{"id":4327,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-algebraic-expressions-ex-12-2\/"},"modified":"2018-07-09T10:17:20","modified_gmt":"2018-07-09T04:47:20","slug":"ncert-solutions-for-class-7-maths-exercise-12-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 12.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#NCERT_Solutions_for_Class_7_Maths_Algebraic_Expressions\" >NCERT Solutions for Class 7 Maths\u00a0Algebraic Expressions<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Class_%E2%80%93VII_Mathematics_Ex_122\" >Class \u2013VII Mathematics (Ex. 12.2)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_1Simplify_combining_like_terms\" >Question 1.Simplify combining like terms:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_2Add\" >Question 2.Add:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#v_tex14x_10y_%E2%80%93_12xy_%E2%80%93_1318_%E2%80%93_7x_%E2%80%93_10y_8xy4xy_14x_10y_%E2%80%93_12xy_%E2%80%93_13_18_%E2%80%93_7x_%E2%80%93_10y_8xy_4xytex\" >(v) {tex}14x + 10y &#8211; 12xy &#8211; 13,18 &#8211; 7x &#8211; 10y + 8xy,4xy = 14x + 10y &#8211; 12xy &#8211; 13 + 18 &#8211; 7x &#8211; 10y + 8xy + 4xy{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_3Subtract\" >Question 3.Subtract:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_4a_What_should_be_added_to_texx2_xy_y2tex_to_obtain_tex2x2_3xytex\" >Question 4.(a) What should be added to {tex}{x^2} + xy + {y^2}{\/tex} to obtain {tex}2{x^2} + 3xy?{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_5What_should_be_taken_away_from_tex3x2_%E2%80%93_4y2_5xy_20tex_to_obtain_tex_%E2%80%93_x2_%E2%80%93_y2_6xy_20tex\" >Question 5.What should be taken away from {tex}3{x^2} &#8211; 4{y^2} + 5xy + 20{\/tex} to obtain {tex} &#8211; {x^2} &#8211; {y^2} + 6xy + 20{\/tex} ?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#Question_6a_From_the_sum_of_tex3x_%E2%80%93_y_11tex_and_tex_%E2%80%93_y_%E2%80%93_11tex_subtract_the_sum_of_tex3x2_%E2%80%93_5xtex_and_tex_%E2%80%93_x2_2x_5tex\" >Question 6.(a) From the sum of {tex}3x &#8211; y + 11{\/tex} and {tex} &#8211; y &#8211; 11,{\/tex} subtract the sum of {tex}3{x^2} &#8211; 5x{\/tex} and {tex} &#8211; {x^2} + 2x + 5.{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#b_According_to_question\" >(b) According to question,<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#NCERT_Solutions_for_Class_7_Maths_Exercise_122\" >NCERT Solutions for Class 7 Maths Exercise 12.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-12-2\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 12.