{"id":4314,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-rational-numbers-ex-9-1\/"},"modified":"2018-07-07T12:03:11","modified_gmt":"2018-07-07T06:33:11","slug":"ncert-solutions-for-class-7-maths-exercise-9-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 9.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#NCERT_Solutions_for_Class_7_Maths_Rational_Numbers\" >NCERT Solutions for Class 7 Maths\u00a0Rational Numbers<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Class_%E2%80%93VII_Mathematics_Ex_91\" >Class \u2013VII Mathematics (Ex. 9.1)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_1List_five_rational_numbers_between\" >Question 1.List five rational numbers between:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_2Write_four_more_rational_numbers_in_each_of_the_following_patterns\" >Question 2.Write four more rational numbers in each of the following patterns:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_3Give_four_rational_numbers_equivalent_to\" >Question 3.Give four rational numbers equivalent to:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_4Draw_the_number_line_and_represent_the_following_rational_numbers_on_it\" >Question 4.Draw the number line and represent the following rational numbers on it:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_5The_points_P_Q_R_S_T_U_A_and_B_on_the_number_line_are_such_that_TR_RS_SU_and_AP_PQ_QB_Name_the_rational_numbers_represented_by_P_Q_R_and_S\" >Question 5.The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_6Which_of_the_following_pairs_represent_the_same_rational_numbers\" >Question 6.Which of the following pairs represent the same rational numbers:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_7Rewrite_the_following_rational_numbers_in_the_simplest_form\" >Question 7.Rewrite the following rational numbers in the simplest form:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_8Fill_in_the_boxes_with_the_correct_symbol_out_of_and\" >Question 8.Fill in the boxes with the correct symbol out of &lt;, &gt; and =:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_9Which_is_greater_in_each_of_the_following\" >Question 9.Which is greater in each of the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#Question_10Write_the_following_rational_numbers_in_ascending_order\" >Question 10.Write the following rational numbers in ascending order:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#NCERT_Solutions_for_Class_7_Maths_Exercise_91\" >NCERT Solutions for Class 7 Maths Exercise 9.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 9.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Rational Numbers <\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-rational-numbers\/1518\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 9.1\" width=\"147\" height=\"186\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Rational_Numbers\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Rational Numbers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VII_Mathematics_Ex_91\"><\/span><strong>Class \u2013VII Mathematics (Ex. 9.1)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1List_five_rational_numbers_between\"><\/span><strong>Question 1.<\/strong>List five rational numbers between:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex} &#8211; 1{\/tex} and 0<\/p>\n<p>(ii) {tex} &#8211; 2{\/tex} and {tex} &#8211; 1{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 4}}{5}{\/tex} and {tex}\\frac{{ &#8211; 2}}{3}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 1}}{2}{\/tex} and {tex}\\frac{2}{3}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex} &#8211; 1{\/tex} and 0<\/p>\n<p>Let us write {tex} &#8211; 1{\/tex} and 0 as rational numbers with denominator 6.