{"id":4659,"date":"2016-05-17T11:49:00","date_gmt":"2016-05-17T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-4\/"},"modified":"2018-10-25T17:36:36","modified_gmt":"2018-10-25T12:06:36","slug":"ncert-solutions-class-11-chemistry-equilibrium-part-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/","title":{"rendered":"NCERT Solutions for Class 11 Chemistry Equilibrium Part-1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/#NCERT_Class_11_Chemistry_Chapter_wise_Solutions\" >NCERT Class 11 Chemistry Chapter wise Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/#NCERT_Solutions_for_Class_11_Chemistry_Equilibrium_Part-1\" >NCERT Solutions for Class 11 Chemistry Equilibrium Part-1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/#NCERT_Solutions_for_Class_11_Chemistry_Chapter_7_Equilibrium\" >NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/#NCERT_Solutions_for_Science_Class_3rd_to_12th\" >NCERT Solutions for Science Class 3rd to 12th<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 11 Chemistry Equilibrium Part-1\u00a0solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Chemistry chapter wise Solutions for Class 11\u00a0 and all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 11 Chemistry\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-11-chemistry\/1356\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"alignright\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/11_Chemistry_Book.jpg\" alt=\"NCERT Solutions for Class 11 Chemistry Equilibrium Part-1\" width=\"100\" height=\"142\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Class_11_Chemistry_Chapter_wise_Solutions\"><\/span><span class=\"underline-text\">NCERT Class 11 Chemistry Chapter wise Solutions<\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li>1 \u2013 Some Basic Concepts of Chemistry<\/li>\n<li>2 \u2013 Structure of Atom<\/li>\n<li>3 \u2013 Classification of Elements and Periodicity in Properties<\/li>\n<li>4 \u2013 Chemical Bonding and Molecular Structure<\/li>\n<li>5 \u2013 States of Matter<\/li>\n<li>6 \u2013 Thermodynamics<\/li>\n<li>7 \u2013 Equilibrium<\/li>\n<li>8 \u2013 Redox Reactions<\/li>\n<li>9 \u2013 Hydrogen<\/li>\n<li>10 \u2013 The s-Block Elements<\/li>\n<li>11 \u2013 The p-Block Elements<\/li>\n<li>12 \u2013 Organic Chemistry \u2013 Some Basic Principles and Techniques<\/li>\n<li>13 \u2013\u00a0Hydrocarbons<\/li>\n<li>14 \u2013\u00a0Environmental Chemistry<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_11_Chemistry_Equilibrium_Part-1\"><\/span>NCERT Solutions for Class 11 Chemistry Equilibrium Part-1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>1. A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.<\/p>\n<p>a) What is the initial effect of the change on vapour pressure?<\/p>\n<p>b) How do rates of evaporation and condensation change initially?<\/p>\n<p>c) What happens when equilibrium is restored finally and what will be the final vapour pressure?<\/p>\n<p>2. What is <img decoding=\"async\" style=\"height: 24px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image001.png\" \/> for the following equilibrium when the equilibrium concentration of each substance is: [<img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image002.png\" \/> ]= 0.60 M, [<img decoding=\"async\" style=\"height: 24px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image003.png\" \/> ] = 0.82 M and [<img decoding=\"async\" style=\"height: 24px; width: 32px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image004.png\" \/> ] = 1.90 M ? <img decoding=\"async\" style=\"height: 24px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image005.png\" \/><br \/>\n3. At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms <img decoding=\"async\" style=\"height: 24px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image008.png\" \/>Calculate<img decoding=\"async\" style=\"height: 25px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image009.png\" \/> for the equilibrium.<\/p>\n<p>4. Write the expression for the equilibrium constant, <em>Kc<\/em> for each of the following reactions:<\/p>\n<p><img decoding=\"async\" style=\"height: 123px; width: 442px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image014.png\" \/><br \/>\n5. Find out the value of <em>Kc<\/em> for each of the following equilibria from the value of <em>Kp<\/em>:<\/p>\n<p><img decoding=\"async\" style=\"height: 53px; width: 391px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image016.png\" \/><\/p>\n<p>6. For the following equilibrium, <img decoding=\"async\" style=\"height: 25px; width: 93px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image026.png\" \/> <img decoding=\"async\" style=\"height: 25px; width: 221px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image027.png\" \/><\/p>\n<p>Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is<img decoding=\"async\" style=\"height: 24px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image001.png\" \/> , for the reverse reaction?<\/p>\n<p>7. Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression?