{"id":4299,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-simple-equations-ex-4-2\/"},"modified":"2018-07-06T17:52:09","modified_gmt":"2018-07-06T12:22:09","slug":"ncert-solutions-for-class-7-maths-exercise-4-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 4.2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#NCERT_Solutions_for_Class_7_Maths_Simple_Equations\" >NCERT Solutions for Class 7 Maths\u00a0Simple Equations<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#Question_1Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\" >Question 1.Give first the step you will use to separate the variable and then solve the equations:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#Question_2Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\" >Question 2.Give first the step you will use to separate the variable and then solve the equations<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#Question_3Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\" >Question 3.Give first the step you will use to separate the variable and then solve the equations<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#Question_4Solve_the_following_equation\" >Question 4.Solve the following equation:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#NCERT_Solutions_for_Class_7_Maths_Exercise_42\" >NCERT Solutions for Class 7 Maths Exercise 4.2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 4.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Simple Equations\u00a0<\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-simple-equations\/1513\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 4.2\" width=\"164\" height=\"208\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Simple_Equations\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Simple Equations<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: center;\"><strong>Class \u2013VII Mathematics (Ex. 4.2)<\/strong><\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\"><\/span><strong>Question 1.<\/strong>Give first the step you will use to separate the variable and then solve the equations:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}x &#8211; 1 = 0{\/tex}<\/p>\n<p>(b) {tex}x + 1 = 0{\/tex}<\/p>\n<p>(c) {tex}x &#8211; 1 = 5{\/tex}<\/p>\n<p>(d) {tex}x + 6 = 2{\/tex}<\/p>\n<p>(e) {tex}y &#8211; 4 = &#8211; 7{\/tex}<\/p>\n<p>(f) {tex}y &#8211; 4 = 4{\/tex}<\/p>\n<p>(g) {tex}y + 4 = 4{\/tex}<\/p>\n<p>(h) {tex}y + 4 = &#8211; 4{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}x &#8211; 1 = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}x &#8211; 1 + 1 = 0 + 1{\/tex} [Adding 1 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}x = 1{\/tex}<\/p>\n<p>(b) {tex}x + 1 = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}x + 1 &#8211; 1 = 0 &#8211; 1{\/tex} [Subtracting 1 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}x = &#8211; 1{\/tex}<\/p>\n<p>(c) {tex}x &#8211; 1 = 5{\/tex} {tex} \\Rightarrow {\/tex} {tex}x &#8211; 1 + 1 = 5 + 1{\/tex} [Adding 1 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}x = 6{\/tex}<\/p>\n<p>(d) {tex}x + 6 = 2{\/tex} {tex} \\Rightarrow {\/tex} {tex}x + 6 &#8211; 6 = 2 &#8211; 6{\/tex} [Subtracting 6 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}x = &#8211; 4{\/tex}<\/p>\n<p>(e) {tex}y &#8211; 4 = &#8211; 7{\/tex} {tex} \\Rightarrow {\/tex} {tex}y &#8211; 4 + 4 = &#8211; 7 + 4{\/tex} [Adding 4 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}y = &#8211; 3{\/tex}<\/p>\n<p>(f) {tex}y &#8211; 4 = 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}y &#8211; 4 + 4 = 4 + 4{\/tex} [Adding 4 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}y = 8{\/tex}<\/p>\n<p>(g) {tex}y + 4 = 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}y + 4 &#8211; 4 = 4 &#8211; 4{\/tex} [Subtracting 4 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}y = 0{\/tex}<\/p>\n<p>(h) {tex}y + 4 = &#8211; 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}y + 4 &#8211; 4 = &#8211; 4 &#8211; 4{\/tex} [Subtracting 4 both sides]\n<p>{tex} \\Rightarrow {\/tex} {tex}y = &#8211; 8{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\"><\/span><strong>Question 2.