<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 1 = \\frac{{ &#8211; 6}}{6}{\/tex} and 0 = {tex}\\frac{0}{6}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 6}}{6} &lt; \\frac{{ &#8211; 5}}{6} &lt; \\frac{{ &#8211; 4}}{6} &lt; \\frac{{ &#8211; 3}}{6} &lt; \\frac{{ &#8211; 2}}{6} &lt; \\frac{{ &#8211; 1}}{6} &lt; 0{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 1 &lt; \\frac{{ &#8211; 5}}{6} &lt; \\frac{{ &#8211; 2}}{3} &lt; \\frac{{ &#8211; 1}}{2} &lt; \\frac{{ &#8211; 1}}{3} &lt; \\frac{{ &#8211; 1}}{6} &lt; 0{\/tex}<\/p>\n<p>Therefore, five rational numbers between {tex} &#8211; 1{\/tex} and 0 would be<\/p>\n<p>{tex}\\frac{{ &#8211; 5}}{6},\\frac{{ &#8211; 2}}{3},\\frac{{ &#8211; 1}}{2},\\frac{{ &#8211; 1}}{3},\\frac{{ &#8211; 1}}{6}{\/tex}<\/p>\n<p>(ii) {tex} &#8211; 2{\/tex} and {tex} &#8211; 1{\/tex}<\/p>\n<p>Let us write {tex} &#8211; 2{\/tex} and {tex} &#8211; 1{\/tex} as rational numbers with denominator 6.<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 2 = \\frac{{ &#8211; 12}}{6}{\/tex} and {tex} &#8211; 1 = \\frac{{ &#8211; 6}}{6}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 12}}{6} &lt; \\frac{{ &#8211; 11}}{6} &lt; \\frac{{ &#8211; 10}}{6} &lt; \\frac{{ &#8211; 9}}{6} &lt; \\frac{{ &#8211; 8}}{6} &lt; \\frac{{ &#8211; 7}}{6} &lt; \\frac{{ &#8211; 6}}{6}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 2 &lt; \\frac{{ &#8211; 11}}{6} &lt; \\frac{{ &#8211; 5}}{3} &lt; \\frac{{ &#8211; 3}}{2} &lt; \\frac{{ &#8211; 4}}{3} &lt; \\frac{{ &#8211; 7}}{6} &lt; &#8211; 1{\/tex}<\/p>\n<p>Therefore, five rational numbers between {tex} &#8211; 2{\/tex} and {tex} &#8211; 1{\/tex} would be<\/p>\n<p>{tex}\\frac{{ &#8211; 11}}{6},\\frac{{ &#8211; 5}}{3},\\frac{{ &#8211; 3}}{2},\\frac{{ &#8211; 4}}{3},\\frac{{ &#8211; 7}}{6}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 4}}{5}{\/tex} and {tex}\\frac{{ &#8211; 2}}{3}{\/tex}<\/p>\n<p>Let us write {tex}\\frac{{ &#8211; 4}}{5}{\/tex} and {tex}\\frac{{ &#8211; 2}}{3}{\/tex} as rational numbers with the same denominators.<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 4}}{5} = \\frac{{ &#8211; 36}}{{45}}{\/tex} and {tex}\\frac{{ &#8211; 2}}{3} = \\frac{{ &#8211; 30}}{{45}}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 36}}{{45}} &lt; \\frac{{ &#8211; 35}}{{45}} &lt; \\frac{{ &#8211; 34}}{{45}} &lt; \\frac{{ &#8211; 33}}{{45}} &lt; \\frac{{ &#8211; 32}}{{45}} &lt; \\frac{{ &#8211; 31}}{{45}} &lt; \\frac{{ &#8211; 30}}{{45}}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 4}}{5} &lt; \\frac{{ &#8211; 7}}{9} &lt; \\frac{{ &#8211; 34}}{{45}} &lt; \\frac{{ &#8211; 11}}{{15}} &lt; \\frac{{ &#8211; 32}}{{45}} &lt; \\frac{{ &#8211; 31}}{{45}} &lt; \\frac{{ &#8211; 2}}{3}{\/tex}<\/p>\n<p>Therefore, five rational numbers between {tex}\\frac{{ &#8211; 4}}{5}{\/tex} and {tex}\\frac{{ &#8211; 2}}{3}{\/tex} would be<\/p>\n<p>{tex}\\frac{{ &#8211; 7}}{9},\\frac{{ &#8211; 34}}{{45}},\\frac{{ &#8211; 11}}{{15}},\\frac{{ &#8211; 32}}{{45}},\\frac{{ &#8211; 31}}{{45}},\\frac{{ &#8211; 2}}{3}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 1}}{2}{\/tex} and {tex}\\frac{2}{3}{\/tex}<\/p>\n<p>Let us write {tex}\\frac{{ &#8211; 1}}{2}{\/tex} and {tex}\\frac{2}{3}{\/tex} as rational numbers with the same denominators.