_from_the_number_we_get_a_perfect_square\" >We know that, if we subtract the remainder from the number, we get a perfect square.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#5_Find_the_least_number_which_must_be_added_to_each_of_the_following_numbers_so_as_to_get_a_perfect_square_Also_find_the_square_root_of_the_perfect_square_so_obtained\" >5. Find the least number which must be added to each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#Hence_the_square_root_of_256_is_16\" >Hence, the square root of 256 is 16.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#6_Find_the_length_of_the_side_of_a_square_whose_area_is\" >6. Find the length of the side of a square whose area is?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#7_In_a_right_triangle_ABC_B\" >7. In a right triangle ABC, B =<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#8_A_gardener_has_1000_plants_He_wants_to_plant_these_in_such_a_way_that_the_number_of_rows_and_number_of_columns_remain_same_Find_the_minimum_number_of_plants_he_needs_more_for_this\" >8. A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and number of columns remain same. Find the minimum number of plants he needs more for this.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#9_There_are_500_children_in_a_school_For_a_PT_drill_they_have_to_stand_in_such_a_manner_that_the_number_of_rows_is_equal_to_number_of_columns_How_many_children_would_be_left_out_in_this_arrangement\" >9. There are 500 children in a school. For a P.T. drill they have to stand in such a manner that the number of rows is equal to number of columns. How many children would be left out in this arrangement?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#NCERT_Solutions_for_Class_8_Maths_Exercise_64\" >NCERT Solutions for Class 8 Maths Exercise 6.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/#CBSE_app_for_Class_8\" >CBSE app for Class 8<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 8 Maths Exercise 6.4 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 8 Maths\u00a0Squares and Square Roots\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-08-mathematics-squares-and-square-roots\/1455\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/08_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 8 Maths Exercise 6.4\" width=\"143\" height=\"180\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Squares_and_Square_Roots\"><\/span>NCERT Solutions for Class 8 Maths\u00a0Squares and Square Roots<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VIII_Mathematics_Ex_64\"><\/span><strong>Class \u2013VIII Mathematics (Ex. 6.4)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"NCERT_SOLUTION\"><\/span><strong>NCERT SOLUTION<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"1_Find_the_square_roots_of_each_of_the_following_numbers_by_Division_method\"><\/span><strong>1. Find the square roots of each of the following numbers by Division method:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 2304\u00a0\u00a0\u00a0\u00a0 (ii) 4489<\/strong><\/p>\n<p><strong>(iii) 3481\u00a0\u00a0\u00a0\u00a0 (iv) 529<\/strong><\/p>\n<p><strong>(v) 3249\u00a0\u00a0\u00a0\u00a0 (vi) 1369<\/strong><\/p>\n<p><strong>(vii) 5776\u00a0\u00a0\u00a0\u00a0 (viii) 7921<\/strong><\/p>\n<p><strong>(ix) 576\u00a0\u00a0\u00a0\u00a0 (x) 1024<\/strong><\/p>\n<p><strong>(xi) 3136\u00a0\u00a0\u00a0\u00a0 (xii) 900<\/strong><\/p>\n<p><strong>Ans. (i)<\/strong> 2304<\/p>\n<p>Hence, the square root of 2304 is 48.<\/p>\n<p><img decoding=\"async\" id=\"Picture 193\" style=\"height: 139px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image001.jpg\" \/><\/p>\n<p><strong>(ii)<\/strong> 4489<\/p>\n<p>Hence, the square root of 4489 is 67.<\/p>\n<p><img decoding=\"async\" id=\"Picture 200\" style=\"height: 141px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image002.jpg\" \/><\/p>\n<p><strong>(iii)<\/strong> 3481<\/p>\n<p>Hence, the square root of 3481 is 59.<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" style=\"float: left; height: 138px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image003.jpg\" \/><\/p>\n<p><strong>(iv)<\/strong> 529<\/p>\n<p>Hence, the square root of 529 is 23.<\/p>\n<p><img decoding=\"async\" id=\"Picture 214\" style=\"height: 139px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image004.jpg\" \/><\/p>\n<p><strong>(v)<\/strong> 3249<\/p>\n<p>Hence, the square root of 3249 is 57.<\/p>\n<p><img decoding=\"async\" id=\"Picture 221\" style=\"height: 138px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image005.jpg\" \/><\/p>\n<p><strong>(vi)<\/strong> 1369<\/p>\n<p>Hence, the square root of 1369 is 37.<\/p>\n<p><img decoding=\"async\" id=\"Picture 228\" style=\"height: 138px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image006.jpg\" \/><\/p>\n<p><strong>(vii)<\/strong> 5776<\/p>\n<p>Hence, the square root of 5776 is 76.<\/p>\n<p><img decoding=\"async\" id=\"Picture 235\" style=\"height: 140px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image007.jpg\" \/><\/p>\n<p><strong>(viii)<\/strong> 7921<\/p>\n<p>Hence, the square root of 7921 is 89.