<\/strong>Give first the step you will use to separate the variable and then solve the equations<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}3l = 42{\/tex}<\/p>\n<p>(b) {tex}\\frac{b}{2} = 6{\/tex}<\/p>\n<p>(c) {tex}\\frac{p}{7} = 4{\/tex}<\/p>\n<p>(d) {tex}4x = 25{\/tex}<\/p>\n<p>(e) {tex}8y = 36{\/tex}<\/p>\n<p>(f) {tex}\\frac{z}{3} = \\frac{5}{4}{\/tex}<\/p>\n<p>(g) {tex}\\frac{a}{5} = \\frac{7}{{15}}{\/tex}<\/p>\n<p>(h) {tex}20t = &#8211; 10{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}3l = 42{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3l}}{3} = \\frac{{42}}{3}{\/tex} [Dividing both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}l = 14{\/tex}<\/p>\n<p>(b) {tex}\\frac{b}{2} = 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{b}{2} \\times 2 = 6 \\times 2{\/tex} [Multiplying both sides by 2]\n<p>{tex} \\Rightarrow {\/tex} {tex}b = 12{\/tex}<\/p>\n<p>(c) {tex}\\frac{p}{7} = 4{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{p}{7} \\times 7 = 4 \\times 7{\/tex} [Multiplying both sides by 7]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 28{\/tex}<\/p>\n<p>(d) {tex}4x = 25{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{4x}}{4} = \\frac{{25}}{4}{\/tex} [Dividing both sides by 4]\n<p>{tex} \\Rightarrow {\/tex} {tex}x = \\frac{{25}}{4}{\/tex}<\/p>\n<p>(e) {tex}8y = 36{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{8y}}{8} = \\frac{{36}}{8}{\/tex} [Dividing both sides by 8]\n<p>{tex} \\Rightarrow {\/tex} {tex}y = \\frac{9}{2}{\/tex}<\/p>\n<p>(f) {tex}\\frac{z}{3} = \\frac{5}{4}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{z}{3} \\times 3 = \\frac{5}{4} \\times 3{\/tex} [Multiplying both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}z = \\frac{{15}}{4}{\/tex}<\/p>\n<p>(g) {tex}\\frac{a}{5} = \\frac{7}{{15}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{a}{5} \\times 5 = \\frac{7}{{15}} \\times 5{\/tex} [Multiplying both sides by 5]\n<p>{tex} \\Rightarrow {\/tex} {tex}a = \\frac{7}{3}{\/tex}<\/p>\n<p>(h) {tex}20t = &#8211; 10{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{20t}}{{20}} = \\frac{{ &#8211; 10}}{{20}}{\/tex} [Dividing both sides by 20]\n<p>{tex} \\Rightarrow {\/tex} {tex}t = \\frac{{ &#8211; 1}}{2}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Give_first_the_step_you_will_use_to_separate_the_variable_and_then_solve_the_equations\"><\/span><strong>Question 3.<\/strong>Give first the step you will use to separate the variable and then solve the equations<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}3n &#8211; 2 = 46{\/tex}<\/p>\n<p>(b) {tex}5m + 7 = 17{\/tex}<\/p>\n<p>(c) {tex}\\frac{{20p}}{3} = 40{\/tex}<\/p>\n<p>(d) {tex}\\frac{{3p}}{{10}} = 6{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}3n &#8211; 2 = 46{\/tex}<\/p>\n<p><strong>Step I<\/strong>: {tex}3n &#8211; 2 + 2 = 46 + 2{\/tex} {tex} \\Rightarrow {\/tex} {tex}3n = 48{\/tex}<\/p>\n[Adding 2 both sides]\n<p><strong>Step II:<\/strong> {tex}\\frac{{3n}}{3} = \\frac{{48}}{3}{\/tex} {tex} \\Rightarrow {\/tex} {tex}n = 16{\/tex} [Dividing both sides by 3]\n<p>(b) {tex}5m + 7 = 17{\/tex}<\/p>\n<p><strong>Step I<\/strong>: {tex}5m + 7 &#8211; 7 = 17 &#8211; 7{\/tex} {tex} \\Rightarrow {\/tex} {tex}5m = 10{\/tex} [Subtracting 7 both sides]\n<p><strong>Step II<\/strong>: {tex}\\frac{{5m}}{5} = \\frac{{10}}{5}{\/tex} {tex} \\Rightarrow {\/tex}{tex}m = 2{\/tex} [Dividing both sides by 5]\n<p>(c) {tex}\\frac{{20p}}{3} = 40{\/tex}<\/p>\n<p><strong>Step I<\/strong>: {tex}\\frac{{20p}}{3} \\times 3 = 40 \\times 3{\/tex} {tex} \\Rightarrow {\/tex} {tex}20p = 120{\/tex} [Multiplying both sides by 3]\n<p><strong>Step II<\/strong>: {tex}\\frac{{20p}}{{20}} = \\frac{{120}}{{20}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}p = 6{\/tex} [Dividing both sides by 20]\n<p>(d) {tex}\\frac{{3p}}{{10}} = 6{\/tex}<\/p>\n<p><strong>Step I<\/strong>: {tex}\\frac{{3p}}{{10}} \\times 10 = 6 \\times 10{\/tex} {tex} \\Rightarrow {\/tex} {tex}3p = 60{\/tex} [Multiplying both sides by 10]\n<p><strong>Step II<\/strong>: {tex}\\frac{{3p}}{3} = \\frac{{60}}{3}{\/tex} {tex} \\Rightarrow {\/tex} {tex}p = 20{\/tex} [Dividing both sides by 3]\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.2<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Solve_the_following_equation\"><\/span><strong>Question 4.