<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 1}}{2} = \\frac{{ &#8211; 3}}{6}{\/tex} and {tex}\\frac{2}{3} = \\frac{4}{6}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 3}}{6} &lt; \\frac{{ &#8211; 2}}{6} &lt; \\frac{{ &#8211; 1}}{6} &lt; 0 &lt; \\frac{1}{6} &lt; \\frac{2}{6} &lt; \\frac{3}{6} &lt; \\frac{4}{6}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 1}}{2} &lt; \\frac{{ &#8211; 1}}{3} &lt; \\frac{{ &#8211; 1}}{6} &lt; 0 &lt; \\frac{1}{6} &lt; \\frac{1}{3} &lt; \\frac{1}{2} &lt; \\frac{2}{3}{\/tex}<\/p>\n<p>Therefore, five rational numbers between {tex}\\frac{{ &#8211; 1}}{2}{\/tex} and {tex}\\frac{2}{3}{\/tex} would be {tex}\\frac{{ &#8211; 1}}{3},\\frac{{ &#8211; 1}}{6},0,\\frac{1}{6},\\frac{1}{3}{\/tex}.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Write_four_more_rational_numbers_in_each_of_the_following_patterns\"><\/span><strong>Question 2.<\/strong>Write four more rational numbers in each of the following patterns:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 3}}{5},\\frac{{ &#8211; 6}}{{10}},\\frac{{ &#8211; 9}}{{15}},\\frac{{ &#8211; 12}}{{20}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 1}}{4},\\frac{{ &#8211; 2}}{8},\\frac{{ &#8211; 3}}{{12}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 1}}{6},\\frac{2}{{ &#8211; 12}},\\frac{3}{{ &#8211; 18}},\\frac{4}{{ &#8211; 24}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 2}}{3},\\frac{2}{{ &#8211; 3}},\\frac{4}{{ &#8211; 6}},\\frac{6}{{ &#8211; 9}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 3}}{5},\\frac{{ &#8211; 6}}{{10}},\\frac{{ &#8211; 9}}{{15}},\\frac{{ &#8211; 12}}{{20}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 3 \\times 1}}{{5 \\times 1}},\\frac{{ &#8211; 3 \\times 2}}{{5 \\times 2}},\\frac{{ &#8211; 3 \\times 3}}{{5 \\times 3}},\\frac{{ &#8211; 3 \\times 4}}{{5 \\times 4}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>Therefore, the next four rational numbers of this pattern would be<\/p>\n<p>{tex}\\frac{{ &#8211; 3 \\times 5}}{{5 \\times 5}},\\frac{{ &#8211; 3 \\times 6}}{{5 \\times 6}},\\frac{{ &#8211; 3 \\times 7}}{{5 \\times 7}},\\frac{{ &#8211; 3 \\times 8}}{{5 \\times 8}}{\/tex} = {tex}\\frac{{ &#8211; 15}}{{25}},\\frac{{ &#8211; 18}}{{30}},\\frac{{ &#8211; 21}}{{35}},\\frac{{ &#8211; 24}}{{40}}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 1}}{4},\\frac{{ &#8211; 2}}{8},\\frac{{ &#8211; 3}}{{12}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 1 \\times 1}}{{4 \\times 1}},\\frac{{ &#8211; 1 \\times 2}}{{4 \\times 2}},\\frac{{ &#8211; 1 \\times 3}}{{4 \\times 3}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p>Therefore, the next four rational numbers of this pattern would be<\/p>\n<p>{tex}\\frac{{ &#8211; 1 \\times 4}}{{4 \\times 4}},\\frac{{ &#8211; 1 \\times 5}}{{4 \\times 5}},\\frac{{ &#8211; 1 \\times 6}}{{4 \\times 6}},\\frac{{ &#8211; 1 \\times 7}}{{4 \\times 7}}{\/tex} = {tex}\\frac{{ &#8211; 4}}{{16}},\\frac{{ &#8211; 5}}{{20}},\\frac{{ &#8211; 6}}{{24}},\\frac{{ &#8211; 7}}{{28}}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 1}}{6},\\frac{2}{{ &#8211; 12}},\\frac{3}{{ &#8211; 18}},\\frac{4}{{ &#8211; 24}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 1 \\times 1}}{{6 \\times 1}},\\frac{{1 \\times 2}}{{ &#8211; 6 \\times 2}},\\frac{{1 \\times 3}}{{ &#8211; 6 \\times 3}},\\frac{{1 \\times 4}}{{ &#8211; 6 \\times 4}},&#8230;&#8230;&#8230;{\/tex}<\/p>\n<p>Therefore, the next four rational numbers of this pattern would be<\/p>\n<p>{tex}\\frac{{1 \\times 5}}{{ &#8211; 6 \\times 5}},\\frac{{1 \\times 6}}{{ &#8211; 6 \\times 6}},\\frac{{1 \\times 7}}{{ &#8211; 6 \\times 7}},\\frac{{1 \\times 8}}{{ &#8211; 6 \\times 8}}{\/tex} = {tex}\\frac{5}{{ &#8211; 30}},\\frac{6}{{ &#8211; 36}},\\frac{7}{{ &#8211; 42}},\\frac{8}{{ &#8211; 48}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 2}}{3},\\frac{2}{{ &#8211; 3}},\\frac{4}{{ &#8211; 6}},\\frac{6}{{ &#8211; 9}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 2 \\times 1}}{{3 \\times 1}},\\frac{{2 \\times 1}}{{ &#8211; 3 \\times 1}},\\frac{{2 \\times 2}}{{ &#8211; 3 \\times 2}},\\frac{{2 \\times 3}}{{ &#8211; 3 \\times 3}},&#8230;&#8230;&#8230;.