<\/p>\n<p><img decoding=\"async\" id=\"Picture 242\" style=\"height: 145px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image008.jpg\" \/><\/p>\n<p><strong>(ix)<\/strong> 576<\/p>\n<p>Hence, the square root of 576 is 24.<\/p>\n<p><img decoding=\"async\" id=\"Picture 253\" style=\"height: 136px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image009.jpg\" \/><\/p>\n<p><strong>(x)<\/strong> 1024<\/p>\n<p>Hence, the square root of 1024 is 32.<\/p>\n<p><img decoding=\"async\" id=\"Picture 260\" style=\"height: 134px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image010.jpg\" \/><\/p>\n<p><strong>(xi)<\/strong> 3136<\/p>\n<p>Hence, the square root of 3136 is 56.<\/p>\n<p><img decoding=\"async\" id=\"Picture 263\" style=\"height: 141px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image011.jpg\" \/><\/p>\n<p><strong>(xii)<\/strong> 900<\/p>\n<p>Hence, the square root of 900 is 30.<\/p>\n<p><img decoding=\"async\" id=\"Picture 270\" style=\"height: 130px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image012.jpg\" \/><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"2_Find_the_number_of_digits_in_the_square_root_of_each_of_the_following_numbers_without_any_calculation\"><\/span><strong>2. Find the number of digits in the square root of each of the following numbers (without any calculation):<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 64\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(ii) 144<\/strong><\/p>\n<p><strong>(iii) 4489\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(iv) 27225<\/strong><\/p>\n<p><strong>(v) 390625<\/strong><\/p>\n<p><strong>Ans. (i)<\/strong> Here, 64 contains two digits which is even.<\/p>\n<p>Therefore, number of digits in square root = <img decoding=\"async\" style=\"height: 41px; width: 63px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image013.png\" \/><\/p>\n<p><strong>(ii)<\/strong> Here, 144 contains three digits which is odd.<\/p>\n<p>Therefore, number of digits in square root = <img decoding=\"async\" style=\"height: 41px; width: 131px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image014.png\" \/><\/p>\n<p><strong>(iii)<\/strong> Here, 4489 contains four digits which is even.<\/p>\n<p>Therefore, number of digits in square root = <img decoding=\"async\" style=\"height: 41px; width: 67px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image015.png\" \/><\/p>\n<p><strong>(iv)<\/strong> Here, 27225 contains fivr digits which is odd.<\/p>\n<p>Therefore, number of digits in square root = <img decoding=\"async\" style=\"height: 41px; width: 85px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image016.png\" \/><\/p>\n<p>&nbsp;<\/p>\n<p><strong>(v)<\/strong> Here, 390625 contains six digits which is even.<\/p>\n<p>Therefore, number of digits in square root = <img decoding=\"async\" style=\"height: 41px; width: 65px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image017.png\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"3_Find_the_square_root_of_the_following_decimal_numbers\"><\/span><strong>3. Find the square root of the following decimal numbers:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 2.56\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(ii) 7.29<\/strong><\/p>\n<p><strong>(iii) 51.84\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(iv) 42.25<\/strong><\/p>\n<p><strong>(v) 31.36<\/strong><\/p>\n<p><strong>Ans. (i)<\/strong> 2.56<\/p>\n<p>Hence, the square root of 2.56 is 1.6.<\/p>\n<p><img decoding=\"async\" id=\"Picture 277\" style=\"height: 137px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image018.jpg\" \/><\/p>\n<p><strong>(ii)<\/strong> 7.29<\/p>\n<p>Hence, the square root of 7.29 is 2.7.<\/p>\n<p><img decoding=\"async\" id=\"Picture 284\" style=\"height: 140px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image019.jpg\" \/><\/p>\n<p><strong>(iii)<\/strong> 51.84<\/p>\n<p>Hence, the square root of 51.84 is 7.2.<\/p>\n<p><img decoding=\"async\" id=\"Picture 291\" style=\"height: 141px; width: 116px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image020.jpg\" \/><\/p>\n<p><strong>(iv)<\/strong> 42.25<\/p>\n<p>Hence, the square root of 42.25 is 6.5.<\/p>\n<p><img decoding=\"async\" id=\"Picture 298\" style=\"height: 129px; width: 110px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image021.jpg\" \/><\/p>\n<p><strong>(v)<\/strong> 31.36<\/p>\n<p>Hence, the square root of 31.36 is 5.6.<\/p>\n<p><img decoding=\"async\" id=\"Picture 305\" style=\"height: 139px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image022.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"4_Find_the_least_number_which_must_be_subtracted_from_each_of_the_following_numbers_so_as_to_get_a_perfect_square_Also_find_the_square_root_of_the_perfect_square_so_obtained\"><\/span><strong>4. Find the least number which must be subtracted from each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 402\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(ii) 1989<\/strong><\/p>\n<p><strong>(iii) 3250\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(iv) 825<\/strong><\/p>\n<p><strong>(v) 4000<\/strong><\/p>\n<p><strong>Ans<\/strong>. (i) 402<\/p>\n<p>We know that, if we subtract the remainder from the number, we get a perfect square.