<\/p>\n<p>8. Reaction between <img decoding=\"async\" style=\"height: 24px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image030.png\" \/> takes place as follows: <img decoding=\"async\" style=\"height: 24px; width: 188px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image031.png\" \/><\/p>\n<p>If a mixture of 0.482 mol of <img decoding=\"async\" style=\"height: 24px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image032.png\" \/> and 0.933 mol of <img decoding=\"async\" style=\"height: 24px; width: 20px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image033.png\" \/> is placed in a 10 L reaction vessel and allowed to form <img decoding=\"async\" style=\"height: 24px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image034.png\" \/> at a temperature for which<img decoding=\"async\" style=\"height: 25px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image035.png\" \/> , determine the composition of equilibrium mixture.<\/p>\n<p>9. Nitric oxide reacts with <img decoding=\"async\" style=\"height: 24px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image045.png\" \/> and gives nitrosyl bromide as per reaction given below:<\/p>\n<p><img decoding=\"async\" style=\"height: 24px; width: 208px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image046.png\" \/><\/p>\n<p>When 0.087 mol of NO and 0.0437 mol of <img decoding=\"async\" style=\"height: 24px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image045.png\" \/> are mixed in a closed container at constant temperature, 0.0518 mol of NO Br is obtained at equilibrium. Calculate equilibrium amount of NO and <img decoding=\"async\" style=\"height: 24px; width: 27px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image045.png\" \/>.<\/p>\n<p>10. At 450 K, <img decoding=\"async\" style=\"height: 27px; width: 124px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image050.png\" \/> bar for the given reaction at equilibrium.<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 167px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image051.png\" \/><\/p>\n<p>What is <img decoding=\"async\" style=\"height: 24px; width: 23px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image001.png\" \/> at this temperature?<\/p>\n<p>11. A sample of <img decoding=\"async\" style=\"height: 27px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image057.png\" \/> is placed in flask at a pressure of 0.2 atm. At equilibrium the partial pressure of HI(g) is 0.04 atm. What is <img decoding=\"async\" style=\"height: 25px; width: 24px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image058.png\" \/> for the given equilibrium?<\/p>\n<p><img decoding=\"async\" style=\"height: 24px; width: 165px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image059.png\" \/><\/p>\n<p>12. A mixture of 1.57 mol of<img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image063.png\" \/> , 1.92 mol of <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image064.png\" \/> and 8.13 mol of <img decoding=\"async\" style=\"height: 25px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image065.png\" \/> is introduced into a 20 L reaction vessel at 500 K. At this temperature, the equilibrium constant, <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image066.png\" \/> for the reaction <img decoding=\"async\" style=\"height: 25px; width: 257px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image067.png\" \/><\/p>\n<p>Is the reaction mixture at equilibrium? If not, what is the direction of the net reaction?<\/p>\n<p>13. The equilibrium constant expression for a gas reaction is,<\/p>\n<p><img decoding=\"async\" style=\"height: 58px; width: 134px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image074.png\" \/><\/p>\n<p>Write the balanced chemical equation corresponding to this expression.<\/p>\n<p>14. One mole of <img decoding=\"async\" style=\"height: 25px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image076.png\" \/> and one mole of CO are taken in 10 L vessel and heated to<\/p>\n<p>725 K. At equilibrium 40% of water (by mass) reacts with CO according to the equation,<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 243px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image077.png\" \/><\/p>\n<p>Calculate the equilibrium constant for the reaction.<\/p>\n<p>15. At 700 K, equilibrium constant for the reaction<\/p>\n<p><img decoding=\"async\" style=\"height: 35px; width: 176px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image081.png\" \/> is 54.8. If 0.5 <img decoding=\"async\" style=\"height: 21px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image082.png\" \/> of <img decoding=\"async\" style=\"height: 25px; width: 38px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image083.png\" \/> is present at equilibrium at 700 K, what are the concentration of <img decoding=\"async\" style=\"height: 25px; width: 112px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image084.png\" \/> assuming that we initially started with <img decoding=\"async\" style=\"height: 25px; width: 38px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image083.png\" \/> and allowed it to reach equilibrium at 700 K?<\/p>\n<p>16. What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICl was 0.78 M?