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Algebraic Expressions\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-algebraic-expressions\/1521\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 12.2\" width=\"164\" height=\"208\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Algebraic_Expressions\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Algebraic Expressions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VII_Mathematics_Ex_122\"><\/span><strong>Class \u2013VII Mathematics (Ex. 12.2)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Simplify_combining_like_terms\"><\/span><strong>Question 1.<\/strong>Simplify combining like terms:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>{tex}21b &#8211; 32 + 7b &#8211; 20b{\/tex}<\/li>\n<li>{tex} &#8211; {z^2} + 13{z^2} &#8211; 5x + 7{z^3} &#8211; 15z{\/tex}<\/li>\n<li>{tex}p &#8211; \\left( {p &#8211; q} \\right) &#8211; q &#8211; \\left( {q &#8211; p} \\right){\/tex}<\/li>\n<li>{tex}3a &#8211; 2b &#8211; ab &#8211; \\left( {a &#8211; b + ab} \\right) + 3ab + b &#8211; a{\/tex}<\/li>\n<li>{tex}5{x^2}y &#8211; 5{x^2} + 3y{x^2} &#8211; 3{y^2} + {x^2} &#8211; {y^2} + 8x{y^2} &#8211; 3{y^2}{\/tex}<\/li>\n<li>{tex}\\left( {3{y^2} + 5y &#8211; 4} \\right) &#8211; \\left( {8y &#8211; {y^2} &#8211; 4} \\right){\/tex}<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}21b &#8211; 32 + 7b &#8211; 20b = 21b + 7b &#8211; 20b &#8211; 32{\/tex}<\/p>\n<p>= {tex}28b &#8211; 20b &#8211; 32{\/tex} = {tex}8b &#8211; 32{\/tex}<\/p>\n<p>(ii) {tex} &#8211; {z^2} + 13{z^2} &#8211; 5z + 7{z^3} &#8211; 15z = 7{z^3} + \\left( { &#8211; {z^2} + 13{z^2}} \\right) &#8211; \\left( {5z + 15z} \\right){\/tex}<\/p>\n<p>= {tex}7{z^3} + 12{z^2} &#8211; 20z{\/tex}<\/p>\n<p>(iii) {tex}p &#8211; \\left( {p &#8211; q} \\right) &#8211; q &#8211; \\left( {q &#8211; p} \\right) = p &#8211; p + q &#8211; q &#8211; q + p{\/tex}<\/p>\n<p>= {tex}p &#8211; p + p + q &#8211; q &#8211; q{\/tex} = {tex}p &#8211; q{\/tex}<\/p>\n<p>(iv) {tex}3a &#8211; 2b &#8211; ab &#8211; \\left( {a &#8211; b + ab} \\right) + 3ab + b &#8211; a = 3a &#8211; 2b &#8211; ab &#8211; a + b &#8211; ab + 3ab + b &#8211; a{\/tex}<\/p>\n<p>= {tex}3a &#8211; a &#8211; a &#8211; 2b + b + b &#8211; ab &#8211; ab + 3ab{\/tex}<\/p>\n<p>= {tex}\\left( {3a &#8211; a &#8211; a} \\right) &#8211; \\left( {2b &#8211; b &#8211; b} \\right) &#8211; \\left( {ab + ab &#8211; 3ab} \\right){\/tex}<\/p>\n<p>= {tex}a &#8211; 0 &#8211; \\left( { &#8211; ab} \\right){\/tex}<\/p>\n<p>= {tex}a + ab{\/tex}<\/p>\n<p>(v) {tex}5{x^2}y &#8211; 5{x^2} + 3y{x^2} &#8211; 3{y^2} + {x^2} &#8211; {y^2} + 8x{y^2} &#8211; 3{y^2} = 5{x^2}y + 3y{x^2} + 8x{y^2} &#8211; 5{x^2} + {x^2} &#8211; 3{y^2} &#8211; {y^2} &#8211; 3{y^2}{\/tex}<\/p>\n<p>= {tex}\\left( {5{x^2}y + 3{x^2}y} \\right) + 