<\/p>\n<p>Here, we get remainder 2. Therefore 2 must be subtracted from 402 to get a perfect square.<\/p>\n<p><img decoding=\"async\" id=\"Picture 312\" style=\"height: 137px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image023.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a0402 \u2013 2 = 400<\/p>\n<p>Hence, the square root of 400 is 20.<\/p>\n<p><img decoding=\"async\" id=\"Picture 319\" style=\"height: 135px; width: 117px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image025.jpg\" \/><\/p>\n<p><strong>(ii)<\/strong> 1989<\/p>\n<h6><span class=\"ez-toc-section\" id=\"We_know_that_if_we_subtract_the_remainder_from_the_number_we_get_a_perfect_square\"><\/span>We know that, if we subtract the remainder from the number, we get a perfect square.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 326\" style=\"height: 138px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image026.jpg\" \/><\/p>\n<p>Here, we get remainder 53. Therefore 53must be subtracted from 1989 to get a perfect square.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a01989 \u2013 53 = 1936<\/p>\n<p>Hence, the square root of 1936 is 44.<\/p>\n<p><img decoding=\"async\" id=\"Picture 333\" style=\"height: 138px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image027.jpg\" \/><\/p>\n<p><strong>(iii)<\/strong> 3250<\/p>\n<p>We know that, if we subtract the remainder from the number, we get a perfect square.<\/p>\n<p><img decoding=\"async\" id=\"Picture 340\" style=\"height: 137px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image028.jpg\" \/><\/p>\n<p>Here, we get remainder 1. Therefore 1 must be subtracted from 3250 to get a perfect square.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a03250 \u2013 1 = 3249<\/p>\n<p>Hence, the square root of 3249 is 57.<\/p>\n<p><img decoding=\"async\" id=\"Picture 347\" style=\"height: 140px; width: 126px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image029.jpg\" \/><\/p>\n<p><strong>(iv)<\/strong> 825<\/p>\n<p>We know that, if we subtract the remainder from the number, we get a perfect square.<\/p>\n<p><img decoding=\"async\" id=\"Picture 354\" style=\"height: 136px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image030.jpg\" \/><\/p>\n<p>Here, we get remainder 41. Therefore 41 must be subtracted from 825 to get a perfect square.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a0825 \u2013 41 = 784<\/p>\n<p>Hence, the square root of 784 is 28.<\/p>\n<p><img decoding=\"async\" id=\"Picture 361\" style=\"height: 137px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image031.jpg\" \/><\/p>\n<p><strong>(v)<\/strong> 4000<\/p>\n<p>We know that, if we subtract the remainder from the number, we get a perfect square.<\/p>\n<p><img decoding=\"async\" id=\"Picture 368\" style=\"height: 134px; width: 118px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image032.jpg\" \/><\/p>\n<p>Here, we get remainder 31. Therefore 31 must be subtracted from 4000 to get a perfect square.<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a04000 \u2013 31 = 3969<\/p>\n<p>Hence, the square root of 3969 is 63.<\/p>\n<p><img decoding=\"async\" id=\"Picture 375\" style=\"height: 138px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image033.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"5_Find_the_least_number_which_must_be_added_to_each_of_the_following_numbers_so_as_to_get_a_perfect_square_Also_find_the_square_root_of_the_perfect_square_so_obtained\"><\/span><strong>5. Find the least number which must be added to each of the following numbers so as to get a perfect square. Also, find the square root of the perfect square so obtained:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>(i) 525\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(ii) 1750<\/strong><\/p>\n<p><strong>(iii) 252\u00a0\u00a0\u00a0\u00a0 <\/strong><\/p>\n<p><strong>(iv) 1825<\/strong><\/p>\n<p><strong>(v) 6412<\/strong><\/p>\n<p><strong>Ans. (i)<\/strong> 525<\/p>\n<p>Since remainder is 41.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 72px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image034.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image035.png\" \/>\u00a0= 529<\/p>\n<p>Hence, number to be added<\/p>\n<p>= 529 \u2013 525 = 4<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a0525 + 4 = 529<\/p>\n<p>Hence, the square root of 529 is 23.<\/p>\n<p><img decoding=\"async\" id=\"Picture 382\" style=\"height: 130px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image036.jpg\" \/><\/p>\n<p><strong>(ii)<\/strong> 1750<\/p>\n<p>Since remainder is 69.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image037.