<\/p>\n<p><img decoding=\"async\" style=\"height: 27px; width: 259px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image095.png\" \/><\/p>\n<p>17. <img decoding=\"async\" style=\"height: 25px; width: 25px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image100.png\" \/> = 0.04 atm at 899 K for the equilibrium shown below. What is the equilibrium concentration of <img decoding=\"async\" style=\"height: 25px; width: 40px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image101.png\" \/> when it is placed in a flask at 4.0 atm pressure and allowed to come to equilibrium?<\/p>\n<p><img decoding=\"async\" style=\"height: 30px; width: 196px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image102.png\" \/><\/p>\n<p>18. Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as:<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 382px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image106.png\" \/><\/p>\n<p>(i) Write the concentration ratio (reaction quotient), <img decoding=\"async\" style=\"height: 25px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image107.png\" \/> , for this reaction (note: water is not in excess and is not a solvent in this reaction)<\/p>\n<p>(ii) At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. Calculate the equilibrium constant.<\/p>\n<p>(iii) Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime. Has equilibrium been reached?<\/p>\n<p>19. A sample of pure <img decoding=\"async\" style=\"height: 25px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image115.png\" \/> was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of <img decoding=\"async\" style=\"height: 25px; width: 36px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image115.png\" \/> was found to be<img decoding=\"async\" style=\"height: 21px; width: 130px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image116.png\" \/> . If value of <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image066.png\" \/> is 8.3 \u00d7<img decoding=\"async\" style=\"height: 21px; width: 31px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image117.png\" \/> , what are the concentrations of <img decoding=\"async\" style=\"height: 25px; width: 94px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image118.png\" \/> at equilibrium?<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image119.png\" \/><\/p>\n<p>20. One of the reactions that takes place in producing steel from iron ore is the reduction of iron (II) oxide by carbon monoxide to give iron metal and<img decoding=\"async\" style=\"height: 25px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image125.png\" \/> .<\/p>\n<p>FeO (s) + CO (g) <img decoding=\"async\" style=\"height: 15px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image126.png\" \/> Fe (s) + <img decoding=\"async\" style=\"height: 25px; width: 30px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image127.png\" \/> (g); <em>Kp<\/em>= 0.265 at 1050 K.<\/p>\n<p>What are the equilibrium partial pressures of CO and <img decoding=\"async\" style=\"height: 25px; width: 30px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image127.png\" \/> at 1050 K if the initial partial pressures are: <img decoding=\"async\" style=\"height: 25px; width: 28px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image128.png\" \/> = 1.4 atm and <img decoding=\"async\" style=\"height: 25px; width: 33px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image129.png\" \/> = 0.80 atm?<\/p>\n<p>21. Equilibrium constant, <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image066.png\" \/> for the reaction<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image139.png\" \/> at 500 K is 0.061.<\/p>\n<p>At a particular time, the analysis shows that composition of the reaction mixture is 3.0 <img decoding=\"async\" style=\"height: 21px; width: 55px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image140.png\" \/><img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image063.png\" \/> , 2.0 <img decoding=\"async\" style=\"height: 25px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image141.png\" \/> and 0.5 mol<img decoding=\"async\" style=\"height: 25px; width: 60px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image142.png\" \/> . Is the reaction at equilibrium? If not in which direction does the reaction tend to proceed to reach equilibrium?<\/p>\n<p>22. Bromine monochloride, BrCl decomposes into bromine and chlorine and reaches the equilibrium:<\/p>\n<p><img decoding=\"async\" style=\"height: 25px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image145.png\" \/> for which <em>Kc<\/em>= 32 at 500 K. If initially pure BrCl is present at a concentration of <img decoding=\"async\" style=\"height: 21px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image146.png\" \/> <img decoding=\"async\" style=\"height: 21px; width: 49px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image082.png\" \/> , what is its molar concentration in the mixture at equilibrium?<\/p>\n<p>23. At 1127 K and 1 atm pressure, a gaseous mixture of CO and <img decoding=\"async\" style=\"height: 25px; width: 30px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image127.png\" \/> in equilibrium with solid carbon has 90.55% CO by mass <img decoding=\"async\" style=\"height: 25px; width: 174px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image151.png\" \/>. Calculate <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image066.png\" \/> for this reaction at the above temperature.