8x{y^2} &#8211; \\left( {5{x^2} &#8211; {x^2}} \\right) &#8211; \\left( {3{y^2} + {y^2} + 3{y^2}} \\right){\/tex}<\/p>\n<p>= {tex}8{x^2}y + 8x{y^2} &#8211; 4{x^2} &#8211; 7{y^2}{\/tex}<\/p>\n<p>(vi) {tex}\\left( {3{y^2} + 5y &#8211; 4} \\right) &#8211; \\left( {8y &#8211; {y^2} &#8211; 4} \\right) = 3{y^2} + 5y &#8211; 4 &#8211; 8y + {y^2} + 4{\/tex}<\/p>\n<p>= {tex}\\left( {3{y^2} + {y^2}} \\right) + \\left( {5y &#8211; 8y} \\right) &#8211; \\left( {4 &#8211; 4} \\right){\/tex}<\/p>\n<p>= {tex}4{y^2} &#8211; 3y &#8211; 0{\/tex} = {tex}4{y^2} &#8211; 3y{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 12.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Add\"><\/span><strong>Question 2.<\/strong>Add:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>{tex}3mn, &#8211; 5mn,8mn &#8211; 4mn{\/tex}<\/li>\n<li>{tex}t &#8211; 8tz,3tz &#8211; z,z &#8211; t{\/tex}<\/li>\n<li>{tex} &#8211; 7mn + 5,12mn + 2,9mn &#8211; 8, &#8211; 2mn &#8211; 3{\/tex}<\/li>\n<li>{tex}a + b &#8211; 3,b &#8211; a + 3,a &#8211; b + 3{\/tex}<\/li>\n<li>{tex}14x + 10y &#8211; 12xy &#8211; 13,18 &#8211; 7x &#8211; 10y + 8xy,4xy{\/tex}<\/li>\n<li>{tex}5m &#8211; 7n,3n &#8211; 4m + 2,2m &#8211; 3mn &#8211; 5{\/tex}<\/li>\n<li>{tex}4{x^2}y, &#8211; 3x{y^2}, &#8211; 5x{y^2},5{x^2}y{\/tex}<\/li>\n<li>{tex}3{p^2}{q^2} &#8211; 4pq + 5, &#8211; 10{p^2}{q^2},15 + 9pq + 7{p^2}{q^2}{\/tex}<\/li>\n<li>{tex}ab &#8211; 4a,4b &#8211; ab,4a &#8211; 4b{\/tex}<\/li>\n<li>{tex}{x^2} &#8211; {y^2} &#8211; 1,{y^2} &#8211; 1 &#8211; {x^2},1 &#8211; {x^2} &#8211; {y^2}{\/tex}<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}3mn, &#8211; 5mn,8mn, &#8211; 4mn = 3mn + \\left( { &#8211; 5mn} \\right) + 8mn + \\left( { &#8211; 4mn} \\right){\/tex}<\/p>\n<p>= {tex}\\left( {3 &#8211; 5 + 8 &#8211; 4} \\right)mn{\/tex} = {tex}2mn{\/tex}<\/p>\n<p>(ii) {tex}t &#8211; 8tz,3tz &#8211; z,z &#8211; t = t &#8211; 8tz + 3tz &#8211; z + z &#8211; t{\/tex}<\/p>\n<p>= {tex}t &#8211; t &#8211; 8tz + 3tz &#8211; z + z{\/tex}<\/p>\n<p>= {tex}\\left( {1 &#8211; 1} \\right)t + \\left( { &#8211; 8 + 3} \\right)tz + \\left( { &#8211; 1 + 1} \\right)z{\/tex}<\/p>\n<p>= {tex}0 &#8211; 5tz + 0{\/tex} = {tex} &#8211; 5tz{\/tex}<\/p>\n<p>(iii) {tex} &#8211; 7mn + 5,12mn + 2,9mn &#8211; 8, &#8211; 2mn &#8211; 3 = &#8211; 7mn + 5 + 12mn + 2 + 9mn &#8211; 8 + \\left( { &#8211; 2mn} \\right) &#8211; 3{\/tex}<\/p>\n<p>= {tex} &#8211; 7mn + 12mn + 9mn &#8211; 2mn + 5 + 2 &#8211; 8 &#8211; 3{\/tex}<\/p>\n<p>= {tex}\\left( { &#8211; 7 + 12 + 9 &#8211; 2} \\right)mn + 7 &#8211; 11{\/tex}<\/p>\n<p>= {tex}12mn &#8211; 4{\/tex}<\/p>\n<p>(iv) {tex}a + b &#8211; 3,b &#8211; a + 3,a &#8211; b + 3 = a + b &#8211; 3 + b &#8211; a + 3 + a &#8211; b + 3{\/tex}<\/p>\n<p>= {tex}\\left( {a &#8211; a + a} \\right) + \\left( {b + b &#8211; b} \\right) &#8211; 3 + 3 + 3{\/tex}<\/p>\n<p>= {tex}a + b + 3{\/tex}<\/p>\n<h6><span class=\"ez-toc-section\" id=\"v_tex14x_10y_%E2%80%93_12xy_%E2%80%93_1318_%E2%80%93_7x_%E2%80%93_10y_8xy4xy_14x_10y_%E2%80%93_12xy_%E2%80%93_13_18_%E2%80%93_7x_%E2%80%93_10y_8xy_4xytex\"><\/span>(v) {tex}14x + 10y &#8211; 12xy &#8211; 13,18 &#8211; 7x &#8211; 10y + 8xy,4xy = 14x + 10y &#8211; 12xy &#8211; 13 + 18 &#8211; 7x &#8211; 10y + 8xy + 4xy{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>= {tex}14x &#8211; 7x + 10y &#8211; 10y &#8211; 12xy + 8xy + 4xy &#8211; 13 + 18{\/tex}<\/p>\n<p>= {tex}7x + 0y + 0xy + 5{\/tex} = {tex}7x + 5{\/tex}<\/p>\n<p>(vi) {tex}5m &#8211; 7n,3n &#8211; 4m + 2,2m &#8211; 3mn &#8211; 5 = 5m &#8211; 7n + 3n &#8211; 4m + 2 + 2m &#8211; 3mn &#8211; 5{\/tex}<\/p>\n<p>= {tex}5m &#8211; 4m + 2m &#8211; 7n + 3n &#8211; 3mn + 2 &#8211; 5{\/tex}<\/p>\n<p>= {tex}\\left( {5 &#8211; 4 + 2} \\right)m + \\left( { &#8211; 7 + 3} \\right)n &#8211; 3mn &#8211; 3{\/tex}<\/p>\n<p>= {tex}3m &#8211; 4n + 3mn &#8211; 3{\/tex}<\/p>\n<p>(vii) {tex}4{x^2}y, &#8211; 3x{y^2}, &#8211; 5x{y^2},5{x^2}y = 4{x^2}y + ( &#8211; 3x{y^2}) + ( &#8211; 5x{y^2}) + 5{x^2}y{\/tex}<\/p>\n<p>= {tex}4{x^2}y + 5{x^2}y &#8211; 3x{y^2} &#8211; 5x{y^2}{\/tex}<\/p>\n<p>= {tex}9{x^2}y &#8211; 8x{y^2}{\/tex}<\/p>\n<p>(viii) {tex}3{p^2}{q^2} &#8211; 4pq + 5, &#8211; 10{p^2}{q^2},15 + 9pq + 7{p^2}{q^2}{\/tex} = {tex}3{p^2}{q^2} &#8211; 4pq + 5 + \\left( { &#8211; 10{p^2}{q^2}} \\right) + 15 + 9pq + 7{p^2}{q^2}{\/tex}<\/p>\n<p>= {tex}3{p^2}{q^2} &#8211; 10{p^2}{q^2} + 7{p^2}{q^2} + 4pq + 9pq + 5 + 15{\/tex}<\/p>\n<p>= {tex}\\left( {3 &#8211; 10 + 7} \\right){p^2}{q^2} + \\left( { &#8211; 4 + 9} \\right)pq + 20{\/tex}<\/p>\n<p>= {tex}0{p^2}{q^2} + 5pq + 20{\/tex} = {tex}5pq + 20{\/tex}<\/p>\n<p>(ix) {tex}ab &#8211; 4a,4b &#8211; ab,4a &#8211; ab = ab &#8211; 4a + 4b &#8211; ab + 4a &#8211; ab{\/tex}<\/p>\n<p>= {tex} &#8211; 4a + 4a + 4b &#8211; 4b + ab &#8211; ab{\/tex}<\/p>\n<p>= {tex}0 + 0 + 0 = 0{\/tex}<\/p>\n<p>(x) {tex}{x^2} &#8211; {y^2} &#8211; 1,{y^2} &#8211; 1 &#8211; {x^2},1 &#8211; {x^2} &#8211; {y^2}{\/tex} = {tex}{x^2} &#8211; {y^2} &#8211; 1 + {y^2} &#8211; 1 &#8211; {x^2} + 1 &#8211; {x^2} &#8211; {y^2}{\/tex}<\/p>\n<p>= {tex}{x^2} &#8211; {x^2} &#8211; {x^2} &#8211; {y^2} + {y^2} &#8211; {y^2} &#8211; 1 &#8211; 1 + 1{\/tex}<\/p>\n<p>= {tex}\\left( {1 &#8211; 1 &#8211; 1} \\right){x^2} + \\left( { &#8211; 1 + 1 &#8211; 1} \\right){y^2} &#8211; 1 &#8211; 1 + 1{\/tex}<\/p>\n<p>= {tex} &#8211; {x^2} &#8211; {y^2} &#8211; 1{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 12.