{"id":4635,"date":"2016-05-17T11:49:00","date_gmt":"2016-05-17T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-15-1\/"},"modified":"2016-05-17T13:37:26","modified_gmt":"2016-05-17T08:07:26","slug":"ncert-solutions-class-11-maths-exercise-15-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-15-1\/","title":{"rendered":"NCERT Solutions class-11 Maths Exercise 15.1"},"content":{"rendered":"

Exercise 15.1<\/strong><\/p>\n

Find the mean deviation about the mean for the data in Exercises 1 and 2.<\/strong><\/p>\n

1. 4, 7, 8, 9, 10, 12, 13, 17<\/strong><\/p>\n

Ans. <\/strong>Mean of the given data <\/p>\n

<\/p>\n

Mean deviation about mean = = = 3<\/p>\n

\n

2. 38, 70, 48, 40, 42, 55, 63, 46, 54, 44<\/strong><\/p>\n

Ans. <\/strong>Mean of the given data <\/p>\n

<\/p>\n

Mean deviation about mean = <\/p>\n

= = 8.4<\/p>\n

\n

Find the mean deviation about the median for the data in Exercises 3 and 4.<\/strong><\/p>\n

3. 13, 17, 16, 14, 11, 13, 10, 16, 11, 18, 12, 17<\/strong><\/p>\n

Ans. <\/strong>Arranging the data in ascending order, 10, 11, 12, 13, 13, 14, 16, 11, 18, 12, 17<\/p>\n

Here, (even number)<\/p>\n

Mean = <\/p>\n

= = 13.5<\/p>\n

<\/p>\n

Mean deviation about median = <\/p>\n

= = 2.33<\/p>\n

\n

4. 36, 72, 46, 42, 60, 45, 53, 46, 51, 49<\/strong><\/p>\n

Ans. <\/strong>Arranging the data in ascending order, 36, 42, 45, 46, 46, 49, 51, 53, 60, 72<\/p>\n

Here, (even number)<\/p>\n

Mean = = = 47.5<\/p>\n

<\/p>\n

Mean deviation about median = <\/p>\n

= = 7<\/p>\n

\n

Find the mean deviation about the mean for the data in Exercises 5 and 6.<\/strong><\/p>\n

5. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Mean <\/p>\n

= = 14<\/p>\n

Mean deviation about mean = <\/p>\n

= = 6.32<\/p>\n

\n

6. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Mean <\/p>\n

= = 50<\/p>\n

Mean deviation about mean = <\/p>\n

= = 16<\/p>\n

\n

Find the mean deviation about the median for the data in Exercises 7 and 8.<\/strong><\/p>\n

7. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Here, = 13 and = 7<\/p>\n

Median = 7<\/p>\n

Mean deviation about median = <\/p>\n

= = 3.23<\/p>\n

\n

8. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Here, = 14.5 and = 21<\/p>\n

Median = 30<\/p>\n

Mean deviation about median = <\/p>\n

= = 5.1<\/p>\n

\n

Find the mean deviation about the mean for the data in Exercises 9 and 10.<\/strong><\/p>\n

9. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Mean <\/p>\n

= = 358<\/p>\n

Mean deviation about mean = <\/p>\n

= = 157.92<\/p>\n

\n

10. <\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Mean <\/p>\n

= = 125.3<\/p>\n

Mean deviation about mean = <\/p>\n

= = 11.28<\/p>\n

\n

11. Find the mean deviation about median for the following data:<\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Here, = 25<\/p>\n

Median class = 20 \u2013 30<\/p>\n

Median = <\/p>\n

= 20 + 7.86 = 27.86<\/p>\n

Mean deviation about median = <\/p>\n

= = 10.37<\/p>\n

\n

12. Calculate the mean deviation about median age for the age distribution of 100 persons given below:<\/strong><\/p>\n

<\/p>\n

Ans. <\/strong><\/p>\n

<\/p>\n

Here, = 50<\/p>\n

Median class = 35.5 \u2013 40.5<\/p>\n

Median = <\/p>\n

= 35.5 + 2.5 = 38<\/p>\n

Mean deviation about median = <\/p>\n

= = 7.35<\/p>\n","protected":false},"excerpt":{"rendered":"

Exercise 15.1 Find the mean deviation about the mean for the data in Exercises 1 and 2. 1. 4, 7, 8, 9, 10, 12, 13, 17 Ans. Mean of the given data Mean deviation about mean = = = 3 2. 38, 70, 48, 40, 42, 55, 63, 46, 54, 44 Ans. Mean of the … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[47,281],"tags":[],"class_list":["post-4635","post","type-post","status-publish","format-standard","hentry","category-cbse-class-11","category-ncert-solutions"],"yoast_head":"\nNCERT Solutions class-11 Maths Exercise 15.1 | myCBSEguide<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-15-1\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions class-11 Maths Exercise 15.1 | myCBSEguide\" \/>\n<meta property=\"og:description\" content=\"Exercise 15.1 Find the mean deviation about the mean for the data in Exercises 1 and 2. 1. 4, 7, 8, 9, 10, 12, 13, 17 Ans. Mean of the given data Mean deviation about mean = = = 3 2. 38, 70, 48, 40, 42, 55, 63, 46, 54, 44 Ans. Mean of the ... Read more\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-15-1\/\" \/>\n<meta property=\"og:site_name\" content=\"myCBSEguide\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/mycbseguide\/\" \/>\n<meta property=\"article:published_time\" content=\"2016-05-17T06:19:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2016-05-17T08:07:26+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/maths\/ch15\/Ex15.1\/image001.png\" \/>\n<meta name=\"author\" content=\"myCBSEguide\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:site\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"myCBSEguide\" \/>\n\t<meta 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