<\/p>\n<p>24. Calculate a) \u0394<em>G<\/em>\u00b0and b) the equilibrium constant for the formation of <img decoding=\"async\" style=\"height: 25px; width: 35px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image160.png\" \/> from NO and <img decoding=\"async\" style=\"height: 25px; width: 22px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image161.png\" \/> at 298 K <img decoding=\"async\" style=\"height: 31px; width: 181px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image162.png\" \/> Where <img decoding=\"async\" style=\"height: 27px; width: 89px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image163.png\" \/> = 52.0 kJ\/mol<\/p>\n<p><img decoding=\"async\" style=\"height: 27px; width: 83px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image164.png\" \/> = 87.0 kJ\/mol<\/p>\n<p><img decoding=\"async\" style=\"height: 27px; width: 78px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image165.png\" \/> = 0 kJ\/mol<\/p>\n<p>25. Does the number of moles of reaction products increase, decrease or remain same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?<\/p>\n<p>(a) <img decoding=\"async\" style=\"height: 25px; width: 190px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image119.png\" \/><\/p>\n<p>(b) <img decoding=\"async\" style=\"height: 25px; width: 205px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image170.png\" \/><\/p>\n<p>(c) <img decoding=\"async\" style=\"height: 25px; width: 267px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/chemistry\/ch07\/image171.png\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_11_Chemistry_Chapter_7_Equilibrium\"><\/span>NCERT Solutions for Class 11 Chemistry Chapter 7 Equilibrium<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>NCERT Solutions for Class 11 Chemistry Equilibrium Part-1 PDF (Download) Free<\/strong>\u00a0from myCBSEguide app and myCBSEguide website. Ncert solution class 11 Chemistry includes text book solutions from both part 1 and part 2. NCERT Solutions for CBSE Class 11 Chemistry have total 14 chapters. 11 Chemistry NCERT Solutions in PDF for free Download on our website. Ncert Chemistry class 11 solutions PDF and Chemistry ncert class 11 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Science_Class_3rd_to_12th\"><\/span>NCERT Solutions for Science Class 3rd to 12th<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-12-physics\/\">Physics NCERT Solutions for Class 12<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-12-chemistry\/\">Chemistry NCERT Solutions for Class 12<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-12-biology\/\">Biology NCERT Solutions for Class 12<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-11-physics\/\">Physics NCERT solutions for Class 11<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-11-chemistry\/\">Chemistry NCERT Solutions for Class 11<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-11-biology\/\">Biology NCERT solutions for Class 11<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science\/\">Science NCERT Solutions for Class 10<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science\/\">NCERT Solutions for Class 9 Science<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-science\/\">Science NCERT solutions for Class 8<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-science\/\">NCERT solutions for Class 7 Science<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-6-science\/\">Science NCERT Solutions for Class 6<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-5-evs\/\">EVS NCERT Solutions for Class 5<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-4-evs\/\">NCERT Solutions for Class 4 EVS<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-3-evs\/\">EVS NCERT Solutions for Class 3<\/a><\/li>\n<\/ul>\n<p>To download\u00a0NCERT Solutions for class 11 Chemistry, Physics, Biology, History, Political Science, Economics, Geography, Computer Science, Home Science, Accountancy, Business Studies and Home Science; do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and\u00a0<strong>myCBSEguide.com<\/strong>\u00a0website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 11 Chemistry Equilibrium Part-1\u00a0solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Chemistry chapter wise Solutions for Class &#8230; <a title=\"NCERT Solutions for Class 11 Chemistry Equilibrium Part-1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-chemistry-equilibrium-part-1\/\" aria-label=\"More on NCERT Solutions for Class 11 Chemistry Equilibrium Part-1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[47,281],"tags":[283,320,1449,216],"class_list":["post-4659","post","type-post","status-publish","format-standard","hentry","category-cbse-class-11","category-ncert-solutions","tag-cbse-study-material","tag-chemistry","tag-class-11","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 11 Chemistry Equilibrium Part-1<\/title>\n<meta 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