{"id":4301,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-2\/"},"modified":"2018-07-06T18:16:24","modified_gmt":"2018-07-06T12:46:24","slug":"ncert-solutions-for-class-7-maths-exercise-4-4","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 4.4"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#NCERT_Solutions_for_Class_7_Maths_Simple_Equations\" >NCERT Solutions for Class 7 Maths\u00a0Simple Equations<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#Class_%E2%80%93VII_Mathematics_Ex_44\" >Class \u2013VII Mathematics (Ex. 4.4)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#Question_1Set_up_equations_and_solve_them_to_find_the_unknown_numbers_in_the_following_cases\" >Question 1.Set up equations and solve them to find the unknown numbers in the following cases:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#Question_2Solve_the_following\" >Question 2.Solve the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#Question_3Solve_the_following\" >Question 3.Solve the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#Question_4Solve_the_following_riddle\" >Question 4.Solve the following riddle:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#NCERT_Solutions_for_Class_7_Maths_Exercise_44\" >NCERT Solutions for Class 7 Maths Exercise 4.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-4\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 4.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Simple Equations\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-simple-equations\/1513\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 4.4\" width=\"164\" height=\"208\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Simple_Equations\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Simple Equations<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VII_Mathematics_Ex_44\"><\/span><strong>Class \u2013VII Mathematics (Ex. 4.4)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Set_up_equations_and_solve_them_to_find_the_unknown_numbers_in_the_following_cases\"><\/span><strong>Question 1.<\/strong>Set up equations and solve them to find the unknown numbers in the following cases:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>Add 4 to eight times a number; you get 60.<\/li>\n<li>One-fifth of a number minus 4 gives 3.<\/li>\n<li>If I take three-fourth of a number and add 3 to it, I get 21.<\/li>\n<li>When I subtracted 11 from twice a number, the result was 15.<\/li>\n<li>Munna subtracts thrice the number of notebooks he has from 50, he finds the result to be 8.<\/li>\n<li>Ibenhal thinks of a number. If she adds 19 to it divides the sum by 5, she will get 8.<\/li>\n<li>Answer thinks of a number. If he takes away 7 from {tex}\\frac{5}{2}{\/tex} of the number, the result is {tex}\\frac{{11}}{2}.{\/tex}<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Let the number be {tex}x.{\/tex}<\/p>\n<p>According to the question, {tex}8x + 4 = 60{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}8x = 60 &#8211; 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}8x = 56{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}x = \\frac{{56}}{8}{\/tex} {tex} \\Rightarrow {\/tex} {tex}x = 7{\/tex}<\/p>\n<p>(b) Let the number be {tex}y.{\/tex}<\/p>\n<p>According to the question, {tex}\\frac{y}{5} &#8211; 4 = 3{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{y}{5} = 3 + 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{y}{5} = 7{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}y = 7 \\times 5{\/tex} {tex} \\Rightarrow {\/tex} {tex}y = 35{\/tex}<\/p>\n<p>(c) Let the number be {tex}z.{\/tex}<\/p>\n<p>According to the question, {tex}\\frac{3}{4}z + 3 = 21{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{3}{4}z = 21 &#8211; 3{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{3}{4}z = 18{\/tex} {tex} \\Rightarrow {\/tex} {tex}3z = 18 \\times 4{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}3z = 72{\/tex} {tex} \\Rightarrow {\/tex} {tex}z = \\frac{{72}}{3}{\/tex} {tex} \\Rightarrow {\/tex} {tex}z = 24{\/tex}<\/p>\n<p>(d) Let the number be {tex}x.{\/tex}<\/p>\n<p>According to the question, {tex}2x &#8211; 11 = 15{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}2x = 15 + 11{\/tex} {tex} \\Rightarrow {\/tex} {tex}2x = 26{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}x = \\frac{{26}}{2}{\/tex} {tex} \\Rightarrow {\/tex} {tex}x = 13{\/tex}<\/p>\n<p>(e) Let the number be {tex}m.{\/tex}<\/p>\n<p>According to the question, {tex}50 &#8211; 3m = 8{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 3m = 8 &#8211; 50{\/tex} {tex} \\Rightarrow {\/tex} {tex} &#8211; 3m = &#8211; 42{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}m = \\frac{{ &#8211; 42}}{{ &#8211; 3}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}m = 14{\/tex}<\/p>\n<p>(f) Let the number be {tex}n.{\/tex}<\/p>\n<p>According to the question, {tex}\\frac{{n + 19}}{5} = 8{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}n + 19 = 8 \\times 5{\/tex} {tex} \\Rightarrow {\/tex} {tex}n + 19 = 40{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}n = 40 &#8211; 19{\/tex} {tex} \\Rightarrow {\/tex} {tex}n = 21{\/tex}<\/p>\n<p>(g) Let the number be {tex}x.{\/tex}<\/p>\n<p>According to the question, {tex}\\frac{5}{2}x &#8211; 7 = \\frac{{11}}{2}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{5}{2}x = \\frac{{11}}{2} + 7{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{5}{2}x = \\frac{{11 + 14}}{2}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{5}{2}x = \\frac{{25}}{2}{\/tex} {tex} \\Rightarrow {\/tex} {tex}5x = \\frac{{25 \\times 2}}{2}{\/tex} {tex} \\Rightarrow {\/tex} {tex}5x = 25{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}x = \\frac{{25}}{5}{\/tex} {tex} \\Rightarrow {\/tex} {tex}x = 5{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Solve_the_following\"><\/span><strong>Question 2.