{\/tex}<\/p>\n<p>Therefore, the next four rational numbers of this pattern would be<\/p>\n<p>{tex}\\frac{{2 \\times 4}}{{ &#8211; 3 \\times 4}},\\frac{{2 \\times 5}}{{ &#8211; 3 \\times 5}},\\frac{{2 \\times 6}}{{ &#8211; 3 \\times 6}},\\frac{{2 \\times 7}}{{ &#8211; 3 \\times 7}}{\/tex} = {tex}\\frac{8}{{ &#8211; 12}},\\frac{{10}}{{ &#8211; 15}},\\frac{{12}}{{ &#8211; 18}},\\frac{{14}}{{ &#8211; 21}}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Give_four_rational_numbers_equivalent_to\"><\/span><strong>Question 3.<\/strong>Give four rational numbers equivalent to:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 2}}{7}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{5}{{ &#8211; 3}}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{4}{9}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 2}}{7}{\/tex}<\/p>\n<p>{tex}\\frac{{ &#8211; 2 \\times 2}}{{7 \\times 2}} = \\frac{{ &#8211; 4}}{{14}},{\/tex}{tex}\\frac{{ &#8211; 2 \\times 3}}{{7 \\times 3}} = \\frac{{ &#8211; 6}}{{21}},{\/tex}{tex}\\frac{{ &#8211; 2 \\times 4}}{{7 \\times 4}} = \\frac{{ &#8211; 8}}{{28}},{\/tex}{tex}\\frac{{ &#8211; 2 \\times 5}}{{7 \\times 5}} = \\frac{{ &#8211; 10}}{{35}}{\/tex}<\/p>\n<p>Therefore, four equivalent rational numbers are {tex}\\frac{{ &#8211; 4}}{{14}},\\frac{{ &#8211; 6}}{{21}},\\frac{{ &#8211; 8}}{{28}},\\frac{{ &#8211; 10}}{{35}}{\/tex}.<\/p>\n<p>(ii) {tex}\\frac{5}{{ &#8211; 3}}{\/tex}<\/p>\n<p>{tex}\\frac{{5 \\times 2}}{{ &#8211; 3 \\times 2}} = \\frac{{10}}{{ &#8211; 6}},{\/tex}{tex}\\frac{{5 \\times 3}}{{ &#8211; 3 \\times 3}} = \\frac{{15}}{{ &#8211; 9}},{\/tex}{tex}\\frac{{5 \\times 4}}{{ &#8211; 3 \\times 4}} = \\frac{{20}}{{ &#8211; 12}},{\/tex}{tex}\\frac{{5 \\times 5}}{{ &#8211; 3 \\times 5}} = \\frac{{25}}{{ &#8211; 15}}{\/tex}<\/p>\n<p>Therefore, four equivalent rational numbers are {tex}\\frac{{10}}{{ &#8211; 6}},\\frac{{15}}{{ &#8211; 9}},\\frac{{20}}{{ &#8211; 12}},\\frac{{25}}{{ &#8211; 15}}{\/tex}.<\/p>\n<p>(iii) {tex}\\frac{4}{9}{\/tex}<\/p>\n<p>{tex}\\frac{{4 \\times 2}}{{9 \\times 2}} = \\frac{8}{{18}},{\/tex}{tex}\\frac{{4 \\times 3}}{{9 \\times 3}} = \\frac{{12}}{{27}},{\/tex}{tex}\\frac{{4 \\times 4}}{{9 \\times 4}} = \\frac{{16}}{{36}},{\/tex}{tex}\\frac{{4 \\times 5}}{{9 \\times 5}} = \\frac{{20}}{{45}}{\/tex}<\/p>\n<p>Therefore, four equivalent rational numbers are {tex}\\frac{8}{{18}},\\frac{{12}}{{27}},\\frac{{16}}{{36}},\\frac{{20}}{{45}}{\/tex}.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Draw_the_number_line_and_represent_the_following_rational_numbers_on_it\"><\/span><strong>Question 4.<\/strong>Draw the number line and represent the following rational numbers on it:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{3}{4}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 5}}{8}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 7}}{4}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{7}{8}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{3}{4}{\/tex}<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch09_02.jpg\" \/><\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 5}}{8}{\/tex}<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch09_03.jpg\" \/><\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 7}}{4}{\/tex}<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch09_04.jpg\" \/><\/p>\n<p>(iv) {tex}\\frac{7}{8}{\/tex}<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch09_05.