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Subtract\"><\/span><strong>Question 3.<\/strong>Subtract:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>{tex} &#8211; 5{y^2}{\/tex} from {tex}{y^2}{\/tex}<\/li>\n<li>{tex}6xy{\/tex} from {tex} &#8211; 12xy{\/tex}<\/li>\n<li>{tex}\\left( {a &#8211; b} \\right){\/tex} from {tex}\\left( {a + b} \\right){\/tex}<\/li>\n<li>{tex}a\\left( {b &#8211; 5} \\right){\/tex} from {tex}b\\left( {5 &#8211; a} \\right){\/tex}<\/li>\n<li>{tex} &#8211; {m^2} + 5mn{\/tex} from {tex}4{m^2} &#8211; 3mn + 8{\/tex}<\/li>\n<li>{tex} &#8211; {x^2} + 10x &#8211; 5{\/tex} from {tex}5x &#8211; 10{\/tex}<\/li>\n<li>{tex}5{a^2} &#8211; 7ab + 5{b^2}{\/tex} from {tex}3ab &#8211; 2{a^2} &#8211; 2{b^2}{\/tex}<\/li>\n<li>{tex}4pq &#8211; 5{q^2} &#8211; 3{p^2}{\/tex} from {tex}5{p^2} + 3{q^2} &#8211; pq{\/tex}<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}{y^2} &#8211; \\left( { &#8211; 5{y^2}} \\right){\/tex} = {tex}{y^2} + 5{y^2}{\/tex} = {tex}6{y^2}{\/tex}<\/p>\n<p>(ii) {tex} &#8211; 12xy &#8211; \\left( {6xy} \\right){\/tex} = {tex} &#8211; 12xy &#8211; 6xy{\/tex} = {tex} &#8211; 18xy{\/tex}<\/p>\n<p>(iii) {tex}\\left( {a + b} \\right) &#8211; \\left( {a &#8211; b} \\right){\/tex} = {tex}a + b &#8211; a + b{\/tex} = {tex}a &#8211; a + b + b{\/tex} = {tex}2b{\/tex}<\/p>\n<p>(iv) {tex}b\\left( {5 &#8211; a} \\right) &#8211; a\\left( {b &#8211; 5} \\right){\/tex} = {tex}5b &#8211; ab &#8211; ab + 5a{\/tex} = {tex}5b &#8211; 2ab + 5a{\/tex} = {tex}5a + 5b &#8211; 2ab{\/tex}<\/p>\n<p>(v) {tex}4{m^2} &#8211; 3mn + 8 &#8211; \\left( { &#8211; {m^2} + 5mn} \\right){\/tex} = {tex}4{m^2} &#8211; 3mn + 8 + {m^2} &#8211; 5mn{\/tex}<\/p>\n<p>= {tex}4{m^2} + {m^2} &#8211; 3mn &#8211; 5mn + 8{\/tex}<\/p>\n<p>= {tex}5{m^2} &#8211; 8mn + 8{\/tex}<\/p>\n<p>(vi) {tex}5x &#8211; 10 &#8211; \\left( { &#8211; {x^2} + 10x &#8211; 5} \\right){\/tex} = {tex}5x &#8211; 10 + {x^2} &#8211; 10x + 5{\/tex}<\/p>\n<p>= {tex}{x^2} + 5x &#8211; 10x &#8211; 10 + 5{\/tex} = {tex}{x^2} &#8211; 5x &#8211; 5{\/tex}<\/p>\n<p>(vii) {tex}3ab &#8211; 2{a^2} &#8211; 2{b^2} &#8211; \\left( {5{a^2} &#8211; 7ab + 5{b^2}} \\right){\/tex} = {tex}3ab &#8211; 2{a^2} &#8211; 2{b^2} &#8211; 5{a^2} + 7ab &#8211; 5{b^2}{\/tex}<\/p>\n<p>= {tex}3ab + 7ab &#8211; 2{a^2} &#8211; 5{a^2} &#8211; 2{b^2} &#8211; 5{b^2}{\/tex}<\/p>\n<p>= {tex}10ab &#8211; 7{a^2} &#8211; 7{b^2}{\/tex}<\/p>\n<p>= {tex} &#8211; 7{a^2} &#8211; 7{b^2} + 10ab{\/tex}<\/p>\n<p>(viii) {tex}5{p^2} + 3{q^2} &#8211; pq &#8211; \\left( {4pq &#8211; 5{q^2} &#8211; 3{p^2}} \\right){\/tex} = {tex}5{p^2} + 3{q^2} &#8211; pq &#8211; 4pq + 5{q^2} + 3{p^2}{\/tex}<\/p>\n<p>= {tex}5{p^2} + 3{p^2} + 3{q^2} + 5{q^2} &#8211; pq &#8211; 4pq{\/tex}<\/p>\n<p>= {tex}8{p^2} + 8{q^2} &#8211; 5pq{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 12.