{"id":4468,"date":"2016-05-16T11:49:00","date_gmt":"2016-05-16T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-12-maths-miscellaneous-2\/"},"modified":"2018-05-07T17:56:47","modified_gmt":"2018-05-07T12:26:47","slug":"ncert-solutions-class-12-maths-miscellaneous-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-12-maths-miscellaneous-2\/","title":{"rendered":"NCERT Solutions class 12 Maths Miscellaneous"},"content":{"rendered":"

NCERT Solutions class 12 Maths Miscellaneous Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n

Download\u00a0NCERT solutions for\u00a0Inverse Trigonometric Function\u00a0<\/a>as PDF.<\/strong><\/p>\n

\"NCERT<\/p>\n

NCERT Solutions class 12 Maths Inverse Trigonometric Function<\/h2>\n

Find the value of the following:<\/strong><\/p>\n

1. \u00a0<\/strong><\/p>\n

Ans. <\/strong><\/p>\n

\u00a0= <\/p>\n

= <\/p>\n

= <\/p>\n

= \u00a0i.e., , value of \u00a0lies in I quadrant.<\/p>\n

= \u00a0= <\/p>\n

\n

2. \u00a0<\/strong><\/p>\n

Ans. <\/strong><\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= \u00a0i.e., , value of \u00a0lies in I quadrant.<\/p>\n

= \u00a0= <\/p>\n

\n

3. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let \u00a0 so that <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

Since <\/p>\n

= \u00a0= \u00a0= <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

4. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let \u00a0so that <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

Again, Let \u00a0so that <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

Since <\/p>\n

= <\/p>\n

= <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

5. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let so that <\/p>\n

\u00a0<\/p>\n

Again, Let \u00a0so that <\/p>\n

<\/p>\n

Since \u00a0= <\/p>\n

= <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

6. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let \u00a0so that <\/p>\n

<\/p>\n

Again, Let \u00a0so that <\/p>\n

\u00a0<\/p>\n

Since \u00a0= <\/p>\n

= <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

7. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let \u00a0so that <\/p>\n

<\/p>\n

\u00a0<\/p>\n

Again, Let \u00a0so that <\/p>\n

<\/p>\n

<\/p>\n

Since \u00a0= <\/p>\n

= <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

8. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>L.H.S. = <\/p>\n

= <\/p>\n

<\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

R.H.S.<\/p>\n

\n

9. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Let \u00a0so that <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

\n

10. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>We know that\u00a0 \u00a0= <\/p>\n

Again,\u00a0 <\/p>\n

= <\/p>\n

L.H.S. = <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

\n

11. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Putting \u00a0so that <\/p>\n

L.H.S. = <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

Dividing every term by <\/p>\n

= <\/p>\n

= <\/p>\n

= \u00a0= <\/p>\n

= \u00a0= R.H.S.<\/p>\n

\n

12. Prove that: \u00a0<\/strong><\/p>\n

Ans. <\/strong>L.H.S. = <\/p>\n

= <\/p>\n

= \u00a0\u2026(i) <\/p>\n

Now, let \u00a0so that <\/p>\n

<\/p>\n

From eq. (i), \u00a0= R.H.S.<\/p>\n

\n

13. Solve the equation: \u00a0<\/strong><\/p>\n

Ans. <\/strong><\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\n

14. Solve the equation: \u00a0<\/strong><\/p>\n

Ans. <\/strong>Putting <\/p>\n

<\/p>\n

\u00a0<\/p>\n

<\/p>\n

<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

<\/p>\n

\n

15. \u00a0is equal to:<\/strong><\/p>\n

(A) \u00a0<\/strong><\/p>\n

(B) \u00a0<\/strong><\/p>\n

(C) \u00a0<\/strong><\/p>\n

(D) <\/strong><\/p>\n

Ans. <\/strong>Let \u00a0where \u00a0so that <\/p>\n

\u00a0<\/p>\n

Putting <\/p>\n

\u00a0<\/p>\n

Therefore, option (D) is correct.<\/p>\n

\n

16. \u00a0then \u00a0is equal to:<\/strong><\/p>\n

(A) <\/strong><\/p>\n

(B) \u00a0<\/strong><\/p>\n

(C) 0 <\/strong><\/p>\n

(D) \u00a0<\/strong><\/p>\n

Ans. <\/strong>Putting \u00a0so that <\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

\u00a0<\/p>\n

<\/p>\n

\u00a0<\/p>\n

\u00a0\u00a0<\/p>\n

\u00a0<\/p>\n

<\/p>\n

\u00a0<\/p>\n

\u00a0\u00a0or <\/p>\n

\u00a0\u00a0or <\/p>\n

But \u00a0does not satisfy the given equation.<\/p>\n

Therefore, option (C) is correct.<\/p>\n

\n

NCERT Solutions class 12 Maths Miscellaneous<\/strong><\/p>\n

17. \u00a0is equal to:<\/strong><\/p>\n

(A) <\/strong><\/p>\n

(B) <\/strong><\/p>\n

(C) <\/strong><\/p>\n

(D) \u00a0<\/strong><\/p>\n

Ans. <\/strong><\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

= <\/p>\n

Therefore, option (C) is correct.<\/p>\n

NCERT Solutions class 12 Maths Miscellaneous<\/h2>\n

NCERT Solutions Class 12 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 12 Maths includes text book solutions from both part 1 and part 2. NCERT Solutions for CBSE Class 12 Maths have total 13 chapters. 12 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 12 solutions PDF and Maths ncert class 12 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide<\/p>\n

CBSE App for Students<\/h2>\n

To download\u00a0NCERT Solutions for class 12 Physics, Chemistry, Biology, History, Political Science, Economics, Geography, Computer Science, Home Science, Accountancy, Business Studies and Home Science; do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions class 12 Maths Miscellaneous Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1432,281],"tags":[283,1342,321,216],"class_list":["post-4468","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-12","category-ncert-solutions","tag-cbse-study-material","tag-class-12","tag-mathematics","tag-ncert-solutions"],"yoast_head":"\nNCERT Solutions class 12 Maths Miscellaneous | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions class 12 Maths Miscellaneous in PDF format for free download. 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