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5The_points_P_Q_R_S_T_U_A_and_B_on_the_number_line_are_such_that_TR_RS_SU_and_AP_PQ_QB_Name_the_rational_numbers_represented_by_P_Q_R_and_S\"><\/span><strong>Question 5.<\/strong>The points P, Q, R, S, T, U, A and B on the number line are such that, TR = RS = SU and AP = PQ = QB. Name the rational numbers represented by P, Q, R and S.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch09_01.png\" \/><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Each part which is between the two numbers is divided into 3 parts.<\/p>\n<p>Therefore, A = {tex}\\frac{6}{3},{\/tex} P = {tex}\\frac{7}{3},{\/tex} Q = {tex}\\frac{8}{3}{\/tex} and B = {tex}\\frac{9}{3}{\/tex}<\/p>\n<p>Similarly T = {tex}\\frac{{ &#8211; 3}}{3},{\/tex} R = {tex}\\frac{{ &#8211; 4}}{3},{\/tex} S = {tex}\\frac{{ &#8211; 5}}{3}{\/tex} and U = {tex}\\frac{{ &#8211; 6}}{3}{\/tex}<\/p>\n<p>Thus, the rational numbers represented P, Q, R and S are {tex}\\frac{7}{3},\\frac{8}{3},\\frac{{ &#8211; 4}}{3}{\/tex} and {tex}\\frac{{ &#8211; 5}}{3}{\/tex} respectively.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_6Which_of_the_following_pairs_represent_the_same_rational_numbers\"><\/span><strong>Question 6.<\/strong>Which of the following pairs represent the same rational numbers:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 7}}{{21}}{\/tex} and {tex}\\frac{3}{9}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 16}}{{20}}{\/tex} and {tex}\\frac{{20}}{{ &#8211; 25}}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 2}}{{ &#8211; 3}}{\/tex} and {tex}\\frac{2}{3}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 3}}{5}{\/tex} and {tex}\\frac{{ &#8211; 12}}{{20}}{\/tex}<\/p>\n<p>(v) {tex}\\frac{8}{{ &#8211; 5}}{\/tex} and {tex}\\frac{{ &#8211; 24}}{{15}}{\/tex}<\/p>\n<p>(vi) {tex}\\frac{1}{3}{\/tex} and {tex}\\frac{{ &#8211; 1}}{9}{\/tex}<\/p>\n<p>(vii) {tex}\\frac{{ &#8211; 5}}{{ &#8211; 9}}{\/tex} and {tex}\\frac{5}{{ &#8211; 9}}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 7}}{{21}}{\/tex} and {tex}\\frac{3}{9}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 7}}{{21}}{\/tex} = {tex}\\frac{{ &#8211; 1}}{3}{\/tex} and {tex}\\frac{3}{9}{\/tex} = {tex}\\frac{1}{3}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{{ &#8211; 1}}{3}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{1}{3}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 7}}{{21}}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{3}{9}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 16}}{{20}}{\/tex} and {tex}\\frac{{20}}{{ &#8211; 25}}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 16}}{{20}}{\/tex} = {tex}\\frac{{ &#8211; 4}}{5}{\/tex} and {tex}\\frac{{20}}{{ &#8211; 25}}{\/tex} = {tex}\\frac{4}{{ &#8211; 5}} = \\frac{{ &#8211; 4}}{5}{\/tex}<\/p>\n[Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{{ &#8211; 4}}{5}{\/tex} = {tex}\\frac{{ &#8211; 4}}{5}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 16}}{{20}}{\/tex} = {tex}\\frac{{20}}{{ &#8211; 25}}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 2}}{{ &#8211; 3}}{\/tex} and {tex}\\frac{2}{3}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 2}}{{ &#8211; 3}}{\/tex} = {tex}\\frac{2}{3}{\/tex} and {tex}\\frac{2}{3}{\/tex} = {tex}\\frac{2}{3}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{2}{3}{\/tex} = {tex}\\frac{2}{3}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 2}}{{ &#8211; 