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4a_What_should_be_added_to_texx2_xy_y2tex_to_obtain_tex2x2_3xytex\"><\/span><strong>Question<\/strong> 4.(a) What should be added to {tex}{x^2} + xy + {y^2}{\/tex} to obtain {tex}2{x^2} + 3xy?{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(b) What should be subtracted from {tex}2a + 8b + 10{\/tex} to get {tex} &#8211; 3a + 7b + 16{\/tex} ?<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Let {tex}p{\/tex} should be added.<\/p>\n<p>Then according to question,<\/p>\n<p>{tex}{x^2} + xy + {y^2} + p = 2{x^2} + 3xy{\/tex} {tex} \\Rightarrow {\/tex} {tex}p = 2{x^2} + 3xy &#8211; \\left( {{x^2} + xy + {y^2}} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 2{x^2} + 3xy &#8211; {x^2} &#8211; xy &#8211; {y^2}{\/tex} {tex} \\Rightarrow {\/tex} {tex}p = 2{x^2} &#8211; {x^2} &#8211; {y^2} + 3xy &#8211; xy{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}p = {x^2} &#8211; {y^2} + 2xy{\/tex}<\/p>\n<p>Hence, {tex}{x^2} &#8211; {y^2} + 2xy{\/tex} should be added.<\/p>\n<p>(b) Let {tex}q{\/tex} should be subtracted.<\/p>\n<p>Then according to question,<\/p>\n<p>{tex}2a + 8b + 10 &#8211; q = &#8211; 3a + 7b + 16{\/tex} {tex} \\Rightarrow {\/tex} {tex} &#8211; q = &#8211; 3a + 7b + 16 &#8211; \\left( {2a + 8b + 10} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; q = &#8211; 3a + 7b + 16 &#8211; 2a &#8211; 8b &#8211; 10{\/tex} {tex} \\Rightarrow {\/tex} {tex} &#8211; q = &#8211; 3a &#8211; 2a + 7b &#8211; 8b + 16 &#8211; 10{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; q = &#8211; 5a &#8211; b + 6{\/tex} {tex} \\Rightarrow {\/tex}{tex}q = &#8211; \\left( { &#8211; 5a &#8211; b + 6} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 5a + b &#8211; 6{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 12.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5What_should_be_taken_away_from_tex3x2_%E2%80%93_4y2_5xy_20tex_to_obtain_tex_%E2%80%93_x2_%E2%80%93_y2_6xy_20tex\"><\/span><strong>Question 5.<\/strong>What should be taken away from {tex}3{x^2} &#8211; 4{y^2} + 5xy + 20{\/tex} to obtain {tex} &#8211; {x^2} &#8211; {y^2} + 6xy + 20{\/tex} ?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Let {tex}q{\/tex} should be subtracted.