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 20px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image038.png\" \/>\u00a0= 1764<\/p>\n<p>Hence, number to be added<\/p>\n<p>= 1764 \u2013 1750 = 14<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a01750 + 14 = 1764<\/p>\n<p>Hence, the square root of 1764 is 42.<\/p>\n<p><img decoding=\"async\" id=\"Picture 389\" style=\"height: 138px; width: 107px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image039.jpg\" \/><\/p>\n<p><strong>(iii)<\/strong> 252<\/p>\n<p>Since remainder is 27.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 71px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image040.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image041.png\" \/>\u00a0= 256<\/p>\n<p>Hence, number to be added<\/p>\n<p>= 256 \u2013 252 = 4<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a0252 + 4 = 256<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Hence_the_square_root_of_256_is_16\"><\/span>Hence, the square root of 256 is 16.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 396\" style=\"height: 138px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image042.jpg\" \/><\/p>\n<p><strong>(iv)<\/strong> 1825<\/p>\n<p>Since remainder is 61.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image043.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image044.png\" \/>\u00a0= 1849<\/p>\n<p>Hence, number to be added = 1849 \u2013 1825 = 24<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a01825 + 24 = 1849<\/p>\n<p>Hence, the square root of 1849 is 43.<\/p>\n<p><img decoding=\"async\" id=\"Picture 403\" style=\"height: 138px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image045.jpg\" \/><\/p>\n<p><strong>(v)<\/strong> 6412<\/p>\n<p>Since remainder is 12.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 80px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image046.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 21px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image047.png\" \/>\u00a0= 6561<\/p>\n<p>Hence, number to be added<\/p>\n<p>= 6561 \u2013 6412 = 149<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a06412 + 149 = 6561<\/p>\n<p>Hence, the square root of 6561 is 81.<\/p>\n<p><img decoding=\"async\" id=\"Picture 410\" style=\"height: 136px; width: 114px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image048.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"6_Find_the_length_of_the_side_of_a_square_whose_area_is\"><\/span><strong>6. Find the length of the side of a square whose area is<img decoding=\"async\" style=\"height: 21px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image049.png\" \/>?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. <\/strong>Let the length of side of a square be <img decoding=\"async\" style=\"height: 15px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image050.png\" \/>\u00a0meter.<\/p>\n<p>Area of square <img decoding=\"async\" style=\"height: 29px; width: 99px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image051.png\" \/><\/p>\n<p>According to question,<\/p>\n<p><img decoding=\"async\" style=\"height: 104px; width: 126px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image052.jpg\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 21px; width: 19px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image053.png\" \/>\u00a0= 441<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 23px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image055.png\" \/>= <img decoding=\"async\" style=\"height: 24px; width: 84px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image056.png\" \/><\/p>\n<p>= <img decoding=\"async\" style=\"height: 19px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image057.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 15px; width: 13px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image050.png\" \/>= 21 m<\/p>\n<p>Hence, the length of side of a square is 21 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"7_In_a_right_triangle_ABC_B\"><\/span><strong>7. In a right triangle ABC, <\/strong><strong><img decoding=\"async\" style=\"height: 16px; width: 17px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image058.png\" \/>B = <img decoding=\"async\" style=\"height: 21px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image059.png\" \/><\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" id=\"Picture 4\" style=\"height: 117px; width: 136px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image060.jpg\" \/><\/p>\n<p><strong>(i) If AB = 6 cm, BC = 8 cm, find AC.<\/strong><\/p>\n<p><strong>(ii) If AC = 13 cm, BC = 5 cm, find AB.<\/strong><\/p>\n<p><strong>Ans. <\/strong>(a) Using Pythagoras theorem,<\/p>\n<p><img decoding=\"async\" style=\"height: 21px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image061.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/><img decoding=\"async\" style=\"height: 29px; width: 131px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image062.