3}}{\/tex} = {tex}\\frac{2}{3}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 3}}{5}{\/tex} and {tex}\\frac{{ &#8211; 12}}{{20}}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 3}}{5}{\/tex} = {tex}\\frac{{ &#8211; 3}}{5}{\/tex} and {tex}\\frac{{ &#8211; 12}}{{20}}{\/tex} = {tex}\\frac{{ &#8211; 3}}{5}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{{ &#8211; 3}}{5}{\/tex} = {tex}\\frac{{ &#8211; 3}}{5}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 3}}{5}{\/tex} = {tex}\\frac{{ &#8211; 12}}{{20}}{\/tex}<\/p>\n<p>(v) {tex}\\frac{8}{{ &#8211; 5}}{\/tex} and {tex}\\frac{{ &#8211; 24}}{{15}}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{8}{{ &#8211; 5}}{\/tex} = {tex}\\frac{{ &#8211; 8}}{5}{\/tex} and {tex}\\frac{{ &#8211; 24}}{{15}}{\/tex} = {tex}\\frac{{ &#8211; 8}}{5}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{{ &#8211; 8}}{5}{\/tex} = {tex}\\frac{{ &#8211; 8}}{5}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{8}{{ &#8211; 5}}{\/tex} = {tex}\\frac{{ &#8211; 24}}{{15}}{\/tex}<\/p>\n<p>(vi) {tex}\\frac{1}{3}{\/tex} and {tex}\\frac{{ &#8211; 1}}{9}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{1}{3}{\/tex} = {tex}\\frac{1}{3}{\/tex} and {tex}\\frac{{ &#8211; 1}}{9}{\/tex} = {tex}\\frac{{ &#8211; 1}}{9}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{1}{3}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{{ &#8211; 1}}{9}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{1}{3}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{{ &#8211; 1}}{9}{\/tex}<\/p>\n<p>(vii) {tex}\\frac{{ &#8211; 5}}{{ &#8211; 9}}{\/tex} and {tex}\\frac{5}{{ &#8211; 9}}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 5}}{{ &#8211; 9}}{\/tex} = {tex}\\frac{5}{9}{\/tex} and {tex}\\frac{5}{{ &#8211; 9}}{\/tex} = {tex}\\frac{5}{9}{\/tex} [Converting into lowest term]\n<p>{tex}\\because {\/tex} {tex}\\frac{5}{9}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{5}{{ &#8211; 9}}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{ &#8211; 5}}{{ &#8211; 9}}{\/tex}{tex} \\ne {\/tex}{tex}\\frac{5}{{ &#8211; 9}}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_7Rewrite_the_following_rational_numbers_in_the_simplest_form\"><\/span><strong>Question 7.<\/strong>Rewrite the following rational numbers in the simplest form:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 8}}{6}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{25}}{{45}}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 44}}{{72}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 8}}{{10}}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 8}}{6}{\/tex} = {tex}\\frac{{ &#8211; 8 \\div 2}}{{6 \\div 2}}{\/tex} = {tex}\\frac{{ &#8211; 4}}{3}{\/tex} [H.C.F. of 8 and 6 is 2]\n<p>(ii){tex}\\frac{{25}}{{45}}{\/tex} = {tex}\\frac{{25 \\div 5}}{{45 \\div 5}}{\/tex} = {tex}\\frac{5}{9}{\/tex}<\/p>\n[H.C.F. of 25 and 45 is 5]\n<p>(iii){tex}\\frac{{ &#8211; 44}}{{72}}{\/tex} = {tex}\\frac{{ &#8211; 44 \\div 4}}{{72 \\div 4}}{\/tex} = {tex}\\frac{{ &#8211; 11}}{{18}}{\/tex} [H.C.F. of 44 and 72 is 4]\n<p>(iv) {tex}\\frac{{ &#8211; 8}}{{10}}{\/tex} = {tex}\\frac{{ &#8211; 8 \\div 2}}{{10 \\div 2}}{\/tex} = {tex}\\frac{{ &#8211; 4}}{5}{\/tex} [H.C.F. of 8 and 10 is 2]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_8Fill_in_the_boxes_with_the_correct_symbol_out_of_and\"><\/span><strong>Question 8.