{"id":4298,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-simple-equations-ex-4-1\/"},"modified":"2018-07-06T17:37:39","modified_gmt":"2018-07-06T12:07:39","slug":"ncert-solutions-for-class-7-maths-exercise-4-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 4.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#NCERT_Solutions_for_Class_7_Maths_Simple_Equations\" >NCERT Solutions for Class 7 Maths\u00a0Simple Equations<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Class_%E2%80%93VII_Mathematics_Ex_41\" >Class \u2013VII Mathematics (Ex. 4.1)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_1Complete_the_last_column_of_the_table\" >Question 1.Complete the last column of the table:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_2Check_whether_the_value_given_in_the_brackets_is_a_solution_to_the_given_equation_or_not\" >Question 2.Check whether the value given in the brackets is a solution to the given equation or not:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_3Solve_the_following_equations_by_trial_and_error_method\" >Question 3.Solve the following equations by trial and error method:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_4Write_equations_for_the_following_statements\" >Question 4.Write equations for the following statements:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_5_Write_the_following_equations_in_statement_form\" >Question 5. Write the following equations in statement form:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#Question_6Set_up_an_equation_in_the_following_cases\" >Question 6.Set up an equation in the following cases:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#NCERT_Solutions_for_Class_7_Maths_Exercise_41\" >NCERT Solutions for Class 7 Maths Exercise 4.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-4-1\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 4.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Simple Equations <\/strong><strong><a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-simple-equations\/1513\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 4.1\" width=\"189\" height=\"240\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Simple_Equations\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Simple Equations<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VII_Mathematics_Ex_41\"><\/span><strong>Class \u2013VII Mathematics (Ex. 4.1)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Complete_the_last_column_of_the_table\"><\/span><strong>Question 1.<\/strong>Complete the last column of the table:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<table class=\"responsive\" cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td><strong>S. No.<\/strong><\/td>\n<td>Equation<\/td>\n<td>Value<\/td>\n<td><strong>Say, whether the Equation is satisfied. (Yes \/ No)<\/strong><\/td>\n<\/tr>\n<tr>\n<td>1<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x = 3{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>2<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x = 0{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>3<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x =- 3{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>4<\/td>\n<td>{tex}x &#8211; 7 = 1{\/tex}<\/td>\n<td>{tex}x = 7{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>5<\/td>\n<td>{tex}x &#8211; 7 = 1{\/tex}<\/td>\n<td>{tex}x = 8{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>6<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x = 0{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>7<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x = 5{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>8<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x =- 5{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>9<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m =- 6{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>10<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m = 0{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>11<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m = 6{\/tex}<\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>Answer:<\/strong><\/p>\n<table class=\"responsive\" cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td><strong>S. No.