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/><img decoding=\"async\" style=\"height: 21px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image063.png\" \/>= 36 + 84 = 100<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>AC = 10 cm<\/p>\n<p>(b) Using Pythagoras theorem,<\/p>\n<p><img decoding=\"async\" style=\"height: 21px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image061.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 29px; width: 131px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image064.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 21px; width: 115px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image065.png\" \/><\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 20px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image066.png\" \/>\u00a0= 169 \u2013 25<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0<img decoding=\"async\" style=\"height: 20px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image066.png\" \/>\u00a0= 144<\/p>\n<p><img decoding=\"async\" style=\"height: 16px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image054.png\" \/>\u00a0AB= 12 cm<\/p>\n<p><img decoding=\"async\" id=\"Picture 7\" style=\"height: 127px; width: 154px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image067.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"8_A_gardener_has_1000_plants_He_wants_to_plant_these_in_such_a_way_that_the_number_of_rows_and_number_of_columns_remain_same_Find_the_minimum_number_of_plants_he_needs_more_for_this\"><\/span><strong>8. A gardener has 1000 plants. He wants to plant these in such a way that the number of rows and number of columns remain same. Find the minimum number of plants he needs more for this.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. <\/strong>Here, plants = 1000<\/p>\n<p>Since remainder is 39.<\/p>\n<p>Therefore <img decoding=\"async\" style=\"height: 21px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image068.png\" \/><\/p>\n<p>Next perfect square number <img decoding=\"async\" style=\"height: 21px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image069.png\" \/>\u00a0= 1024<\/p>\n<p>Hence, number to be added<\/p>\n<p>= 1024 \u2013 1000 = 24<\/p>\n<p><img decoding=\"async\" style=\"height: 13px; width: 15px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image024.png\" \/>\u00a01000 + 24 = 1024<\/p>\n<p>Hence, the gardener required 24 more plants.<\/p>\n<p><img decoding=\"async\" id=\"Picture 417\" style=\"height: 142px; width: 120px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image070.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 8 Maths Exercise 6.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"9_There_are_500_children_in_a_school_For_a_PT_drill_they_have_to_stand_in_such_a_manner_that_the_number_of_rows_is_equal_to_number_of_columns_How_many_children_would_be_left_out_in_this_arrangement\"><\/span><strong>9. There are 500 children in a school. For a P.T. drill they have to stand in such a manner that the number of rows is equal to number of columns. How many children would be left out in this arrangement?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Ans. <\/strong>Here, Number of children = 500<\/p>\n<p>By getting the square root of this number, we get,<\/p>\n<p>In each row, the number of children is 22.<\/p>\n<p>And left out children are 16.<\/p>\n<p><img decoding=\"async\" id=\"Picture 424\" style=\"height: 138px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/08\/maths\/6_4\/image071.jpg\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_8_Maths_Exercise_64\"><\/span>NCERT Solutions for Class 8 Maths Exercise 6.4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 8\u00a0Mathematics PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 8\u00a0Mathematics includes text book solutions from Class 8 Maths Book . NCERT Solutions for CBSE Class 8 Maths have total 16 chapters. 8 Maths NCERT Solutions in PDF for free Download on our website. Ncert class 8 solutions PDF and Maths ncert class 8 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_8\"><\/span>CBSE app for Class 8<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 8 Social Science, Computer Science, Home Science,Hindi ,English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 8 Maths Exercise 6.4 Class 8 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 8 &#8230; <a title=\"NCERT Solutions for Class 8 Maths Exercise 6.4\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-maths-exercise-6-4\/\" aria-label=\"More on NCERT Solutions for Class 8 Maths Exercise 6.4\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1382,281],"tags":[283,1523,321,1485,216],"class_list":["post-4700","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-08","category-ncert-solutions","tag-cbse-study-material","tag-class-8","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 8 Maths Exercise 6.4 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 8 Maths Exercise 6.4 in PDF format for free download. 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