<\/strong>Fill in the boxes with the correct symbol out of &lt;, &gt; and =:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 5}}{7}\\boxed{{\\text{ }}}\\frac{2}{3}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 4}}{5}\\boxed{{\\text{ }}}\\frac{{ &#8211; 5}}{7}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 7}}{8}\\boxed{{\\text{ }}}\\frac{{14}}{{ &#8211; 16}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 8}}{5}\\boxed{{\\text{ }}}\\frac{{ &#8211; 7}}{4}{\/tex}<\/p>\n<p>(v) {tex}\\frac{1}{{ &#8211; 3}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 1}}{4}{\/tex}<\/p>\n<p>(vi) {tex}\\frac{5}{{ &#8211; 11}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 5}}{{11}}{\/tex}<\/p>\n<p>(vii) {tex}0\\boxed{{\\text{ }}}\\frac{{ &#8211; 7}}{6}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 5}}{7}\\boxed{{\\text{ &lt; }}}\\frac{2}{3}{\/tex} Since, the positive number if greater than negative number.<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 4 \\times 7}}{{5 \\times 7}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 5 \\times 5}}{{7 \\times 5}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 28}}{{35}}\\boxed{{\\text{ &lt; }}}\\frac{{ &#8211; 25}}{{35}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 4}}{5}\\boxed{{\\text{ &lt; }}}\\frac{{ &#8211; 5}}{7}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 7 \\times 2}}{{8 \\times 2}}\\boxed{{\\text{ }}}\\frac{{14 \\times \\left( { &#8211; 1} \\right)}}{{ &#8211; 16 \\times \\left( { &#8211; 1} \\right)}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 14}}{{16}}\\boxed{{\\text{ = }}}\\frac{{ &#8211; 14}}{{16}}{\/tex} {tex} \\Rightarrow {\/tex}{tex}\\frac{{ &#8211; 7}}{8}\\boxed{{\\text{ = }}}\\frac{{14}}{{ &#8211; 16}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 8 \\times 4}}{{5 \\times 4}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 7 \\times 5}}{{4 \\times 5}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 32}}{{20}}\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 35}}{{20}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 8}}{5}\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 7}}{4}{\/tex}<\/p>\n<p>(v) {tex}\\frac{1}{{ &#8211; 3}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 1}}{4}{\/tex} {tex} \\Rightarrow {\/tex}{tex}\\frac{1}{{ &#8211; 3}}\\boxed{{\\text{ &lt; }}}\\frac{{ &#8211; 1}}{4}{\/tex}<\/p>\n<p>(vi) {tex}\\frac{5}{{ &#8211; 11}}\\boxed{{\\text{ }}}\\frac{{ &#8211; 5}}{{11}}{\/tex} {tex} \\Rightarrow {\/tex}{tex}\\frac{5}{{ &#8211; 11}}\\boxed{{\\text{ = }}}\\frac{{ &#8211; 5}}{{11}}{\/tex}<\/p>\n<p>(vii) {tex}0\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 7}}{6}{\/tex} Since, 0 is greater than every negative number.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_9Which_is_greater_in_each_of_the_following\"><\/span><strong>Question 9.<\/strong>Which is greater in each of the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{2}{3},\\frac{5}{2}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 5}}{6},\\frac{{ &#8211; 4}}{3}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 3}}{4},\\frac{2}{{ &#8211; 3}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 1}}{4},\\frac{1}{4}{\/tex}<\/p>\n<p>(v) {tex} &#8211; 3\\frac{2}{7}, &#8211; 3\\frac{4}{5}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{2 \\times 2}}{{3 \\times 2}} = \\frac{4}{6}{\/tex} and {tex}\\frac{{5 \\times 3}}{{2 \\times 3}} = \\frac{{15}}{6}{\/tex}<\/p>\n<p>Since {tex}\\frac{4}{6}\\boxed{{\\text{ &lt; }}}\\frac{{15}}{6}{\/tex}<\/p>\n<p>Therefore {tex}\\frac{2}{3}\\boxed{{\\text{ }} &lt; {\\text{ }}}\\frac{5}{2}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{{ &#8211; 5 \\times 1}}{{6 \\times 1}} = \\frac{{ &#8211; 5}}{6}{\/tex} and {tex}\\frac{{ &#8211; 4 \\times 2}}{{3 \\times 2}} = \\frac{{ &#8211; 8}}{6}{\/tex}<\/p>\n<p>Since {tex}\\frac{{ &#8211; 5}}{6}\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 