<\/strong>Solve the following equation:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}10p = 100{\/tex}<\/p>\n<p>(b) {tex}10p + 10 = 100{\/tex}<\/p>\n<p>(c) {tex}\\frac{p}{4} = 5{\/tex}<\/p>\n<p>(d) {tex}\\frac{{ &#8211; p}}{3} = 5{\/tex}<\/p>\n<p>(e) {tex}\\frac{{3p}}{4} = 6{\/tex}<\/p>\n<p>(f) {tex}3s = &#8211; 9{\/tex}<\/p>\n<p>(g) {tex}3s + 12 = 0{\/tex}<\/p>\n<p>(h) {tex}3s = 0{\/tex}<\/p>\n<p>(i) {tex}2q = 6{\/tex}<\/p>\n<p>(j) {tex}2q &#8211; 6 = 0{\/tex}<\/p>\n<p>(k) {tex}2q + 6 = 0{\/tex}<\/p>\n<p>(l) {tex}2q + 6 = 12{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}10p = 100{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{10p}}{{10}} = \\frac{{100}}{{10}}{\/tex} [Dividing both sides by 10]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 10{\/tex}<\/p>\n<p>(b) {tex}10p + 10 = 100{\/tex} {tex} \\Rightarrow {\/tex} {tex}10p + 10 &#8211; 10 = 100 &#8211; 10{\/tex} [Subtracting both sides 10]\n<p>{tex} \\Rightarrow {\/tex} {tex}10p = 90{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{10p}}{{10}} = \\frac{{90}}{{10}}{\/tex} [Dividing both sides by 10]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 9{\/tex}<\/p>\n<p>(c) {tex}\\frac{p}{4} = 5{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{p}{4} \\times 4 = 5 \\times 4{\/tex} [Multiplying both sides by 4]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 20{\/tex}<\/p>\n<p>(d) {tex}\\frac{{ &#8211; p}}{3} = 5{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{ &#8211; p}}{3} \\times \\left( { &#8211; 3} \\right) = 5 \\times \\left( { &#8211; 3} \\right){\/tex} [Multiplying both sides by \u2013 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = &#8211; 15{\/tex}<\/p>\n<p>(e) {tex}\\frac{{3p}}{4} = 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3p}}{4} \\times 4 = 6 \\times 4{\/tex} [Multiplying both sides by 4]\n<p>{tex} \\Rightarrow {\/tex} {tex}3p = 24{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3p}}{3} = \\frac{{24}}{3}{\/tex} [Dividing both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}p = 8{\/tex}<\/p>\n<p>(f) {tex}3s = &#8211; 9{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3s}}{3} = \\frac{{ &#8211; 9}}{3}{\/tex} [Dividing both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}s = &#8211; 3{\/tex}<\/p>\n<p>(g) {tex}3s + 12 = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}3s + 12 &#8211; 12 = 0 &#8211; 12{\/tex} [Subtracting both sides 10]\n<p>{tex} \\Rightarrow {\/tex} {tex}3s = &#8211; 12{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3s}}{3} = \\frac{{ &#8211; 12}}{3}{\/tex} [Dividing both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}s = &#8211; 4{\/tex}<\/p>\n<p>(h) {tex}3s = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{3s}}{3} = \\frac{0}{3}{\/tex} [Dividing both sides by 3]\n<p>{tex} \\Rightarrow {\/tex} {tex}s = 0{\/tex}<\/p>\n<p>(i) {tex}2q = 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{2q}}{2} = \\frac{6}{2}{\/tex} [Dividing both sides by 2]\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{\/tex}<\/p>\n<p>(j) {tex}2q &#8211; 6 = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}2q &#8211; 6 + 6 = 0 + 6{\/tex} [Adding both sides 6]\n<p>{tex} \\Rightarrow {\/tex} {tex}2q = 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{2q}}{2} = \\frac{6}{2}{\/tex} [Dividing both sides by 2]\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{\/tex}<\/p>\n<p>(k) {tex}2q + 6 = 0{\/tex} {tex} \\Rightarrow {\/tex} {tex}2q + 6 &#8211; 6 = 0 &#8211; 6{\/tex} [Subtracting both sides 6]\n<p>{tex} \\Rightarrow {\/tex} {tex}2q = &#8211; 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{2q}}{2} = \\frac{{ &#8211; 6}}{2}{\/tex} [Dividing both sides by 2]\n<p>{tex} \\Rightarrow {\/tex} {tex}q = &#8211; 3{\/tex}<\/p>\n<p>(l) {tex}2q + 6 = 12{\/tex} {tex} \\Rightarrow {\/tex} {tex}2q + 6 &#8211; 6 = 12 &#8211; 6{\/tex} [Subtracting both sides 6]\n<p>{tex} \\Rightarrow {\/tex} {tex}2q = 6{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{{2q}}{2} = \\frac{6}{2}{\/tex} [Dividing both sides by 2]\n<p>{tex} \\Rightarrow {\/tex} {tex}q = 3{\/tex}<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_42\"><\/span>NCERT Solutions for Class 7 Maths Exercise 4.2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 4.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 7 Maths Exercise 4.2\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-2\/\" aria-label=\"More on NCERT Solutions for Class 7 Maths Exercise 4.2\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1388,281],"tags":[283,1535,321,1485,216],"class_list":["post-4299","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-07","category-ncert-solutions","tag-cbse-study-material","tag-class-7","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 7 Maths Exercise 4.2 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 7 Maths Exercise 4.2 in PDF format for free download. 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