<\/strong>Solve the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>The teacher tells the class that the highest marks obtained by a student in her class are twice the lowest marks plus 7. The highest score is 87. What is the lowest score?<\/li>\n<li>In an isosceles triangle, the base angles are equal. The vertex angle is {tex}40^\\circ .{\/tex} What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is {tex}180^\\circ .{\/tex})<\/li>\n<li>Sachin scored twice as many runs as Rahul. Together, their runs fell two short of a double century. How many runs did each one score?<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Let the lowest marks be {tex}y.{\/tex}<\/p>\n<p>According to the question, {tex}2y + 7 = 87{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}2y = 87 &#8211; 7{\/tex} {tex} \\Rightarrow {\/tex} {tex}2y = 80{\/tex} {tex} \\Rightarrow {\/tex} {tex}y = \\frac{{80}}{2}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}y = 40{\/tex}<\/p>\n<p>Thus, the lowest score is 40.<\/p>\n<p>(b) Let the base angle of the triangle be {tex}b.{\/tex}<\/p>\n<p>Given, {tex}a = 40^\\circ ,b = c{\/tex}<\/p>\n<p>Since, {tex}a + b + c = 180^\\circ {\/tex} [Angle sum property of a triangle]\n<p>{tex} \\Rightarrow {\/tex} {tex}40^\\circ + b + b = 180^\\circ {\/tex}<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/07\/mathematics\/07_math_ncert_ch04_01.jpg\" \/><\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}40^\\circ + 2b = 180^\\circ {\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}2b = 180^\\circ &#8211; 40^\\circ {\/tex} {tex} \\Rightarrow {\/tex} {tex}2b = 140^\\circ {\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}b = \\frac{{140^\\circ }}{2}{\/tex} {tex} \\Rightarrow {\/tex} {tex}b = 70^\\circ {\/tex}<\/p>\n<p>Thus, the base angles of the isosceles triangle are {tex}70^\\circ {\/tex} each.<\/p>\n<p>(c) Let the score of Rahul be {tex}x{\/tex} runs and Sachin\u2019s score is {tex}2x.{\/tex}<\/p>\n<p>According to the question, {tex}x + 2x = 198{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}3x = 198{\/tex} {tex} \\Rightarrow {\/tex} {tex}x = \\frac{{198}}{3}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}x = 66{\/tex}<\/p>\n<p>Thus, Rahul\u2019s score = 66 runs<\/p>\n<p>And Sachin\u2019s score = 2 x 66 = 132 runs.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Solve_the_following\"><\/span><strong>Question 3.<\/strong>Solve the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<ol>\n<li>Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. How many marbles does Parmit have?<\/li>\n<li>Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. What is Laxmi\u2019s age?<\/li>\n<li>People of Sundergram planted a total of 102 trees in the village garden. Some of the trees were fruit trees. The number of non-fruit trees were two more than three times the number of fruit trees. What was the number of fruit trees planted?<\/li>\n<\/ol>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) Let the number of marbles Parmit has be {tex}m.{\/tex}<\/p>\n<p>According to the question, {tex}5m + 7 = 37{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}5m = 37 &#8211; 7{\/tex} {tex} \\Rightarrow {\/tex} {tex}5m = 30{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}m = \\frac{{30}}{5}{\/tex} {tex} \\Rightarrow {\/tex} {tex}m = 6{\/tex}<\/p>\n<p>Thus, Parmit has 6 marbles.<\/p>\n<p>(ii) Let the age of Laxmi be {tex}y{\/tex} years.<\/p>\n<p>Then her father\u2019s age = {tex}\\left( {3y + 4} \\right){\/tex} years<\/p>\n<p>According to question, {tex}3y + 4 = 49{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}3y = 49 &#8211; 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}3y = 45{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}y = \\frac{{45}}{3}{\/tex} {tex} \\Rightarrow {\/tex} {tex}y = 15{\/tex}<\/p>\n<p>Thus, the age of Laxmi is 15 years.<\/p>\n<p>(iii) Let the number of fruit trees be {tex}t.{\/tex}<\/p>\n<p>Then the number of non-fruits tree = {tex}3t + 2{\/tex}<\/p>\n<p>According to the question, {tex}t + 3t + 2 = 102{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}4t + 2 = 102{\/tex} {tex} \\Rightarrow {\/tex} {tex}4t = 102 &#8211; 2{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}4t = 100{\/tex} {tex} \\Rightarrow {\/tex} {tex}t = \\frac{{100}}{4}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}t = 25{\/tex}<\/p>\n<p>Thus, the number of fruit trees are 25.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Solve_the_following_riddle\"><\/span><strong>Question 4.<\/strong>Solve the following riddle:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>I am a number, Tell my identity!<\/p>\n<p>Take me seven times over, And add a fifty!<\/p>\n<p>To reach a triple century, You still need forty!<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Let the number be {tex}n.{\/tex}<\/p>\n<p>According to the question, {tex}7n + 50 + 40 = 300{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}7n + 90 = 300{\/tex} {tex} \\Rightarrow {\/tex} {tex}7n = 300 &#8211; 90{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}7n = 210{\/tex} {tex} \\Rightarrow {\/tex} {tex}n = \\frac{{210}}{7}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}n = 30{\/tex}<\/p>\n<p>Thus, the required number is 30.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_44\"><\/span>NCERT Solutions for Class 7 Maths Exercise 4.4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 4.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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