<\/strong><\/td>\n<td>Equation<\/td>\n<td>Value<\/td>\n<td><strong>Say, whether the Equation is satisfied. (Yes \/ No)<\/strong><\/td>\n<\/tr>\n<tr>\n<td>1<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x = 3{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>2<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x = 0{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>3<\/td>\n<td>{tex}x + 3 = 0{\/tex}<\/td>\n<td>{tex}x =- 3{\/tex}<\/td>\n<td>Yes<\/td>\n<\/tr>\n<tr>\n<td>4<\/td>\n<td>{tex}x &#8211; 7 = 1{\/tex}<\/td>\n<td>{tex}x = 7{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>5<\/td>\n<td>{tex}x &#8211; 7 = 1{\/tex}<\/td>\n<td>{tex}x = 8{\/tex}<\/td>\n<td>Yes<\/td>\n<\/tr>\n<tr>\n<td>6<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x = 0{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>7<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x = 5{\/tex}<\/td>\n<td>Yes<\/td>\n<\/tr>\n<tr>\n<td>8<\/td>\n<td>{tex}5x = 25{\/tex}<\/td>\n<td>{tex}x =- 5{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>9<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m =- 6{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>10<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m = 0{\/tex}<\/td>\n<td>No<\/td>\n<\/tr>\n<tr>\n<td>11<\/td>\n<td>{tex}\\frac{m}{3} = 2{\/tex}<\/td>\n<td>{tex}m = 6{\/tex}<\/td>\n<td>Yes<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Check_whether_the_value_given_in_the_brackets_is_a_solution_to_the_given_equation_or_not\"><\/span><strong>Question 2.<\/strong>Check whether the value given in the brackets is a solution to the given equation or not:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}n + 5 = 19\\left( {n = 1} \\right){\/tex}<\/p>\n<p>(b) {tex}7n + 5 = 19\\left( {n = &#8211; 2} \\right){\/tex}<\/p>\n<p>(c) {tex}7n + 5 = 19\\left( {n = 2} \\right){\/tex}<\/p>\n<p>(d) {tex}4p &#8211; 3 = 13\\left( {p = 1} \\right){\/tex}<\/p>\n<p>(e) {tex}4p &#8211; 3 = 13\\left( {p = &#8211; 4} \\right){\/tex}<\/p>\n<p>(f) {tex}4p &#8211; 3 = 13\\left( {p = 0} \\right){\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}n + 5 = 19\\left( {n = 1} \\right){\/tex}<\/p>\n<p>Putting {tex}n = 1{\/tex} in L.H.S.,<\/p>\n<p>1 + 5 = 6<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} \\ne {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}n = 1{\/tex} is not the solution of given equation.<\/p>\n<p>(b) {tex}7n + 5 = 19\\left( {n = &#8211; 2} \\right){\/tex}<\/p>\n<p>Putting {tex}n = &#8211; 2{\/tex} in L.H.S.,<\/p>\n<p>{tex}7\\left( { &#8211; 2} \\right) + 5 = &#8211; 14 + 5 = &#8211; 9{\/tex}<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} \\ne {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}n = &#8211; 2{\/tex} is not the solution of given equation.<\/p>\n<p>(c) {tex}7n + 5 = 19\\left( {n = 2} \\right){\/tex}<\/p>\n<p>Putting {tex}n = 2{\/tex} in L.H.S.,<\/p>\n<p>{tex}7\\left( 2 \\right) + 5 = 14 + 5 = 19{\/tex}<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} = {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}n = 2{\/tex} is the solution of given equation.<\/p>\n<p>(d) {tex}4p &#8211; 3 = 13\\left( {p = 1} \\right){\/tex}<\/p>\n<p>Putting {tex}p = 1{\/tex} in L.H.S.,<\/p>\n<p>{tex}4\\left( 1 \\right) &#8211; 3 = 4 &#8211; 3 = 1{\/tex}<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} \\ne {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}p = 1{\/tex} is not the solution of given equation.<\/p>\n<p>(e) {tex}4p &#8211; 3 = 13\\left( {p = &#8211; 4} \\right){\/tex}<\/p>\n<p>Putting {tex}p = &#8211; 4{\/tex} in L.H.S.,<\/p>\n<p>{tex}4\\left( { &#8211; 4} \\right) &#8211; 3 = &#8211; 16 &#8211; 3 = &#8211; 19{\/tex}<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} \\ne {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}p = &#8211; 4{\/tex} is not the solution of given equation.<\/p>\n<p>(f) {tex}4p &#8211; 3 = 13\\left( {p = 0} \\right){\/tex}<\/p>\n<p>Putting {tex}p = 0{\/tex} in L.H.S.,<\/p>\n<p>{tex}4\\left( 0 \\right) &#8211; 3 = 0 &#8211; 3 = &#8211; 3{\/tex}<\/p>\n<p>{tex}\\because {\/tex} L.H.S. {tex} \\ne {\/tex} R.H.S.,<\/p>\n<p>{tex}\\therefore {\/tex} {tex}p = 0{\/tex} is not the solution of given equation.