8}}{6}{\/tex} Therefore {tex}\\frac{{ &#8211; 5}}{6}\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 4}}{3}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 3 \\times 3}}{{4 \\times 3}} = \\frac{{ &#8211; 9}}{{12}}{\/tex} and {tex}\\frac{{2 \\times \\left( { &#8211; 4} \\right)}}{{ &#8211; 3 \\times \\left( { &#8211; 4} \\right)}} = \\frac{{ &#8211; 8}}{{12}}{\/tex}<\/p>\n<p>Since {tex}\\frac{{ &#8211; 9}}{{12}}\\boxed{{\\text{ &lt; }}}\\frac{{ &#8211; 8}}{{12}}{\/tex}<\/p>\n<p>Therefore {tex}\\frac{{ &#8211; 3}}{4}\\boxed{{\\text{ }} &lt; {\\text{ }}}\\frac{2}{{ &#8211; 3}}{\/tex}<\/p>\n<p>(iv) {tex}\\frac{{ &#8211; 1}}{4}\\boxed{{\\text{ &lt; }}}\\frac{1}{4}{\/tex} Since positive number is always greater than negative number.<\/p>\n<p>(v) {tex} &#8211; 3\\frac{2}{7} = \\frac{{ &#8211; 23}}{7} = \\frac{{ &#8211; 23 \\times 5}}{{7 \\times 5}} = \\frac{{ &#8211; 115}}{{35}}{\/tex} and {tex} &#8211; 3\\frac{4}{5} = \\frac{{ &#8211; 19}}{5} = \\frac{{ &#8211; 19 \\times 7}}{{5 \\times 7}} = \\frac{{ &#8211; 133}}{{35}}{\/tex}<\/p>\n<p>Since {tex}\\frac{{ &#8211; 115}}{{35}}\\boxed{{\\text{ &gt; }}}\\frac{{ &#8211; 133}}{{35}}{\/tex}<\/p>\n<p>Therefore{tex} &#8211; 3\\frac{2}{7}\\boxed{{\\text{ &gt; }}} &#8211; 3\\frac{4}{5}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 9.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_10Write_the_following_rational_numbers_in_ascending_order\"><\/span><strong>Question 10.<\/strong>Write the following rational numbers in ascending order:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}\\frac{{ &#8211; 3}}{5},\\frac{{ &#8211; 2}}{5},\\frac{{ &#8211; 1}}{5}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{1}{3},\\frac{{ &#8211; 2}}{9},\\frac{{ &#8211; 4}}{3}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 3}}{7},\\frac{{ &#8211; 3}}{2},\\frac{{ &#8211; 3}}{4}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\frac{{ &#8211; 3}}{5},\\frac{{ &#8211; 2}}{5},\\frac{{ &#8211; 1}}{5}{\/tex}{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 3}}{5} &lt; \\frac{{ &#8211; 2}}{5} &lt; \\frac{{ &#8211; 1}}{5}{\/tex}<\/p>\n<p>(ii) {tex}\\frac{1}{3},\\frac{{ &#8211; 2}}{9},\\frac{{ &#8211; 4}}{3}{\/tex} {tex} \\Rightarrow {\/tex}{tex}\\frac{3}{9},\\frac{{ &#8211; 2}}{9},\\frac{{ &#8211; 12}}{9}{\/tex} [Converting into same denominator]\n<p>Now {tex}\\frac{{ &#8211; 12}}{9} &lt; \\frac{{ &#8211; 2}}{9} &lt; \\frac{3}{9}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 4}}{3} &lt; \\frac{{ &#8211; 2}}{9} &lt; \\frac{1}{3}{\/tex}<\/p>\n<p>(iii) {tex}\\frac{{ &#8211; 3}}{7},\\frac{{ &#8211; 3}}{2},\\frac{{ &#8211; 3}}{4}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; 3}}{2} &lt; \\frac{{ &#8211; 3}}{4} &lt; \\frac{{ &#8211; 3}}{7}{\/tex}<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_91\"><\/span>NCERT Solutions for Class 7 Maths Exercise 9.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 9.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 7 Maths Exercise 9.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-9-1\/\" aria-label=\"More on NCERT Solutions for Class 7 Maths Exercise 9.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1388,281],"tags":[283,1535,321,1485,216],"class_list":["post-4314","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-07","category-ncert-solutions","tag-cbse-study-material","tag-class-7","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 7 Maths Exercise 9.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 7 Maths Exercise 9.1 in PDF format for free download. 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