<\/p>\n<p>Then according to question,<\/p>\n<p>{tex}3{x^2} &#8211; 4{y^2} + 5xy + 20 &#8211; q = &#8211; {x^2} &#8211; {y^2} + 6xy + 20{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{x^2} &#8211; 4{y^2} + 5xy + 20 &#8211; \\left( { &#8211; {x^2} &#8211; {y^2} + 6xy + 20} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{x^2} &#8211; 4{y^2} + 5xy + 20 + {x^2} + {y^2} &#8211; 6xy &#8211; 20{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{x^2} + {x^2} &#8211; 4{y^2} + {y^2} + 5xy &#8211; 6xy + 20 &#8211; 20{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 4{x^2} &#8211; 3{y^2} &#8211; xy + 0{\/tex}<\/p>\n<p>Hence, {tex}4{x^2} &#8211; 3{y^2} &#8211; xy{\/tex} should be subtracted.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 12.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_6a_From_the_sum_of_tex3x_%E2%80%93_y_11tex_and_tex_%E2%80%93_y_%E2%80%93_11tex_subtract_the_sum_of_tex3x2_%E2%80%93_5xtex_and_tex_%E2%80%93_x2_2x_5tex\"><\/span><strong>Question<\/strong> 6.(a) From the sum of {tex}3x &#8211; y + 11{\/tex} and {tex} &#8211; y &#8211; 11,{\/tex} subtract the sum of {tex}3{x^2} &#8211; 5x{\/tex} and {tex} &#8211; {x^2} + 2x + 5.{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) According to question,<\/p>\n<p>{tex}\\left( {3x &#8211; y + 11} \\right) + \\left( { &#8211; y &#8211; 11} \\right) &#8211; \\left( {3x &#8211; y &#8211; 11} \\right){\/tex} = {tex}3x &#8211; y + 11 &#8211; y &#8211; 11 &#8211; 3x + y + 11{\/tex}<\/p>\n<p>= {tex}3x &#8211; 3x &#8211; y &#8211; y + y + 11 &#8211; 11 + 11{\/tex}<\/p>\n<p>= {tex}\\left( {3 &#8211; 3} \\right)x &#8211; \\left( {1 + 1 &#8211; 1} \\right)y + 11 + 11 &#8211; 11{\/tex}<\/p>\n<p>= {tex}0x &#8211; y + 11{\/tex} = {tex} &#8211; y + 11{\/tex}<\/p>\n<h6><span class=\"ez-toc-section\" id=\"b_According_to_question\"><\/span>(b) According to question,<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>{tex}\\left[ {\\left( {4 + 3x} \\right) + \\left( {5 &#8211; 4x + 2{x^2}} \\right)} \\right] &#8211; \\left[ {\\left( {3{x^2} &#8211; 5x} \\right) + \\left( { &#8211; {x^2} + 2x + 5} \\right)} \\right]{\/tex}<\/p>\n<p>= {tex}\\left[ {4 + 3x + 5 &#8211; 4x + 2{x^2}} \\right] &#8211; \\left[ {3{x^2} &#8211; 5x &#8211; {x^2} + 2x + 5} \\right]{\/tex}<\/p>\n<p>= {tex}\\left[ {2{x^2} + 3x &#8211; 4x + 5 + 4} \\right] &#8211; \\left[ {3{x^2} &#8211; {x^2} + 2x &#8211; 5x + 5} \\right]{\/tex}<\/p>\n<p>= {tex}\\left[ {2{x^2} &#8211; x + 9} \\right] &#8211; \\left[ {2{x^2} &#8211; 3x + 5} \\right]{\/tex}<\/p>\n<p>= {tex}2{x^2} &#8211; x + 9 &#8211; 2{x^2} + 3x &#8211; 5{\/tex}<\/p>\n<p>= {tex}2{x^2} &#8211; 2{x^2} &#8211; x + 3x + 9 &#8211; 5{\/tex}<\/p>\n<p>= {tex}2x + 4{\/tex}<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_122\"><\/span>NCERT Solutions for Class 7 Maths Exercise 12.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 12.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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