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Solve_the_following_equations_by_trial_and_error_method\"><\/span><strong>Question 3.<\/strong>Solve the following equations by trial and error method:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}5p + 2 = 17{\/tex}<\/p>\n<p>(ii) {tex}3m &#8211; 14 = 4{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}5p + 2 = 17{\/tex}<\/p>\n<p>Putting {tex}p = &#8211; 3{\/tex} in L.H.S. {tex}5\\left( { &#8211; 3} \\right) + 2{\/tex} = {tex} &#8211; 15 + 2 = &#8211; 13{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 13 \\ne 17{\/tex} Therefore, {tex}p = &#8211; 3{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = &#8211; 2{\/tex} in L.H.S. {tex}5\\left( { &#8211; 2} \\right) + 2 = {\/tex}{tex} &#8211; 10 + 2 = &#8211; 8{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 8 \\ne 17{\/tex} Therefore, {tex}p = &#8211; 2{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = &#8211; 1{\/tex} in L.H.S. {tex}5\\left( { &#8211; 1} \\right) + 2 = {\/tex}{tex} &#8211; 5 + 2 = &#8211; 3{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 3 \\ne 17{\/tex} Therefore, {tex}p = &#8211; 1{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = 0{\/tex} in L.H.S. {tex}5\\left( 0 \\right) + 2 = {\/tex}{tex}0 + 2 = 2{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}2 \\ne 17{\/tex} Therefore, {tex}p = 0{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = 1{\/tex} in L.H.S. {tex}5\\left( 1 \\right) + 2 = {\/tex}{tex}5 + 2 = 7{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}7 \\ne 17{\/tex} Therefore, {tex}p = 1{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = 2{\/tex} in L.H.S. {tex}5\\left( 2 \\right) + 2 = {\/tex}{tex}10 + 2 = 12{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}12 \\ne 17{\/tex} Therefore, {tex}p = 2{\/tex} is not the solution.<\/p>\n<p>Putting {tex}p = 3{\/tex} in L.H.S. {tex}5\\left( 3 \\right) + 2 = {\/tex}{tex}15 + 2 = 17{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}17 = 17{\/tex} Therefore, {tex}p = 3{\/tex} is the solution.<\/p>\n<p>(ii) {tex}3m &#8211; 14 = 4{\/tex}<\/p>\n<p>Putting {tex}m = &#8211; 2{\/tex} in L.H.S. {tex}3\\left( { &#8211; 2} \\right) &#8211; 14 = &#8211; 6 &#8211; 14 = &#8211; 20{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 20 \\ne 4{\/tex} Therefore, {tex}m = &#8211; 2{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = &#8211; 1{\/tex} in L.H.S. {tex}3\\left( { &#8211; 1} \\right) &#8211; 14 = &#8211; 3 &#8211; 14 = &#8211; 17{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 17 \\ne 4{\/tex} Therefore, {tex}m = &#8211; 1{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 0{\/tex} in L.H.S. {tex}3\\left( 0 \\right) &#8211; 14 = 0 &#8211; 14 = &#8211; 14{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 14 \\ne 4{\/tex} Therefore, {tex}m = 0{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 1{\/tex} in L.H.S. {tex}3\\left( 1 \\right) &#8211; 14 = 3 &#8211; 14 = &#8211; 11{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 11 \\ne 4{\/tex} Therefore, {tex}m = 1{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 2{\/tex} in L.H.S. {tex}3\\left( 2 \\right) &#8211; 14 = 6 &#8211; 14 = &#8211; 8{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 8 \\ne 4{\/tex} Therefore, {tex}m = 2{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 3{\/tex} in L.H.S. {tex}3\\left( 3 \\right) &#8211; 14 = 9 &#8211; 14 = &#8211; 5{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 5 \\ne 4{\/tex} Therefore, {tex}m = 3{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 4{\/tex} in L.H.S. {tex}3\\left( 4 \\right) &#8211; 14 = 12 &#8211; 14 = &#8211; 2{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex} &#8211; 2 \\ne 4{\/tex} Therefore, {tex}m = 4{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 5{\/tex} in L.H.S. {tex}3\\left( 5 \\right) &#8211; 14 = 15 &#8211; 14 = 1{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}1 \\ne 4{\/tex} Therefore, {tex}m = 5{\/tex} is not the solution.<\/p>\n<p>Putting {tex}m = 6{\/tex} in L.H.S. {tex}3\\left( 6 \\right) &#8211; 14 = 18 &#8211; 14 = 4{\/tex}<\/p>\n<p>{tex}\\because {\/tex}{tex}4 = 4{\/tex} Therefore, {tex}m = 6{\/tex} is the solution.