{"id":4591,"date":"2016-05-17T09:49:00","date_gmt":"2016-05-17T04:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-5-2\/"},"modified":"2016-05-17T10:46:37","modified_gmt":"2016-05-17T05:16:37","slug":"ncert-solutions-class-11-maths-exercise-5-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-5-2\/","title":{"rendered":"NCERT Solutions class-11 Maths Exercise 5.2"},"content":{"rendered":"

Exercise 5.2<\/strong><\/p>\n

Find the modulus and the argument of each of the complex numbers in exercises 1 to 2.<\/strong><\/p>\n

1. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in third quadrant]\n

<\/p>\n

Therefore, and arg<\/p>\n

\n

2. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in second quadrant]\n

<\/p>\n

Therefore, and arg<\/p>\n

\n

Convert each of the complex numbers given in Exercises 3 to 8 in the polar form.<\/strong><\/p>\n

3. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in fourth quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n

\n

4. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in second quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n

\n

5. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in third quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n

\n

6. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in second quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n

\n

7. <\/strong><\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in first quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n

\n

8.<\/strong> <\/p>\n

Ans. <\/strong>Given: <\/p>\n

and <\/p>\n

Squaring both sides and adding both the equations, we get<\/p>\n

<\/p>\n

<\/p>\n

and <\/p>\n

and <\/p>\n

[ lies in first quadrant]\n

<\/p>\n

Therefore, Polar form of is <\/p>\n","protected":false},"excerpt":{"rendered":"

Exercise 5.2 Find the modulus and the argument of each of the complex numbers in exercises 1 to 2. 1. Ans. Given: and Squaring both sides and adding both the equations, we get and and [ lies in third quadrant] Therefore, and arg 2. Ans. Given: and Squaring both sides and adding both the equations, … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[47,281],"tags":[],"class_list":["post-4591","post","type-post","status-publish","format-standard","hentry","category-cbse-class-11","category-ncert-solutions"],"yoast_head":"\nNCERT Solutions class-11 Maths Exercise 5.2 | myCBSEguide<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-5-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions class-11 Maths Exercise 5.2 | myCBSEguide\" \/>\n<meta property=\"og:description\" content=\"Exercise 5.2 Find the modulus and the argument of each of the complex numbers in exercises 1 to 2. 1. Ans. Given: and Squaring both sides and adding both the equations, we get and and [ lies in third quadrant] Therefore, and arg 2. Ans. Given: and Squaring both sides and adding both the equations, ... Read more\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-11-maths-exercise-5-2\/\" \/>\n<meta property=\"og:site_name\" content=\"myCBSEguide\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/mycbseguide\/\" \/>\n<meta property=\"article:published_time\" content=\"2016-05-17T04:19:00+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2016-05-17T05:16:37+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/11\/maths\/ch05\/Ex5.2\/image001.png\" \/>\n<meta name=\"author\" content=\"myCBSEguide\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:site\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"myCBSEguide\" \/>\n\t<meta name=\"twitter:label2\" 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