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Write_equations_for_the_following_statements\"><\/span><strong>Question 4.<\/strong>Write equations for the following statements:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) The sum of numbers {tex}x{\/tex} and 4 is 9.<\/p>\n<p>(ii) 2 subtracted from {tex}y{\/tex} is 8.<\/p>\n<p>(iii) Ten times {tex}a{\/tex} is 70.<\/p>\n<p>(iv) The number {tex}b{\/tex} divided by 5 gives 6.<\/p>\n<p>(v) Three-fourth of {tex}t{\/tex} is 15.<\/p>\n<p>(vi) Seven times {tex}m{\/tex} plus 7 gets you 77.<\/p>\n<p>(vii) One-fourth of a number {tex}x{\/tex} minus 4 gives 4.<\/p>\n<p>(viii) If you take away 6 from 6 times {tex}y,{\/tex} you get 60.<\/p>\n<p>(ix) If you add 3 to one-third of {tex}z,{\/tex} you get 30.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}x + 4 = 9{\/tex}<\/p>\n<p>(ii) {tex}y &#8211; 2 = 8{\/tex}<\/p>\n<p>(iii) {tex}10a = 70{\/tex}<\/p>\n<p>(iv) {tex}\\frac{b}{5} = 6{\/tex}<\/p>\n<p>(v) {tex}\\frac{3}{4}t = 15{\/tex}<\/p>\n<p>(vi) {tex}7m + 7 = 77{\/tex}<\/p>\n<p>(vii) {tex}\\frac{x}{4} &#8211; 4 = 4{\/tex}<\/p>\n<p>(viii) {tex}6y &#8211; 6 = 60{\/tex}<\/p>\n<p>(ix) {tex}\\frac{z}{3} + 3 = 30{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5_Write_the_following_equations_in_statement_form\"><\/span><strong>Question 5. <\/strong>Write the following equations in statement form:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) {tex}p + 4 = 15{\/tex}<\/p>\n<p>(ii) {tex}m &#8211; 7 = 3{\/tex}<\/p>\n<p>(iii) {tex}2m = 7{\/tex}<\/p>\n<p>(iv) {tex}\\frac{m}{5} = 3{\/tex}<\/p>\n<p>(v) {tex}\\frac{{3m}}{5} = 6{\/tex}<\/p>\n<p>(vi) {tex}3p + 4 = 25{\/tex}<\/p>\n<p>(vii) {tex}4p &#8211; 2 = 18{\/tex}<\/p>\n<p>(viii) {tex}\\frac{p}{2} + 2 = 8{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) The sum of numbers {tex}p{\/tex} and 4 is 15.<\/p>\n<p>(ii) 7 subtracted from {tex}m{\/tex} is 3.<\/p>\n<p>(iii) Two times {tex}m{\/tex} is 7.<\/p>\n<p>(iv) The number {tex}m{\/tex} is divided by 5 gives 3.<\/p>\n<p>(v) Three-fifth of the number {tex}m{\/tex} is 6.<\/p>\n<p>(vi) Three times {tex}p{\/tex} plus 4 gets 25.<\/p>\n<p>(vii) If you take away 2 from 4 times {tex}p,{\/tex} you get 18.<\/p>\n<p>(viii) If you added 2 to half is {tex}p,{\/tex} you get 8.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 4.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_6Set_up_an_equation_in_the_following_cases\"><\/span><strong>Question 6.<\/strong>Set up an equation in the following cases:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i) Irfan says that he has 7 marbles more than five times the marbles Parmit has. Irfan has 37 marbles. (Tale {tex}m{\/tex} to be the number of Parmit\u2019s marbles.)<\/p>\n<p>(ii) Laxmi\u2019s father is 49 years old. He is 4 years older than three times Laxmi\u2019s age. (Take Laxmi\u2019s age to be {tex}y{\/tex} years.)<\/p>\n<p>(iii) The teacher tells the class that the highest marks obtained by a student in her class are twice the lowest marks plus 7. The highest score is 87. (Take the lowest score to be {tex}l.{\/tex} )<\/p>\n<p>(iv) In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be {tex}b{\/tex} in degrees. Remember that the sum of angles of a triangle is {tex}180^\\circ .{\/tex})<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) Let {tex}m{\/tex} be the number of Parmit\u2019s marbles.<\/p>\n<p>{tex}\\therefore {\/tex} {tex}5m + 7 = 37{\/tex}<\/p>\n<p>(ii) Let the age of Laxmi be {tex}y{\/tex} years.<\/p>\n<p>{tex}\\therefore {\/tex} {tex}3y + 4 = 49{\/tex}<\/p>\n<p>(iii) Let the lowest score be {tex}l.{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}2l + 7 = 87{\/tex}<\/p>\n<p>(iv) Let the base angle of the isosceles triangle be {tex}b,{\/tex} so vertex angle = {tex}2b.{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} {tex}2b + b + b = 180^\\circ {\/tex}{tex} \\Rightarrow {\/tex} {tex}4b = 180^\\circ {\/tex} [Angle sum property of a {tex}\\Delta {\/tex}]\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_41\"><\/span>NCERT Solutions for Class 7 Maths Exercise 4.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 4.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. 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